Explanation:
The X chromosome (females have 2 of them while males have 1) is five times larger than the Y chromosome and has 10 times the number of genes.
A roller coaster has a mass of 250 kg,
and is 50 meters above the ground, what
is the potential energy?
A roller coaster has a mass of 250 kg, and it is 50 meters above the ground, then the potential energy will be equal to 122.5 KJ.
What is Potential energy?Potential energy is a type of energy stored that depends on the interaction between various substances. A spring's energy rises when it is crushed or expanded. A steel ball has more energy stored if it is lifted just above the floor as contrasted to dropping to the ground. As raised, it can do greater labor.
Instead of being a property of specific entities or atoms, potential energy is a property of systems. For instance, a system made up of Earth and the raised ball has far more stored energy as they move apart.
In system components, where the configurations, or spatial arrangements, dictate the magnitude of the forces that apply against one another, potential energy arises.
From the data given in the question,
Mass, m = 250 kg
Height, h = 50 meters and,
g = 9.8 m/s²
[tex]Potential energy(PE)=mgh[/tex]
PE = 250 × 50 × 9.8
PE = 122500 J or,
PE = 122.5 KJ.
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At am outdoor market, a bunch of bananas is set into oscillatory motion with an amplitude of 29.8981 cm on spring with a spring constant
Answer:
Hello your question lacks some very vital information hence I will give you a general equation where you can input the missing values and get your answer
answer : mass of Bananas ( m ) = [tex]\frac{A^2}{V^2} * K[/tex]
To calculate for weight of Bananas = m * g where g = 9.8
Explanation:
Given an amplitude ( A )= 29.8981
Spring constant = x ( unknown )
maximum speed of Bananas( v ) = wA ( unknown )
question : calculate the weight of the bananas
First step : calculate the period of oscillation
T = [tex]\frac{2\pi }{vA}[/tex] --- ( 1 )
next step : express T in terms of mass ( m ) of the bananas
= [tex]2\pi \sqrt{\frac{m}{k} } = \frac{2\pi }{vA}[/tex]
∴ m/k = A^2 / v^2
hence mass of Bananas ( m ) = [tex]\frac{A^2}{V^2} * K[/tex]
To calculate for weight = m * g
A boy who is riding his bicycle, moves with an initial velocity of 5 m/s. ten second later, he is moving at 15 m/s. what is his acceleration
Answer:
1 m/s²
Explanation:
From the question,
Using
a = (v-u)/t.................... Equation 1
Where a = accelartion of the bicycle, v = Final velocity, u = initial velocity, t = time.
Given: v = 15 m/s, u = 5 m/s, t = 10 s
Substitute these values into equation 1
a = (15-5)/10
a = 10/10
a = 1 m/s²
Hence the acceleration of the bicycle is 1 m/s²
A marble has a volume of 1 mL. How much water will it displace in a graduated cyclinder
A.
1 mm
B.
more than 1 mL
C.
less than 1 mL
D.
1mL
A decibel measures the _____________ of sound.
A.pitch
B,frequency
C.loudness
D.amplitude
You are sharing a house with a few roommates. One of them plays on the basketball team, and is exactly 200 cm tall. The heights of you and the other roommates are 188 cm, 175 cm, and 160 cm. You want to buy the minimum height mirror that will allow all of you to see your entire selves, when the mirror is mounted in a fixed position on the wall. Assume each person's eyes are at a level 95% of their height. How tall a mirror should you buy
Answer:
119 cm
Explanation:
Given heights : 200cm , 188 cm , 175 cm, 160 cm
since the eyes are at 95% level
95% of 200 cm = 190 cm
95% of 160 cm = 152 cm
hence the allowable height of mirror = 200 - ( 5 + 76 ) = 119 cm
and The mirror should be hung 75cm from the floor
Which of the following ways of writing 1000w is incorrect?
