Answer:
The function prototypes are as follows:
int findSum(int fn, int sn, int tn);
int findMin(int fn, int sn, int tn);
int findMax(int fn, int sn, int tn);
The functions are as follows:
int findSum(int fn, int sn, int tn){
return fn+sn+tn;}
int findMin(int fn, int sn, int tn){
int min = fn;
if(sn<=min && sn<=tn){
min = sn; }
if(tn <= min && tn <= sn){
min = tn; }
return min;}
int findMax(int fn, int sn, int tn){
int max = fn;
if(sn>=max && sn>=tn){
max = sn; }
if(tn>=max && tn>=sn){
max = tn; }
return max;}
Explanation:
Given
See attachment 1 for the main function
Required
Write the following functions
findSumfind MinfindMax.The following represents the function prototypes
int findSum(int fn, int sn, int tn);
int findMin(int fn, int sn, int tn);
int findMax(int fn, int sn, int tn);
This declares the findSum function
int findSum(int fn, int sn, int tn){
This returns the sum of the three numbers
return fn+sn+tn;}
This declares the findMin function
int findMin(int fn, int sn, int tn){
This initialzes min (i.e. minumum) to fn
int min = fn;
This checks if sn is the minimum
if(sn<=min && sn<=tn){
min = sn; }
This checks if tn is the minimum
if(tn <= min && tn <= sn){
min = tn; }
This returns the minimum of the three numbers
return min;}
This declares the findMax function
int findMax(int fn, int sn, int tn){
This initialzes max (i.e. maximum) to fn
int max = fn;
This checks if sn is the maximum
if(sn>=max && sn>=tn){
max = sn; }
This checks if tn is the maximum
if(tn>=max && tn>=sn){
max = tn; }
This returns the maximum of the three numbers
return max;}
See cpp attachment for complete program which includes the main
what can a user modify on a business card using the Edit Business card in the dialog box?
how many stages needed to have powerful amplifier?
Power amplifier stages in a real circuit. Circuit diagram of a three stage practical audio power amplifier is shown in the figure below. Small signal transistor Q1 and its associated components form the voltage amplification stage.
Answer:
Generally you should pick an amplifier that can deliver power equal to twice the speaker's program/continuous power rating. This means that a speaker with a “nominal impedance” of 8 ohms and a program rating of 350 watts will require an amplifier that can produce 700 watts into an 8 ohm load.
True or false you cannot get a computer virus is you instal antivirus
Answer: F
Explanation: There are many ways hackers can get into your computer, and many ways can bypass an antivirus so it is False
Please Fix This For Me
print ("Please enter a number between 1 and 100")
n = input
if = n < 1 and n > 100:
if = (n // 2 == 0):
print (n, "is even")
if = (n // 3 == 0):
print (n, "is odd")
else:
print("You have not entered a number between 1 and 100.")
Answer:
The correction is as follows:
n = int(input("Please [tex]enter\ a[/tex] [tex]number\ between\ 1[/tex] and 100: "))
if n < 1 or n > 100:
print("You [tex]have\ not[/tex] entered a [tex]number\ between\ 1[/tex] and 100.")
elif n % 2 == 0:
print (n, "is even")
else:
print (n, "is odd")
Explanation:
See attachment for explanation
Consider the following method:
public static String joinTogether(int num, String[] arr)
{
String result = "";
for (String x : arr)
{
result = result + x.substring(0, num);
}
return result;
}
The following code appears in another method in the same class:
String[] words = {"dragon", "chicken", "gorilla"};
int number = 4;
System.out.println(joinTogether(number, words));
What is printed when the code above is executed?
a. dragonchickengorilla
b. drachigor
c. dragchicgori
d. dragochickgoril
e. There is an error in the program, it does not run
Answer: b.
Explanation:
How SPARQL 1.1 has advantage over SPARQL 1.0??
Using a tag, set the color to green for all tags.
Answer:
<style>
p {
background-color: rgb(255, 0, 0);
}
h1 {
background-color: rgb(0, 255, 0);
}
ol {
background-color: rgb(97,51,47);
}
</style>
Explanation:
Put this at the top of your code. It should target the paragraph tag, the header h1 tag, and the Ordered List (OL) tag individually and set their background colors respectively.
It's been a while since I've done CSS so you might have to tweak the syntax a bit, but it should look something like that.