Could I get help on this question please . My parents won’t help me /:

Could I Get Help On This Question Please . My Parents Wont Help Me /:

Answers

Answer 1

Answer:

Tarzan will be moving at 7.4 m/s.

Explanation:

From the question given above, the following data were obtained:

Height (h) of cliff = 2.8 m

Initial velocity (u) = 0 m/s

Final velocity (v) =?

NOTE: Acceleration due to gravity (g) = 9.8 m/s²

Finally, we shall determine how fast (i.e final velocity) Tarzan will be moving at the bottom. This can be obtained as follow:

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 2.8)

v² = 0 + 54.88

v² = 54.88

Take the square root of both side

v = √54.88

v = 7.4 m/s

Therefore, Tarzan will be moving at 7.4 m/s at the bottom.


Related Questions

Universal Gravitation Problem Set
Highlight Given information in GREEN. Highlight what you are solving for in YELLOW.
Formula: Fg= G*M,*M,/d? G= 6.67 * 10-11 N*M°/Kg?
The distance between Earth and its moon is 3.84 x 10 meters. Earth's mass is
m = 5.98 x 1024 kilograms and the mass of the moon is 7.36 x 1022 kilograms.
What is the force between Earth and the moon?

Answers

Answer:

The force between Earth and the moon is 1.99x10²⁶ N.

Explanation:

The force between Earth and the moon can be found using the Gravitational Force equation:

[tex] F_{g} = \frac{Gm_{E}m_{m}}{d^{2}} [/tex]

Where:

d: is the distance between Earth and the moon = 3.84x10⁵ m

G: is the gravitational constant = 6.67x10⁻¹¹ Nm²/kg²

[tex]m_{E}[/tex]: is the Earth's mass = 5.98x10²⁴ kg

[tex]m_{m}[/tex]: is the moon's mass = 7.36x10²² kg

Hence, the force is:

[tex] F_{g} = \frac{Gm_{E}m_{m}}{d^{2}} = \frac{6.67 \cdot 10^{-11} Nm^{2}/kg^{2}*5.98\cdot 10^{24} kg*7.36\cdot 10^{22} kg}{(3.84\cdot 10^{5} m)^{2}} = 1.99 \cdot 10^{26} N [/tex]

Therefore, the force between Earth and the moon is 1.99x10²⁶ N.

I hope it helps you!          

Students in an introductory physics lab are performing an experiment with a parallel-plate capacitor made of two circular aluminum plates, each 20 cm in diameter, separated by 1.0 cm. How much charge can be added to each of the plates before a spark jumps between the two plates? For such flat electrodes, the field that causes a spark is at the high end of the range pre- sented in the chapter; assume a value of 3 * 106 N/C.

Answers

Answer:

Q = 0.83 μC

Explanation:

Assuming that plates are much larger than the distance between them, we can think the electric field as constant and perpendicular to the outer surface of the plates.Applying Gauss' law to a rectangular surface half inside one of the plates and half outside it, since E and A are parallel each other, and E is zero on the other three faces, we can find the following expression for the electric field created by the charge on the plate:

      [tex]E = \frac{Q*A}{\epsilon_{0} } (1)[/tex]

Solving for Q, replacing E by the maximum electric field that doesn't cause the dielectric strength to break (3*10⁶ N/C), we get:

      [tex]Q_{max} = E_{max} * \pi *\frac{d^{2}}{4} *\epsilon_{0} = 3e6N/C*\pi *\frac{(0.2m)^{2} }{4} * 8.85e-12C2/Nm2 = 0.83\mu C (2)[/tex]

I need help with this, I can't figure it out.
Here is the link:
https://platform.breakoutedu.com/game/play/fun-in-the-sun-140559-XMWCQF1LPL

Answers

Answer:

Star, Triangle, Circle, Rhombus, Square.Left, Down, Right, Down, Up.2,3,2,4.L,O,O,K,I,N,G,F,L,Y.

