Can someone help? This is hard

Answer:

Bala Bala Bala Bala Bala

Step-by-step explanation:

what is the slope of the Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah answer is answer the question Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah Blah

Answer:

y =47.5.

Step-by-step explanation:

First eliminate the fractions by multiplying through by the LCM of 7 and 3 which is 21:

21* 6[y-2]/7-21*12 = 21*2[y-7]/3

18(y - 2) - 252 = 14(y - 7)

18y -36 - 252 = 14y - 98

18y - 14y = -98 + 36 + 252

4y = 190

y = 190/4

y = 47.5.

Answer:

sqrt(10)

Step-by-step explanation:

[tex] \sqrt[2]{ x_{2} - x_{1}) + ( y_{2} - y_{1})} [/tex]

Answer:

10:24

Step-by-step explanation:

if school starts at 7:15 and you stay in the first 4 periods for 47 minutes each, that totals 3 hours, 8 minutes

7:16 + 3 hrs, 8 min = 10:24

Answer:

If you are not in Iceland, then you are not in Reykjavik.

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

The contrapositive of a statement is as follows:

"Switching the hypothesis and conclusion of a conditional statement and negating both. For example, the contrapositive of "If it is raining then the grass is wet" is "If the grass is not wet then it is not raining."

So, for this one, we need to switch as well!

If you are in Reykjavik, then you are in Iceland.

If you are NOT in Iceland, then you are not in Reykjavik.

The answer would be D

Answer:

7

Step-by-step explanation:

i know

Answer:

49 square metres

Step-by-step explanation:

The area of a square is the length of the side times itself.

The area is 7 x 7 = 49

Answer:

x = 14

Step-by-step explanation:

21 ÷[tex]\frac{2}{3}[/tex] = 14

Answer:

x = 31 1/2

Step-by-step explanation:

- Isolate x by multiplying 2/3 on each side, cancelling out the one of its original placement

- You can't divide by a fraction, so KCF (Keep Change Flip):

      x = 21 * 3/2

      = 63/2 or 31 1/2

Ages of swapna and suma are 33 and 7 years old respectively

If Swapna is 26 years older than her daughter Suma, then;

x = y + 26 ............... 1

6 years later:

Age of Swapna  = x + 6

Age of Suna = y + 6

If Swapna will be thrice as old as Suma, then;

x + 6  = 3(y + 6) ................. 2

Substitute equation 1 into 2:

y + 26 + 6 = 3y + 18

y + 32 = 3y + 18

-2y = -14

y = 7

Since x = y + 26

x = 26 + 7

x = 33

Hence ages of swapna and suma are 33 and 7 years old respectively

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Answer:

f(x)=125k(1.05)x

Step-by-step explanation:

ommg

ok so every year it increase by 5%, aka 105%

which is 125k*105/100x which is the first one f(x)=125k(1.05)x

if u are not sure than use cross of elinimation

cant be 2nd one cause its not correct

third one ur decreasing

fourth one is just like the 2nd one

Answer:

no its not a function

Step-by-step explanation:

because the lines on the graph are not equal\in a straight line(the puppy is not gaining the same amount each week)

Answer: 60%

Step-by-step explanation: if the question is saying the item was already 40% an ADDITIONAL (adding) 20% will make the item 60% off meaning your percentage of savings is 60%

Step-by-step explanation:

Distributive property

Answer:

y = x + 7

Step-by-step explanation:

If the slope is 1, the original equation is y = mx + b, with m being 1.

Now substitute -6 and 1 for x and y and solve for b

1 = 1(-6) + b

1 = -6 + b

7 = b

Put it all together:

y = x + 7

========================================================

Explanation:

Let x and y be two positive whole numbers. They may or may not be equal.

The first bag has the ratio of red to blue as 3:5, which scales up to 3x:5x after multiplying both parts by x. We have 3x red and 5x blue.

The second bag has the ratio 3:2 which scales up to 3y:2y. This bag has 3y red and 2y blue.

We can make a handy table to keep track of all the expressions

[tex]\begin{array}{|c|c|c|}\cline{1-3}\text{ } & \text{Red} & \text{Blue}\\ \cline{1-3}\text{bag 1} & 3x & 5x\\ \cline{1-3}\text{bag 2} & 3y & 2y\\ \cline{1-3}\end{array}[/tex]

Based on that, we can then say:

Effectively, I added down along each column of that table.

Divide the two expressions for R and B to lead to the fraction 11/9, which is directly from the ratio 11:9

So,

(total red)/(total blue) = 11/9

R/B = 11/9

(3x+3y)/(5x+2y) = 11/9

---------------------

Let's cross multiply and then solve for y

(3x+3y)/(5x+2y) = 11/9

9(3x+3y) = 11(5x+2y)

27x+27y = 55x+22y

27y-22y = 55x-27x

5y = 28x

y = 28x/5

y = (28/5)x

y = 5.6x

We'll keep this in mind for later.

---------------------

Now let:

Recall that we had 3x red and 5x blue for the first bag. That means we have 3x+5x = 8x marbles in the first bag. Therefore, F = 8x.

Also, we had 3y red and 2y blue for the second bag.

So we have S = 3y+2y = 5y

Then we can apply further substitution to say

S = 5y

S = 5(5.6x) .... plug in y = 5.6x

S = 28x

---------------------

In short,

for some positive whole number x. We don't have enough info to pin down what x is exactly; however, it doesn't really matter. This is because the x variable will cancel when dividing F over S

F/S = (8x)/(28x) = 8/28 = 2/7

The fraction 2/7 leads directly to the final answer of the ratio 2:7

In other words, the ratio 8x:28x simplifies fully to 2:7 after dividing both parts by 4x.

The ratio between the total marbles of the first bag and the second bag is 2:7.

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

Example:

2x + 4 = 9 is an equation.

We have,

x marbles in the first bag.

red marbles = 3x

blue marbles = 5x

y marbles in the second bag.

red marbles = 3y

blue marbles = 2y

Now,

Total red marbles in both bags.

3x + 3y = 11 _____(1)

3x = 11 - 3y

x = (11 - 3y) / 3

Total blue marbles in both bags.

5x + 2y = 9 ______(2)

From (1) and (2) we get,

Multiply 2 in (1).

6x + 6y = 22

6y = 22 - 6x _____(3)

Multiply 3 in (2)

15x + 6y = 27 ______(4)

Putting (3) in (4)

15x + 22 - 6x = 27

9x = 27 - 22

9x = 5

x = 5/9

Now,

x = 5/9 in (3)

6y = 22 - 6(5/9)

6y = 22 - 10/3

6y = (66 - 10)/3

y = 56/18

y = 28/9

Now,

First bag.

Red marbles = 3x = 3 x 5/9 = 5/3

Blue marbles = 5x = 5 x 5/9 = 25/9

Total marbles = 5/3 + 25/9 = (15 + 25)/9 = 40/9

Second bag.

Red marbles = 3y = 3 x 28/9 = 28/3

Blue marbles = 2y = 2 x 28/9 = 56/9

Total marbles = 28/3 + 56/9 = (84 + 56)/9 = 140/9

Now,

The ratio between the total marbles of the first bag and the second bag.

= 40 :140

= 4:14

= 2:7

Thus,

The ratio is 2:7.

Learn more about equations here:

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Answer:

????????????????????????

Answer: 4

Step-by-step explanation: If Caleb starts with 4 and subtracts 6, he'll get -2. -2 times 2, equals -4. If he starts with 4 and subtracts 8, he'll again end up with -4, meaning the original number is 4!

4-6= (-2)

-2*2= (-4)

4-8= (-4)

Answer:

  x = 10

Step-by-step explanation:

The diagonals of a rectangle are the same length. This means ...

  AC = BD

  x +6 = 2x -4

  10 = x . . . . . . . . add 4-x to both sides

The figure is a rectangle for x=10.

x+y=0

Step-by-step explanation:

x= 1.75

y= -1.75

[tex]\huge \rm༆ Answer ༄[/tex]

The equivalent expression is ~

Refer to attachment for solution ~

For x such that 0 < x < [tex]\frac{\pi}{2}[/tex], the mathematical expression is:

[tex]\frac{\sqrt{1 \;-cos^2x} }{sinx} + \frac{\sqrt{1 \;-sin^2x} }{cosx} = 1+1=2[/tex]

Given the following data:

In Trigonometry, you should take note of the following mathematical expression:

[tex]sin^2x + cos^2x = 1[/tex]

Therefore, we can obtain the following:

[tex]sin^2x = 1 - cos^2x[/tex]   ...equation 1.

[tex]cos^2x = 1 - sin^2x[/tex]    ...equation 2.

Substituting the equations respectively, we have:

[tex]\frac{\sqrt{1 \;-cos^2x} }{sinx} + \frac{\sqrt{1 \;-sin^2x} }{cosx} = \frac{\sqrt{sin^2x} }{sinx} + \frac{\sqrt{cos^2x} }{cosx}\\\\[/tex]

Taking the square roots, we have:

[tex]\frac{sinx}{sinx} + \frac{cosx}{cosx} = 1 +1\\\\1+1=2[/tex]

Therefore, for x such that 0 < x < [tex]\frac{\pi}{2}[/tex], the expression is:

[tex]\frac{\sqrt{1 \;-cos^2x} }{sinx} + \frac{\sqrt{1 \;-sin^2x} }{cosx} = 1+1=2[/tex]

Read more on trigonometry here: https://brainly.com/question/4515552

Answer:

56

Step-by-step explanation:

Answer:

i think its 140 because u got to add all the sides in order to subtract from 180

i dont know  if its right but that is what i think UwU

Answer:

5,600 g of flour

10,000g of sugar

3,200g of ginger

4,400g of butter

Just have to multiply each ingredient by 40

Im pretty sure It would be a decrease

Answer: x= -2, y= 3

Step-by-step explanation:

3x+5y=9

X-y=-5

Multiply bottom equation by 5

3x+5y=9

5x-5y=-25

3x + 5x=8x

5y-5y cancels out

9-25= -16

8x= -16

X= -2

Plug -2 back into equation of choice to find y

3(-2)+5y=9

-6+5y=9

Add -6 to both sides

-6+6 cancels

9+6=15

5y=15

Y=3

Answer:  659

Step by step solution:

Answer:

659

Step-by-step explanation:

0659

8 5272

0

52

48

 47

 40

   72

   72

     0

Dividend:

5272

Divisor:

8

Quotient:

659

Remainder:

0

You may have to write this on paper because it might be hard for you to understand. I'm sorry if this isn't helping and it is very confusing, this is the only way that I could explain it. Thank you for the question and I hope you enjoy your answer :)

Answer:

y= 2/3x+8

Step-by-step explanation:

you add 10 to both sides then combine -2 with 10 to get 8

then 1x times 2/3 is 2/3x and -3 times 2/3 is -2

Answer: The equation is not an identity

==========================================================

Explanation:

We'll expand out the right hand side to see if we can simplify it to the left hand side. The stuff on the left will stay the same for each step.

I'll use  c = a+b as a way to help distribute.

[tex]a^4 + b^4 = (a+b)(a^3 - a^2b-ab^2 + b^3)\\\\a^4 + b^4 = c(a^3 - a^2b-ab^2 + b^3)\\\\a^4 + b^4 = a^3c - a^2bc-ab^2c + b^3c\\\\a^4 + b^4 = a^3(c) - a^2b(c)-ab^2(c) + b^3(c)\\\\a^4 + b^4 = a^3(a+b) - a^2b(a+b)-ab^2(a+b) + b^3(a+b)\\\\a^4 + b^4 = a^4+a^3b - a^3b-a^2b^2-a^2b^2-ab^3 + ab^3+b^4\\\\a^4 + b^4 = a^4+(a^3b - a^3b)+(-a^2b^2-a^2b^2)+(-ab^3 + ab^3)+b^4\\\\a^4 + b^4 = a^4-2a^2b^2+b^4\\\\[/tex]

Unfortunately, we can't go any further. We have a^4 and b^4 on the right hand side, but we also have the term -2a^2b^2 that didn't cancel out. Therefore, the original equation is not an identity.

----------------

Here's another way you can see that we don't have an identity.

Let's say we fixed 'a' to be equal to 1.

That means the equation

[tex]a^4 + b^4 = (a+b)(a^3 - a^2b-ab^2 + b^3)[/tex]

would turn into

[tex]1^4 + b^4 = (1+b)(1^3 - 1^2b-1b^2 + b^3)[/tex]

and simplify to

[tex]1 + b^4 = (1+b)(1 - b-b^2 + b^3)[/tex]

Now replace b with x and you'll have the two equations to represent the left and right hand sides

[tex]y = 1+x^4\\y = (1+x)(1-x-x^2+x^3)[/tex]

which you can graph on the same xy axis. You should note that the two equations produce different curves. The curves would need to be identical if we wanted an identity to happen.

Side note: you can pick other values for 'a' instead of just 1.

Answer:

(7,-2)

Step-by-step explanation:

Answer:

(7, - 2 )

Step-by-step explanation:

x - y = 9 ( add y to both sides )

x = y + 9 → (1)

2x + 5y = 4 → (2)

Substitute x = y + 9 into (2)

2(y + 9) + 5y = 4 ← distribute parenthesis and simplify left side

2y + 18 + 5y = 4

7y + 18 = 4 ( subtract 18 from both sides )

7y = - 14 ( divide both sides by 7 )

y = - 2

Substitute y = - 2 into (1)

x = - 2 + 9 = 7

solution is (7, - 2 )