Christina has 6 pieces of candy in her lunchbox. Rachel gives Christina more pieces of candy. Now Christina has 18 pieces of candy. How many pieces of candy did Rachel give Christina?

Answer:

x² - 3x + 5 - [24÷(x+3)]

Step-by-step explanation:

1. Expand (x³ + 2x - 6x - 9)

            = x³ - 4x - 9

2. Divide [x³ - 4x - 9 by x+3]

            = x² + [(-3x^2-4x-9) ÷ (x+3)]

3. Divide [(-3x^2-4x-9) by (x+3)]

            = -3x + [(5x-9) ÷ (x+3)]

x² - 3x + [(5x-9) ÷ (x+3)]

4. Divide [(5x-9) ÷ (x+3)]

            = 5 + [(-24) ÷ (x+3)]

x² - 3x + 5 + [(-24) ÷ (x+3)]

= x² - 3x + 5 - [24 ÷ (x+3)]

Answer:

r > -5

Step-by-step explanation:

r - 6 > -11

 + 6   + 6

---------------

r > -5

hope this helps! :D

have a miraculous day, and brainliest is immensely appreciated!! <3

The range is [tex]\boxed{-4 \leq y < 0}[/tex].

Answer: I looked it up please give a brainliest if correct:

Step-by-step explanation: I looked it up y copying and pasting and thats probably what you should have done never hurts to try new ways a lot of people said D.

Answer:

I would say D.

Step-by-step explanation:

Please double check i don't want you to fail your quiz

Answer:

hmm i would say its -2 and 1/2.. although i am a little rusty at this..but this is what i choose

Step-by-step explanation:

Answer:

a and d is correct I did the test and got 100 .

Answer:

Four

Step-by-step explanation:

I recoloured the hyperbola to enfasize the two different equations (the other is a circle. The solution of the equations are the point where the two graphs touch, which are circled in black.

Solving steps:-

5x+3y=−4

y−2x=6

-->To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

5x+3y=−4,−2x+y=6

-->Choose one of the equations and solve it for x by isolating x on the left hand side of the equal sign.

5x+3y=−4

-->Subtract 3y from both sides of the equation.

5x=−3y−4

--> Divide both sides by 5.

x = 1/5(-3y - 4)

--> Multiply 1/5 −3y−4.

x = -3/5y - 4/5

--> Substitute -3y - 4/ 5 for x n the other equation, −2x+y=6.

-2 (-3/5y - 4/5) + y = 6

--> Multiply −2 times -3y - 4/ 5

6/5y + 8/5 + y = 6

--> Add 6y/5 to y

11/5y + 8/5 = 6

--> Subtract 8/5 from both sides of the equation.

11/5y = 22/5

--> Divide both sides of the equation by 11/5, which is the same as multiplying both sides by the reciprocal of the fraction.

y = 2

--> Substitute 2 for y in x= -3/5y - 4/5. Because the resulting equation contains only one variable, you can solve for x directly.

x = -3/5 x 2 - 4/5

--> Multiply -3/5 times 2.

x = -6 - 4/ 5

--> Add -4/5 to -6/5 by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.

x = -2

--> The equation is now solved.

Answer : x = -2, y = 2

Explanation : If you think this answer is good, please give "Brainliest" or rate/heart my answer. Hope this helps you.

Answer:

5/7

Step-by-step explanation:

The greatest common factor of 25/35 is 5, 25/5=5, 35/5=7, therefore your answer is 5/7.

Answer:

is this all the information from the question

Answer:

Refer to link below:

Step-by-step explanation:

https://brainly.com/question/25868816?referrer=searchResults

Answer:

600-230=L

Step-by-step explanation:

L means Left or What's left

Answer:

The slope is 4/5 i dont know unit rate though, hope this helps:)

Answer:

Mateo's data shows a negative association

Step-by-step explanation:

Okay, so the y-axis is his amount of typos. The x-axis is the number of pages.

We can clearly see the typos found number increasing through the number of pages. Which is bad :/

Hope this helps :)

[tex]\text{Given that,}\\\\2(x^2+y^2)^2 = 25 (x^2-y^2)\\\\\implies 2\dfrac{d}{dx} (x^2 +y^2)^2 = 25 \dfrac{d}{dx} (x^2 -y^2)\\\\\implies 2 \cdot 2(x^2 +y^2) \dfrac{d}{dx}(x^2 +y^2) = 25\left[2x - 2y \dfrac{dy}{dx} \right]\\\\\implies (4x^2 +4y^2)\left(2x + 2y\dfrac{dy}{dx}\right) = 50x - 50y\dfrac{dy}{dx}\\\\\\\implies 8x^3+8x^2y \dfrac{dy}{dx} + 8xy^2 +8y^3\dfrac{dy}{dx} = 50x -50y \dfrac{dy}{dx}\\\\\\\implies 8x^2y \dfrac{dy}{dx} + 8y^3\dfrac{dy}{dx}+50y \dfrac{dy}{dx} = 50x -8x^3 -8xy^2\\\\[/tex]

[tex]\implies (8x^2y +8y^3 + 50y)\dfrac{dy}{dx} =50x -8x^3 -8xy^2\\\\\implies \dfrac{dy}{dx} = \dfrac{50x -8x^3 -8xy^2}{8x^2y+8y^3+50y}\\\\\implies \dfrac{dy}{dx}= \dfrac{25x-4x^3-4xy^2}{4x^2y+4y^3+25y}\\\\\\\implies \dfrac{dy}{dx} = \dfrac{x(25-4x^2-4y^2)}{y(4x^2 +4y^2 +25)}\\\\\\\text{Slope at}~~ (-3,-1)\\\\m=\dfrac{dy}{dx} = \dfrac{-3[25-4(-3)^2-4(-1)^2]}{(-1)[4(-3)^2 + 4(-1)^2+25]} = -\dfrac{45}{65} = -\dfrac 9{13}[/tex]

[tex]\text{Equation with given points,}\\\\y+1 = -\dfrac9{13}(x+3)\\\\\implies y = -\dfrac 9{13} x - \dfrac {27}{13} -1\\\\\implies y= -\dfrac 9{13} x - \dfrac{40}{13}\\\\\text{Hence the equation of this tangent line is now in a form of y= mx+b,}\\\\\text{where}~ m = -\dfrac 9{13}~ \text{and}~ b = -\dfrac{40}3[/tex]

Answer:

Step-by-step explanation:

       -(4q+8) + 6q = 12q - 5/6(18q + 6)

Open brackets:

<=>  - 4q - 8 + 6q = 12q - 5/6*18q - 5/6*6

<=>  - 4q - 8 + 6q = 12q - 15q - 5

Put q in one side and non q in one side:

<=> - 4q + 6q - 12q + 15q = 8 - 5

<=> 5q = 3

<=> q = 3/5

Given that

3 cos 80° cosec 10° + 2 sin 59° sec 31°

⇛3 cos(90°-10°) cosec 10°+2 sin (90°-31°) sec 31°

We know that

sin (90° - A) = cos A

cos (90°-A) = sin A

⇛3 sin 10° cosec 10° + 2 cos 31° sec 31°

⇛3 sin 10° (1/sin 10°) + 2 cos 31° (1/cos 31°)

⇛3 (sin 10°/sin 10°) + 2 (cos 31°/cos 31°)

⇛3 (1) + 2(1)

⇛3+2

⇛5

Answer: Therefore, 3cos 80°cosec 10°+2cos 59°sec 31° = 5.

also read similar questions: (sin teta + sec teta)^ + (cos teta+ cosec teta )^ = (1 + sec x cosec)^

https://brainly.com/question/87846?referrer

Answer:

5

Step-by-step explanation:

you can rewrite this as

3cos(90*-10*) x 1/sin(10*) + 2sin(90*-31*) x 1/cos(31*)

=3sin(10*) x 1/sin(10*) + 2cos31* x 1/cos(31*)

reduce with sin(10*) to get

3+2cos(31*) x 1/cos(31*)

cross out the cos 31* on both sides to leave you with

3+2

5

Answer:

[tex]\huge\boxed{x=15;\ y=4}[/tex]

Step-by-step explanation:

Proportion:

[tex]\dfrac{x}{18}=\dfrac{5}{6}\qquad|\text{cross multiply}\\\\(x)(6)=(18)(5)\\\\6x=90\qquad|\text{divide both sides by 6}\\\\\huge\boxed{x=15}[/tex]

[tex]\dfrac{y}{5}=\dfrac{12}{x}[/tex]

substitute x = 15:

[tex]\dfrac{y}{5}=\dfrac{12:3}{15:3}\\\\\dfrac{y}{5}=\dfrac{4}{5}\qquad|\text{cross multiply}\\\\(y)(5)=(5)(4)\\\\5y=20\qquad|\text{divide both sides by 5}\\\\\huge\boxed{y=4}[/tex]

The prime numbers after 167, 118, 82, 57, 41 are 37, 31, 29, 23, 19, 17, 13, 11, 7, 5, 3, 2.

Prime numbers are numbers that are divisible by 1 and itself.

This are number greater than one with only two factors which are 1 and itself.

In other words, this number, when they are divided by another number other

than 1 or itself , one will get a remainder that is not zero.

Example of prime numbers are 2, 5, 7, 11, 13 etc.

The prime numbers after  167, 118, 82, 57, 41 are as follows:

37, 31, 29, 23, 19, 17, 13, 11, 7, 5, 3, 2.

learn more about prime number here: https://brainly.com/question/26013414

Answer:

About 11 Weeks

Step-by-step explanation:

I found out by multiplying 11 by 20 and got 220. Then, adding 50 is 270, which is just over 259. It's not ten because 200 is just underneath his goal.

Answer:

x = 14

Step-by-step explanation:

1) Multiply both sides by 2.

x = 7 * 2

2) Simplify 7 * 2 to 14.

x = 14

Answer:

D.

Step-by-step explanation:

when using diversions in fractions to whole numbers you will always multiply the denominator by the whole number. So 2 x 7 equals 14. :))

Answer:

x=5

Step-by-step explanation:

there is no y intercept

[tex]\huge\textbf{Hey there!}[/tex]

[tex]\mathbf{3x - 2x = 5}\\\mathbf{\rightarrow 1x = 5}\\\textbf{DIVIDE 1 to BOTH SIDES}\\\mathbf{\rightarrow \dfrac{1x}{1}=\dfrac{5}{1}}\\\textbf{CANCEL out: }\mathbf{\dfrac{1}{1}\textbf{ because it gives you 1}}\\\textbf{KEEP: }\mathbf{\dfrac{5}{1}}\textbf{ because it helps solve for the x-value.}\\\textbf{NEW EQUATION: }\mathbf{x = \dfrac{5}{1}}\\\textbf{SIMPLIFY IT!}\\\mathbf{x = 5}\\\\\\\\\\\huge\textbf{Therefore, your answer is: \boxed{\mathsf{x = 5}}}\huge\checkmark[/tex]

[tex]\huge\textbf{Good luck on your assignment \& enjoy}\\\huge\textbf{your day!}[/tex]

~[tex]\mathbf{Amphitrite1040:)}[/tex]

expanded form true

Step-by-step explanation: