Does anyone know what the answer is for the question???

Answer:

Matt=26

Brown=11

Step-by-step explanation:

Just trust me!!!

The present age of Matt given the information in the question is 26.

The present age of Brown given the information in the question is 8.

4y - 6 = x equation 1

x + y + 6 = 43 equation 2

Where:

Subsistute for x in equation 2

4y - 6 + y + 3 = 43

Combine similar terms

5y = 40

y = 8

Subsitute for y in equation 1

4(8) - 6 = x

32 - 6 = 26

To learn more about simultaneous equations, please check: https://brainly.com/question/25875552

Answer:

4

Step-by-step explanation:

  28 = 22 • 7  

   12 = 22 • 3  

   32 = 25

Answer:

I would need to see the models to answer this question.

Answer:

?

Step-by-step explanation:

Range is the output values which are the y values.

The dot is at y = 2 and the line moves upward to the right off the graph. This means the line will continue to infinity.

The range would be 2 to infinity.

(2, infinity)

Answer:

[tex](a)\ y =0\ or\ y=4\ or\ y=6[/tex]

[tex](b) \ (-\infty,4)\ u\ (6,\infty)[/tex]

[tex](c)\ (4,6)[/tex]

Step-by-step explanation:

Given

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

Solving (a): The constants

This implies that:

[tex]\frac{dy}{dt} = 0[/tex]

So, we have:

[tex]y^4 - 10y^3 + 24y^2 = 0[/tex]

Factorize:

[tex]y^2(y^2 - 10y + 24) = 0[/tex]

Expand and Factorize the expression in bracket

[tex]y^2(y^2 - 6y - 4y + 24) = 0[/tex]

[tex]y^2(y(y - 6) - 4(y - 6)) = 0[/tex]

[tex]y^2(y - 4)(y - 6) = 0[/tex]

Split

[tex]y^2 =0\ or\ y-4=0\ or\ y-6=0[/tex]

Solve for y

[tex]y =0\ or\ y=4\ or\ y=6[/tex]

The above represents the constants

Solving (b): Increasing values

Here

[tex]\frac{dy}{dx} > 0[/tex]

Follow the same process in (a) but replace all = with >

i.e.

[tex]y^2(y - 4)(y - 6) > 0[/tex]

[tex]y >0\ or\ y>4\ or\ y>6[/tex]

Test the values of each inequality

For [tex]y > 6[/tex]; say [tex]y = 7[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = 7^4 - 10*7^3 + 24*7^2[/tex]

[tex]\frac{dy}{dt} = 147[/tex]

[tex]147 > 0[/tex]

This is true for [tex]\frac{dy}{dx} > 0[/tex];  This implies that: [tex](6, \infty)[/tex]

For [tex]y > 4[/tex] Say [tex]y = 5[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = 5^4 - 10*5^3 + 24*5^2[/tex]

[tex]\frac{dy}{dt} = -25[/tex]

This is false:

Say [tex]y = 3[/tex] i.e. [tex]y < 4[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = 3^4 - 10*3^3 + 24*3^2[/tex]

[tex]\frac{dy}{dt} = 27[/tex]

[tex]27 > 0[/tex]

This is true for [tex]\frac{dy}{dx} > 0[/tex]. This implies that: [tex](0,4)[/tex]

For [tex]y > 0[/tex]

[tex]y > 0[/tex] implies that: [tex]y < 4[/tex]

For [tex]y < 0[/tex] say [tex]y = -1[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = (-1)^4 - 10*(-1)^3 + 24*(-1)^2[/tex]

[tex]\frac{dy}{dt} = 35[/tex]

This is true for [tex]\frac{dy}{dx} > 0[/tex]. This implies that [tex](-\infty, 0)[/tex]

We have: [tex](-\infty,0), (0,4)\ and\ (6,\infty)[/tex]

[tex](-\infty,0)\ and\ (0,4)[/tex] can be combined to give: [tex](-\infty,4)[/tex]

So, the interval is: [tex](-\infty,4)\ u\ (6,\infty)[/tex]

Solving (c): Decreasing values

Here

[tex]\frac{dy}{dx} < 0[/tex]

i.e.

