Answer:
NH₃ is the limiting reactant.Theoretical yield = 120 kg% yield = 72.9 %Explanation:
2NH₃ (aq) + CO₂ (aq) → CH₄N₂O (aq) + H₂O (l)First we convert the given masses of reactants to moles, using their respective molar masses:
68.2 kg NH₃ ÷ 17 kg/kmol = 4.01 kmol NH₃105 kg CO₂ ÷ 44 kg/kmol = 2.39 kmol CO₂2.39 kmol of CO₂ would react completely with (2.39 * 2) 4.78 kmol of NH₃. There are not as many NH₃ kmoles so NH₃ is the limiting reactant.
We calculate how much urea would form with a 100% yield, using the moles of limiting reactant:
4.01 kmol NH₃ * [tex]\frac{1kmolCH_4N_2O}{2kmolNH_3}[/tex] = 2.00 kmol CH₄N₂OWe convert that amount to kg:
2.00 kmol CH₄N₂O * 60 kg/kmol = 120 kg CH₄N₂OFinally we calculate the percent yield:
87.5 kg / 120 kg * 100% = 72.9 %What is the percent composition of dinotrogen pentoxide? With work shown please
Answer:
%N = 25.94%
%O = 74.06%
Explanation:
Step 1: Calculate the mass of nitrogen in 1 mole of N₂O₅
We will multiply the molar mass of N by the number of N atoms in the formula of N₂O₅.
m(N): 2 × 14.01 g = 28.02 g
Step 2: Calculate the mass of oxygen in 1 mole of N₂O₅
We will multiply the molar mass of O by the number of O atoms in the formula of N₂O₅.
m(O): 5 × 16.00 g = 80.00 g
Step 3: Calculate the mass of 1 mole of N₂O₅
We will sum the masses of N and O.
m(N₂O₅) = m(N) + m(O) = 28.02 g + 80.00 g = 108.02 g
Step 4: Calculate the percent composition of N₂O₅
We will use the following expression.
%Element = m(Element)/m(Compound) × 100%
%N = m(N)/m(N₂O₅) × 100% = 28.02 g/108.02 g × 100% = 25.94%
%O = m(O)/m(N₂O₅) × 100% = 80.00 g/108.02 g × 100% = 74.06%
Practice Problem 12.39 Partially correct answer. Your answer is partially correct. Try again. Acid-catalyzed hydration of 1-methylcyclohexene yields two alcohols. The major product does not undergo oxidation, while the minor product will undergo oxidation because the major product is Entry field with incorrect answer 2-methylcyclohexanol , which is a Entry field with incorrect answer secondary alcohol. These alcohols do not generally undergo oxidation. The minor product (Entry field with incorrect answer 1-methylcyclohexan-2-ol ) is asecondary alcohol and can undergo oxidation to yield a(n)
Answer:
See explanation and image attached
Explanation:
The acid-catalyzed hydration of 1-methylcyclohexene proceeds by an SN1 mechanism. The reaction involves the formation of carbocations.
Two carbocations are formed leading to the major and minor products. The major product is obtained from the tertiary (more stable) carbocation while the minor product is obtained from the secondary (less stable carbocation).
Tertiary alcohols are not oxidized, hence the major product does not undergo oxidation. However, secondary alcohols are oxidized to ketones.
Would you expect a reaction to occur with Hydrogen gas and Copper (II) chloride?
The copper itself can react with hydrogen
Here is the chemical reaction
2CuCl2(aq) + H2(g) -> 2CuCl(s) + 2HCl(g)
A sample of potassium has an average atomic mass of 39.0983amu. There are three isotopic forms of potassium element in the sample. About 93.2581% of the potassium atoms are 38.9637amu mass (39K); 0.0117% are 39.9639amu mass (40K), and the remaining isotope 41K is of 40.9618amu mass. Calculate the percentage composition of 41K. Report your answer with five significant figures.
Answer:
Percent Composition of 41K = 6.7302%
Explanation:
The explination is in the image.
The percentage composition of 41K isotope of potassium according to the given data is 6.7302 percent.
