Example of kinetic to thermal? And explain how the energy is changing forms? Please help

Answers

Answer 1

Answer:

Indeed

Explanation:

Answer 2

Answer:

A roller coaster that is running heating up the rails

Explanation:

the enery is changing forms due to friction and cunduction


Related Questions

is 468km per minute describing speed or velocity

Answers

velocity probably well that’s what i would put

If there are two forces going in the same direction how would you find the net force?

a
add
b
multiply
c
subtract
d
divide

Answers

Answer:

A) Add

Explanation:

Answer:

a. add

Explanation:

Net [anything] is just a fancy way of saying total.

(Note that you would subtract if they were going in opposite directions. (Technically, you would be adding a negative, but that's the same as subtracting.))

A tennis ball covers a distance of 12 meters in 0.4 seconds what is the velocity of the tennis ball?

Answers

V=d/t
V=12/0.4
V=30 m/s

Answer:

30m/s

Explanation:

Given parameters:

Distance  = 12m

Time taken  = 0.4s

Unknown:

Velocity of the tennis ball = ?

Solution:

Velocity of a body is the displacement per unit of time.

  Velocity  = [tex]\frac{displacement}{time}[/tex]  

So;

      Velocity  = [tex]\frac{12}{0.4}[/tex]   = 30m/s

What does AS>0 mean?|
I

Answers

Answer:

Significant Other

Explanation:

that comes to mind when I see that

A force of 900 N pushes a wedge 0.10 m into a log. If the work done on the log is 50 J, what is the efficiency of the wedge?

Answers

Answer:

I'm fairly certain it's 1,800

Explanation:

The efficiency of the wedge with force F=900 N displaces the wedge 0.10 m is 55.55%  or 56%.

What is the efficiency of the machine?

The efficiency of the machine equals the ratio of output energy and input energy. It is also defined as the ratio of work done on a load by the machine to the work done on the effort by the machine.

A load is defined as the weight lifted by the machine. The effort is defined as the force applied to bring the desired change in the load. Work done is defined as the product of force and displacement.

The efficiency, η = Output power / Input power, and the highest efficiency of the machine is equal to one. The efficiency of the machine has no unit. The efficiency η = (Actual work done / Ideal work done) × 100.

From the given,

Force = 900 N

Displacement = 0.1 m

Work done = F × s = 900×0.1 = 90 J

Actual work done = 50 J

Efficiency,η = (50/90) × 100

           η  = 55.55 %

Thus, the efficiency of the wedge is 55.56%.

To learn more about the Efficiency of a machine:

https://brainly.com/question/11752408

#SPJ3

Sodium and phosphorus combine to form Na3P. What is the name of this compound? phosphorus sodiate phosphorus sodide sodium phosphate sodium phosphide

Answers

Answer:

Sodium phosphide

Explanation:

Answer:

sodium phosphide

Explanation:

i just took the test. Good luck!! Have a great day!!

A 50 kg bumper car with a 40 kg child and it is at rest when a 60 kg child in her own bumper car slams into it the collision last point1 seconds and the rubber bumpers are perfectly bouncy with no heating from the collision what is the force experienced by the first car

Answers

Answer:

 F = 99 v₂₀

v₂₀ = 1 m / s,        F = 99 N

Explanation:

In this exercise it is asked to find the force during the collision, for this we use the relationship between the momentum and the momentum of car 1

            I = Δp

            F t = p_f- p₀

            F t = m (v_f -v₀)                        (1)

We must find the final speed of car 1, for this we define a system formed by the two cars, in this case the forces during the collision are internal and the moment is conserved

initial instant. Before the crash

        p₀ = 0 + m₂ v₂₀

         

final instant. After the crash

        p_f = m₁ v₁ + m₂ v_{2f}

the moment is preserved

        p₀ = p_f

        m₂ v₂₀ = m₁ v_{1f} + m₂ v_{2f}           (2)

        m₂ (v₂₀ - v_2f}) = m₁ v_{1f}

as the collision is elastic the kinetic energy is also conserved

        K₀ = K_f

        ½ m₂ v₂₀² = ½ m₁ v_{1f}² + ½ m₂ v_{2f}²

        m₂ (v₂₀² -v_{2f}²) = m₁ v_{1f}²

let's write our system of equations, using

         a² - b² = (a + b) (a-b)

         m₂ (v₂₀ - v_{2f}) = m₁ v_{1f}

         m₂ (v₂₀ -v_{2f}) (v₂₀ + v_{2f}) = m₁ v_{1f}²

to solve we divide the equations

       v₂₀ + v_{2f} = v_{1f}

with this we substitute in equation 2 and find the speed of each car, in this case we need the speed of car 1

         m₂ v₂₀ = m₁ v_{1f} + m₂ (v_{1f}-v₂₀)

         2m₂ v₂₀ = (m₁ + m₂) v_{1f}

          v_{1f} = [tex]\frac{2m_2}{m_1+m_2} v_{2o}[/tex]

We substitute in the drive ratio of car 1

            F t = m (v_f -v₀)

            F = m₁ (\frac{2m_2}{m_1+m_2}  v_{2o} - 0) / t

            F = [tex]\frac{2m_1 m_2 }{m_1+m_2} \ \frac{v_{2o}}{t}[/tex]

the mass of each car is the mass of the car plus the mass of the boy

           m₁ = 50 +40 = 90 kg

           m₂ = 50 +60 = 110 kg

     

time is t = 1

         

we substitute the values

           F = [tex]\frac{ 2\ 90 \ 110}{90+110} \ \frac{v_{2o}}{1}[/tex]2 90 100/90 + 110 vo2 / 1

           F = 99 v₂₀

The value of the initial velocity of car 2 is not indicated in the problem, if this velocity is known it can be included and the force value is obtained, suppose that the initial velocity v₂₀ = 1 m / s

           F = 99 N

which term describes when a substance is changed from a liquid to a gas

Answers

Answer:

vasporisation

Explanation:

process used to change liquid to gass

Answer:

I believe it's Evaportation or another word would be Vaporisation.

Explanation:

hope this helps! ^^

Please please help me with those questions please please help me

Answers

Explanation:

a) E= fs

b) 2E = mv²

c) E= Mc ²

How do simple
machines magnify
forces?

Answers

Answer:

Motion at one end of the beam results in motion at the other end in the opposite direction.

Explanation:

The location of the fulcrum can magnify (or reduce) the force applied at one end at the expense (or advantage) of the distance over which the other end travels. Sorry if I get this wrong! I am in 5th grade. ♥

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