Answer:
v = 32.345 m/s
Explanation:
given data
radius r = 0.330 m
angular speed = 15.6 revolutions/s
solution
we will get here linear speed v, that is express as
v = r × w .....................1
here w = 17.5 × 2 × π radians
so now put value in eq1
v = 0.330 × 15.6× 2 × π
v = 32.345 m/s
Before working this problem, review Conceptual Example 14. A pellet gun is fired straight downward from the edge of a cliff that is 14.7 m above the ground. The pellet strikes the ground with a speed of 27.2 m/s. How far above the cliff edge would the pellet have gone had the gun been fired straight upward
Answer:
23.04 m
Explanation:
We'll begin by calculating the initial velocity of the pellet. This can be obtained as follow:
Height (h) of cliff = 14.7 m
Final velocity (v) = 27.2 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Initial velocity (u) =?
v² = u² + 2gh
27.2² = u² + (2 × 9.8 × 14.7)
739.84 = u² + 288.12
Collect like terms
u² = 739.84 – 288.12
u² = 451.72
Take the square root of both side
u = √451.72
u = 21.25 m/s
Thus, the initial velocity of the pellet is 21.25 m/s.
Finally, we shall determine the maximum height to which the pellet would have gone assuming the gun was fired straight upward. This can be obtained as follow:
Initial velocity (u) = 21.25 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) = 0 m/s (at maximum height)
Maximum height (h) =?
v² = u² – 2gh (since the pellet is going against gravity.
0² = 21.25² – (2 × 9.8 × h)
0 = 451.5625 – 19.6h
Collect like terms
0 – 451.5625 = –19.6h
–451.5625 = –19.6h
Divide both side by –19.6
h = –451.5625 / –19.6
h = 23.04 m
Therefore, the pellet will reach a maximum height of 23.04 m above the cliff.
Electric and gravitational forces have many similar features because they follow idenitical mathematical formulas. In particular,________ in electricity plays the equivalent role of mass in gravity, while_______ , plays a role corresponding to free-fall acceleration. Because of this kinematics describing projectiles in gravity would carry over to electricity, but the main difference is that in electricity we have__________ , while in gravity mass is always positive, which means gravity is_______ , but electricity________ .
Answer:
Electric and gravitational forces have many similar features because they follow idenitical mathematical formulas. In particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field, plays a role corresponding to free-fall acceleration. Because of this kinematics describing projectiles in gravity would carry over to electricity, but the main difference is that in electricity we have positive and negative charges, while in gravity mass is always positive, which means gravity is always attractive, but electricity could be attractive and repulsive.
Explanation:
The formulas of Electric and gravitational fields are as follow
Electric Field
F(electric)=kq1q2/r^2
Gravitationlal Fieeld
F(grav)=GMm/r^2
As you see both follow the inverse square law in the formula
Both of these act between two bodies without having any contact. The gravitational field acts on the mass of an object Whereas the electric field acts on the charge.
The gravitational field can only attractive while the electric field can be attractive or repulsive.
Normally electric field is stronger than the gravitational field.
In particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field,
What is gravitational force?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
Electric and gravitational forces have many similar features because they follow identical mathematical formulas.
In particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field,
Plays a role corresponding to free-fall acceleration. Because of these kinematics describing projectiles in gravity would carry over to electricity,
but the main difference is that in electricity we have positive and negative charges, while in gravity mass is always positive,
which means gravity is always attractive, but electricity could be attractive and repulsive.
Hence, in particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field,
To learn more about the gravitational force refer to the link;
https://brainly.com/question/24783651
What is the mass of a block concrete that gains 52,800 joules of energy when its temperature is increased by 5 degrees Celsius specific heat of concrete 880 J/K degrees Celsius
Answer:
12 kg
Explanation:
q = 52,800 J
c = 880 J/(kg * K) Pretty sure you missed the kg here
ΔT = 5 °C = 5 K (reminder that this only applies to ΔT and not T)
q = mcΔT ⇒ m = q/(cΔT) = 52,800 J / (880 J/(kg * K) * 5 K) = 12 kg
The mass of a block concrete that gains 52,800 joules of energy when its temperature is increased by 5 degrees Celsius specific heat of concrete 880 J/K degrees Celsius is 12kg
The formula for calculating the quantity of heat energy absorbed by the block is expressed as:
Q = mcΔt
Q is the quantity of heat = 52,800 Joules
m is the mass of the concrete
c is the specific heat of concrete = 880 J/K
Δt is the change in temperature = 5 degrees
substitute the given values into the formula:
[tex]52800=m(880)(5)\\52800 = 4400m\\m=\frac{52800}{4400}\\m= 12kg[/tex]
Hence the mass of a block of concrete that gains 52,800 joules of energy when its temperature is increased by 5 degrees Celsius specific heat of concrete 880 J/K degrees Celsius is 12kg
Learn more here: https://brainly.com/question/22991121
A car initially traveling 7 m/s speeds up uniformly at a rate of 3 m/s2 until it reaches a velocity of 22 m/s. How much time did it take the car to reach this final velocity?
