Answer:I can't see the question
Explanation:so i dont konw
Now set the tension to low and wiggle the wrench to create more waves. Can you explain how moving the first point on the string, the one closest to the wrench, affects the next point on the spring? How does this fit with your understanding of the force of a stretched spring?
Answer:
When the string moves, it creates a very small change in the distance to the next point, th
Explanation:
When the string moves, it creates a very small change in the distance to the next point, this generates a restoring force that tends to push the string back, this small disturbance propagates along the string and is what creates the pulse.
This is similar to what happens when a spring is stretched and a restoring force is generated shaved by the law of shortening.
F = k Dx
Answer:
As the first particle travels upward, it pulls on the next particle, which follows the first particle upward. Then next in line is pulled up in turn, and so on. The motion of each particle follows the one before it, either up or down, with a slight lag in time. This succession of particles moving up or down travels along the string as a wave. Eventually, it pulls every particle along the string up and down in series.
Explanation:
A small motor uses 200 watts to do 4000 joules of work. How much time this take to occur?
You are planning an investigation that explores the properties of matter. Which of the following will help you discover a physical property?
Experiment: place a powder into a beaker that contains a liquid/Result: the beaker gets hotter
Experiment: place a powder into a beaker that contains a liquid/Result: the solid dissolves into the liquid
Experiment: place a powder into a beaker that contains a liquid/Result: the mixture begins to fizz and bubble
Experiment: place a powder into a beaker that contains a liquid/Result: the mixture catches fire and burns down the lab
Answer:
I will post your answer soon
Explanation:
If you are planning an investigation that explores the properties of matter, then experiment: place a powder into a beaker that contains a liquid Result : the beaker gets hotter will help you discover a physical property.
What is experiment ?An experiment is a technique used to confirm or deny a hypothesis, as well as assess the possibility or effectiveness of something that has never been done before. Experiments show what happens when a certain component is modified, which sheds light on cause-and-effect relationships. The purpose and scope of experiments vary widely, but they always rely on a repeatable process and a rational examination of the outcomes. Natural experimental experiments are also a thing.
While a child may conduct simple experiments to better understand how objects fall to the ground, scientific teams may spend years conducting thorough research to increase their understanding of a phenomenon.
This experiment shows enthalpy is positive, heat is absorbed in this experiment. this breaks the atoms and it needed the energy.
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A steel ball bearing is released from a height H and
rebounds after hitting a steel plate to a height H.
What is true about the collision with the steel plate?
Answer:
ELASTIC collision
kinetic energy is conservate
Explanation:
As the ball bounces to the same height, it can be stated that the impact with the floor is ELASTIC.
As the floor does not move the conservation of the moment
po = pf
-mv1 = m v2
- v1 = v2
So the speed with which it descends is equal to the speed with which it rises
Therefore the kinetic energy of the ball before and after the collision is the same
Answer:
CORRECT (SELECTED)
It is elastic since kinetic energy was conserved.
Explanation:
I know the answer but what type of energy is this.
Answer:
Elastic potential energy
Explanation:
Answer:
elastic energy
Explanation:
2. A large collection of stars, gas, and dust is called a _____?
Help me please
There’s 2 questions.
Answer:
50 Joules of work on the system Total distance is 1m W= F ×D 50 Joules = F × 1m F= 50 Newtons W= 1234 J D= 451234= F × 45 meters F= 27.42 Newtons I do exams and quizzes if ur interestedUn bloque de 3 kg en reposo se deja libre a una altura de 5 m sobre una rampa curva y sin rozamiento. Al pie de la rampa se encuentra un resorte de constante k = 400 N/m, como se muestra en la fig. El objeto desliza por la rampa y llega a chocar contra el resorte comprimiéndolo una distancia x antes de que quede en reposo momentáneamente. Determinar: a) La velocidad con la que el bloque alcanza al resorte. ____________________ b) La distancia x que el bloque comprime al resorte. __________________ c) La velocidad con la que el bloque es expulsado por el resorte. ____________________ d) La altura que alcanza sobre la parte curva. ________________ e) ¿Alcanzará la misma altura si la rampa no está libre de rozamiento? ___________________
Answer:
a) La velocidad del bloque cuando llega al resorte es de aproximadamente 9,9 m / s
b) La distancia a la que se comprime el resorte es de aproximadamente 0,86 m
c) La velocidad con la que el resorte expulsa el bloque es de aproximadamente 9,9 m / s
d) La altura que alcanza el bloque es de 5 metros.
e) El bloque no alcanzará la misma altura si la rampa no está libre de fricción
Explanation:
a) Los parámetros dados del bloque son;
La masa del bloque, m = 3 kg
La altura a la que se coloca el bloque, h = 5 m
La constante de resorte, k = 400 N / m
La aceleración debida a la gravedad, g = 9,8 m / s²
La energía potencial de un cuerpo, P.E. = m · g · h
Por tanto, la energía potencial inicial del bloque, P.E. se da como sigue;
P.E. = 3 kg × 9,8 m / s² × 5 m = 147 julios
P.E. = 147 julios
La energía cinética del bloque al pie de la rampa, K.E. = 1/2 · m · v²
Dónde;
v = La velocidad del bloque cuando llega al resorte
Por lo tanto, para el bloque dado tenemos;
K.E. = 1/2 · m · v² = 1/2 × 3 kg × v²
Por el principio de conservación de la energía, tenemos;
El PE. del bloque en reposo a una altura de 5 m = La energía cinética al pie de la rampa. K.E.
∴ P.E. = K.E.
147 J = 1/2 × 3 kg × v²
v² = 147 J / (1/2 × 3 kg) = 98 m² / s²
v = √ (98 m² / s²) = 7 · √2 m / s
v = 7 · √2 m / s ≈ 9,9 m / s
b) La energía recibida por el resorte comprimido, E = 1/2 · k · x²
Dónde;
k = La constante del resorte = 400 N / m
x = La distancia a la que se comprime el resorte
Por el principio de conservación de la energía, tenemos;
La energía recibida por el resorte comprimido, E = La energía potencial inicial del resorte, P.E.
∴ E = 1/2 · k · x² = P.E.
De lo que tenemos;
E = 1/2 × 400 N / m × x² = 147 julios
x² = 147 Julios / (1/2 × 400 N / m) = 0,735 m²
x = √ (0,735 m²) = 0,7 · √ (3/2) m ≈ 0,86 m
La distancia a la que se comprime el resorte = x ≈ 0.86 m
c) La velocidad con la que el resorte expulsa el bloque se indica a continuación;
La energía en el resorte = 1/2 · k · x² = La energía cinética dada al bloque, 1/2 · m · v²
∴ 1/2 · k · x² = 1/2 · m · v²
∴ La velocidad con la que el bloque es expulsado por el resorte, v = La velocidad con la que el bloque llega al resorte = 7 · √2 m / s
La velocidad con la que el resorte expulsa el bloque, v = 7 · √2 m / s ≈ 9,9 m / s
d) La altura que alcanza el bloque también viene dada por la siguiente relación anterior;
P.E. = K.E.
∴ m · g · h = 1/2 · m · v²
v = 7 · √2 m / s
De donde tenemos h = La altura inicial del bloque en la rampa = 5 metros
e) El bloque no alcanzará la misma altura si la rampa no está libre de fricción porque se utilizará energía para superar la fuerza de fricción
a) La velocidad final del bloque es aproximadamente 9.903 metros por segundo.
b) El resorte se deforma 0.858 metros.
c) Por el principio de la conservación de energía y sabiendo la ausencia de fuerzas disipativas, la velocidad del objeto expulsado del resorte es aproximadamente 9.903 metros por segundo.
d) Por el principio de la conservación de energía y si existieran fuerzas disipativas, la altura máxima sería menor a la hallada en el punto a).
a) Conforme a la situación de este problema, la energía cinética traslacional final ([tex]K[/tex]), en joules, es igual a la energía potencial gravitacional inicial ([tex]U[/tex]), en joules.
[tex]U = K[/tex] (1)
Por las definiciones de las energías cinética traslacional y potencial gravitacional expandimos la ecuación anterior:
[tex]m\cdot g\cdot h = \frac{1}{2}\cdot m\cdot v^{2}[/tex] (1)
Ahora despejamos la velocidad de esa ecuación:
[tex]v = \sqrt{2\cdot g\cdot h}[/tex]
Donde:
[tex]m[/tex] - Masa del bloque, en kilogramos.[tex]g[/tex] - Aceleración gravitacional, en metros por segundo al cuadrado.[tex]h[/tex] - Altura inicial del bloque, en metros.[tex]v[/tex] - Velocidad final del bloque, en metros por segundo.Si sabemos que [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] y [tex]h = 5\,m[/tex], entonces la velocidad final del bloque es:
[tex]v = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (5\,m)}[/tex]
[tex]v\approx 9.903\,\frac{m}{s}[/tex]
La velocidad final del bloque es aproximadamente 9.903 metros por segundo.
b) Por el principio de conservación de la energía, la energía cinética traslacional inicial es igual a la energía potencial elástica final, cuyas fórmula es la siguiente:
[tex]\frac{1}{2}\cdot k\cdot x^{2} = \frac{1}{2}\cdot m \cdot v^{2}[/tex] (2)
Where:
[tex]k[/tex] - Constante de resorte, en newtons por metro.[tex]x[/tex] - Deformación del resorte, en metros.Ahora despejamos la deformación del resorte:
[tex]x = \sqrt{\frac{m}{k} }\cdot v[/tex] (3)
Si sabemos con [tex]k = 400\,\frac{N}{m}[/tex], [tex]m = 3\,kg[/tex] y [tex]v \approx 9.903\,\frac{m}{s}[/tex], entonces la deformación del resorte es:
[tex]x = \sqrt{\frac{3\,kg }{400\,\frac{N}{m} } }\cdot \left(9.903\,\frac{m}{s} \right)[/tex]
[tex]x \approx 0.858\,m[/tex]
El resorte se deforma 0.858 metros.
c) Por el principio de la conservación de energía y sabiendo la ausencia de fuerzas disipativas, la velocidad del objeto expulsado del resorte es aproximadamente 9.903 metros por segundo.
d) Por el principio de la conservación de energía y si existieran fuerzas disipativas, la altura máxima sería menor a la hallada en el punto a).
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A box has a 20 N force applied to it to move it 5 m. What is the work done on the box? 4 J 4 N 25 J 100 J
PLEASE PLEASE HELPPP!
Select all that apply!
Answer:
1 AND 3
Explanation:
A 1000kg truck is moving at a velocity of 4m/s what is it's momentum?
Answer:
4000 kg m/s
Explanation:
p=mv
p = momentum in kg m/sm = mass in kgv = velocity in m/ssubstitute values into the formula above to get:
p=1000x4
p=4000 kg m/s
Help with physics please! Offering a bunch of points!
Hurry pls I need help
Answer:
away from each other
Explanation:
Thus, two negative charges repel one another, while a positive charge attracts a negative charge. The attraction or repulsion acts along the line between the two charges. The size of the force varies inversely as the square of the distance between the two charges.
1. Which of the following is an example of a force?
-0.1 Newtons to the left
-5 m/s/s
-0.5 m/s/s
-10 Newtons
PLEASE Help! Physics Question
Answer:
hundred metre race on sports day started by a gun firing when the gun is fired a pop of smoke comes out of the gunners will you suggest about trigonometry right here is the sound of the explosion before or at it seems of of smoking containers out of the governor ke this answer about something I don't know I am sorry
Which is an example of physical weathering?
a- limestone in rock dissolving when acid rain flows across it
b- bits of rock rusting when exposed to oxygen and water
c- wind blowing off bits of a rock over time
d- oxidation of certain metals in rock
An example of physical weathering is the wind that is blowing off bits of a rock over time. This results into breaking down of large rocks. Thus, the correct option is C.
What is Physical weathering?Physical weathering is also called as mechanical weathering. It is a process which causes the disintegration of large rocks, minerals, and large soil particles without any chemical change. The primary process in physical weathering is the abrasion, it is the process by which clasts and other particles are reduced in size and mix up with soil.
Physical weathering occurs when large rocks are broken down through mechanical processes such as wind blowing, water, gravitational force, freeze-thaw cycles, or the growth of roots into the rocks.
Therefore, the correct option is C.
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A free body diagram represents all of the following except:
a)the object
b)forces as vectors
c)forces exerted by the object
d)forces exerted on the object
Answer:
c
Explanation:
A free body diagram doesn't show forces exerted by the object.
A free body diagram represents all the given choices except the one which is "forces exerted by the object"
Diagrams that represent the approximate magnitude as well as the direction of all pressures exerted on either an item throughout a particular condition.Drawing such a free-body schematic or the model seems to be a key step towards pattern recognition throughout mechanical because it allows you to see every one of the influences operating on a particular element.
Thus the above answer is right.
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PLEASE HELP !! A 10 ohm resistor is connected to a 9V battery how much current is flowing through the circuit?
Resitance (R)= 10 Ohm
Potential difference (V) = 9V
V= IR
I= V/R
I= 9/10
I= 0.9 Ampere
Therefore 0.9 Ampere of current is flowing through the circuit.
The current through the circuit can be calculated using Ohm's law. The current flowing through the circuit with a resistance of 10 ohm and 9 V is 0.9 ampere.
What is Ohm's law?Ohm's law states that the potential difference or voltage across a circuit is the product of the current and resistance through the circuit. Thus as current or resistance increases, voltage across the circuit also increases.
According to Ohm's law, V= IR.
Given the voltage V = 9 V
Resistance R = 10 ohm
Current = voltage/ resistance (V/R)
= 9 V/ 10 Ω.
= 0.9 A.
Therefore, the current passing through the circuit is 0.9 A.
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Question 5 of 10
A dog pushes against the front door for 3 seconds with a force of 88 N. What
impulse has the
dog applied to the door?
A. 264 kg•m/s
O B. 77.2 kg•m/s
O C. 29.3 kg•m/s
OD. 128 kg•m/s
SLEMT
Answer:
265 Kg.m/sExplanation:
Impulse = Force × time
So 88× 3 =264!!
Answer:
264 kg*m/s
Explanation:
hey, what is rectilinear propagation of light ?
Please help me with this
Answer:
The most correct option for the magnitude of the velocity of the ship relative to the port is;
33 km/h
Explanation:
The given parameters of the cargo ship are;
The speed of the cargo ship = 25 km/h
The direction of the cargo ship, θ₁ = 20° North of East
The speed of the current = 10 km/h
The direction of the current, θ₂ = 15° North of East relative to the port
Therefore the direction of the ship relative to the port, 'θ', is given as the sum of θ₁ and θ₂ as follows;
θ = θ₁ + θ₂ = 20° + 15° = 35°
The component of the velocities relative to the port are given as follows;
The velocity of the ship, v₁ = 25·cos(35°)·i + 25·sin(35°)·j
The velocity of the current , v₂ = 10·cos(15°)·i + 10·sin(15°)·j
The velocity of the ship relative to the port, v = (25·cos(35°) + 10·cos(15°))·i + (25·sin(35°) + 10·sin(15°))·j
∴ v ≈ 30.14·i + 16.93·j
The magnitude of 'v' is [tex]\left | v \right |[/tex] = √(30.14² + 16.93²) ≈ 34.6
Therefore, the magnitude of the velocity of the ship relative to the port, [tex]\left | v \right |[/tex] ≈ 34.6 km/h.
Therefore, the closest correct option for the velocity of the ship relative to the port is 33 km/h
Answer:
The correct option for the magnitude of the velocity of the ship relative to the port is...
(33 km/h)
. Calculate the unbalanced force acting on a 0.50 kg toy rocket that accelerates at a constant rate with a velocity of 20 m/s (up) to 45 m/s (up) in 0.7 s.
Answer:
17.85N
Explanation:
Given data
m= 0.5kg
u= 20m/s
v= 45m/s
t= 0.7second
From
F= mΔv/t
substitute
F=0.5*(45-20)/0.7
F=0.5*25/0.7
F=12.5/0.7
F=17.85
Hence the force is 17.85N
a car travels straight for 20 miles on a road that is 30 north of east. what is the easiest component of the cars displacement to the nearest tenth of a mile
A -17.3 miles
B -10.0miles
C 10.0 miles
D 17.3 miles
Answer:
17.3 miles
Explanation:
two girls drag a bag across the floor. One girl exerts a force of 10 newtons and the other girl a force of 30 Newton's in the same direction. Calculate the resultant force on the bag.
Answer:
Explanation:
The resultant would be a combination of the two forces. We need to add them together since they are exerting a force in the same direction.
10+30= 40 N of force
How many seconds does it take for net force 20N to change the velocity to a 5kg mass by 2m/s?
Answer:
0.5 second
Explanation:
We are given that
Force, F=20 N
Mass, m=5 kg
Change in velocity,=2m/s
We have to find the time taken to change the velocity .
We know that
Force, F=ma
Where
Acceleration, a=Change in velocity/time
[tex]a=\frac{2}{t}[/tex]
Substitute the values
[tex]20=5\times \frac{2}{t}[/tex]
[tex]t=\frac{5\times 2}{20}[/tex]
[tex]t=0.5 s[/tex]
Please help will give brainliest
Answer:
1. The human exerts a force when he pulls the bow back and launches it.
2. Gravity causes the arrow to fall down, and air resistance slows the arrow down, as it is in the opposite direction.
3. If the arrow has more mass, it would require to have a greater force exerted on it to make it fly farther. So the archer would most likely not reach as high of a top speed.
Explanation:
brainliest :)
How can I skip class:
A: Fake sick.
B: Have a heating pad on my heat to have a fake fever.
C: Fake barf
D: Act fine until a test the neb sick
Answer:
c gl
Explanation:
::::::::::::::::::::::::
A hair dryer transfers 48K J of energy in one minute. What is the power rating of the hairdryer? *
Answer:
800W
Explanation:
48,000/60=800
The power rating of the hairdryer is 800W.
What is Power?Power can be defined as the rate at which work is done by an object. The S.I unit of power is Watt(W).
The formula of power will be
Power = Work done/time
A hair dryer transfers 48K J of energy in one minute.
1 minute = 60 seconds
P = 48,000/60
P = 800 W
Hence, the power rating of the hairdryer is 800W.
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All of the following are sources of calories except HELP ASAP!!!
Answer:
vitamins don't contain calories
AP physics! Will give brainliest to correct answer!
Answer:
D
Explanation:
Answer:
HELLO THERE
Explanation:
D