failure to mix a specimen containing an anticoagulant by inverting the sealed specimen container several times after collection of the specimen

445.616 lb of CO2.

Equation for the reaction:

C8H18 + 25/2O2(g) --> 8CO2(g) + 9H2O(g)

Given:

The volume of gasoline = 25gallon

Converting gallon to ml,

25 gallon * 3.785 l/1 gallon * 1000 ml/1 l

= 94,625 ml

Density of the gasoline = 0.692 g/ml

Mass = density * volume

= 94,625 * 0.692

=  65480g

Molar mass of octane = (8*12) + (18*1)

= 114 g/mol.

Number of moles = mass/molar mass

= 65480/114

= 574.390 mol.

From the above equation, 1 mole of octane was completely burnt to give off 8 moles of CO2.

By stoichiometry,

Number of moles of CO2 = 574.390* 8

= 4595.122 mol of CO2.

Molar mass of CO2 = 12 + (2*16)

= 44 g/mol

Mass of CO2 = number of moles * molar mass

= 4595.122 * 44

=202,185.40 g

Converting g to pound,

= 202,185.40 g *1 kg/1000 g * 2.204 lb/1kg

= 445.616 lb of CO2.

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moles of hydrogen present in a 43.50 ml sample at 25.5 degrees celsius and 772.8 torr are 0.0017

This problem can be solved by ideal gas law

PV=nRT

P = pressure, 772.8torr × (1atm/ 760 torr)= 1.01 atm

V = volume, 43.50mL (1L/1000mL)= 0.0435L

T = temperature, 25 deg celcius or 273 +25.5= 298.5K

R = 0.0821 (L*atm/K*mol) (constant)

We have to find out n

n= PV/RT

n= (1.01atm)(0.0435L) / (0.0821 L*atm/K*mol) (298.5K)

n= 0.0439 / 24.5

n = 0.0017

Therefore, no of moles of hydrogen are 0.0017.

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One molecule of sucrose is burned with oxygen to make carbon dioxide and water.

What is sucrose?

The components of the disaccharide sugar sucrose are glucose and fructose. It is produced naturally by plants and is the main component of white sugar. C12H22O11 is the chemical formula for it.

To extract and refine sucrose for human use, either sugarcane or sugar beet are employed. Crushing the cane creates raw sugar, which is subsequently delivered to other sectors to be refined into pure sucrose. Sugar mills are usually located in tropical regions near to sugarcane plantations.

C12H22O11 + 12O2 = 12CO2 + 11H2O

When one molecule of sucrose is burnt, we get 12 carbon dioxide molecules.

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Some of them consist of two small atoms attached to a bigger one. Some are negatively charged, and consist of one big atom attached to the small one. The arrow is pointing to a hydrogen ion.

Option A is correct

The hydrogen ion is the only particle that is an atom and also carry a positive charge, i.e., a hydrogen ion is a positively charged atom.

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Question is in complete , missing part is given below :

The figure shows a solution of different molecules. Some of them consist of two small atoms attached to a bigger one. Some are negatively charged, and consist of one big atom attached to the small one. There are also small positively charged atoms, which are pointed by an arrow.

A. hydrogen ion

B. hydronium ion

C. electron

D. hydroxide ion

E. water molecule

The density is = 2.27 g/ml.

A certain object's mass in relation to its volume is measured by its density. High density is a term used to describe materials that are exceedingly compact and have a high mass.

A substance's density is defined as its mass per unit of volume. Density is most frequently represented by the symbol, however Latin letter D may also be used. Mass divided by volume is the definition of density in mathematics:

row = m/V

where is the density, m is the mass, and V is the volume.

Given in the question:

Mass of piece of sulfur= 227g

The volume of water that has been disoplaced= (150-50)mL =100mL

We can find the density by:

Density = Mass/Volume

Density =  227/100

Density = 2.27 g/ml

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The mass of one mole of this unknown compound 'XY' is 76.26gm.

Given here, the 1 mol of unknown compund 'XY' and mass of X and Y are 35.67gm and 40.59 gm respectively.

Molar mass of XY = molar mass of X + molar mass of Y=35.67gm + 40.59 gm = 76.26gm.