Answer:
t = 5 s
Explanation:
Data:
Initial Velocity (Vo) = 7 m/sAcceleration (a) = 3 m/s²Final Velocity (Vf) = 22 m/sTime (t) = ?Use formula:
[tex]\boxed{t=\frac{Vf - Vo}{a}}[/tex]Replace:
[tex]\boxed{t=\frac{22\frac{m}{s} -7\frac{m}{s}}{3\frac{m}{s^{2}}}}[/tex]Solve the subtraction of the numerator:
[tex]\boxed{t=\frac{15\frac{m}{s}}{3\frac{m}{s^{2}}}}[/tex]It divides:
[tex]\boxed{t=5\ s}[/tex]How much time did it take the car to reach this final velocity?
It took a time of 5 seconds.
Bungee jumping is an example of
A. wind resistance and insanity
B. gravitational and air pressure energy
C. gravitational and elastic energy
What simple machine can best be described as "a simple machine that uses an inclined plane wrapped around a rod"? *
a wedge
a screw
a wheel and axle
a lever
In July 2015, Oregon State University, the National Oceanic and Atmospheric Administration, and the Coast Guard cooperated to send a hydrophone into Challenger Deep, the deepest part of the Mariana Trench. The titanium shelled recording device withstood the pressure 10,994 meters (nearly 7 miles!) under the ocean's surface. The hydrophone recorded 23 days of audio from the deepest part of the ocean floor. If the spherical hydrophone has a radius of 10 cm, what is the total force exerted on the titanium shell by the ocean water
Answer:
Explanation:
Pressure due to water column as deep as 10994 meters can be given by the following expression
Pressure = h d g , where h is depth of water , d is density of water and g is acceleration due to gravity .
Pressure = 10994 x 10³ x 9.8
= 10.77 x 10⁷ N / m²
Pressure will act on curved surface of the spherical shell , the effective surface area will be π R² where R is radius of the surface .
Effective surface = 3.14 x 0.1²
= .0314 m²
Total force = pressure due to water column x effective surface
= 10.77 x 10⁷ x .0314 N.
= 33.82 x 10⁵ N .
fertilization that takes place when the union of the sex cells happens outside the body
Answer:external
Explanation:EDGE 2021
Problem 6: A bullet in a gun is accelerated from rest from the firing chamber to the end of the barrel at an average rate of 6.3 × 105 m/s2 for 8.2 × 10-4 s.Ball,removedc795646bb4371e1754411a7dadf94458c503446af1b6450bb3269c1f97e8ef53removedremoved58b1e9a401041b69266daacea519e828d050d14013adc67f8c64697e40f2ef89removedtheexpertta - tracking id: 0W86-2A-6A-4E-962A-28979. In accordance with Expert TA's Terms of Service. copying this information to any solutions sharing website is strictly forbidden. Doing so may result in termination of your Expert TA Account.show answer No Attempt What is the gun’s muzzle velocity (that is, the bullet’s final speed), in meters per second
Answer:
v = 5.166 10² m / s
Explanation:
We can solve this exercise using the kinematics equations
v = v₀ + at
as the bullet starts from rest its initial velocity is zero
v = a t
let's calculate
v = 6.3 10⁵ 8.2 10⁻⁴
v = 5.166 10² m / s
A car starts from rest and accelerates uniformly at a rate of 2.0 meter per second squared for 4.0 seconds. During this time interval, the car traveled ________ meters.
Answer:
16
Explanation:
[tex] \frac{1}{2} \times 2 \times {4}^{2} = 16[/tex]
What does Fgrav or Fg mean when its next to a vector arrow?
Could I get help on this question please
Answer:
124.51 m
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 49.4 m/s
Final velocity (v) = 0 m/s (at maximum height)
Maximum height (h) =?
NOTE: Acceleration due to gravity (g) = 9.8 m/s²
The maximum height to which the cannon ball attained before falling back can be obtained as illustrated below:
v² = u² – 2gh ( since the ball is going against gravity)
0² = 49.4² – (2 × 9.8 × h)
0 = 2440.36 – 19.6h
Collect like terms
0 – 2440.36 = –19.6h
–2440.36 = –19.6h
Divide both side by –19.6
h = –2440.36 / –19.6
h = 124.51 m
Therefore, maximum height to which the cannon ball attained before falling back is 124.51 m
A student claims an object in motion must experience a force to stay in motion. Do you agree or disagree?
Answer:
agree because there is always a force that causes motion..
Can someone please help me get this right pleaseee I’ll mark brainless .
Answer:i think it is c
Explanation:
Answer:
Explanation: i think its c to try it
Pls help!!
1 example of a conductor and 1 example of a insulator in your EVERYDAY world.
Answer:
here
Explanation:
Examples of insulators include plastics, Styrofoam, paper, rubber, glass and dry air.
Examples of conductors include metals, aqueous solutions of salts
Review Conceptual Example 6 as background for this problem. A car is traveling to the left, which is the negative direction. The direction of travel remains the same throughout this problem. The car's initial speed is 17.8 m/s, and during a 4.68-second interval, it changes to a final speed of (a)23.5 m/s and (b)15.3 m/s. In each case, find the acceleration (magnitude and algebraic sign).
Answer:
(a) 1.21 m/s² (b) 1.75 m/s²
Explanation:
The initial speed of the car, u = 17.8 m/s
Case 1.
Final speed of the car, v = 23.5 m/s
Time, t = 4.68-s
Acceleration = rate of change of velocity
[tex]a=\dfrac{23.5 -17.8 }{4.68}\\\\a=1.21\ m/s^2[/tex]
Case 2.
Final speed of the car, v = 15.3 m/s
[tex]a=\dfrac{23.5 -15.3}{4.68}\\\\a=1.75\ m/s^2[/tex]
Hence, this is the required solution.
Acceleration is the change in the velocity of a body with time.
What is acceleration?The term acceleration is the change in the velocity of a body with time. We have to find the acceleration in two separate cases;
Case 1;
a = -(23.5 m/s - 17.8 m/s)/4.68-s
a = -1.2 m/s^2
Case 2;
a = -(15.3 m/s - 17.8 m/s)/4.68-s
a = 0.53 ms-2
Learn more about acceleration: https://brainly.com/question/12134554
If a solid metal sphere and a hollow metal sphere of equal diameters are each given the same charge, the electric field (E) midway between the center and the surface is...A. greater for the solid sphere than for the hollow sphere.B. greater for the hollow sphere than for the solid sphere.C. zero for bothD. equal in magnitude for both, but one is opposite in direction from the other.
Answer:
C. zero for both
Explanation:
In case of solid metal sphere , when it is given any charge , all the charges are transferred on the surface and within surface no charge exists . In case of hollow metal sphere , all charges reside on surface . In this way , in both solid and hollow sphere , all charge reside on the surface and no charge resides inside it . Hence due to absence of any charge inside , there is no electric field inside the sphere in both the cases .
Hence in both the case electric field is zero .
option C is correct .
3. If the gravitational force between 2 objects is 50 N, what is the gravitational
force when the distance between the two is increased to four times the distance?
The gravitational force : 3.125 N
Further explanationGiven
F₁ = 50 N
Required
F₂
Solution
Newton's Gravity Law:
[tex]\rm F=G.\dfrac{m_1.m_2}{r^2}[/tex]
with F = gravitational force,
G = gravitational constant,
m1, m2 = mass of object,
r = distance between two objects.
The value of m and G are the same , so :
F₁ ≈ 1/r₁²
The distance between the two is increased to four times:
r₂ = 4r₁
F₂ = 1/(4r₁)²
F₂ = 1/16r₁²
F₂ = F₁ x 1/16
F₂ = 50 : 16
F₂ = 3.125 N
A spacecraft is flying away from the moon toward earth.
What will be true of the moon’s gravitational pull on the spacecraft?
It will decrease.
It will increase.
It will repel the spacecraft.
It will remain the same.
Answer:
it will decrease
Explanation:
According to the law of universal gravitation, the gravitational force exerted by the moon on the spacecraft is equal to the product of their masses and inversely proportional to the square of the distance that separates them. Therefore, as the spacecraft moves away, its distance increases and the force of attraction exerted by the moon decreases.
Answer:
A. It will increase
Explanation:
I took the quiz on K12 and this was the correct option.
Hope I helped
Based on your average reaction time, how much time would it take to react to a traffic situation and stop a car traveling at 60 mph (1 mph equals 0.45 m/s) if you could decelerate the car at a rate of -3.4m/s2?
What distance would you travel (in meters) as the car came to a stop in the above situation?
Avg Reaction time: 0.218 ms
Answer:
d = 106.41 m
Explanation:
Given that,
Initial speed of the car, u = 60 mph = 26.9 m/s
The deceleration in the car, a = -3.4 m/s²
The average reaction time, t = 0.218 m/s
It finally stops, final velocity, v = 0
We need to find the distance covered by the car as it come to a stop.
