Evaluate the expression for x = 5 and y = -1
xy - y =

Answer:

1)x=1.5

2) p=0.7

Step-by-step explanation:

Answer:

(71.10-57)/3=amount of gigabytes, 14.10/3=4 gigabytes allowed

Step-by-step explanation:

$71.10-$57=$14.10, the amount of money that Jonathan can spend on gigabytes. Then, determine how many times 3 can go into 14.10: 4 times. Jonathan can use four gigabytes and keep his bill under $71.10 a month.

Answer:

sum of interior angles =180×3= 540°

m<F= 540-105-113-107-87

=128°

m<F= 128°

Answer:

$0.73

Step-by-step explanation:

Let's say an orange costs O dollars and a grapefuit costs G dollars.

We add G dollars for each grapefuit and O dollars for each orange, so, for example, 12 grapefuit = G added 12 times = 12 *G = 12G

a.

6G = 10O

12G + 24O = 12

6 grapefuit = 6G = 10 oranges = 10O

b.

6G = 10O

12G + 24O = 12

We can solve this using substitution. First, we can solve the first equation for G. After that, we can plug that into the second to find O and go from there.

6G = 10O

divide both sides by 6 to remove the coefficient for G

G = (10/6)O

plug that into the second equation

12*(10/6)O + 24O = 12

20O + 24O = 12

44O = 12

divide both sides by 44 to solve for O

O=12/44 = 6/22

6G = 10O

6G = 60/22

divide both sides by 6 to solve for G

10/22 = G

c.

These solutions mean that an orange (O) costs 6/22 dollars and a grapefuit (G) costs 10/22, so 1O + 1G = 16/22 dollars ≈ $0.73. Note that O and G are kept as fractions because they are not exact dollar amounts, e.g. 0.27 repreating

Answer:

[tex]1. \: \: \: a = \frac{5}{7} \\ 2. \: \: \: 4 \\ 3. \: \: \: 15 {x}^{2} + 60x + 135 \\ 4. \: \: \: m = {75}^{o} \\ [/tex]

Step-by-step explanation:

[tex]1. \: \: 7a - 8 = 13 \\ 7a - 8 + 8 = 13 + 8 \\ 7a = 5 \\ \frac{7a}{7} = \frac{5}{7} \\ a = \frac{5}{7} \\ [/tex]

[tex]2. \: \: \: 4 = 2 \times 2 \\ 8 = 2 \times 2 \times 2 \\ 4 \\ [/tex]

[tex]3. \: \: \: 15 {(x + 3)}^{2} \\ 15(x + 3)(x + 3) \\15 (x + 3)(x + 3) \\ 15 |x(x + 3) + 3(x + 3)| \\ 15 ({x}^{2} + 3x + 3x + 9 )\\ 15( {x}^{2} + 6x + 9) \\ {15x}^{2} + 60x + 135 \\ [/tex]

[tex]4. \: \: \: m = {75}^{o} (opposite \: angles)[/tex]

Answer:

The answer is $242

Step-by-step explanation:

We can set up two equations for this one:

286 = 13 * (rate per hour)

divide both sides by 13:

22 = rate per hour

Then knowing her rate per hour is 22 dollars

22 * 11 hours of work = $242

At the same rate she will make $242 in 11 hours.

Kala made $286 for 13 hours of work . Therefore, let's find the rate.

Rate is simply the ratio between two values with different units. In our case, its the amount made in dollars versus the time taken to make that amount.

Therefore,

rate = amount made(dollars)/ time taken(hours)

rate = 286 / 13

rate = 22 dollars per hour

At the same rate the amount she will make in 11 hours can be calculated as follows:

rate  = amount / 11

22 = amount(dollars) / 11

cross multiply

amount(dollars) = 22 × 11

amount(dollars) = $242

learn more on rate here: https://brainly.com/question/8062121?referrer=searchResults

Answer:

the answer to the question is 15$

Answer:

The answer is t^-1 (r)=120r/120-r

i hope this is right sry if im wrong have a good day :)

The inverse of Janine's equation is [tex]r = \frac{120t}{120-t}[/tex] .

Resistance is a measure of the opposition to current flow in an electrical circuit. Resistance is measured in ohms, symbolized by the Greek letter omega (Ω).

According to the question

Janine is building a circuit that contains two lightbulbs in parallel.

One of the lightbulbs has a resistance of 120 ohms.

R = 120ohms

r = resistance of the second lightbulb

t = total resistance in the circuit  

[tex]t = \frac{120r}{r+120}[/tex]

Now,

The inverse of Janine's equation in which we will make r independent

[tex]t = \frac{120r}{r+120}[/tex]

[tex]t(r+120) = 120r[/tex]

[tex]tr + 120t = 120r[/tex]

[tex]120t = 120r - tr[/tex]

[tex]120t = r(120-t)[/tex]

[tex]r = \frac{120t}{120-t}[/tex]

Hence, the inverse of Janine's equation is [tex]r = \frac{120t}{120-t}[/tex] .