Explanation: You're welcome ✓

write any three applicataion pressure in our daily life ?​

Answers

Answer:

because the gravity of the earth

A person is standing on a level floor. His head, upper torso, arms, and hands together weigh 458 N and have a center of gravity that is 1.34 m above the floor. His upper legs weigh 120 N and have a center of gravity that is 0.766 m above the floor. Finally, his lower legs and feet together weigh 89.8 N and have a center of gravity that is 0.204 m above the floor. Relative to the floor, find the location of the center of gravity for the entire body.

Answers

Answer:

the location of the center of gravity for the entire body is 1.08 m

Explanation:

Given the data in the question;

w1 = 458 N, y1 = 1.34 m

w2 = 120 N, y2 = 0.766 m

w3 = 89.8 N, y2 = 0.204 m

The location arrangement of the body part is vertical, locate the overall centre of gravity by simply replacing the horizontal position x by the vertical position y as measured relative to the floor.

so,

[tex]Y_{centre of gravity}[/tex] = (w1y1 + w2y2 + w3y3 ) / ( w1 + w2 + w3 )

so we substitute in our values

[tex]Y_{centre of gravity}[/tex] = (458×1.34 + 120×0.766 + 89.8×0.204 ) / ( 458 + 120 + 89.8 )

[tex]Y_{centre of gravity}[/tex] = 723.9592 / 667.8

[tex]Y_{centre of gravity}[/tex] = 1.08 m

Therefore, the location of the center of gravity for the entire body is 1.08 m

The amount of energy a substance has depends on the state of matter
the substance is in at the time.

True
or False

Answers

False I believe!
Hope it’s right!

What color is seen when cyan light is shown on magenta paper

Answers

Answer:

blue

You see white. What happens when you shine cyan light on a magenta shirt? You see blue.

Explanation:

image.
A concave lens always produces a(n)
A. inverted
o
B. real
C. virtual
D. magnified

Answers

Answer : B - real

Explanation : 1. you can see the image the way it is as in its no in a mirror.
2. The image will not be inverted

But it could be magnified too tbh. But I would go for real

Answer:

Explanation:

Its Virtual, how would you describe the image formed by a convex mirrior? virtual upright, smaller

A force of 350 N is applied to an object that accelerated at a rate of 5 m/sec2. What is the mass of the object

Answers

Answer:

7/ m5sec per minute ckvhxrsuvj

A sodium ion, Na+ , has a positive charge because it
A. gained an electron.
B. lost a proton.
C. gained a neutron.
D. lost an electron.

Answers

D. lost an electron

because they have free electron in the outermost shell which they will like to denote, in order to attain stable configuration

ELE Review questions
POSSIBLE POINTS: 3
Match the energy transformation sequence with the device it describes:
A hair dryer plugged into the wall
a
A hand crank generator emergency radio
A battery operated fan
11 CE to ELE
+ ELE to KE
:: KE to ELE
h
1
2
A Review

Answers

Answer:

1. ELE to KE = Electrical energy conversion to kinetic energy.

2. KE to ELE = kinetic energy conversion to electrical energy.

3. CE to ELE = chemical energy conversion to electrical energy.

Explanation:

The Law of Conservation of Energy states that energy cannot be destroyed but can only be transformed or converted from one form to another.

Some examples of energy are chemical energy, electrical energy, kinetic energy, sound energy, potential energy, light energy, etc.

The transformation of energy from one form to another are described below;

1. A hair dryer plugged into the wall: it involves the conversion of electrical energy to kinetic energy. The energy type present in the wall socket is electrical energy which powers the hair dryer to have kinetic energy i.e the energy possessed due to motion of hair dryer.

2. A hand crank generator emergency radio: it illustrates the conversion of kinetic energy to electrical energy. The hand crank generator possess kinetic energy as it is being wounded before it is then converted into electrical energy which powers the radio.

3. A battery operated fan: it illustrates the conversion of chemical energy to electrical energy. The cells present in battery possess chemical energy that is being converted into electrical energy to power the fan.