[tex]y^2(y - 4)(y - 6) < 0[/tex]

[tex]y <0\ or\ y<4\ or\ y<6[/tex]

Test the values of each inequality

For [tex]y < 6[/tex]; say [tex]y = 5[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = 5^4 - 10*5^3 + 24*5^2[/tex]

[tex]\frac{dy}{dt} = -25[/tex]

This is true for [tex]\frac{dy}{dx} < 0[/tex];  This implies that: [tex](\infty,6)[/tex]

For [tex]y < 4[/tex]; say [tex]y = 3[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = 3^4 - 10*3^3 + 24*3^2[/tex]

[tex]\frac{dy}{dt} = 27[/tex]

This is false

Say [tex]y = 5[/tex] i.e.  [tex]y > 4[/tex]

This is the same as: [tex]y < 6[/tex]

So, we have the interval to be: [tex](4,\infty)[/tex]

For [tex]y < 0[/tex] say [tex]y = -1[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = (-1)^4 - 10*(-1)^3 + 24*(-1)^2[/tex]

[tex]\frac{dy}{dt} = 35[/tex]

This is false

Say [tex]y = 2[/tex] i.e [tex]y > 0[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = 2^4 - 10*2^3 + 24*2^2[/tex]

[tex]\frac{dy}{dt} = 32[/tex]

This is also false

So, the intervals are: [tex](4,\infty)[/tex] and [tex](\infty,6)[/tex].

This can be merged as: [tex](4,6)[/tex]

Hence, the interval for [tex]\frac{dy}{dt} < 0[/tex] is [tex](4,6)[/tex]

Answer:

Personification is your answer.

Hope it helps!!!

Answer: x greater-than or equal-to 2,236

Step-by-step explanation:

5,000-2,764= 2,236

so Li's family still needs to save at least $2,236

Answer:

A

Step-by-step explanation:

bc

Answer:

4123

Step-by-step explanation:

A=Pert,

where A is the balance of the account, P is the principal, r is the annual interest rate (as a decimal), and t is the time (in years). We are given that P=2800, r=0.043, and t=9. Substituting the values into the formula and using a calculator to evaluate, we find

A=Pert=2800e(0.043)(9)≈4123.16

Answer:

96 cm³

Step-by-step explanation:

v = 4 x 3 x 8 = 96 cm³

Answer:

The volume of the prism is 96cm^3

Step-by-step explanation:

You multpily 4*3*8=96

Answer:12/15

Step-by-step explanation: first you add 7+5=12

then add 12+3=15

Answer:

Step-by-step explanation:

Answer:

17x + 56 = 0

Step-by-step explanation:

add 2x and 15x

Answer:

3 expodent 12

Step-by-step explanation:

Answer:

#7

#8

The difference:

#9

#10

Max is right

Answer:

I think the answer is 5 down and over to the left 3.

Step-by-step explanation:

I just counted from the point on the (4,3) and counted down until it was line up with the other point. Next, I counted from there to the other point.

This question is incomplete, the complete question is;

An article in Knee Surgery, Sports Traumatology, Arthroscopy (2005, Vol. 13, pp. 273-279), considered arthroscopic meniscal repair with an absorbable screw. Results showed that for tears greater than 25 millimeters, 13 of 19 repairs were successful while for shorter tears, 22 of 30 repairs were successful.

a) Is there evidence that the success rate is greater for longer tears? Use alpha=0.05

Answer:

P-value = 0.6443

Now, since the p-value( 0.6443 ) is greater than the significance level (0.05), We fail to reject null hypothesis.

Therefore, there is no significant difference in the successive proportion ( rate ). [tex]p[/tex]₁ =  [tex]p[/tex]₂

Step-by-step explanation:

Given the data in the question;

         Sample of tears greater than 25;

number of successive repairs X₁ = 13

number of repair n₁ = 19

proportion of successive repairs [tex]p[/tex]₁ = 13/19 = 0.68

q₁ = 1 -  [tex]p[/tex]₁ = 1 - 0.68 = 0.32

        Sample of tears shorter than 25;

number of successive repairs X₂ = 22

number of repair n₂ = 30

proportion of successive repairs [tex]p[/tex]₂ = 22/30 = 0.73

q₂ = 1 -  [tex]p[/tex]₂ = 1 - 0.73 = 0.27

so;

