Answer:
The solution to a system of linear equations is the ordered pair (or pairs) that satisfies all equations in the system. The solution is the ordered pair(s) common to all lines in the system when the lines are graphed.
Lines that cross at a point (or points) are defined as a consistent system of equations. The place(s) where they cross are the solution(s) to the system.
Parallel lines do not cross. They have the same slope and different y-intercepts. They are an example of an inconsistent system of equations. An inconsistent system of equations has no solution.
Two equations that actually are the same line have an infinite number of solutions. This is an example of a dependent system of equations.
Step-by-step explanation:
Solve the system of equations graphically.
3x + 2y = 4
−x + 3y = −5
Solution
Graph each line and determine where they cross.
The lines intersect once at (2, −1).
A graphic solution to a system of equations is only as accurate as the scale of the paper or precision of the lines. At times the point of intersection will need to be estimated on the graph. When an exact solution is necessary, the system should be solved algebraically, either by substitution or by elimination.
Substitution Method
To solve a system of equations by substitution, solve one of the equations for a variable, for example x. Then replace that variable in the other equation with the terms you deemed equal and solve for the other variable, y. The solution to the system of equations is always an ordered pair.
Example
Solve the following system of equations by substitution.
x + 3y = 18
2x + y = 11
Solution
Solve for a variable in either equation. (If possible, choose a variable that does not have a coefficient to avoid working with fractions.)
In this case, it's easiest to rewrite the first equation by solving for x.
x + 3y = 18
x = −3y + 18
Next, substitute (−3y + 18) in for x into the other equation. Solve for y.
2( 3y + 12x + y = 11
2(−3y + 18) + y = 11-------Substitute -3y + 18 in for
−6y + 36 + y = 11-------Distribute.
2(3y −5y + 36 = 11-------Combine like terms.
2(3y + 18−5y = −25-----Subtract 36 from both sides
2(3y + 18) + y = 5---- -Divide both sides by -5.
Then, substitute y = 5 into your rewritten equation to find x.
x = −3y + 18
x = −3(5) + 18
x = −15 + 18
x = 3
Identify the solution. A check using x = 3 and y = 5 in both equations will show that the solution is the ordered pair (3, 5).
Elimination Method
Another way to solve a system of equations is by using the elimination method. The aim of using the elimination method is to have one variable cancel out. The resulting sum will contain a single variable that can then be identified. Once one variable is found, it can be substituted into either of the original equations to find the other variable.
Example
Find the solution to the system of equations by using the elimination method.
x − 2y = 9
3x + 2y = 11
Solution
Add the equations.
x − 2y = 9
3x + 2y = 11
4x + 2y = 20
Isolate the variable in the new equation
4x = 20
x = 5
Substitute x = 5 into either of the original equations to find y.
x − 2y = 9
(5) − 2y = 9
−2y = 4
y = −2
Identify the ordered pair that is the solution. A check in both equations will show that (5, −2) is a solution.
It may be necessary to multiply one or both of the equations in the system by a constant in order to obtain a variable that can be eliminated by addition. For example, consider the system of equations below:
3x + 2y = 6
x − 5y = 8
Both sides of the second equation above could be multiplied by −3. Multiplying the equation by the same number on both sides does not change the value of the equation. It will result in an equation whereby the x values can be eliminated through addition.
Special Cases
In some circumstances, both variables will drop out when adding the equations. If the resulting expression is not true, then the system is inconsistent and has no solution.
4x + 6y = 13
6x + 9y = 17
3(4x + 6y = 13)
2(6x + 9y = 17)
12x + 18y = 39
12x + 18y = 34
0 = 5
The equation is false. The system has no solution.
If both variables drop out and the resulting expression is true, then the system is dependent and has infinite solutions.
6x + 15y = 24
4x + 10y = 16
2(6x + 15y = 24)
3(4x + 10y = 16)
12x + 30y = 48
12x + 30y = 48
0 = 0
The equation is true. The system has an infinite number of solutions. (Notice that both of the original equations reduce to 2x + 5y = 8. All solutions to the system lie on this line.)
1.)Which of the following is a linear inequality in two variables?
a. 3x≤16
b. 3m-4m>5
c. 9q+4<12
d. 11+2t ≥ 3?
[tex] \large╚»★«╝ { \mathcal{Answer }}╚»★«╝[/tex]
The Correct option among them is B
[tex] \sf3m - 4n > 5[/tex]_____________________________________
The other options have one variable each, but according to the given question there should be two variables in the inequality.
The only choice satisfying the conditions is Option B
having two variables in it ( that is "m" and "n" )
[tex] ꧁ \: \large \frak{Eternal \: Being } \: ꧂[/tex]
Evaluate the algebraic expression if w= -0.5, x = 2, y= -3, and z = 2.5.
2w^2 - 3x + y - 8z
Answer:
-28.50
Step-by-step explanation:
Given the algebraic expression, 2w² - 3x + y - 8z, where w = -0.5, x = 2, y= -3, and z = 2.5:
Substitute the given values for the variables to evaluate the algebraic expression.
2w² - 3x + y - 8z
= 2(-0.5)² - 3(2) + (-3) - 8(2.5)
= 2(0.25) - 6 - 3 - 20
= 0.50 - 6 - 3 - 20
= -28.50
Therefore, 2w² - 3x + y - 8z = -28.50.
Answer:
-28.5
Step-by-step explanation:
Substitute the values for their given variables and evaluate.
[tex]2w^2-3x+y-8z\\\\2(-0.5)^2-3(2)+(-3)-8(2.5)\\\\2(0.25)-6-3-20\\\\0.5-6-3-20\\\\-28.5[/tex]
(2³ x 2⁵) ÷ 2⁸
Solution
Answer:
it is 1
Step-by-step explanation:
Let's use PEMDAS (do the parenthesis first).
2 to the 3 = 2x2x2 = 8
2 to the 5 = 2x2x2x2x2 = 32
8 x 32 = 256 (all the solutions are factors of 2048).
2 to the 8 = 2x2x2x2x2x2x2x2 = 256 again
256 / 256 = 1
Help !!!!!!!!!!!!!!!!!!!!
Answer:
Step-by-step explanation:
One must rearrange the function to decreasing value of exponents
f(x) = -7x⁴ + 8x³ - 3x² - 9x + 11
to see that it is a 4th degree polynomial with leading coefficient of -7
which of the following are perfect cubes 1)3375 2)8000 3)6859
Answer:
all are perfect cubes
Step-by-step explanation:
you can just cube root the numbers and bom if it aint decimal its a perfect cube
Compare the expressions 7+3^2-2⋅5 and (3/4+1/8)÷1/8 using , =, or . Show your work. Answer:
[tex]A=7+3^2 -2 \cdot 5 = 7 + 9 - 10 = 9-3=6\\\\\\B = \left(\dfrac 34 + \dfrac 18\right) \div \dfrac 18 = \dfrac 78 \times 8 =7\\\\\\B>A[/tex]
The expression relation is 7+3²-2⋅5 > (3/4+1/8)÷1/8.
What is Inequality?Mathematical expressions with inequalities are those in which the two sides are not equal. Contrary to equations, we compare two values in inequality. Less than (or less than or equal to), greater than (or greater than or equal to), or not equal to signs are used in place of the equal sign.
Given:
First, 7+3²-2⋅5
Solving the above expression
= 7 + 9 -2.5
= 16 - 2.5
= 13.5
Second,
(3/4+1/8)÷1/8
= (6/8 + 1/8) ÷ 1/8
= 7/8 ÷ 1/8
= 7/8 x 8/1
= 7
Hence, 7+3²-2⋅5 > (3/4+1/8)÷1/8.
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List all the factors pairs in the table 64
(1, 64), (2, 32), (4, 16), (8, 8).
Answer:
1 x 64
2 x 32
4 x 16
8 x 8
Step-by-step explanation:
Factors of 64: 1, 2, 4, 8, 16, 32 and 64.
Pairs:
1 x 64
2 x 32
4 x 16
8 x 8
Hope this helps :)
Draw a square and its diaginals
Answer:
you cant draw......................
Step-by-step explanation:
The height of a parallelogram is 6[tex]a^{2}[/tex][tex]b^{5}[/tex] and the base of a parallelogram is 4[tex]a^{3}[/tex][tex]b^{4}[/tex] Find the area of the parallelogram using the formula A = bh
[tex]\text{Area of parallelogram} = \text{Base}~ \times~\text{Height} = (4a^3b^4)(6a^2 b^5)=24a^5 b^9[/tex]
Determine whether each situation represents a discrete or continuous function.
a. The function y = 30.48x converts length from x feet to y centimeters. [ A. discrete , B. continuous ]
b. The function y = 3x + 2 represents the amount of water y in gallons in a tank after x minutes.
[ A. discrete ,B. continuous ]
Answer:
Both of those are continuous
Step-by-step explanation:
A discrete function is only defined for a specified countable set of x, neither of the two provided fit that description. On the other hand, both are defined for arbitrary positive real numbers.
The value of both functions is defined for a continuous interval of x thus both will be continuous.
What is a function?A certain kind of relationship called a function binds inputs to essentially one output.
The nature of the relationship defines the function for example y = sinx and y = x +6 like that.
Given the first function →
y = 30.48x where x is feet and y is a centimeter of conversion.
Now, it is known that for every foot interval there will be a centimeter that exists therefore they will be defined for all continuous intervals of x so it will be continuous.
The second function →
y = 3x + 2 where x is minutes and y is the number of gallons in a tank.
Now since for every minute of the interval, there will be a certain amount of gallons in the tank so it will be also continuous.
Hence "The value of both functions is defined for a continuous interval of x thus both will be continuous".
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What is the equation of a line that passes through the points (3, 6) and (8, 4)?
Answer:
[tex]y=-\frac{2}{5} x+\frac{36}{5}[/tex]
Step-by-step explanation:
→ Find the gradient
[tex]\frac{4-6}{8-3}= \frac{-2}{5} =-\frac{2}{5}[/tex]
→ Write into y = mx + c format
[tex]y=-\frac{2}{5} x+c[/tex]
→ Substitute in ( 3 , 6 )
[tex]6 = -\frac{6}{5} +c[/tex] ∴ [tex]c = 6+\frac{6}{5} =\frac{36}{5}[/tex]
→ Rewrite into y = mx + c format
[tex]y=-\frac{2}{5} x+\frac{36}{5}[/tex]
one added to the square root of the sum of a number and one is equal to four. find the number
[tex]\stackrel{\textit{one added to the }\sqrt{\qquad }}{1+\sqrt{\quad }}~~,~~ \stackrel{\sqrt{~~}\textit{ of a number and one}}{\sqrt{x+1}}\implies 1+\sqrt{x+1}\stackrel{\textit{equals}}{=}4 \\\\\\ \sqrt{x+1}=3\implies \left( \sqrt{x+1} \right)^2=3^2\implies x+1=9\implies \boxed{x=8}[/tex]
The mass of Earth is approximately 6 x 10^27 that of the Sun is 330,000 times as much. The gravitational constant is 6.7 x 10^-8 cm/s2.g. The distance of Earth from the Sun is about 1.5 x 10^12 cm. Compute, approximately, the work necessary to increase the distance of Earth from the Sun by 1 cm.
Answer:
12.89
Step-by-step explanation:
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URGENT: HELP ME WITH THE MATH PROBLEMS!!
(Note This Needs To Be Done Tonight!)
Answer:
1. 3 and 1/5 improper: 11/15
2. 3 and 3/4 improper: 15/16
3. 1 and 2/3 improper: 5/6
4. 2 and 1/2 improper: 5/6
5. 3 and 2/10 improper: 32/40
6. 3 and 3/9 improper: 30/36
7. 1 and 2/6 improper: 8/12
pls help, what is the slope of the graph?
well, let's take 2 points from it and get it :) , say let's use (4 , 5) and (-1 , 5)
[tex](\stackrel{x_1}{4}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{5}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{-1}-\underset{x_1}{(4)}}}\implies \cfrac{0}{-5}\implies 0[/tex]
bearing in mind that for any horizonal line it's always 0.
The cost of 2 bunches of
roses and 5 bunches of
carnations is £45.
The cost of 3 bunches of
roses and 4 bunches of
carnations is £50.
Find the cost of one bunch of each
Answer:
vtdOveractivity of the pituitary gland is called hyperpituitarism. Several disorders related to an overactive pituitary gland can occur.
...
Symptoms may include:
Nervousness.Rapid or irregular heartbeat.Weight loss.Fatigue.Muscular weakness.
you have to estimate
Answer:
75,388
Step-by-step explanation:
Long Multiplication form
[tex]\mathrm{Mutliply\:the\:bold\:numbers}[/tex]
[tex]\frac{\begin{matrix}\space\space&8&0&\textbf{2}\\ \times \:&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&8\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\space\space&8&\textbf{0}&2\\ \times \:&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&0&8\end{matrix}}[/tex]
[tex]\mathrm{Multiply}\\\\8\cdot \:4=32[/tex]
[tex]\mathrm{Carry\:}3\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}2\mathrm{\:in\:the\:result\:line}[/tex]
[tex]\frac{\begin{matrix}\space\space&3&\space\space&\space\space&\space\space\\ \space\space&\space\space&\textbf{8}&0&2\\ \times \:&\space\space&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&2&0&8\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:carried\:digit,\:}3\mathrm{,\:to\:the\:result}[/tex]
[tex]\frac{\begin{matrix}\space\space&3&\space\space&\space\space&\space\space\\ \space\space&\space\space&8&0&2\\ \times \:&\space\space&\space\space&9&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\end{matrix}}[/tex]
[tex]\mathrm{Multiply\:the\:top\:number\:by\:the\:bolded\:digit\:of\:the\:bottom\:number}[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&\textbf{8}&\textbf{0}&\textbf{2}\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\end{matrix}}[/tex]
[tex]\mathrm{Mutliply\:the\:bold\:numbers}:\quad \:2\cdot \:9=18[/tex]
[tex]\mathrm{Carry\:}1\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}8\mathrm{\:in\:the\:result\:line}[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&1&\space\space\\ \space\space&\space\space&8&0&\textbf{2}\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&\space\space&\space\space&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:carried\:number\:to\:the\:multiplication}:\quad \:1+0\cdot \:9=1[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&\textbf{1}&\space\space\\ \space\space&\space\space&8&\textbf{0}&2\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&\space\space&1&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Mutliply\:the\:bold\:numbers}:\quad \:8\cdot \:9=72[/tex]
[tex]\mathrm{Carry\:}7\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}2\mathrm{\:in\:the\:result\:line}[/tex]
[tex]\frac{\begin{matrix}\space\space&7&\space\space&1&\space\space\\ \space\space&\space\space&\textbf{8}&0&2\\ \times \:&\space\space&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&2&1&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:carried\:digit,\:}7\mathrm{,\:to\:the\:result}[/tex]
[tex]\frac{\begin{matrix}\space\space&7&\space\space&1&\space\space\\ \space\space&\space\space&8&0&2\\ \times \:&\space\space&\space\space&9&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ 7&2&1&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:rows\:to\:get\:the\:answer.\:\:\:Fill\:in\:trailing\:zeros\:\:(not\:required)}[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&8&0&2\\ \space\space&\times \:&\space\space&9&4\end{matrix}}{\begin{matrix}0&3&2&0&8\\ 7&2&1&8&0\end{matrix}}[/tex] [tex]=75,388[/tex]
See Image for the addition:
On two investments totaling $14,000, Peter lost 4% on one and earned 6% on the other. If his net annual receipts were $312, how much was each investment?
Answer:
5280 , 8720
Step-by-step explanation:
suppose the one is x, another is y
x+y=14000
y(6%)-x(4%)=312
x=5280
y=8720
net annual receipt means the income so you have to substract the lost from the gains
Which of the following could be a helpful first step in solving this equation for q?
p2q+2q=11
Question 5 options:
Combine p2q+2q
Divide the whole equation by 11.
Divide the first term by p2
Factor a q out of p2q+2q
Answer:
D: Factor a q out of p^2 q+ 2q
Step-by-step explanation:
I took the test. Hope it was helpful! :)
The first step in solving this equation p²q+2q=11 for q will be to factor q out of p²q+2q. Option D is correct.
What is the equation?An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.
It is given that, the equation is,
p²q+2q=11
Take q common from the L.H.S as
q(p²+2)=11
The value of q is obtained by rearranging the equation as,
q=11/(p²+2)
The value of q obtained after solving the equation p²q+2q=11 will be q=11/(p²+2).
Thus, the first step in solving this equation p²q+2q=11 for q will be to factor q out of p²q+2q. Option D is correct.
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least common denominator of both 4/x^2*t and x/t^2
Step-by-step explanation:
LCD of 4/x²t and x/t²
= LCM(x²t , t²)
= x²t²
Form an equation to help you solve this problem Four identical lumps of gold on one side of some scales balance with one identical lump and a 22kg mass. Find the mass of one lump of gold. kg
Answer:
equation= 4x=x+22kg
Step-by-step explanation:
i hope it helped :))
Select all of the following that are quadratic equations. 7x2 + 14x = 0 x3 - 3x2 + 1 = 0 5x - 7 = 0 x2 + 3x -5 = 0 x - 5 = 9x + 7 x2 - x = 3x + 7
Answer:
7x2 + 14x = 0
x2 + 3x -5 = 0
x2 - x = 3x + 7
Step-by-step explanation:
A quadratic equation has the highest power of x to the second power. It must have x to the second power
7x2 + 14x = 0 quadratic
x3 - 3x2 + 1 = 0 not quadratic but cubic
5x - 7 = 0 not quadratic but linear
x2 + 3x -5 = 0 quadratic
x - 5 = 9x + 7 not quadratic but linear
x2 - x = 3x + 7 quadratic
50 points + brainliest answer questions 7 and 8 with work and all
Answer:
7) m∠BHE = 146°
8) m∠BAC = 25°
Step-by-step explanation:
Question 7:Given that, [tex]\displaystyle\mathsf{\overline{CD}\:||\:\overline{EF}}[/tex], and that [tex]\displaystyle\mathsf{\overline{AB}}[/tex] is a transveral.
We are also provided with the following measures of the angles: m∠DGH = 2x, and m∠FHB = 5x - 51.
∠DGH and ∠FHB are also corresponding angles, as they have corresponding positions on the same side of the transversal, [tex]\displaystyle\mathsf{\overline{AB}}[/tex]. These two angles also have the same measure.
Solve for x:In order to find the measure of ∠BHE, we could set up an equality statement on ∠DGH and ∠FHB to solve for the value of x.
m∠DGH = m∠FHB
2x = 5x - 51
Add 51 and subtract 2x from both sides of the equation:
2x -2x + 51 = 5x - 2x - 51 + 51
51 = 3x
Divide both sides by 3:
[tex]\displaystyle\mathsf{\frac{51}{3}\:=\:\frac{3x}{3}}[/tex]
x = 17
⇒ m∠DGH = 2x = 2(17) = 34°,
⇒ m∠FHB = 5x - 51 = 5(17) - 51 = 34°.
Since ∠FHB and ∠BHE are supplements (whose sum add up to 180°), we could determine the measure of ∠BHE as follows:
m∠BHE + m∠FHB = 180°
m∠BHE + 34° = 180°
m∠BHE + 34°- 34° = 180°- 34°
m∠BHE = 146°.
Therefore, the measure of ∠BHE is 146°.
Question 8:Given that ΔABC with [tex]\displaystyle\mathsf{\overline{AC}}[/tex] extended to D, and that m∠ABC = 63° and m∠BCD = 92°:
The Exterior Angle Theorem states that the measure of an exterior angle of a triangle is equal to the sum of the two nonadjacent interior angles. In other words: ∠BCD = ∠BAC + ∠ABC.
Before we could apply the Exterior Angle Theorem, we must first find m∠BAC. Since ∠BCD and ∠BCA are supplements:
m∠BCD + m∠BCA = 180°
92° + m∠BCA = 180°
92° - 92°+ m∠BCA = 180° - 92°
m∠BCA = 88°
Solve for m∠BAC:Now that we have the measure for ∠BCA, we can find m∠BAC by applying the Triangle Sum Theorem where it states that the sum of the interior angles of a triangle is equal to 180°.
m∠BCD + m∠ABC + m∠BAC = 180°
92° + 63° + m∠BAC = 180°
125° + m∠BAC = 180°
155° - 155° + m∠BAC = 180° - 155°
m∠BAC = 25°
Therefore, the measure of ∠BAC is 25°.
Please tell me how much can 6 go into 14 without going over 14
i need help on this math problem
Answer:
Step-by-step explanation:
Slope: 3/1 (positive: line go uphill)
y-intercept: -5
Place your pencil on the vertical line (y) on -5. Go up 3 units and 1 to the right, repeat and trace the line (actually you only need two points to trace a line)
Flying against the wind, a jet travels 3780 miles in 6 hours. Flying with the wind, the same jet travels 5950miles in 7 hours. What is the rate of the jet in still air and what is the rate of the wind? 1111 Rate of the jet in still air:
The rate of the jet in still air is 740 mph and the rate of the wind is 110 mph.
The given parameters;
distance traveled against the wind, d₁ = 3780 milestime of motion, t₁ = 6 hoursdistance traveled with wind, d₂ = 5950 milestime of motion, t₂ = 7 hoursLet the rate of the jet in still air = R₁
Let the rate of the wind = R₂
The rate of the jet against the wind:
[tex]R_1 - R_2 = \frac{3780}{6} \\\\R_1 - R_2 = 630[/tex]
The rate of the jet with the wind:
[tex]R_1 + R_2 = \frac{5950}{7} \\\\R_1 + R_2 = 850\\\\[/tex]
The rate of the jet in still air is calculated as follows;
[tex]R_1 = \frac{630 + 850}{2} \\\\R_1 = 740 \ mph[/tex]
The rate of the wind is calculated as follows;
[tex]R_1 - R_2 = 630\\\\R_2 = R_1 - 630\\\\R_2 = 740 - 630 \\\\R_2 = 110 \ mph[/tex]
Thus, the rate of the jet in still air is 740 mph and the rate of the wind is 110 mph.
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HELP ME PLEASE!!!!!!!!!!!
Answer:
SAS theorem >This is the correct
Answer:
SSS theoremStep-by-step explanation:
[tex] \huge\colorbox{pink}{hope \: its \: help}[/tex]
Which expression is the factored form of−4.5n+3?
−1.5(3n+2)
−3(1.5n+1)
−3(1.5n−1)
−1.5(−3n+2)
Answer:
— 3 (1.5n — 1)
Step-by-step explanation:
[tex] - 4.5n + 3 = - \frac{9}{2} n + 3 = 3( - \frac{3}{2} n + 1) = - 3( \frac{3}{2}n - 1) \\ = - 3(1.5n - 1)[/tex]
PLS HELP REWARDING A LOT!!
Answer:
157°
Step-by-step explanation:
Sum of interior angles of polygon
(n-2)*180 ---- n = total number of sides
7 angles, 7 sides
5*180 = 900
final angle will be
900-162-115-125-138-105-98
=157
Answer:
157
Step-by-step explanation:
it is obvious that it's a heptagon
so (n-2) x180
n=7
(7-2) x 180 =900
900-162-115-125-138-105-98
900-743=157
final unknown=157°
7(x+7)≤56 plz help im bad at math
Answer:x[tex]\geq[/tex]1
Step-by-step explanation:
remove the brackets
7x+49≤56
collect like terms
7x≤56-49
7x[tex]\geq[/tex]7
divide both sides by 7
x[tex]\geq[/tex]1