Answer:
A. The reaction proceeds in the forward and reverse directions at the same rate.
B. Both the forward and the reverse reactions are achievable.
D. There is no net change in concentrations of reactants and products.
Explanation:
Chemical equilibrium can be defined as the state of a reversible reaction in which the concentration (rate) of the forward reaction is equal to the concentration (rate) of the backward or reverse reaction. Thus, both the reactants and products of the chemical equation don't have the tendency to change with respect to time.
Hence, the options that are true of chemical equilibria include the following;
I. The reaction moves in both forward and reverse directions simultaneously i.e at the same rate.
II. The chemical equation can attain both forward and reverse reactions.
III. The concentrations of both reactants and products are the same i.e there's no net change.
Answer:
A B D knewton
Explanation:
Please give me the answer please
Answer:
A. 30cm³
Explanation:
Based on the chemical reaction:
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
1 mol of calcium carbonate reacts with 2 moles of HCl to produce 1 mol of CO₂
To solve this question we must convert the mass of each reactant to moles. With the moles we can find limiting reactant and the moles of CO₂ produced. Using PV = nRT we can find the volume of the gas:
Moles CaCO₃ -Molar mass: 100.09g/mol-
1.00g * (1mol / 100.09g) = 9.991x10⁻³ moles
Moles HCl:
50cm³ = 0.0500dm³ * (0.05 mol / dm³) = 2.5x10⁻³ moles
For a complete reaction of 2.5x10⁻³ moles HCl there are necessaries:
2.5x10⁻³ moles HCl * (1mol CaCO₃ / 2mol HCl) = 1.25x10⁻³ moles CaCO₃. As there are 9.991x10⁻³ moles, HCl is limiting reactant.
The moles produced of CO₂ are:
2.5x10⁻³ moles HCl * (1mol CO₂ / 2mol HCl) = 1.25x10⁻³ moles CO₂
Using PV = nRT
Where P is pressure = 1atm assuming STP
V volume in L
n moles = 1.25x10⁻³ moles CO₂
R gas constant = 0.082atmL/molK
T = 273.15K at STP
V = nRT / P
1.25x10⁻³ moles * 0.082atmL/molK*273.15K / 1atm = V
0.028L = V
28cm³ = V
As 28cm³ ≈ 30cm³
Right option is:
A. 30cm³How does the entropy change in the reaction 2C3H6(g) + 9O2(g) → 6C02(g) + 6H2O (g)?
I will mark brainliest!! Thank you so much!!
Answer:
The entropy increases!!!
Explanation:
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The entropy increases in the reaction.
What is entropy?Entropy is defined as the measure of the disorder of a system.Entropy is an extensive property of a thermodynamic system, to put it in simple words, its value changes depending on the amount of matter that is present.Entropy is denoted by the letter S and has units of joules per kelvin (JK−1)The entropy increases in the reaction if the total number of product molecules are greater than the total number of reactant molecules.
2C3H6(g) + 9O2(g) → 6C02(g) + 6H2O (g)
In the above reaction, the product molecules are greater than the reactant molecules. Hence, entropy increases.
Hence, we can conclude that option A is the answer.
To learn more about entropy here
https://brainly.com/question/22861773
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PLEASEEEE HELLPPP I CANT FAILL PLSS
Part A. Classify each of these soluble solutes as a strong electrolyte, a weak electrolyte, or a nonelectrolyte. Solutes Formula Nitric acid HNO3 Potassium hydroxide KOH Formic acid HCOOH Ethyl amine CH3CH2NH2 Sodium bromide NaBr Butanol C4H9OH Sucrose C12H22O11
Part B. Enter a molecular equation for the reaction that occurs between aqueous HBr and aqueous LiOH.
Answer:
1. Strong electrolytes = Nitric acid HNO3,Potassium hydroxide KOH, Sodium bromide NaBr
Weak electrolytes = Formic acid HCOOH Ethyl amine CH3CH2NH2, Butanol C4H9OH
Non-electrolyte = Sucrose C12H22O11
2. The reaction between aqueous HBr and aqueous LiOH is shown innthe equation below:
HBr + LiOH ----> NaBr + H₂O
Explanation:
Electrolytes are substances that when in molten state or in aqueous solution dissociate into ions both positively-charged and negatively-charged ions known as actions and anions, which are then able conduct electricity.
Strong electrolytes are aqueous or molten solutions of compounds which ionize completely to produce anions and actions. Ionic compounds such as organic salts, acids and bases are strong electrolytes.
Weak electrolytes only ionize partially, that is, they produce few ions. Some organic salts, acids and bases are weak elctrolytes
From the compounds given above;
Strong electrolytes = Nitric acid HNO3,Potassium hydroxide KOH, Sodium bromide NaBr
Weak electrolytes = Formic acid HCOOH Ethyl amine CH3CH2NH2, Butanol C4H9OH
Non-electrolyte = Sucrose C12H22O11
2. The reaction between aqueous HBr and aqueous LiOH is shown innthe equation below:
HBr + LiOH ----> NaBr + H₂O