1) 1 kW
2) 1 x 10³ W
3) 10 x 10³ W
4) 1.0 x 10³ W
Answer:
the third one is incorrect
Explanation:
10 x 10³= 10^1 x 10^3 = 10^4
Find the tension in the two groups that are holding the 2.9 kg object in Pl., One makes an angle of 35.6° with respect to the vertical group 2 is pulling horizontally
Answer:
≈ 20.35 N [newton's of tension]
Explanation:
( (2.9 × 9.8) ÷ cos(35.6°) ) × sin (35.6°) =
( (28.42) ÷ (≈0.813) ) × (≈0.582) =
(≈34.96) × (≈0.582) = 20.3449446.... ≈ 20.35
Thomas helps his older brothers, who own a junk yard, on the weekends to earn extra money. He likes to help them push broken-down cars to the back of the junk yard because it makes him feel strong. Last Saturday, they pushed three cars with different weights, and he noticed he used different amounts of force for each one. The cars were the following weights:white car: 2,700 poundsred car: 1,500 poundsblue car: 2,100 poundsThink about how much force is needed to move each car. Which correctly organizes the cars in order from the most to least amount of force needed to move them
Answer:
white, blue and red
Explanation:
Force is given by
[tex]F=ma[/tex]
where
m = Mass of object
a = Acceleration of the object
If the acceleration is same for all the cars the force needed to be applied will depend on the mass of the car. The heaviest car requiring the most force and the lightest car requiring the least amount of force.
Here, the weight of the cars in descending order is white, blue and red.
So, the cars in order from the most to least amount of force needed to move them is white, blue and red.
PLS HELP ME
Secondary waves CANNOT travel through
a.
rock.
b.
liquids.
c.
Earth’s mantle.
d.
Earth’s crust.
Answer:
B. Liquids
Explanation:
Just had this question on my test.
Hope this helps :)
A bag of marbles is hanging motionless on a spring scale. What prevents the bag from falling?
Answer:
The vector sum of all forces acting on it is zero, its at equilibrium.
Explanation:
The bag of marbles hanging on a spring scale applies its weight downwards, which was counterbalanced by the reaction from the spring scale (obeying the Newton's third law of motion). And since no external forces are applied to the system, thus the equilibrium of the system.
If the weight of the bag is greater than the reaction from the spring scale, the scale breaks and the system would not be balanced.
A toy gun uses a spring to shoot plastic balls (m = 50 g). The spring is compressed by 3.0 cm. Let k=2.22 × 105 N/m. (a) Of course, you have to do some work on the gun to arm it. How much work do you have to do? (b) Suppose you fire the gun horizontally. How fast does the ball leave the gun? (c) Now suppose you fire the gun straight upwards. How high does the ball go?
Answer:
Explanation:
Given that:
mass of the plastic ball = 50 g = 50 × 10⁻³ kg
spring constant (k) = 2.22 × 10⁵ N/m
compression of spring (x) = 3.0 cm = 3 × 10⁻² m
a) Work done:
[tex]= \dfrac{1}{2}kx^2 \\ \\ = \dfrac{1}{2}\times 2.22 \times 10^{5}\times (3 \times 10^{-2})^2 \\ \\ = 99.9 \ J[/tex]
b) When the gun is fired horizontally;
In the spring, the potential energy is changed to kinetic energy.
i.e.
[tex]\implies \dfrac{1}{2}kx^2 = \dfrac{1}{2}mv^2 \\ \\ 2.22 \times 10^5 \times (3\times 10^{-2}) ^2 =50 \times 10^{-3} \times v^2\\ \\ \mathbf{v= 63.2 m/s}[/tex]
c) The max height the bullet will reach if the gun is being shot upward is:
[tex]H_{max}= \dfrac{v^2}{2g} \\ \\ H_{max}= \dfrac{63.2^2}{2\times 9.8}[/tex]
[tex]\mathbf{H_{max}= 203.9 \ m}[/tex]
A baseball sits motionless near first base on a baseball diamond. What statement best explains why the baseball remains motionless?
A. The forces acting on the baseball are all balanced.
B. There are no forces acting on the baseball.
C. The dirt is placing an unbalanced force on the baseball.
D. The force on the baseball is unbalanced due to gravity.
Answer:
B
Explanation:
There are no forces acting in the baseball
ol
ir Q.No.la ताल भनका क
The unit of density is called derived unit, why?
Answer: Density is measured in kg⋅m−2 . This means that it is derived from fundamental units which are the kilogram and metre. ... hence the kilogram and the metre are SI units and density is a derived unit from these units
Explanation:
they are calculated from the base units mass and length. Density is one derived unit; force, area, volume, specific volume and mass fraction are also derived units. Each derived unit is defined by a quantity equation.
Answer:
Density is obtained through mathematical manipulation.
Explanation:
A derived unit is obtained through mathematical calculation and the result is written with the S.I unit kg/m³
WILL MAKE BRAINLIEST! How does Hooke’s law help us understand the force and energy in elastic materials?
Answer:
How does Hooke’s law help us understand the force and energy in elastic materials?:
When the elastic materials are stretched, the atoms and molecules deform until stress is been applied and when the stress is removed they return to their initial state
Explanation:
Which nucleus completes the following equation?
Answer:
B. [tex]\frac{218}{85} At[/tex]
Explanation:
A P E X
The nucleus that completes the following equation is ²²⁶Ac₈₉
²²²Fr₈₇ →⁴He₂ + ²²⁶Ac₈₉
Therefore the correct answer is option C.
What is radioactive decay?The phenomenon of Radioactive decay is a type of nuclear reaction in which the unstable nucleus of a radioactive element lose energy in the form of nuclear radiation, some examples of radioactive decay are alpha decay, decay, and beta decay.
The complete equation for the nuclear reaction is
²²²Fr₈₇ →⁴He₂ + ²²⁶Ac₈₉
For the given problem the nucleus completes the given equation is ²²⁶Ac₈₉. The correct answer is option C.
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HELP pleaseee which nucleus completes the following equation?
Answer:
its D
Explanation:
i just got it correct on a. p. e. x. :)
A charge of +3.5 nC and a charge of +5.0 nC are separated by 40 cm. Find the equilibrium position for a -6.0 nC charge.
Answer: [tex]18.22\ cm[/tex] from [tex]3.5\ nC[/tex] charge.
Explanation:
Given
The magnitude of the first charge is [tex]Q_1=3.5\ nC[/tex]
The magnitude of the second charge is [tex]Q_2=5\ nC[/tex]
[tex]-6\ nC[/tex] charge must be placed in between the two charges to establish equilibrium
The electrostatic force is given by
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
Equilibrium will be established when force by both the charges balance out each other. Suppose [tex]-6\ nC[/tex] is placed at a distance of [tex]x[/tex] cm from [tex]3.5\ nC[/tex] . So, we can write
[tex]\Rightarrow \dfrac{k(3.5)(-6)}{x^2}=\dfrac{k(5)(-6)}{(40-x)^2}[/tex]
Canceling similar terms
[tex]\Rightarrow \left [ \dfrac{40-x}{x}\right ]^2=\dfrac{10}{7}\\\\\Rightarrow \dfrac{40-x}{x}=\sqrt{\dfrac{10}{7}}=1.195\\\\\Rightarrow 40-x=1.195x\\\Rightarrow 40=2.195x\\\Rightarrow x=18.22\ cm[/tex]
Thus, the equilibrium position is [tex]18.22\ cm[/tex] from [tex]3.5\ nC[/tex] charge.
Answer:
What school do you go to?
Explanation:
A 1.80-kg object is attached to a spring and placed on frictionless, horizontal surface. A horizontal force of 15.0 N is required to hold the object at rest when it is pulled 0.200 m from its equilibrium position (the origin of the x axis). The object is now released from rest from this stretched position, and it subsequently undergoes simple harmonic oscillations.
(a) Find the force constant of the spring.
N/m
(b) Find the frequency of the oscillations.
Hz
(c) Find the maximum speed of the object.
m/s
(d) Where does this maximum speed occur?
x = ±
m
(e) Find the maximum acceleration of the object.
m/s2
(f) Where does the maximum acceleration occur?
x = ±
m
(g) Find the total energy of the oscillating system.