Using third equation of motion to find.
[tex]v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-26.9^2}{2\times (-3.4)}\\\\d=106.41 m[/tex]
So, the car will cover 106.41 m as it comes to a stop.
What is the displacement of the particle in the time interval 7 seconds to 8 seconds?
Answer:
it 1.5 meters
Explanation:
if u could put the option number it will be cool and hope it help and if it doesnt am really sorry ;)
In order for the eye to see an object _____ from the object myst be reflected to your eye.
Light or particle ?
Answer: light from the object
Explanation:
When light is reflected off an object like a lamp or a door is travels in a straight line but in a new direction so if the light enters our eyes we will see the object because our eyes can detect light
Can someone please help me with this worksheet. It’s due today and I have no idea what to do.
write short note on fulcrum
Answer:
The definition of a fulcrum is a pivot point around which a lever turns, or something that plays a central role in or is in the center of a situation or activity.
5. An astronaut has a mass of 65kg where the gravitational field strength is 10N/kg
a. Calculate the weight of the astronaut on earth
[3]
Answer: a) weight on Earth = mass of the object and gravity n the Earth. = 65*10 = 650 kg.
Explanation:
An astronaut has a mass of 65 kg on Earth where the gravitational field strength is 10 N kg A calculate the astronaut's weight on Earth
hope this helps :)
Answer:
650
Explanation:
use the equation
weight = gm
Pluto has a radius of 1.15 x 10^6 m, and its acceleration due to gravity is 0.61 | m/s^2. What is Pluto's mass?
so we will use Newton's gravitational law :
gravitational acceleration = G*m/r^2
G is the gravitational constant = G = 6.673×10^-11 N m^2 kg^-2
after substitution :
6.673×10^-11 * m / (1.15 x 10^6)^2 = 0.61
= 5.04575*10^-23 * m = 0.61
dividing over 5.04575*10^-23 :
m = 1.20894*10^22 kg
pls give me brainliest
Which of the following is a physical quantity that has a magnitude but not
direction?
- vector
- frame of reference
- scalar
- resultant
Answer:
Scalar
Explanation:
A scalar quantity is a physical quantity that has magnitude but no directional attribute.
An example of a scalar is speed and distance.
A vector is a physical quantity that has both magnitude and direction.
An example is displacement and velocity.
Scalar has only the magnitude value specified and nothing else.
The moon accelerates because it is
A. in a vacuum in space.
B. continuously changing direction.
C. a very large sphere.
D. constantly changing its shape.
Answer:
the Answer is b
Explanation:
because the moon usually orbits around our solar system
As the moon continuously changing direction, it accelerates.
Option B. is correct.
Define acceleration.The rate at which an object's velocity changes with respect to time is called acceleration. Accelerations are measured in terms of vectors. The orientation of the net force acting on an object determines the orientation of its acceleration.
The Moon is kept in orbit around us by the gravity of the Earth. It constantly shifting the Moon's velocity direction. This means that, despite its constant speed, gravity causes the Moon to accelerate all the time.
So, as the moon continuously changing direction, it accelerates.
Option B. is correct.
Find out more information about acceleration here:
https://brainly.com/question/2437624?referrer=searchResults
Calculate the electric field associated to an electric dipole for two charges separated 10-8 m with a dipole moment of 10-33 C m. Do not use unit of measure, just a whole number. Give the result in standard notation, not in scientific notation. Use for the Coulomb constant the value k
Answer:
18 N/C
Explanation:
Given that:
Electric field constant, k = 9*10^9 N/c
Distance, r = 10^-8 m
Dipole moment, p = 10^-33
Using the relation for electric field due to dipole :
E = [2KP / r³]
E = (2 * (9*10^9) * 10^-33) ÷ (10^-8)^3
E = (18 * 10^9 * 10^-33) ÷ 10^-24
E = [18 * 10^(9-33)] ÷ 10^-24
E = (18 * 10^-24) / 10^-24
E = 18 * 10^-24+24
E = 18 * 10^0
E = 18 N/C
Although the vocal tract is quite complicated, we can make a simple model of it as an open-closed tube extending from the opening of the mouth to the diaphragm, the large muscle separating the abdomen and the chest cavity. What is the length of this tube if its fundamental frequency equals a typical speech frequency of 230 Hz? Assume a sound speed of 350 m/s.
Answer:
0.76m
Explanation:
Given data
Frequency= 230Hz
speed= 350m/s
Since we are told that the frequency is the fundamental frequency n= 1
For a standing wave
Fn= nv/2L
n= 1
230= 1*350/2*L
230= 350/2L
cross multiply
2L= 350/230
2L=1.521
L=1.521/2
L=0.76m
Hence the length is 0.76m