To know more about  resistance here:

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The constraints to represent the incoming students at the college are [tex]0<x \leq 200[/tex] and [tex]0<y \leq 400[/tex] and this can be determined by using the given data.

Given :

The following steps can be used in order to determine the constraints to represent the incoming students at the college:

Step 1 - The inequalities are formed in order to determine the constraints to represent the incoming students at the college.

Step 2 - The linear equation that represents the situation "two times as many in-state students as out-of-state" is:

[tex]y = 2x[/tex]

Step 3 - The inequality that represents the situation "college only have space to accept 200 out-of-state students" is:

[tex]0<x \leq 200[/tex]

Step 4 - So, the inequality that represents the maximum number of in-state students that college can take is:

[tex]0<y \leq 400[/tex]

Therefore, the correct option is D).

For more information, refer to the link given below:

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Answer:

6, 60, 0.6, 600 are the answers

the questions all use the same digits but that the powers of 10 are different between the dividends and divisors for some

Step-by-step explanation:

Answer:

Option B

176

Step-by-step explanation:

take 11 to the next side of the equation making the division multiplication getting us 16×11=176

Equivalent expressions are expressions that have the same value, and can be used interchangeably.

The result of the sum [tex]2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5})[/tex] is [tex]4x\sqrt[3]{2y} + 8x^2y\sqrt[3]{2y^2})[/tex]

The expression is given as:

[tex]2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5})[/tex]

Rewrite the expression as:

[tex]2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 2 (\sqrt[3]{2^4x^3y}) + 4 (\sqrt[3]{3^3 \times 2x^6y^5})[/tex]

Evaluate the roots

[tex]2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 2 (2x\sqrt[3]{2y}) + 4 (3x^2y\sqrt[3]{2y^2})[/tex]

Open the brackets

[tex]2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 4x\sqrt[3]{2y} + 12x^2y\sqrt[3]{2y^2})[/tex]

The above expression cannot be further simplified.

Hence, the result of the sum [tex]2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5})[/tex] is [tex]4x\sqrt[3]{2y} + 8x^2y\sqrt[3]{2y^2})[/tex]

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The sum of the expression is [tex]4 (\sqrt[3]{x^3y} +12x^2y(\sqrt[3]{ 2 y^2})\\[/tex].

We have to determine, the sum of the given expression.

According to the question,

Expression; [tex]2(\sqrt[3]{16x^3y} +4(\sqrt[3]{56x^6y^5})[/tex]

To determine the sum of the given expression following all the steps given below.

Rewrite the expression term in the form of their cubes,

[tex]\rm = 2(\sqrt[3]{16x^3y} +4(\sqrt[3]{56x^6y^5})\\\\ = 2(\sqrt[3]{2^4x^3y} +4(\sqrt[3]{3^3 \times 2 \times x^6y^5})\\\\= 2\times 2(\sqrt[3]{x^3y} +4\times 3(\sqrt[3]{ 2 \times x^6y^5})\\\\= 4 (\sqrt[3]{x^3y} +12x^2y(\sqrt[3]{ 2 y^2})\\\\=4 (\sqrt[3]{x^3y} +12x^2y(\sqrt[3]{ 2 y^2})\\[/tex]

Hence, The sum of the expression is [tex]4 (\sqrt[3]{x^3y} +12x^2y(\sqrt[3]{ 2 y^2})\\[/tex].

For more details refer to the link given below.

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Answer:

  y = x³ +2x² +x -1

Step-by-step explanation:

The attachment shows the four points we can read from the graph and the cubic regression function that fits them.

  y = x³ +2x² +x -1

_____

Additional comment

It is useful to become familiar with the regression function capability of your graphing calculator or spreadsheet. Free or inexpensive apps are available for tablet or phone, and on the web.

Answer:

the asnwer is (2,3)

Step-by-step explanation:

Answer:

Step-by-step explanation:

Since B is the right angle, AC is the opposite side - hypotenuse.

Use Pythagorean and find the missing side, AB:

There is no info given to link the triangles ABC and XYZ and hence can't provide solution to any dimension of XYZ.

If the scale factor was given as k, then XZ would be:

Answer:

LCM(57624, 416745) = 23,337,720 or  LCM = 23337720

Step-by-step explanation:

List all prime factors for each number.

Prime Factorization of 57624 is:

2 x 2 x 2 x 3 x 7 x 7 x 7 x 7  =>  23 x 31 x 74

Prime Factorization of 416745 is:

3 x 3 x 3 x 3 x 3 x 5 x 7 x 7 x 7  =>  35 x 51 x 73

For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.

The new superset list is

2, 2, 2, 3, 3, 3, 3, 3, 5, 7, 7, 7, 7

Multiply these factors together to find the LCM.