Composition of isotopes:Given that the atomic masses of the potassium isotopes are:
mass of 39K = 38.9637amu
mass of 40K = 39.9639amu
mass of 41K = 40.9618amu
and the percentages are:
percentage of 39K = 93.2581%
percentage of 40K = 0.0117%
percentage of 41K = x
Given average mass of potassium = 39.0983amu
sum (mass of isotopes × percentage abundance) = average mass
38.9637 × 93.2581% + 39.9639 × 0.0117% + 40.9618 × x = 39.0983
x = 6.7302%
So the percentage composition of 41K is 6.7302%
Learn more about composition of isotopes:
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What kind of questions do scientists ask?
A. Ones that there are no right answers to
B. Ones that only deal with scientific issues
C. Ones that deal with matters of opinion
D. Ones that are answered through observing
ones that are answered through observing :)
Answer: D.
Explanation:
ones that are answered through observing.
26. Find the volume of 111.6 grams of NH3 gas.
Answer:
It is 148.82 L
Explanation:
I need more points. And I hope this helps.
How many significant figures
are in this number?
5.67 x 10^2
Answer:
3
Step-by-step explanation:
Hence, the given number has 3 significant figures.
• as it sits on top of a building that is 50 meters tall.
• as it is half-way through a fall off a building that is 50 meters tall and travelling 19.8 meters per second.
• as it is just about to hit the ground from a fall off a building that is 50 meters tall and travelling 28 m/s
What is the potential energy of the ball as it is half-way through the fall (25 meters high)?
PLEASE HELP
MY PARENTS WILL KILL ME IF I DONT GET MY SCHOOL WORK DONE BY 12 PM TODAY!! AND I DONT UNDERSTAND IT!!
If the mass of an unknown object is 2 grams and the volume is 2.35 cubic centimeters, what is the density of that object?
a. _________________________
b. Look back at Table 4.1. Based on your calculated density, what is the substance? _________________________
Answer:
oh ok
Explanation:
A compound is 22.5% nitrogen and 77.5% oxygen, What is the empirical formula of
this compound?
Answer:
[tex]NO_3[/tex]
Explanation:
Hello!
In this case, since percent compositions are used to set up empirical formulas when assuming those percentages are masses, we can fist compute the moles of nitrogen and oxygen in the compound as shown below:
[tex]n_N=22.5g/14.01g/mol=1.61mol\\\\n_O=77.5g/16.00g/mol=4.84mol[/tex]
Now, we divide by the fewest moles to compute the subscripts:
[tex]N=\frac{1.61}{1.61} =1\\\\O=\frac{4.84}{1.61} =3[/tex]
Thus, the empirical formula turns out:
[tex]NO_3[/tex]
Best regards!
What happens to a solute?
Answer:
A
Explanation:
have a great day!!!!!!!!
A 50.8g sample of glass, which has a specific heat capacity of 0.670·J·g?1°C?1, is put into a calorimeter (see sketch at right) that contains 150.0g of water. The temperature of the water starts off at 22.0°C. When the temperature of the water stops changing it's 25.6°C. The pressure remains constant at 1atm. Calculate the initial temperature of the glass sample. Be sure your answer is rounded to the correct number of significant digits.
Answer:
Explanation:
mass of glass m = 50.8 g
specific heat s = .67 J /g °C
initial temperature = t
Loss of heat by glass
= m s Δ t
= 50.8 x .67 x ( t - 25.6 )
= 34.036 x ( t - 25.6 )
Gain of heat by water
= 150 x 4.2 x ( 25.6 - 22.0 )
= 2268
Heat gain = heat lost
2268 = 34.036 x ( t - 25.6 )
2268 = 34.036 t - 871.32
34.036 t = 3139.32
t = 92.23°C .
Aside from invasives like the crown-of-thorns starfish, what other factor is killing the Great Barrier Reef?