A 15 kg mass is lifted to a height of 2m. What is gravitational potential energy at this position

Answers

Answer: 294J

Explanation:

[tex]U_g=mg(y_f-y_i)[/tex]

[tex]U_g=(15)(9.8)(2-0)=294J[/tex]

Answer:

294.3 J

Explanation:

U = mgh

U = energy

m = mass

g = gravity

h = height

so

U = 15kg * 9.81 m/s^2 * 2m

294.3 J (joules) [kg *m^2/s^2]

Approximately where is it currently high tide on Earth? Group of answer choices wherever it is currently noon anywhere that ocean water laps upon the shore on the portion of Earth facing directly toward the Moon and on the portion of Earth facing directly away from the Moon only on the portion of the Earth facing directly toward the Moon

Answers

Answer:

Option D, only on the portion of the Earth facing directly toward the Moon

Explanation:

Tides are caused by the gravitational pull of moon. The part of earth that faces the moon experiences the highest gravitational force and hence the high tides will occur in this regions only. The regions that do not faces the moon experiences low tides. It is the gravity of moon that attracts the ocean water towards itself.

Hence, Option D is correct

why don't we draw lewis dot diagrams for nobel gases

Answers

In a ground-state atom, the first two valence electrons go into the "s" orbital, so they'll be paired and it's appropriate to put a pair of dots into a Lewis dot diagram. ... Noble gases have a complete set of valence electrons (2 for helium and 8 for the others), so this one can't be a noble gas.

A person in car slides to the right when going through a very sharp left turn on the highway. Is that law of inertia or law of acceleration?​

Answers

Answer:

Inertia :)

Explanation:

Could a sea breeze occur at night? Explain why or why not.

Answers

No sea breeze can not occur at night because while sea breezes occur during the day, land breezes occur at night. Despite the difference in times at which the land breezes and sea breezes occur, the reason for the land breeze's formation is basically the same as the sea breeze, but the role of the ocean and land is reversed.
Hope this helps ✌️

A rotating paddle wheel is inserted in a closed pot of water. The stirring action of the paddle wheel heats the water. During the process, 30 kJ of heat is transferred to the water and 5 kJ is lost to the surrounding air. The paddle wheel work amounts to 500 J. Determine the final energy of the system if its initial energy is 10 kJ.

Answers

Answer:

the final energy of the system is 35.5 kJ.

Explanation:

Given;

initial energy of the system, E₁ = 10 kJ

heat transferred to the system, q₁  30 kJ

Heat lost to the surrounding, q₂ = 5kJ

heat gained by the system, Q = q₁ - q₂ = 30 kJ - 5kJ = 25 kJ

work done on the system, W = 500 J = 0.5 kJ

Apply first law of thermodynamic,

ΔU = Q + W

where;

ΔU  is change in internal energy

Q is the heat gained by the system

W is work done on the system

ΔU = 25kJ + 0.5 kJ

ΔU = 25.5 kJ

The final energy of the system is calculated as;

E₂ = E₁ + ΔU

E₂ = 10 kJ + 25.5 kJ

E₂ =  35.5 kJ.

Therefore, the final energy of the system is 35.5 kJ.

A dolphin has a mass of 740 kg. He swims along the water at a velocity of 12 m/s and
jumps out of the water so that he has Gravitational Potential Energy of 53000 J.
How high does the dolphin jump?

Answers

Answer:

I dunno

Explanation:

I really wanted to help you, but then I realized i didnt know how to

A positively charged particle of mass 7.2 x 10-8 kg is traveling due east with a speed of 88 m/s and enters a 0.6-T uniform magnetic field. The particle moves through one-quarter of a circle in a time of 2.2 x 10-3 s, at which time it leaves the field heading due south. All during the motion the particle moves perpendicular to the magnetic field. Determine the magnitude of its charge in mC. (1 mC

Answers

Answer:

q = 8.57 10⁻⁵ mC

Explanation:

For this exercise let's use Newton's second law

         F = ma

where force is magnetic force

        F = q v x B

the bold are vectors, if we write the module of this expression we have

         F = qv B sin θ

as the particle moves perpendicular to the field, the angle is θ= 90º

        F = q vB

the acceleration of the particle is centripetal

        a = v² / r

we substitute

        qvB = m v² / r

         qBr = m v

          q =[tex]\frac{m\ v}{B\ r}[/tex]

The exercise indicates the time it takes in the route that is carried out with constant speed, therefore we can use

          v = d / t

the distance is ¼ of the circle,

          d = [tex]\frac{1}{4} \ 2\pi r[/tex]

           d =[tex]\frac{\pi }{2r}[/tex]

we substitute

           v =  [tex]\frac{\pi r}{2t}[/tex]

           r = [tex]\frac{2 \ t \ v}{\pi }[/tex]

           

let's calculate

           r =[tex]\frac{2 \ 2.2 \ 10^{-3} \ 88}{\pi }[/tex] 2 2.2 10-3 88 /πpi

           r = 123.25 m

         

let's substitute the values

           q = [tex]\frac{ 7.2 \ 10^{-8} \ 88}{ 0.6 \ 123.25}[/tex]7.2 10-8 88 / 0.6 123.25

            q = 8.57 10⁻⁸ C

Let's reduce to mC

           q = 8.57 10⁻⁸ C (10³ mC / 1C)

           q = 8.57 10⁻⁵ mC

whk is thefounder of pakistan?​

Answers

Answer:

Muhammad Ali Jinnah (Urdu: محمد علی جناح‎; born Mahomedali Jinnahbhai; 25 December 1876 – 11 September 1948) was a barrister, politician and the founder of Pakistan.

Mohammed Ali Jinnah, also called Qaid-i-Azam (Arabic: “Great Leader”), (born December 25, 1876?, Karachi, India [now in Pakistan]—died September 11, 1948, Karachi), Indian Muslim politician, who was the founder and first governor-general (1947–48) of Pakistan

A light source emits light with dominant wavelengths in the range of 650 to 690 nm. what is the principle color of light emitted by the source?

Answers

Answer:

Please see below as the answer is self-explanatory.

Explanation:

The visible range extends roughly from 400 nm (violet) to 700 nm (red).Below the violet is the ultra-violet spectrum (with higher energy) and above red, we have the infra-red spectrum.The wavelengths in the range of 650 to 690 nm have red as the dominant color.

You are hiking pine mountain and have finally reached the top. You are peering over the edge and accidentally drop your phone while taking pictures. Your phone falls and hit the
ground 13 seconds later. How tall is the mountain?

Answers

Answer:

The cliff is 12.71m tall.

Explanation:

Why?

Before solving the problem, we must remember that the phone was dropped, it means that there is no initial velocity, also, the acceleration acting on the phone is the acceleration due to gravity.

So, to find how tall is the cliff, we can use the following equations:

\begin{gathered}y=y_o+v_o*t-\frac{1}{2}g*t^{2}\\\\v_f=v_o+g*t\end{gathered}y=yo+vo∗t−21g∗t2vf=vo+g∗t

\begin{gathered}t=\frac{v_f}{g} \\\\t=\frac{-15.75\frac{m}{s}}{-9.81\frac{m}{s^{2}}}=1.61s\end{gathered}t=gvft=−9.81s2m−15.75sm=1.61s

Now that we know the time, we can calculate how tall is the cliff:

\begin{gathered}y=y_o+v_o*t+\frac{1}{2}g*t^{2}\\\\y=0+0*1.61s-\frac{1}{2}*(-9.81\frac{m}{s^{2}})*(1.61s)^{2}\\\\y=12.71m\end{gathered}y=yo+vo∗t+21g∗t2y=0+0∗1.61s−21∗(−9.81s2m)∗(1.61s)2y=12.71m

proof that the kinetic energy of a moving body is half mv square​

Answers

Answer:

1

Explanation:

Can heating cooking oil you’ll be classified as producing a chemical change?

Answers

yes it is boiling creating bubbles that aren't their originally

Explanation:

When cooking oils are subjected to heat in the presence of air and water (from food), such as in deep-fat frying and sautéing (pan frying), they can undergo at least three chemical changes: 1) oxidation of the fatty acids, 2) polymerization of the fatty acids, and 3) breaking apart of the triglyceride molecules into free fatty acids and glycerol by hydrolysis (reaction with water from the food being cooked) (Choe and Min 2007)

a virtual image is formed by
a) simple microscope b) telescope c) the ordinary camera d) a slide projector in a cinema hall​

Answers

Answer: ordinary camera

Explanation:

Answer:

C.

Explanation:

Two carts collide and have a perfectly inelastic collision. Cart1 has a mass of 500 grams and
Cart2 has a mass of 600 grams. Cart1 has an initial westward velocity of 1.6 m/s and collides
with Cart2 which was initially at rest. What is was the final velocity of the two cart system (SI
units)?

Answers

Answer: look at the file

Which list below contains only ionic compounds?
A. CaCl2, H2O, LIF
B. CO2, K20, P4010
C. LiF, CaCl2, Mgo
D. NO2, Mgo, CuCl2

Answers

Answer:

C. LiF, CaCl2, MgO

Explanation:

Ionic compound: It is that compound which consist of negative and position ions and held together by electrostatic force of attraction.

The ionic compound is neutral.

The ionic compound formed between metal and non-metal.

Covalent compound: It is that compound in which sharing of electrons between two atoms occur.

A.[tex]CaCl_2,H_2O,LiF[/tex]

H2O is not ionic compound. It is polar covalent.

Therefore, it does not contain only ionic compounds.

B.CO2,K2O,P4O10

CO2 and P4O10 are not ionic .It is covalent.

Therefore, it does not contain only ionic compounds.

C. LiF,CaCl2 ,MgO

All compounds are ionic because in given compounds one ion is negative  and one is metal (positive).

Therefore, it contains only ionic compounds.

D.NO2,MgO,CuCl2

NO2 is not ionic.

Therefore, it does not contain only ionic compounds.

Option C is correct.

200 newtons x 50 meters =

Answers

Answer:

10,000J

Explanation:Joules is the si unit for work. To find work you must multiply

the force by the distance. force is measured in Newtons. 200N(Force)x50meters(distance)=10,000J(amount of work) plz mark brainliest.

The answer is 10,000 J just multiply them

A 16 g ball at the end of a 1.4 m string is swung in a horizontal circle. It revolves once every 1.09 s. What is the magnitude of the string's tension?



Answer and I will give you brainiliest

Answers

Answer:

6.56

Explanation:

frequency = 1/1.09 = 0.92 Hz

f = 1/(2L) × √T/m

0.92 = 1/2(1.4) × (√T/√16)

0.92 = 0.36 × (√T)/4

multiply all through by 4

3.68 = 1.44 × √T

√T = 3.68/1.44 = 2.56

T = 2.56² = 6.56

The magnitude of the string's tension as it is swung in a horizontal circle is 0.744 Newton

Given the data in the question;

Mass of the ball;[tex]m = 16g = 0.016kg[/tex]String is swung in a horizontal circle, Radius; [tex]r = 1.4m[/tex]Period of revolution; [tex]T = 1.09s[/tex]Magnitude of the string's tension; [tex]F_T = ?[/tex]

First, we need to get magnitude of the centripetal acceleration:

[tex]a_c = \frac{4\pi ^2r}{T^2}[/tex]

We substitute in our given values

[tex]a_c = \frac{4\pi ^2\ *\ 1.4m}{(1.09s)^2} \\\\a_c = 46.519 m/s^2[/tex]

Now, from Newton's Second Law of Motion:

[tex]F = m\ * \ a[/tex]

Where F is the force, m is the mass of the object and a is the acceleration

We substitute into the equation to get the magnitude of the string's tension.

[tex]F = 0.016kg \ *\ 46.519m/s^2[/tex]

[tex]F = 0.744 kg.m/s^2\\\\F = 0.744 N[/tex]

Therefore, the magnitude of the string's tension as it is swung in a horizontal circle is 0.744 Newton

Learn more; https://brainly.com/question/14039108

How much work is done against gravity when lifting a 2-kg sack of groceries a distance of 2.5 meters?

Answers

W = F x d/x = (m x Ag) x h, therefore, mass (2kg x 9.8) x 2.5m = 49J
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