LCM = 2 x 2 x 2 x 3 x 3 x 3 x 3 x 3 x 5 x 7 x 7 x 7 x 7 = 23337720

In exponential form:

LCM = 23 x 35 x 51 x 74 = 23337720

LCM = 23337720

Therefore,

LCM(57624, 416745) = 23,337,720

Answer:

[tex]w_1=-\frac{1}{4},w_2=-2}[/tex]

Step-by-step explanation:

[tex]4w^2+9w=-2[/tex]

[tex]4w^2+9w+2=0[/tex]

[tex]w^2+9w+8=0[/tex]

[tex](w+1)(w+8)=0[/tex]

[tex](4w+1)(w+2)=0[/tex]

[tex]w_1=-\frac{1}{4},w_2=-2}[/tex]

Answer:

x=12

Step-by-step explanation:

4x-6+2x=18

2x-6=18

2x=24

x=12

[tex] =( \frac{1}{2} \times 10.4 \times 16.9) {ft}^{2} \\ = (5.2 \times 16.9) {ft}^{2} \\ = 87.88 {ft}^{2} [/tex]

Answer:

The area of the triangle is 87.88 square feet.

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

20 > -1

Step-by-step explanation:

Well 20 is a positive integer that is 20 units from 0 whereas -1 is a negative integer that is 1 unit behind zero.

[tex]m \cdot n = \sqrt{m^2 -n^2}\\\\\text{When m =5 and n =3,}\\\\\\5\cdot 3 = \sqrt{5^2 -3^2} =\sqrt{25 -9} = \sqrt{16} = 4[/tex]

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{Assuming:}[/tex]

[tex]\mathbf{m\times n = \sqrt{(m^2 - n^2)}}[/tex]

[tex]\huge\textbf{Solving:}[/tex]

[tex]\mathbf{\rightarrow 5\times 3 = \sqrt{(5^2 - 3^2)}}[/tex]

[tex]\mathbf{\rightarrow 15 = \sqrt{(5\times5 - 3\times3)}}[/tex]

[tex]\mathbf{\rightarrow 15 = \sqrt{(25 - 9)}}[/tex]

[tex]\mathbf{\rightarrow 15 = \sqrt{16}}[/tex]

[tex]\mathbf{15\neq4}[/tex]

[tex]\huge\textbf{Thus, this answer should be:}[/tex]

[tex]\huge\boxed{\boxed{\textsf{This statement is most likely: \boxed{\textsf{FALSE}}}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

1000x or 1000 thousand times greater

Step-by-step explanation:

every decimal to the left is 10x greater than the one right of it.

Answer:

$3.74

Step-by-step explanation:

Proportions:

6 pounds ⇔ $22.44

1 pound ⇔ $ C

C = 22.44*1/6

C = $3.74

Answer:

6x+20=5x+25

5 days

Step-by-step explanation:

Let x = the days that they have the same amount of signatures

We know Anna has 20 currently and gets 6 per day, so we can use y=mx+b to describe her linear relationship.

We also know that Sam has 25 and gets 5 per day, so we can again use y=mx+b to describe his linear relationship.

Since both equations equal the variable y, we can say they equal each other and set up 6x+20=5x+25.

Then you subtract 20 from both sides and subtract 5x, so you are left with x =5, or 5 days until they have the same amount of signatures

Hope this made sense :D

Step-by-step explanation:

Simply divide the percent by 100 and multiply by the number. For example, 48.9 /100 x 264 = 129.096 or 0.489 x 264 = 129.096

Rounded to nearest hundredth

= 129.10

Answer:129.10

Step-by-step explanation:

Simply, the equation for the percentage value of a number is:

x*(z%/100%)=y

where x is your initial value, z is your percentage value, and y is the resultant value

for this question, the equations gives us as follows

264*(48.9%/100%)=129.096=129.10

Answer:

Cost of each share is [tex]6Rs[/tex]

Step-by-step explanation:

Let the cost be [tex]5x,7x,4x[/tex]

We have

[tex]5x+7x+4x=96\\\\16x=96\\\\x=6[/tex]

Cost of each share is [tex]6Rs[/tex]

Answer:

[tex]\frac{\frac{1}{4}}{1}=\frac{\frac{5}{6}}{x}[/tex]

Step-by-step explanation:

Per = 1

[tex]\frac{1}{4}[/tex]

So, if we were to solve:

[tex]\frac{1}{4}=\frac{5}{6x}[/tex]

[tex]\frac{1}{4}\cdot \:6x=1\cdot \:5[/tex]

[tex]\frac{3}{2}x=5[/tex]

[tex]\frac{3}{2}x\cdot \:2=5\cdot \:2[/tex]

[tex]3x=10[/tex]

[tex]\frac{3x}{3}=\frac{10}{3}[/tex]

[tex]x=\frac{10}{3}[/tex]

Troy can make [tex]\frac{10}{3}[/tex] dozen of cupcakes.