We can find given mass of 'XY' compound by formula,

Mole = Given mass/Molar mass

1= Given mass /molar mass

Given mass = molar mass.

Given mass = 76.26gm.

So, the given mass of XY is equals to 76.26gm.

Mole is defined as the unit of amount of substance. The quantity of amount of substance is measured in mole as 1mol contain exactly 6.023×1023 particles or entities. Mole is calculated by the ratio of the given mass and the molecular mass of the compound.

The relation of mole and molarity is given by the formula, Molarity is equals to no. of moles of solute divided by the solution in litres. S.I unit of molarity is moles per litre.

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The answers would be for 2nd and 3rd composites are X3Z4 and X4Z3.

The given questions is incorrect, the question is that the first emulsion has the formula X2Z3. also what is the chemical formula for alternate and also the third emulsion?

According to the question,

Mass of X in first emulsion = 1.0 g

Mass of Z in first emulsion = 0.472 g

The chemical formula of first emulsion = X2Z3

This means1.0 g of X is over to 2 intelligencers of X

= > One operative of X = 0.5 g of X.

g of Z is similar to 3 intelligencers of Z< = > one operative of Z = 0.15733 g of X.

Now for the Alternate emulsion,

Mass of X = 1.0 g

intelligencers of X = 1.0/0.5 = 2

Mass of Z = 0.420 grams

Number of intelligencers of Z = 0.420/0.15733 = 2.6695 intelligencers

rate of intelligencers of X to Z = 22.6695 = 3 4

Empirical formula of alternate emulsion = X3Z4

Now for the third emulsion,

Mass of X = 1.0 g

Intelligencers of X = 1/0.5 = 2 intelligencers

Mass of Z = 0.236 grams

Number of intelligencers of Z = 0.236/0.15733 = 1.5 intelligencers

Rate of intelligencers of X to Z = 21.5 = 4 3

Empirical formula of third emulsion = X4Z3

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Answer: three significant figures

Explanation: All zeroes between two nonzero digits are significant, for example, 101 contains three significant figures.

Answer:

Born:  21 November, 1851, Baltimore, Maryland, United States

Died: 17 April , 1898, Baltimore, Maryland, United States

He is an American baseball player,  known as being one of the inventors of the spitball pitch, which was rediscovered or reintroduced to the major leagues after he died. He earned run average: 2.86

Explanation:

I hope this helps

Answer:

Tbh it doesn't look right because A D are atoms B E C are molecules.

Explanation:

The reason I think that is because E is the molecule of elements while B and C are molecules of compounds can you maybe recheck?

In this experiment, simple organic compounds as well as more sophisticated organic compounds including amino acids and hydrocarbons were created.

What is Stanley miller's experiment?

Stanley Miller, a scientist, carried out an experiment in 1953 that might shed light on what happened on the early Earth billions of years ago. In a flask containing a mixture of methane, ammonia, hydrogen, and water, he passed an electrical charge across it. Organic substances, such as amino acids, were produced as a result.

Based on the idea that life might have started from simple chemicals found on the early Earth, Miller conducted the renowned experiment in 1953.

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The Avogadro's number is used to obtain the required results as;

1) 4.69 g

2) 4.26 g

3) 2.158 g

4) 381 g

5) 348.5 L

6)  1008 L

7) 3.6 L

8) 4.7 * 10^4 g

9) 112 L

The Avogadro’s number could be used to deduce the amount of substance. Let us recall that in the theory of Professor Avogadro, the mole is the number of elementary entities of a substance. In this case these elementary entities is a reference to the atoms, molecules and ions that could be found in the substance. With that in mind, we shall now carry out the calculations.

1)  6.02 * 10^23 atoms of helium has a mass of 4g

7.06 x 10^23  He atoms of He has a mass of 4.69 g

2) 6.02 * 10^23 atoms of Mg has a mass of 24 g

1.07 x 10^23 Mg atoms has a mass of 4.26 g

3) 6.02 * 10^23 molecules of O2 has a mass of 32 g/mol

4.06 x 10^22 molecules of O2 has a mass of 2.158 g

4) 6.02 * 10^23 molecules of CO has a mass of 28 g

8.19 x 10^24 molecules CO has a mass of 381 g

5) Number of moles = 2800g/180 g/mol = 15.56 moles

Given that 1 mole occupies 22.4 L

15.56 moles occupies 348.5 L

6) Given that 1 mole occupies 22.4 L

45 moles occupies 1008 L

7) Number of moles of Fe = 9.2 g/56 = 0.16 moles

Given that 1 mole occupies 22.4 L

0.16 moles occupies 3.6 L

8) 6.02 * 10^23 particles have a mass of 102 g

2.8 x 10^26 particles have a mass of 4.7 * 10^4 g

9) Given that 1 mole occupies 22.4 L

5 moles of the acid occupies 112 L

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We may never know the number of people became ill or died as a result of the Chernobyl accident because cancer might not occur for many years after the exposure to the ionizing radiation.

Many of the first responders of the Chernobyl accident died within hours or days of working at the explosion site because of acute radiation sickness.

The Chernobyl accident occur in 1986 due to flawed reactor design operated by untrained personnel.

The Chernobyl did cause serious radiation sickness and contamination over a large population. Although it is difficult to determine the extent to which the negative effects of Chernobyl reached.

Radiation exposure is hazardous and impacts health of people in negative ways, causing cancer and other serious and life threatening illness. Chernobyl caused the same effects as explosions caused radioactive particles to scatter and these moved through the ecosystem through bioaccumulation.

The Chernobyl accident showed us that exposure to radiation can affect people to varying extents over different time scales.

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The reactants has greater energy in an exothermic reaction. Exothermic reactions often produce heat as defined by thermochemistry.

Exothermic reactions often produce heat as defined by thermochemistry as "reactions for which the total standard enthalpy change H is negative."

According to the energy diagram below, in an exothermic reaction, the reactants have a greater energy level than the products. The products are therefore more stable than the reactants. Overall, the reaction's H H H is negative, meaning that energy is expelled as heat.

When new bonds form in the products, less energy is produced during an exothermic reaction than is required to break bonds in the reactants. Energy is continuously released during an exothermic process, frequently in the form of heat. Exothermic reactions characterise all combustion processes.

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The nuclide thorium-230 undergoes alpha emission to give radium-226

Thorium-230 undergoes alpha decay, a form of nuclear decay in which an alpha particle is ejected from the nucleus, and as a result, produces alpha radiation. Because of the imbalance in the energy working to hold the nucleus together or drive the nucleus apart caused by unstable isotopes' neutron to proton ratio, these isotopes are unstable.

This thorium then changes into protactinium 234 and experiences beta-negative decay to yield uranium 234 as a byproduct. With a half-life of 245,000 years, this final isotope progressively decays into thorium 230, another unstable nucleus. Only the creation of a stable nucleus can end any such decay chain.

The nuclide whose radioactive decay product is a certain daughter nuclide is referred to as the parent nuclide (plural parent nuclides) in physics.

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The new concentration of the solution of KBr diluted to 500 mL is 0.106 M

To solve this problem, the formula and the procedure that we have to use is:

c1 * v1 = c2 * v2

Where:

Information about the problem:

Applying the dissolution of concentrations formula and clearing the concentration of the diluted solution(c2), we get:

c1 * v1 = c2 * v2

0.530 M * 100.0 mL = c2 * 500.0 mL

c2 = (0.530 M * 100.0 mL ) / 500.0 mL

c2 = 0.106 M

In chemistry a solution is known as a homogeneous mixture of two or more components called:

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[tex] \bf \implies \: 15.5 \: km[/tex]

We know that,

1 m = 1000 km

1 km = 1/1000 m

We have converted 15500 m to km

[tex] \mapsto \bf \frac{155 \cancel{0} \cancel{0}}{10 \cancel{0} \cancel{0}} = \frac{155}{10} = 15.5 \: km[/tex]

Due to the large specific heat capacity of water, Santa Monica Bay, off the coast of Los Angeles, experiences less seasonal temperature variation than the surrounding air.

What is specific heat capacity?

The amount of heat required to increase a substance's temperature by one degree Celsius (°C) in one gram is known as specific heat. Water has a high specific heat, which means that heating it up requires more energy than heating up other substances.

Specific heat capacity (symbol: c) in SI units is the quantity of heat in joules needed to elevate 1 gram of a substance by 1 Kelvin. J/kgK is another way to put it. It is also possible to express a specific heat capacity in terms of calories per gram of temperature in Celsius.

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James Chadwick discovered the neutron, which was the last of the subatomic particles to be characterized.

James Chadwick bombarded alpha particles on the beryllium surface using radioactive decay o polonium as a source. He discovered penetrating particles with no charge. These particles were fast-moving with no positive or negative charge.

These radiations were made incident on paraffin wax. This experiment was very similar to Rutherford's experiment.

The mass of the neutron was almost equal to the mass of the proton but its penetrating power was higher than a proton. It can penetrate several inches of lead.

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The correct answer is [a].The percent by mass of sodium chloride in a solution of 14.0 g of sodium chloride in enough water to make 91.0 g of solution is 15.4%.

Solution, in chemistry, homogenous mixture of two or more substances in relative amounts that can be varied continuously up to what is called the limit of solubility.

The term solution is commonly applied to liquid state of matter, but solutions of gases and solids are possible. Air, for example, is a solution consisting chiefly of oxygen and nitrogen with the trace amounts of several other gases, and brass is a solution composed of copper and zinc.

Solutions play a significant role in the processes of life. In blood plasma, oxygen from the lungs dissolves and chemically joins with hemoglobin in red blood cells before being delivered to the body's tissues. The byproducts of digestion are also transported to other bodily areas in solution. Many real-world situations can be solved by using liquids' capacity to dissolve other liquids or solids.

Chemists take advantage of differences in the solubility to separate and purify materials and to carry out chemical analysis. Most chemical reactions occur in solution and are influenced by solubilities of the reagents. Materials for chemical manufacturing equipment are selected to resist solvent action of their contents.

Percent by mass= [tex]\frac{weight of solute}{weight of solution}[/tex]*100= [tex]\frac{14}{91}*100= 15.4%[/tex][tex]%[/tex]%

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The maximum values of the electric and magnetic fields is 3.42*[tex]10^{-6}[/tex] T.

Electric fields arise from the electric charges and changing magnetic fields.

An electric charge, or collection of the charges, will have an associated electric field. Any charged object placed in this field will experience an electrostatic force as field interacts with the charge of the object. Field lines represent force a positively charged particle would experience if it were in the field at that point.

A changing magnetic field can also cause the electric charges to move. This phenomenon is commonly used in the electric generators to induce electric currents in wires. The induced current can be increased by causing the larger changes in the magnetic field or by coiling the wire so that more wire is affected by the changing magnetic field.

Magnetic fields arise from the permanent magnets and electric charges in motion.

Magnets can occur naturally (such as the Earth’s magnetic field), or they can be made by magnetizing the ferromagnetic materials.

Intensity I = 1.4*[tex]10^{3}[/tex] w/[tex]m^{2}[/tex]

Total Energy density  [tex]U_{avg}[/tex] = [tex]\frac{1}{2} E_{o}E_{o} ^{2}[/tex]

a) energy density = I/C

  Therefore,  1/2 [tex]E_{o}E_{o}^{2}[/tex] = I/C

     1/2 * 8.85 * [tex]10^{-12}[/tex] * [tex]E_{o}^{2}[/tex] = 1400/(3*[tex]10^{8}[/tex])

[tex]E_{o} ^{2}[/tex] = 105.46*[tex]10^{4}[/tex]

[tex]E_{o}[/tex] = 10.27*[tex]10^{2}[/tex] N/C

[tex]B_{o}[/tex] = [tex]\frac{E_{o} }{C}[/tex] = (10.27*[tex]10^{2}[/tex])/ (3*[tex]10^{8}[/tex]) = 3.42*[tex]10^{-6}[/tex] T

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Answer: 106.68 cm

Explanation:

1 inch=2.54 cm

42 inches * 2.54 cm/1 in=

42 * 2.54 = 106.68 cm

20^250 unique sequence can be formed with different 250 amino acid long polypeptides.