J
(h) Find the speed of the object when its position is equal to one-third of the maximum value.
m/s
(i) Find the magnitude of the acceleration of the object when its position is equal to one-third of the maximum value.
m/s2
Answer:
Explanation:
(a) Force constant = force/displacement = 15/0.2
=75 N/m
(b) For SHM with spring, the angular frequency = sqrt ( force constant / mass )
= sqrt ( 75 / 1.8 )
= 6.455
Frequency = Angular frequency / 2pi
= 1.03Hz
(c) Maximum speed is when object's potential energy is at minimum.
1/2*mass*speed^2 = 1/2*force constant*displacement^2
speed^2 = 75*0.2^2/1.8 = 1.67
speed = sqrt (1.67)
= 1.29 m/s
(d) It occurs at x=0
(e) Maximum acceleration = Force / m = 15/1.8
= 8.33 m/s^2
(f) It occurs at x=0.2m
Answer:
Explanation:
given:
The mass of the object attached to the spring: m = 1.80 kg
The magnitude of the maximum horizontal force exerted: F = 15.0 N
The amplitude of the spring-object oscillation: A = 0.200 m
a. k=15/.2=75N/m
b. (2pi*frequency)^2 = k/m = 75/1.8 = 41.67
frequency = 1.03Hz
c. max speed^2 = amplitude^2*k/m = 0.2^2 * 41.67
max speed = 1.29 m/s
d. x=0m
e. max accel = F/m = 15/1.8 = 8.33 m/s^2
f. x=0.2m
e. energy = 1/2*k*A^2
= 1/2*75*0.2^2
= 1.5J
Two resistors, 2.50 Ω and 4.95 Ω, are wired in series to a 12.00 V battery. What is the equivalent resistance of the circuit?
Answer:
7.45 Ω
Explanation:
From the question given above, the following data were obtained:
Resistor 1 (R₁) = 2.50 Ω
Resistor 2 (R₂) = 4.95 Ω
Voltage (V) = 12 V
Equivalent Resistance (Rₑq) =?
Since the resistors are in series arrangement, the equivalent resistance can be obtained as follow:
Rₑq = R₁ + R₂
Rₑq = 2.5 + 4.95
Rₑq = 7.45 Ω
Therefore, the equivalent resistance is 7.45 Ω
What specific type of tide has the smallest difference between high and low tide?
Answer: Neap tides
Explanation: Neap tides are tides that have the smallest tidal range, and they occur when the Earth the Moon, and the Sun form a 90o angle. They occur exactly halfway between the spring tides when the Moon is at first or last quarter.
Why would you have trouble breathing at high altitudes?
A. it is colder at the top of a mountain
B. the oxygen molecules are spread farther apart
C. the oxygen molecules are closer together
Answer:
A. It is colder at the top of a mountain
Explanation:
The image shows the magnetic field lines around a magnet.
Which statements are true for this magnet?
- the right pole is the south pole
- the left pole is the south pole
- the left pole is the north pole
- the right pole is the north pole
Choose all that apply
Answer:
The right pole is the south pole
The left pole is the north pole
Explanation:
Reason : -
Magnetic field lines emerge from North pole to South pole in a bar magnet.
Why isn't nuclear fusion used to generate electric energy in power plants?
A.
It requires extremely high pressure.
B.
It uses a very rare radioactive isotope.
C.
It releases less energy per gram than uranium does.
D.
It requires converting matter into energy.
Answer:
A) It requires extremely high pressure.
Explanation:
The reasons why we haven't been able to harness power from fusion is that its energy requirements are unbelievably, terribly high.
The correct statement is: "nuclear fusion requires extremely high pressure."
To find the correct statement among all the options, we need to know about nuclear fusion.
What is nuclear fusion?
Nuclear fusion is a nuclear reaction in which nuclei are fused to form another nucleus and releases some energy.How much pressure is required for nuclear fusion?
In a nuclear fusion reaction, 250 billions atmospheric pressure is required. One atmospheric pressure is 101325 pascals.Creating this much pressure is very much difficult.How much energy is released during nuclear fusion?
In nuclear fusion, 17.6 MeV energy is released in a single reaction. Since, two hydrogen atoms are participated, so energy released per nucleon is 8.8 MeV.What is the comparison of energy that released in nuclear fusion and fission?
In a nuclear fission reaction, 200 MeV energy is released in a single reaction and energy per nucleon is less than 1 MeV as an uranium has 238 nucleons.So, nuclear fusion reaction releases more energy as compared to that of nuclear fission.How does we get energy in the nuclear fusion reaction?
In a nuclear fusion reaction, two hydrogen atoms are fused to form a helium atom and the energy is released due the binding energy differences of hydrogen and helium atoms.Thus, we conclude that option (A) is correct.
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A firework is launched with a force of 700 N and a momentum of 200 kg-m/s. How much time before is explodes?
Answer:
t = 0.28 seconds
Explanation:
Given that,
Force acting on a firework, F = 700 N
The momentum of the firework, p =200 kg-m/s
We need to find the time before it explodes. Ket the time be t. We know that, the rate of change of momentum is equal to external frce. So,
[tex]F=\dfrac{P}{t}\\\\t=\dfrac{P}{F}\\\\t=\dfrac{200}{700}\\t=0.28\ s[/tex]
So, the required time is equal to 0.28 seconds.
A physics student of mass 43.0 kg is standing at the edge of the flat roof of a building, 12.0 m above the sidewalk. An unfriendly dog is running across the roof toward her. Next to her is a large wheel mounted on a horizontal axle at its center. The wheel, used to lift objects from the ground to the roof, has a light crank attached to it and a light rope wrapped around it; the free end of the rope hangs over the edge of the roof. The student radius 0.300 m and a moment of inertia of 9.60 kg m^2 for rotation about the axle, how long does it take her to reach the side walk, and how fast will she be moving just beofre she lands?
Answer:
The speed of the student just before she lands, v₂ is approximately 8.225 m/s
Explanation:
The given parameters are;
The mass of the physic student, m = 43.0 kg
The height at which the student is standing, h = 12.0 m
The radius of the wheel, r = 0.300 m
The moment of inertia of the wheel, I = 9.60 kg·m²
The initial potential energy of the female student, P.E.₁ = m·g·h₁
Where;
m = 43.0 kg
g = The acceleration due to gravity ≈ 9.81 m/s²
h = 12.0 h
∴ P.E.₁ = 43 kg × 9.81 m/s² × 12.0 m = 5061.96 J
The kinetic rotational energy of the wheel and kinetic energy of the student supporting herself from the rope she grabs and steps off the roof, K₁, is given as follows;
[tex]K_1 = \dfrac{1}{2} \cdot m \cdot v_{1}^2+\dfrac{1}{2} \cdot I \cdot \omega_{1}^2[/tex]
The initial kinetic energy, 1/2·m·v₁² and the initial kinetic rotational energy, 1/2·m·ω₁² are 0
∴ K₁ = 0 + 0 = 0
The final potential energy of the student when lands. P.E.₂ = m·g·h₂ = 0
Where;
h₂ = 0 m
The final kinetic energy, K₂, of the wheel and student is give as follows;
[tex]K_2 = \dfrac{1}{2} \cdot m \cdot v_{2}^2+\dfrac{1}{2} \cdot I \cdot \omega_{2}^2[/tex]
Where;
v₂ = The speed of the student just before she lands
ω₂ = The angular velocity of the wheel just before she lands
By the conservation of energy, we have;
P.E.₁ + K₁ = P.E.₂ + K₂
∴ m·g·h₁ + [tex]\dfrac{1}{2} \cdot m \cdot v_{1}^2+\dfrac{1}{2} \cdot I \cdot \omega_{1}^2[/tex] = m·g·h₂ + [tex]\dfrac{1}{2} \cdot m \cdot v_{2}^2+\dfrac{1}{2} \cdot I \cdot \omega_{2}^2[/tex]
Where;
ω₂ = v₂/r
∴ 5061.96 J + 0 = 0 + [tex]\dfrac{1}{2} \times 43.0 \, kg \times v_{2}^2+\dfrac{1}{2} \times 9.60 \, kg\cdot m^2 \cdot \left (\dfrac{v_2}{0.300 \, m} }\right ) ^2[/tex]
5,061.96 J = 21.5 kg × v₂² + 53.[tex]\overline 3[/tex] kg × v₂² = 21.5 kg × v₂² + 160/3 kg × v₂²
v₂² = 5,061.96 J/(21.5 kg + 160/3 kg) ≈ 67.643118 m²/s²
v₂ ≈ √(67.643118 m²/s²) ≈ 8.22454363 m/s
The speed of the student just before she lands, v₂ ≈ 8.225 m/s.
Is this right? Please help me ITS SOCIOLOGY
What net force would be required for a 50.5 kg wolf to accelerate at 5.0 m/s^2
Answer:
[tex]\boxed {\boxed {\sf 252.5 \ Newtons }}[/tex]
Explanation:
Force is the push or pull on object that can cause different things, like acceleration. According to Newton's 2nd Law of Motion, it is the product of mass and acceleration.
[tex]F=m*a[/tex]
The mass of the wolf is 50.5 kilograms and the acceleration is 5.0 meters per square second. Therefore:
[tex]m= 50.5 \ kg[/tex][tex]a= 5.0 \ m/s^2[/tex]Substitute the values into the formula.
[tex]F= 50.5 \ kg * 5.0 \ m/s^2[/tex]
Multiply.
[tex]F=252.5 \ kg*m/s^2[/tex]
1 kilogram meter per square second is equal to 1 Newton. Our answer of 252.5 kg*m/s² is equal to 252.5 Newtons.[tex]F= 252.5 \ N[/tex]
The force required is 252.5 Newtons.
The 4kg head of a sledge hammer is moving at 6m/s when it strikes a chisel, driving it into a log. The duration of the impact (or the time for the sledge hammer to stop after contact) is 0.0020s. Find the time average of the impact force
Answer:
The average impact force is 12000 newtons.
Explanation:
By Impact Theorem we know that impact done by the sledge hammer on the chisel is equal to the change in the linear momentum of the former. The mathematical model that represents the situation is now described:
[tex]\bar F \cdot \Delta t = m \cdot (v_{2}-v_{1})[/tex] (1)
Where:
[tex]\bar F[/tex] - Average impact force, in newtons.
[tex]\Delta t[/tex] - Duration of the impact, in seconds.
[tex]m[/tex] - Mass of the sledge hammer, in kilograms.
[tex]v_{1}[/tex], [tex]v_{2}[/tex] - Initial and final velocity, in meters per second.
If we know that [tex]\Delta t = 0.0020\,s[/tex], [tex]m = 4\,kg[/tex], [tex]v_{1} = -6\,\frac{m}{s}[/tex] and [tex]v_{2} = 0\,\frac{m}{s}[/tex], then we estimate the average impact force is:
[tex]\bar F = \frac{m\cdot (v_{2}-v_{1})}{\Delta t}[/tex]
[tex]\bar F = 12000\,N[/tex]
The average impact force is 12000 newtons.
Which statement is true of an alpha particle?
A. It is electromagnetic radiation, not a true particle.
B. It is an electron.
C. It is the largest decay particle
D. It is a particle that travels at the speed of light.
Answer:
Atoms are made up of various parts; the nucleus contains minute particles ... neutrons, and the atom's outer shell contains other particles called electrons. ... Physical Forms of Radiation; Radioactive Decay; Nuclear Fission; Ionizing Radiation ... of high-energy waves that can travel great distances at the speed of light and ...
Explanation:
The true statement of an alpha particle is it is an electron. The correct option is B.
What is an alpha particle?The alpha particle are composite particles which consists of two protons and two neutrons tightly bonded together. They are ejected from the inside the nucleus of heavy radioactive particles, also called alpha decay.
Atoms are made up electrons orbiting in outer shells, protons and neutrons in the nucleus. The radioactive particle emit highly ionized radioactive rays which ionize electrons emitting alpha particle.
Thus, the correct option is B.
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