O increased temperatures
O overactive algae
O reactive forms of oxygen
O coral bleaching
Answer:
increased temperatures
Explanation:
The temperatures are increasing in the ocean because of ocean warming, by climate change. The heat in the ocean stresses healthy corals, which drains them of their vibrant colors, known as bleaching.
How many moles are there in 7.24 grams of calcium carbonate? With work shown
Answer:
0.0723371390261859
Sodium metal reacts with chlorine gas to produce crystals of sodium
chloride. Show phases in your equation.
Answer:
Na(s) + Cl(g) = NaCl(s)
Explanation:
s means solid
g means gas
Metals are solid at room temperature.
Crystals are solids
The volume and number of moles of a gas are held constant. Which of the following is true for the pressure of the gas?
It is inversely proportional to the temperature of the gas.
It is directly proportional to the temperature of the gas.
It is inversely proportional to the mass of the gas.
It is equal to the mass of the gas.
Answer:
it is directly proportional to the temperature of the gas
Explanation:
Fill in the blank with the correct answer to complete the sentence.
Word bank
size
velocity
distance
time
Momentum increases with an increase in mass and
Explanation:
momentum increases with an increase in mass and velocity
A gas occupies 135 cm3 at 143. K. At what Celsius temperature will its volume be 140 cm3? Assume that pressure remains constant.
Answer:
New temperature T2 = -124.7 °C
Explanation:
Given:
Old volume V1 = 135 cm³
New volume V2 = 140 cm³3
Old temperature T1 = 143 K
Find:
New temperature T2
Computation:
V1 / T1 = V2 / T2
135 / 143 = 140 / T2
New temperature T2 = 148.3 K
New temperature T2 = 148.3 - 273
New temperature T2 = -124.7 °C
The lobes are important for speech and language. O A. parietal O B. temporal o o Ο Ο C. frontal O D. occipital
Answer:
Explanation:
D or b
Sorry if wrong
Answer:
temporal
Explanation:
Please help quickly as possible thank you :)
Ce clasă ești sa văd daca te pot ajuta
The spot on the fault where the pressure first releases is called the
Answer:
This movement releases energy and generates seismic waves that can be recorded by specialized instruments used by scientists. The point on a fault at which the first movement or break occurs during an earthquake is called the earthquake's hypocenter
Explanation:
what are three limitations of current cloaking technology.
Get this correct I'll give you 40 points.
Explanation:
1.undetectable to electromagnetic waves
2.hiding an object from an illumination containing diffre t wave lengths become difficult as the object sizes grow.
3. reduce the scattering by two orders.
Electromagnetic waves are unable to detect it. With increasing item sizes, it becomes more challenging to conceal an object from an illumination with various wave lengths. two orders down on the scattering.
What is current cloaking technology?
Current clocking technology is defined as a hypothetical or made-up stealth technology that makes things like people or spaceships completely or partially invisible to certain electromagnetic (EM) spectrum wavelengths. In a specific frequency band, this gadget renders an object "invisible" to electromagnetic radiation. Obviously, cloaks that operate in the visible spectrum have the most fascinating potential uses.
These metamaterials, according to the researchers, can shield a medium-sized antenna from radio waves over a wide range of bandwidths, resulting in clearer communications. However, as visible light wavelengths are far shorter than radio waves, it is practically difficult to conceal huge things from them, such as the human body. The issue with present designs is that they can only handle a certain amount of bandwidth. Even this "perfect" 3D cloak that was previously exhibited could only conceal items from microwaves.
Thus, electromagnetic waves are unable to detect it. With increasing item sizes, it becomes more challenging to conceal an object from an illumination with various wave lengths. two orders down on the scattering.
To learn more about current cloaking technology, refer to the link below:
https://brainly.com/question/10964418
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What is the formula for Triphosphorous nonaoxide
According to the following reaction, how many grams of carbon tetrachloride will be formed upon the complete reaction of 27.7 grams of chlorine gas with excess carbon disulfide? carbon disulfide (s) + chlorine (g) carbon tetrachloride (l) + sulfur dichloride (s) grams carbon tetrachloride
Answer: 15.0 g of [tex]CCl_4[/tex] will be formed upon the complete reaction of 27.7 grams of chlorine gas with excess carbon disulfide
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} Cl_2=\frac{27.7g}{71g/mol}=0.390moles[/tex]
The balanced chemical reaction is:
[tex]CS_2(g)+4Cl_2(g)\rightarrow CCl_4(l)+2SCl_2(s)[/tex]
[tex]Cl_2[/tex] is the limiting reagent as it limits the formation of product and [tex]CS_2[/tex] is the excess reagent.
According to stoichiometry :
4 moles of [tex]Cl_2[/tex] give= 1 mole of [tex]CCl_4[/tex]
Thus 0.390 moles of will give = [tex]\frac{1}{4}\times 0.390=0.0975moles[/tex] of [tex]CCl_4[/tex]
Mass of [tex]CCl_4=moles\times {\text {Molar mass}}=0.0975\times 154=15.0g[/tex]
Thus 15.0 g of [tex]CCl_4[/tex] will be formed upon the complete reaction of 27.7 grams of chlorine gas with excess carbon disulfide
Find the total mass in kilograms of a ring that contains a 5.0 x 10 -1 carat diamond and 7.00 grams of gold.
Answer:
49 вот правильный ответ
PLEASE HELP!!
15POINTS!!! And brainliest
Answer: a. 3.36 L
b. 33.2 g
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
Standard condition of temperature (STP) is 273 K and atmospheric pressure is 1 atm respectively.
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
[tex]\text{Number of moles of} Fe_2O_3=\frac{16.0g}{159.69g/mol}=0.1mole[/tex]
[tex]3O_2(g)+4Fe(s)\rightarrow 2Fe_2O_3(s)[/tex]
a. 2 moles of [tex]Fe_2O_3[/tex] are produced by = [tex]3\times 22.4L=67.2L[/tex] of [tex]O_2[/tex]
Thus 0.1 moles of [tex]Fe_2O_3[tex] are produced by =[tex]\frac{67.2}{2}\times 0.1=3.36L[/tex] of [tex]O_2[/tex]
b. [tex]3\times 22.4L=67.2L[/tex] of [tex]O_2[/tex] react with = [tex]4\times 55.8=223.2g[/tex] of iron
Thus 10.0 L of [tex]O_2[/tex] react with = [tex]\frac{223.2}{67.2}\times 10=33.2g[/tex] of iron
Convert 392 K into Celsius.
Your answer should have three significant figures (round your answer to the nearest whole number).
Use −273∘C for absolute zero.
Answer:
118.85 degrees celsius (not sure if it is)
Answer:
118 is correct
Explanation:
:)
Explain how it's possible that warm temperatures can cause more snow to happen.
Which circuit would light the light. A or B
Answer:
B
Explanation:
you can tell by looking at the image lol the wires have to be connected
(brainliest please? c:)
( although its fine if not im just glad to have helped )
Answer:
The answer is B
Explanation:
The 2013 Rolls Royce Ghost Alpine has a top speed of 155 miles per hour. Calculate the speed in centimeters per second.
AutoChina Shanghai 2013 also plays host to the world debut of the latest Bespoke Collection from the world’s pinnacle super-luxury marque.
The Alpine Trial Centenary Collection celebrates an extraordinary moment in Rolls-Royce and automotive history. A century ago this June, four Rolls-Royce Silver Ghosts embarked on the Austrian Alpine Trials, the most arduous test of automotive endurance of the time.
In performing without fault over 1820 gruelling miles of near impassable mountain terrain, the Rolls-Royce works team and privateer entrant James Radley helped cement the marque’s reputation for peerless reliability and mechanical excellence, a reputation the company proudly retains today. In doing so establishing the legend of Rolls-Royce as maker of the ‘Best Car in the World’.
This limited edition of Rolls-Royce Ghosts feature exquisitely crafted design cues that pay tribute to these extraordinary motor cars. The exterior paint hue, for example takes close inspiration from Radley’s Silver Ghost, a car that stands side-by-side with the 2013 model in Shanghai.
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