Therefore, the correct option is a) 20^250

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Answer: sodium ethanoate

Explanation: I believe that this is correct

The balanced chemical reaction is: ca(oh)2(aq) + 2hcl(aq)-->2 h2o(l).

Redox is a sort of chemical reaction where the substrate's oxidation states change.

An rise in an object's oxidation state or the loss of electrons is referred to as oxidation.

Gaining electrons or lowering an atom's oxidation state are both considered to be reductions in the context of chemical reactions.

Redox reactions can be divided into two categories:

only one electron (typically) moves from the reducing agent to the oxidant during an electron transfer. Redox couples and electrode potentials are frequently used to describe this type of redox reaction.

Atomic transfer refers to the movement of an atom from one substrate to another. For instance, when iron rusts, iron atoms get more oxidized as they change into an oxide at the same time.

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Answer:

has no nucleus; found in unicellular organisms

Explanation:

Hope It Helps

Sorry If I'm Wrong

Answer: Has no nucleus found in unicellular organisms

Explanation:

Prokaryotic cells are primitive cells found in lower organisms. Prokaryotic cells do not have a true cell.

A true nucleus lacks an envelope which contains the nuclear materials.

Most of the organelles lacks membrane bound organelles.

The true nucleus is lacking in prokaryotes.

Eukaryotic cells have true nucleus.

PH = 2.64

PH = - log [H+]

[H+] = 0.00229 M

HA = 0.0199 M

Dissociation equation

HA --> H+ + A-

Ka = [H+][A-]/[HA]

[H+] = [A-]

Ka = (0.00229^2)/0.0158

=3.31 x 10^-4M

What is monoprotic acids?

Any acid with only one hydrogen atom in its formula is called a monoprotic acid, while some acids with multiple hydrogen atoms may also fall under this category. In other words, while all monoprotic acids contain only one hydrogen, not all single-hydrogen acids are monoprotic.
Therefore,

Enough of a monoprotic acid is dissolved in water to produce a 0.0158 m solution. the ph of the resulting solution is 2.64. calculate the a for the acid.

pH = 2.64

pH = - log [H+]

[H+] = 0.00229 M

HA = 0.0199 M

Dissociation equation

HA --> H+ + A-

Ka = [H+][A-]/[HA]

[H+] = [A-]

Ka = (0.00229^2)/0.0158

=3.31 x 10^-4M

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Since half-life of carbon-14 is 5600 years, 1.5625mg of the element will be remaining after 33600 years.

The duration needed for a quantity of a substance to decrease to half of its initial value is known as the half-life. In nuclear physics, the phrase is frequently used to indicate how rapidly unstable atoms disintegrate radioactively or how prolonged stable atoms last. The duration it takes for half of an element in a radioisotope to decay is known as the half-life. The faster an atom decays and the shorter its half-life, the more unstable it is. Additionally, the phrase can be used more broadly to describe any kind of exponential decay.

Given:

Initial quantity of substance, [tex]N_0[/tex] = 100mg

Half-life of the substance, [tex]t_{1/2}[/tex] = 5600 years

Time elapsed, t = 33600 years

To find:

Quantity of substance remaining, [tex]N_t[/tex] = ?

Formula:

[tex]N_t = N_0 * (\frac{1}{2}) ^ (\frac{t}{t_\frac{1}{2} } )[/tex]

Calculations:

[tex]N_t = 100 * (\frac{1}{2}) ^ \frac{33600}{5600}[/tex]

[tex]N_t = 100 * (\frac{1}{2}) ^6[/tex]

[tex]N_t[/tex] = 100 x 0.015625

[tex]N_t[/tex] = 1.5625mg

Result:

Remaining carbon-14 after 33600 years is 1.5625mg.

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Am, In, Ta, As, Se, Rn, Hf, Am

Tantalum and hafnium are transition metals.

An inner transition element is americium.

Main group elements include radon, selenium, and indium.

Metalloids include arsenic.

What is transition metals?

The concise IUPAC definition is expanded by Cotton and Wilkinson by detailing which elements are included. They add scandium and yttrium from group 3, which have a partially full d sub-shell in the metallic state, along with the elements of groups 4 to 11.

They classify lanthanum and actinium as group 3 elements, while they are actually categorized as lanthanides and actinides, respectively.

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