Does anyone know the answer please help!!

Answer:

i think x = -5, y = -7 is a other solution set

Answer:

Perimeter = 12 1/2 in

Area = 9.375 in

Step-by-step explanation:

Perimeter:

(3 3/4) + (3 3/4) + (2 1/2) + (2 1/2) = 12 1/2

Area:

(3 3/4) * (2 1/2) = 9.375

Answer:

P = 12 1/2 in

A = 9 3/8 in²

Step-by-step explanation:

L = 3 3/4 in

W = 2 1/2 in

Area:

A = L × W

A = (3 3/4 in)(2 1/2 in)

A = 15/4 in × 5/2 in

A = 75/8 in²

A = 9 3/8 in²

Perimeter:

P = 2(L + W)

P = 2(3 3/4 in + 2 1/2 in)

P = 2(15/4 in + 5/2 in)

P = 2(15/4 in + 10/4 in)

P = 2(25/4 in)

P = 25/2 in

P = 12 1/2 in

Here is ur answer of your question

Answer:

Number 21 is < number 23 is > number 22 is < and number 24 is >

Step-by-step explanation:

Answer:

225

Step-by-step explanation:

po ang answer ko

please comment if I'm wrong

(a) It looks like you're saying

[tex]\displaystyle F(x) = \int_0^x (t - 3t^2 + 7) \, dt[/tex]

Find the critical points of F(x). By the fundamental theorem of calculus,

F'(x) = x - 3x² + 7

The critical points are where the derivative vanishes. Using the quadratic formula,

x - 3x² + 7 = 0   ⇒   x = (1 ± √85)/6

Compute the second derivative of F :

F''(x) = 1 - 6x

Check the sign of the second derivative at each critical point.

• x = (1 + √85)/6 ≈ 1.703   ⇒   F''(x) < 0

• x = (1 - √85)/6 ≈ -1.370   ⇒   F''(x) > 0

This tells us F attains a minimum of

[tex]F\left(\dfrac{1-\sqrt{85}}6\right) \approx \boxed{-6.080}[/tex]

(b) Split up the domain of F at the critical points, and check the sign of F'(x) over each subinterval.

• over (-∞, -1.370), consider x = -2; then F'(x) = -7 < 0

• over (-1.370, 1.703), consider x = 0; then F'(x) = 7 > 0

• over (1.703, ∞), consider x = 2; then F'(x) = -3 < 0

This tells us that

• F(x) is increasing over ((1 - √85)/6, (1 + √85)/6)

• F(x) is decreasing over (-∞, (1 - √85)/6) and ((1 + √85)/6, ∞)

(c) Solve F''(x) = 0 to find the possible inflection points of F(x) :

F''(x) = 1 - 6x = 0   ⇒   6x = 1   ⇒   x = 1/6

Split up the domain at the inflection point and check the sign of F''(x) over each subinterval.

• over (-∞, 1/6), consider x = 0; then F''(x) = 1 > 0

• over (1/6, ∞), consider x = 2; then F''(x) = -11 < 0

This tells us that

• F(x) is concave up over (-∞, 1/6)

• F(x) is concave down over (1/6, ∞)

Answer:

the word phrase use to represent 6x+ 6 is sum 6x and 6

Step-by-step explanation:

first you sum 6x and 6

Answer:

C. $32.09, since it's not the fixed cost, it changes based on how much drinks are purchased.

Answer:

 (c)  p = vm

Step-by-step explanation:

Momentum, represented by 'p', is the product of mass and velocity. It is a vector quantity, just as velocity is a vector quantity.

  p = vm

According to the two-way table, the correct option is:

From the table, it is taken that:

Hence, the highlighted 0.1 = 10% means that:

You can learn more about two-way tables at https://brainly.com/question/24670062

Answer:

y = 3

x = 2

Step-by-step explanation:

-5x + 4y = 2

9x - 4y = 6

Sum both eq.

-5x + 9x = 4x

+4y - 4y = 0

2 + 6 = 8

then:

4x + 0 = 8

4x = 8

x = 8/4

x = 2

from the first eq.

-5x + 4y = 2

-5*2 + 4y = 2

-10 + 4y = 2

4y = 2 + 10

4y = 12

y = 12/4

y = 3

Check:

from the second eq.

9x - 4y = 6

9*2 - 4*3 = 6

18 - 12 = 6

Answer:30 drinks

Step-by-step explanation:

Answer:

0.459

the 9 rounds the 5 up to a 6 so its 0.46

Answer:

The answer is 0.46

Step-by-step explanation:

The 9 is over 5, so you round up which bumps the 5 up to a 6. It could also be written as 0.460 but the extra 0 is unnecessary.

Step-by-step explanation:

the option you chose (<C~=<Y) is absolutely correct.

Answer:

60 degrees

Step-by-step explanation:

Similar shapes have the same angles but different side lengths.

Answer:

The answer is 60°

Step-by-step explanation:

Because pentagon JKLMN is basically the same as pentagon VWXYZ and if you see in the smaller pentagon the angle for L is 90° and same goes for the bigger pentagon

Answer:

96 oz

Step-by-step explanation:

1 lb= 16 oz

so, 16×6=96

Answer:step 2

Step-by-step explanation:

Therefore, the solved inequality is z > -4.

Hoped this helped.

[tex]BrainiacUser1357[/tex]

Answer:

See explanation

Step-by-step explanation:

Dilation of 4

G (0, 1) G' (0, 4)

F (1, 1) F' (4, 4)

Gx'/Gx = 0 / 0 = 0

Gy' / Gy = 4 / 1 = 4

Fx' / Fx = 4 / 1 = 4

Fy' / Fy = 4 / 1 = 4

Answer:

40x-17

Step-by-step explanation:

Answer:

x = 2.6, y = 2.2

Step-by-step explanation:

if 4y = 2 + 3x - 1 and

y = 2x - 3,

4y = 2 + 3x -1 and 4y = 8x - 12 so

8x - 12 = 2 + 3x - 1

so 5x - 12 = 1,

5x = 13,

x = 2.6

If x = 2.6,

y = 5.6 - 3

so y = 2.2

Please mark me as Brainliest!

Step-by-step explanation:

we use the law of sine :

sin(A)/a = sin(B)/b = sin(C)/c

with the related angles being opposite of the lines.

so, we have

sin(A)/1 = sin(A) = sin(90)/ sqrt(10) = 1/ sqrt(10) =

= 0.316227766...

cos²(A) + sin²(A) = 1

cos(A) = sqrt(1 - sin²(A)) = sqrt(1 - 0.1)) = sqrt(0.9) =

= 0.948683298...

tan(A) = sin(A)/cos(A) = 0.333333333...

cot(A) = 1/tan(A) = 3

sec(A) = 1/cos(A) = 1.054092553...

csc(A) = 1/sin(A) = 3.16227766...

Answer:

84

Step-by-step explanation:

TPS + SPR = RPT and TPS = RPT - SPR

The measure of RPT and SPR are given so we just need to place them and do the calculation

TPS = 137 - 53

TPS = 84

Answer:

128

Step-by-step explanation:

Answer:

22.5 degrees

Step-by-step explanation:

Complementary angles add up to be 90 degrees. You can model the simple equation [tex]x+3x=90[/tex] where is x is the small angle and 3x is the large angle.

[tex]4x=90\\x=22.5[/tex]

the smaller angle is 22.5 degrees

a) The value of [tex]k'(0)[/tex] is [tex]\frac{3\sqrt{3}}{2}[/tex].

b) The value of [tex]m'(5)[/tex] is approximately -0.034.

c) The value of [tex]x[/tex] is approximately 0.622.

a) [tex]f(x)[/tex] is a piecewise function formed by two linear functions, whose form is defined by the following definition:

[tex]f(x) = \frac{y_{2}-y_{1}}{x_{2}-x_{1}} \cdot x + b[/tex] (1)

Where:

Now we proceed to determine the linear functions:

Line 1: [tex]x \in [-1, 2)[/tex]

[tex](x_{1}, y_{1}) = (0, 3)[/tex], [tex](x_{2}, y_{2}) = (1, 5)[/tex], [tex]b = 3[/tex]

[tex]f(x) = \frac{5-3}{1-0}\cdot x + 3[/tex]

[tex]f(x) = 2\cdot x + 3[/tex]

Line 2: [tex]x \in [2, 8][/tex]

[tex](x_{1}, y_{1}) = (2, 7)[/tex], [tex](x_{2}, y_{2}) = (8, 3)[/tex]

First, we determine the slope of function:

[tex]m = \frac{3-7}{8-2}[/tex]

[tex]m = -\frac{2}{3}[/tex]

Now we proceed to determine the intercept of the linear function:

[tex]7 = -\frac{2}{3}\cdot 2 + b[/tex]

[tex]b = \frac{25}{3}[/tex]

[tex]f(x) = -\frac{2}{3}\cdot x +\frac{25}{3}[/tex]

The first derivative of a linear function is its slope, and the first derivative of a product of functions is defined by:

[tex]k'(x) = f'(x)\cdot g(x) + f(x)\cdot g'(x)[/tex]

If we know that [tex]f(x) = 2\cdot x + 3[/tex], [tex]f'(x) = 2[/tex], [tex]g(x) = \sqrt{x^{2}-x+3}[/tex], [tex]g'(x) = \frac{2\cdot x - 1}{2\cdot \sqrt{x^{2}-x+3}}[/tex] and [tex]x = 0[/tex], then:

[tex]k'(x) = 2\cdot \sqrt{x^{2}-x+3}+\frac{(2\cdot x +3)\cdot (2\cdot x - 1)}{2\cdot \sqrt{x^{2}-x+3}}[/tex]

[tex]k'(0) = 2\sqrt{3}-\frac{3}{2\sqrt{3}}[/tex]

[tex]k'(0) = \frac{12-3}{2\sqrt{3}}[/tex]

[tex]k'(0) = \frac{9}{2\sqrt{3}}[/tex]

[tex]k'(0) = \frac{3\sqrt{3}}{2}[/tex]

The value of [tex]k'(0)[/tex] is [tex]\frac{3\sqrt{3}}{2}[/tex].

b) The derivative is found by means of the formulas for the derivative of the product of a function and a constant and the derivative of a division between two functions:

[tex]m'(x) = \frac{f'(x)\cdot g(x)-f(x)\cdot g'(x)}{2\cdot [g(x)]^{2}}[/tex] (2)

If we know that [tex]f(x) = -\frac{2}{3}\cdot x +\frac{25}{3}[/tex], [tex]f'(x) = -\frac{2}{3}[/tex], [tex]g(x) = \sqrt{x^{2}-x+3}[/tex], [tex]g'(x) = \frac{2\cdot x - 1}{2\cdot \sqrt{x^{2}-x+3}}[/tex] and [tex]x = 5[/tex], then:

[tex]f(5) = 5[/tex]

[tex]f'(5) = -\frac{2}{3}[/tex]

[tex]g(5) = \sqrt{23}[/tex]

[tex]g'(5) = \frac{9\sqrt{23}}{46}[/tex]

[tex]m'(5) = \frac{\left(-\frac{2}{3} \right)\cdot \sqrt{23}-\left(-\frac{2}{3} \right)\left(\frac{9\sqrt{23}}{46} \right)}{3\cdot 25}[/tex]

[tex]m'(5) \approx -0.034[/tex]

The value of [tex]m'(5)[/tex] is approximately -0.034.

c) In this case we must find a value of [tex]x[/tex], so that [tex]h'(x) = 2[/tex]. Hence, we have the following formula below:

[tex]5\cdot e^{x}-9\cdot \cos x = 2[/tex]

A quick approach is using a graphing tool a locate a point so that [tex]5\cdot e^{x}-9\cdot \cos x = 2[/tex]. According to this, the value of [tex]x[/tex] is approximately 0.622.

To learn more on derivatives, we kindly invite to check this verified question: https://brainly.com/question/21202620

Answer:

The answer is B

Step-by-step explanation:

plug 2 into x to see

A.

x^2 + 8

2^2 + 8

4 + 8 = 12

B.

3x^2 + 1

3(2)^2 + 1

3(4) + 1

12 + 1 = 13

C.

2x^3 + 5

2(2)^3 + 5

2(8) + 5

16 + 5 = 21

D.

x^2 + x

2^2 + 2

4 + 2 = 6

Step-by-step explanation:

1 10.38

2 16.77

3 11.499

4 11.486

5 0.0947

6 30.52875

7 525

8 32.57862069

9 16.5625