H₀ : There is no significant difference in the successive proportions;  [tex]p[/tex]₁ =  [tex]p[/tex]₂

Hₐ : The successive rate is greater for longer tears [tex]p[/tex]₁ >

Significance level ∝ = 0.05

Test Statistics

Z =  ([tex]p[/tex]₁ -

so we substitute

Z =  ( 0.68 - 0.73 / √[ (0.68 ×0.32 / 19) + ( 0.73×0.27 / 30 ) ]

Z = -0.05 / √[ 0.01802 ]

Z = -0.05 / 0.1342

Z = -0.37  

P-value for the given test, p = P( Z > -0.37 )

= 1 - P( Z ≤ - 0.37 )

= 1 - 0.35569

P-value = 0.6443

Now, since the p-value( 0.6443 ) is greater than the significance level (0.05), We fail to reject null hypothesis.

Therefore, there is no significant difference in the successive proportion ( rate ). [tex]p[/tex]₁ =  [tex]p[/tex]₂

Answer:

169.28

Step-by-step explanation:

18.4x9.2=169.28

9514 1404 393

Answer:

  37°

Step-by-step explanation:

The diagonals of a rhombus are angle bisectors. Angle 1 matches the other half of angle L.

  ∠1 = 37°

__

Angle 2 is the complement, 53°, and angle 3 is the same as angle 2, 53°.

The diagonals of a rhombus are perpendicular bisectors of each other, so angle 4 is 90°.

Answer:

3,990

Step-by-step explanation:

Answer:

yeh you are correct so it will be b is equal to minus 42 minus 9.3 that will be equal to -51.3 so that is the value of b

Answer:

C. (8,1)

Step-by-step explanation:

9514 1404 393

Answer:

  12.5 cm

Step-by-step explanation:

Triangle IDA is a 3-4-5 right triangle with a scale factor of 5. That is, segment AI is 25 cm long. Since IS is half the length of the diagonal, it is ...

  IS = (25 cm)/2

  IS = 12.5 cm

__

If you like, you can work out the length of AI using the Pythagorean theorem:

  AI² = DI² +DA²

  AI = √(15² +20²) = √(225 +400) = √625 = 25

Answer:

Well yes, because it should have cost $3.2 PER gallon

Step-by-step explanation:

Divide 40 by 12.5 to find out how much of a per gallon costs! Hope it helps.

Answer:

8

Step-by-step explanation:

Answer:

-8

Step-by-step explanation:

20-28= -8

Answer:

Confidence Interval =  ( 5.6 < μ < 8.2 )

The interval shows that the mean attractiveness is Above average on a scale of 1 to 10

Step-by-step explanation:

Data Given  : 5, 8, 2, 8, 7, 6, 6, 8, 9, 9, 6, 9

a) construct a confidence interval at a 95% confidence level

confidence interval = x ± tcritical ( s / √ n ) ------ ( 1 )

n = 12

μ (mean) = ( 5+8+2+8+7+6+6+8+9+9+6+9 ) / 12  ≈ 6.92

std ( s ) = √ 1/11 *∑( xi- X )^2

= √ 1/11 *  ( 5 - 6.92)^2 + ( 8 - 6.92)^2 + ( 2 - 6.92)^2 + ( 8 - 6.92)^2 + ( 7-6.92)^2 + ( 6 - 6.92)^2 + (6 - 6.92 )^2 + ( 8 - 6.92 )^2 + ( 9 - 6.92)^2 + ( 9 - 6.92)^2 + ( 6 - 6.92 )^2 + ( 9 - 6.92 )^2

= √ 1/11 * 46.92 =  2.07

tcritical at ∝ 0.05 , df = 11  = 2.20

Back to equation 1

6.92 ± 2.2 ( 2.07 / √ 12 )

( 6.92 ± 1.31 )

Confidence Interval =  ( 5.6 < μ < 8.2 )    

Answer:

The point of a pencil

Step-by-step explanation:

all other three mesure 90 the point of pencil is not square shape in order for it to be right angle its gotta be square shape hope this helps! may i be marked brainliest?

Answer:60

Step-by-step explanation: