The change in time for the first quarter is
seconds.
The change in time for the second quarte 1.39
seconds.
2.07
The change in time for the third quarter is
2.18
seconds.
The change in time for the fourth quarter is
second

Answers

Answer 1

Answer: The change in time for the first quarter is  1.39 seconds.

The change in time for the second quarter is 0.78 seconds.

The change in time for the third quarter is 0.64 seconds.

The change in time for the fourth quarter is 0.54 seconds.  

Explanation: took info from my data and completed lab

Step 5: Measure the Speed of the Toy Car on the Higher Track

Calculate the change in time for each quarter of the track. Record the change in time in Table E of your Student Guide.

Also added the other calculations -

Calculate the average time the car took to reach each checkpoint. Record the average time in Table D of your Student Guide.

The average time to the first quarter checkpoint is 1.39 seconds.  

The average time to the second quarter checkpoint is 2.18 seconds.

The average time to the third quarter checkpoint is 2.82 seconds.

The average time to the finish line is 3.36 seconds.

Calculate the speed of the car at each checkpoint by dividing the distance between each checkpoint, in meters, by the change in time. Record your answers in Table E of your Student Guide.

The speed at the first quarter checkpoint is 1.09 m/s.  

The speed at the second quarter checkpoint is 1.95 m/s.

The speed at the third quarter checkpoint is 2.37 m/s.

The speed at the finish line is 2.80 m/s.

Please make me Brainly..:)

The Change In Time For The First Quarter Isseconds.The Change In Time For The Second Quarte 1.39seconds.2.07The
The Change In Time For The First Quarter Isseconds.The Change In Time For The Second Quarte 1.39seconds.2.07The
The Change In Time For The First Quarter Isseconds.The Change In Time For The Second Quarte 1.39seconds.2.07The
The Change In Time For The First Quarter Isseconds.The Change In Time For The Second Quarte 1.39seconds.2.07The
The Change In Time For The First Quarter Isseconds.The Change In Time For The Second Quarte 1.39seconds.2.07The

Related Questions

Nitric oxide (NO) reacts with oxygen gas to produce nitrogen dioxide. A gaseous mixture contains 0.66 g of nitric oxide and 0.58 g of oxygen gas. After the reaction is complete, what mass of nitrogen dioxide is formed? Which reactant is in excess? How do you know? Suppose you actually recovered 0.91 g of nitrogen dioxide. What is your percent yield?

Answers

Answer:

NO is the limiting reagent.  

In this reaction 0.886 mole of NO2 is produced

Explanation:

The chemical equation for this reaction is  

2NO(g) + O2(g) → 2NO2(g)

In this limiting reagent reaction, 2 moles of NO reacts with one mole of O2  to produce 2 mole of 2NO2

0.886 mole of NO * (2 mole of NO2/2 mole of NO) = 0.886 mole of NO2

0.503 mole of O2 * (1 mole of NO2/1 mole of O2) = 1.01 mole of NO2

Hence, NO is the limiting reagent.  

In this reaction 0.886 mole of NO2 is produced

What do the symbols in the parentheses indicate

Answers

Answer:

(C) the physical state of each reactant and product

Explanation:

Hope this helps

Use this picture to explain that an electrically charged object can attract an uncharged object without any contact. Your answer should be at least three sentences long. (2 points) a balloon hanging from a string with small pieces of paper stuck to the bottom of it, with a few pieces on the ground

Answers

Answer: Insufficient amount of work provided.

Explanation:


How many significant figures are in the number 420,000 mi?

Answers

Answer:

2

Explanation:

zeros are not considered sig figs

Characterize EACH of the three given statements as being TRUE or FALSE and then indicate the collective true-false status of the statements using the choices. (1) Water's boiling point is much higher than expected, based on comparison with other substances, because of hydrogen bonding. (2) In the gaseous state, disruptive forces and cohesive forces are of about the same magnitude. (3) As liquid surface area increases, the rate of evaporation of a liquid increases.

Answers

Answer:

The correct answer is - 1 and 3 are true.

Explanation:

Hydrogen bonds require a lot of energy to be broken as these bonds are relatively strong intermolecular forces which makes the boiling point of liquid like water very high, as it requires a lot of heat to break the intermolecular bonds holding the water molecules together.

An increase in the surface area of the liquid also increases the rate of evaporation as it takes place among the molecules of the liquid on the surface.

Write a net ionic equation for the reaction that occurs when aqueous solutions of hydrofluoric acid and barium hydroxide are combined. Include solubility states

Answers

Answer: The net ionic equation is [tex]2H^+(aq)+2F^-(aq)+Ba^{2+}(aq)+2OH^-(aq)\rightarrow BaF_2(s)+2H_2O(l)[/tex]

Explanation:

The net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as ions that do not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of hydrofluoric acid and barium hydroxide follows:

[tex]2HF(aq)+Ba(OH)_2(aq)\rightarrow BaF_2(s)+2H_2O(l)[/tex]

The ionic form of the above equation follows:

[tex]2H^+(aq)+2F^-(aq)+Ba^{2+}(aq)+2OH^-(aq)\rightarrow BaF_2(s)+2H_2O(l)[/tex]

There are no spectator ions in the ionic form.

The net ionic equation for the above reaction follows:

[tex]2H^+(aq)+2F^-(aq)+Ba^{2+}(aq)+2OH^-(aq)\rightarrow BaF_2(s)+2H_2O(l)[/tex]

The speed of an electron is 1.68*10^8m/s what is the wavelength

Answers

Answer:

[tex]\lambda =4.33x10^{-12}m=4.33pm[/tex]

Explanation:

Hello there!

In this case, since the speed, wavelength and mass of an electron are related via the the Broglie wavelength:

[tex]\lambda =\frac{h}{m*v}[/tex]

Thus, by plugging in the mass of the electron and the Planck's constant, we obtain the following wavelength:

[tex]\lambda =\frac{6.626x10^{-34}J*s}{9.11x10^{-31}kg*1.68x10^{8}m/s}\\\\\lambda =4.33x10^{-12}m=4.33pm[/tex]

Best regards!

If 50.0 g of silicon dioxide is heated with an excess of carbon, 27.9 g of silicon carbide is produced. What is the percent yield of the reaction

Answers

Answer: The percent yield of the reaction is 83.5 %

Explanation:

The given balanced equation is

[tex]SiO_2+3C\rightarrow SiC+2CO[/tex]

[tex]SiO_2[/tex] is the limiting reagent as it limits the formation of product and [tex]C[/tex] is the excess reagent.

According to stoichiometry :

60.08 g of [tex]SiO_2[/tex] produce = 40.11 of [tex]SiC[/tex]

Thus 50.0 of [tex]SiO_2[/tex] will produce=[tex]\frac{40.11}{60.08}\times 50.0=33.4[/tex]  of [tex]SiC[/tex]

 Experimental yield of SiC = 27.9 g

Percent yield = [tex]\frac{\text {Experimental yield}}{\text {theoretical yield}}\times 100=\frac{27.9g}{33.4g}\times 100=83.5\%[/tex]

Thus  percent yield of the reaction is 83.5 %

The percent yield of 83.5 % of 50.0 g of silicon dioxide is heated with an excess of carbon, and 27.9 g of silicon carbide is produced in the reaction.

What is the chemical balance of the equation?

The chemical equations are balanced when the reactants react to form products. The reactants and products react in proper ratios and if they are not in ratio then we balance them by adding the required quantity in the reactants and the products.

The given balanced equation is

[tex]\rm SiO_2+3C---- > SiC+2CO[/tex]

[tex]SiO_2[/tex] is the limiting reagent as it limits the formation of product and is the excess reagent.

According to stoichiometry

60.08 g [tex]SiO_2[/tex] of  produce = 40.11 of [tex]SiC[/tex]

Thus 50.0 of  [tex]SiO_2[/tex] will produce=  [tex]\dfrac{40.11}{60.08} \times 50=33.4\ SiC[/tex]

The experimental yield of SiC = 27.9 g

The percentage yield will be calculated as

[tex]\rm Percentage \ Yield = \frac{Experimental\ yield}{Theoretical \ yield }\times 100[/tex]

[tex]\rm Percentage \ yield =\dfrac{27.9}{33.49} \times 100=83.5[/tex]

Thus the percent yield of 83.5 % of 50.0 g of silicon dioxide is heated with an excess of carbon, and 27.9 g of silicon carbide is produced in the reaction.

To know more about balanced chemical equations follow

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As mentioned in the kinetic molecular theory, what is the main reason that the volume of gas particles can be considered zero?
a)The bonds present in gas particles are stronger than other bonds, pulling atoms in closer to each other, causing a shorter bond length which greatly decreases the volume.
b)When atoms enter the gas phase, they are less affected by gravity, which lowers their mass and in turn, their volume.
c)The real volume of the gas particles is extremely small when compared to the entire volume of their container.
d)Gas particles constantly expand and contract, which constantly alters their volume. When these volumes are averaged, a value of zero is obtained.

Answers

Answer:

The real volume of the gas particles is extremely small when compared to the entire volume of their container.

d)Gas particles constantly expand and contract, which constantly alters their volume. When these volumes are averaged, a value of zero is obtained

Explanation:

The reason for using 1-propanol as the solvent of choice for recrystallization is that triphenylphosphine oxide is more soluble in 1-propanol than the alkene product because triphenylphosphine oxide can use its oxygen to hydrogen-bond to 1-propanol, whereas the alkene has no hydrogen-bonding capability. Triphenylphosphine oxide, therefore, is removed based on its polarity and H-bonding ability.

a. True
b. False

Answers

Answer:

True

Explanation:

Hydrogen bonding is a bond that exists between hydrogen and a highly electronegative element such as oxygen, nitrogen, fluorine etc.

The greater solubility of the triphenylphosphine oxide owes to the hydrogen bonded interaction between it and the 1-propanol.

The alkene lacks such hydrogen bonded interaction because it does not have a highly electronegative atom in its structure.

Hence, triphenylphosphine oxide is removed based on its polarity and hydrogen bonding ability.

How many moles of NaOH are contained in 56.0 mL of a 2.40 M solution of 1 point
NaOH in water? (**Use only numerical answers with 3 significant figures.
The units are given in the question.)
Your answer

Answers

Answer:

1.34 mol

Explanation:

Molarity, which is the molar concentration of a solution, can be calculated by dividing the number of moles (n) by the volume (V).

That is;

Molarity (M) = n/V

According to the information provided in this question;

M = 2.40M

V = 56.0 mL = 56/1000 = 0.056 L

Since molarity = n/V

number of moles = M × V

n = 0.056 × 24

n = 1.34 mol

all metals rust please answer false or true​

Answers

Answer:

True

Explanation:

All metals do rust but at different rates. Gold, platinum, and silver can rust if but at different rates. It can take time for it to rust, if you clean your metals, it won't rust, it'll take awhile before it rusts if you keep cleaning them.

Hopefully this helps :3 sorry if wrong :( plz mark brainiest if correct :D your bootiful/handsome! Have a great day luv <3

-Bee~

What material would make the most efficient hot pack?

●Lithium Chloride
●Sodium Chloride
●Sodium Hydroxide
●Potassium Chloride​

Answers

Answer:

Lithium Chloride would be the best one

Sodium Hydroxide would be the second best

Explanation:

Do nitrates always form precipitates?

Answers

Answer:

Nitrates compared to sulphates are much more soluble therefore won't form precipitates easily.

1. What volume of a 2.50M Kl(aq) is needed to make 200 ml of a 1.OOM KI)aq)?

Answers

Answer:

80 ml

Explanation:

From the question,

Applying Dilution formular

MV = mv................... Equation 1

Where M = Molarity of Kl before dilution, V = Volume of Kl before dilution, m = molarity of Kl after dilution, v = volume of Kl after dilution.

make V the subject of the equation

V = mv/M............. Equation 2

Given: m = 1.00 M, v = 200 ml, M = 2.50 M

Substitute these values into equation 2

V = (1.00×200)/2.50

V = 80 ml

If an equilibrium mixture of the three gases at 600K contains 2.92*10^-2 M COCH(g) and 1.76*10^2 M CO, what is the equilibrium
concentration of Cl2?

Answers

Answer:

C

Explanation:

What is the entropy of this collection of training examples with respect to the positive class B. What are the information gains of A1 and A2 relative to the training dataset For A3, which is a continuous attribute, compute the information gain for every possible split. C. What is the best split (among A1,A2, and A3) according to the information gain

Answers

The data set is missing in the question. The data set is given in the attachment.

Solution :

a). In the table, there are four positive examples and give number of negative examples.

Therefore,

[tex]$P(+) = \frac{4}{9}$[/tex]   and

[tex]$P(-) = \frac{5}{9}$[/tex]

The entropy of the training examples is given by :

[tex]$ -\frac{4}{9}\log_2\left(\frac{4}{9}\right)-\frac{5}{9}\log_2\left(\frac{5}{9}\right)$[/tex]

= 0.9911

b). For the attribute all the associating increments and the probability are :

  [tex]$a_1$[/tex]   +   -

  T   3    1

  F    1    4

Th entropy for   [tex]$a_1$[/tex]  is given by :

[tex]$\frac{4}{9}[ -\frac{3}{4}\log\left(\frac{3}{4}\right)-\frac{1}{4}\log\left(\frac{1}{4}\right)]+\frac{5}{9}[ -\frac{1}{5}\log\left(\frac{1}{5}\right)-\frac{4}{5}\log\left(\frac{4}{5}\right)]$[/tex]

= 0.7616

Therefore, the information gain for [tex]$a_1$[/tex]  is

  0.9911 - 0.7616 = 0.2294

Similarly for the attribute [tex]$a_2$[/tex]  the associating counts and the probabilities are :

  [tex]$a_2$[/tex]  +   -

  T   2    3

  F   2    2

Th entropy for   [tex]$a_2$[/tex] is given by :

[tex]$\frac{5}{9}[ -\frac{2}{5}\log\left(\frac{2}{5}\right)-\frac{3}{5}\log\left(\frac{3}{5}\right)]+\frac{4}{9}[ -\frac{2}{4}\log\left(\frac{2}{4}\right)-\frac{2}{4}\log\left(\frac{2}{4}\right)]$[/tex]

= 0.9839

Therefore, the information gain for [tex]$a_2$[/tex] is

  0.9911 - 0.9839 = 0.0072

[tex]$a_3$[/tex]     Class label      split point       entropy        Info gain

1.0         +                        2.0            0.8484        0.1427

3.0        -                         3.5            0.9885        0.0026

4.0        +                        4.5            0.9183         0.0728

5.0        -

5.0        -                        5.5            0.9839        0.0072

6.0        +                       6.5             0.9728       0.0183

7.0        +

7.0        -                        7.5             0.8889       0.1022

The best split for [tex]$a_3$[/tex]  observed at split point which is equal to 2.

c). From the table mention in part (b) of the information gain, we can say that [tex]$a_1$[/tex] produces the best split.

What are the products for

Answers

Answer:

[tex]ZnCO_3(s)+2KNO_3(aq)[/tex]

Explanation:

Hello there!

In this case, for the referred reactants side, we can evidence that this is a double displacement reaction whereby Zn gets bonded with CO3 and therefore K gets bonded with NO3 to yield:

[tex]Zn(NO_3)_2+K_2CO_3\rightarrow ZnCO_3+2KNO_3[/tex]

Whereas the KNO3 product is aqueous and the ZnCO3 is solid due to the corresponding solubility rules. Thereby, the answer is the third one.

Regards!

The solubility of a solid in a liquid generally increases with increase temperature.

True
Or
False

Answers

Answer:

False, Solubility increases with temperature for most solids.

Explanation:

What type of Weathering is important to sand storms on Mars? Physical or
Chemical?

Why would 3D printing be important on Mars and why would you use material from the surface of Mars.

We could "print" things that we need on Mars.
We could print things that we need on Mars and use material that is already on the planet
It would be so cool
The cost would be less expensive.

Answers

Answer:

1. Physical Weathering

2. Option B

Explanation:

1. Physical weathering

On Mars, there are two types of weathering agents a) wind and b) acid fog. Thus, they will carry out only physical weathering

2. Option B

3D can be used to produce things that are required on the Mars and also the locally available raw material can be used for printing thereby saving the cost.

Iron has a density of 7.87 g/cm^3. What is the mass of 55.2 cm^3 of iron?

Answers

Answer:  Formula: Mass = (Volume)(Density)

Iron Density = 7.87 g/cm^3

Volume of Iron = 55.2 cm^3

Mass=(V)(D)

Mass= (55.2 cm^3) x (7.87 g/cm^3)

Mass=  434,42 g

Explanation:

Iron has a density of 7.87 g/cm³. 434,42 g is the mass of 55.2 cm³ of iron.

What do you mean by density ?

The term density is defined as the measurement of how closely a material is packed together.

It is also defined as the mass per unit volume. Density Symbol is D or ρ Density Formula is ρ = m/V, where ρ is the density, m is the mass of the object and V is the volume of the object.

Density is an important because it allows us to find out what substances will float and what substances will sink when placed in a liquid.

Formula:

Mass = (Volume)(Density)

Given:

Iron Density = 7.87 g/cm³

Volume of Iron = 55.2 cm³

Mass=(V)(D)

Mass= (55.2 cm³) x (7.87 g/cm³)

Mass= 434,42 g

Thus, Iron has a density of 7.87 g/cm³. 434,42 g is the mass of 55.2 cm³ of iron.

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What is the speed of sound in dry air at 20°C?

Answers

343 meters per second


A gas occupies a volume of 2.4 L at 0.14 ATM. What volume will the gas occupy at 0.84 ATM?

Answers

Answer:

0.4 L

Explanation:

Calculate by using Boyle's Law P₁V₁=P₂V₂

(0.14atm)(2.4L) = (0.84atm)(V₂)

0.336 atmL = (0.84atm)(V₂)

V₂ = 0.336 atmL/0.84atm

V₂ = 0.4 L

arrange the following group of atoms in order of increasing atomic size:B,Al,Ga​

Answers

Answer:

Al,Ga,B

Explanation:

Now since i helped you can you help me with this plz

Matteo took 5 math quizzes. The mean of the 5 quizzes was 8.2. Here are four of his quiz scores 7, 7, 8, 10. What is the 5th quiz score? Show work.

Boron ( B )

Aluminium ( Al )

Gallium ( Ga )

Can tell the answer pls

Answers

Explanation: where the article????

From these four cycles which are water cycle, carbon cycle, nitrogen cycle, and phosphorus cycle which cycle has more nutrients

Answers

Answer:

Nitrogen cycle

Explanation:

Why does a red object appear red?
O A. It reflects light of wavelengths other than red.
OB. It absorbs light of red wavelengths.
O C. It absorbs light of wavelengths other than red.
O D. It reflects infrared radiation.
Right answers only for brainly

Answers

Answer:

Objects appear different colours because they absorb some colours (wavelengths) and reflected or transmit other colours. ... For example, a red shirt looks red because the dye molecules in the fabric have absorbed the wavelengths of light from the violet/blue end of the spectrum

A red object appear red because it absorbs light of wavelengths other than red. Therefore, option C is correct.

What is wavelength ?

The distance between identical points (adjacent crests) in adjacent cycles of a waveform signal propagated in space or along a wire is defined as the wavelength. This length is typically specified in wireless systems in meters (m), centimeters (cm), or millimeters (mm) (mm).

A transverse wave's wavelength is defined as the distance between two adjacent crests. A longitudinal wave's wavelength can be calculated as the distance between two adjacent compressions.

The wavelengths that are reflected or transmitted are what we see as colors. A red shirt, for example, appears red because the dye molecules in the fabric have absorbed light wavelengths from the violet/blue end of the spectrum. The only light reflected from the shirt is red light.

Thus, option C is correct.

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most sedimentary rock forms in the ocean.This is because oceans-​

Answers

Answer:

Explanation:

are where most bits of broken rock are deposited.

This is because oceans are where most bits of broken rock are deposited.

The pressure can be increased by doing what?
A)increasing the force and decreasing the area
B)increasing the force and increasing the area
C)decreasing the force and increasing the area
D)none of the above

Answers

A) increasing the force and decreasing the area

Show the equation you will use to calculate the volume of 1 M Cu(NO3)2 (aq) needed to prepare a set of solutions that have concentrations in the range of 1 M to 1x10-4 M in a 10-mL volumetric flask. Write the reduction half-cell reaction for the copper(II) ion. What is the standard potential for an electrochemical cell that is prepared from a copper half-cell and a zinc half-cell

Answers

Answer:

Explanation:

The equation we use to calculate the volume needed to prepare other [tex](C_1,V_1)[/tex] the solution that has a concentration [tex]C_2[/tex]  and volume [tex]V_2[/tex]  is:

[tex]C_1V_1 =C_2V_2[/tex]

[tex]V_1=\dfrac{C_2V_2}{C_1}[/tex]

where;

[tex]C_1[/tex]= concentration of the first solution

[tex]V_1[/tex] = volume of the first solution

[tex]C_2[/tex] = concentration of the second solution

[tex]V_2[/tex] = volume of the second solution

2) Reduction half cell reaction for the copper (II) ion is:

[tex]Cu^{2+} + 2e^- \to Cu[/tex]

3) [tex]Cu^{+2} + 2e^- \to Cu \text{ \ \ \ E = 0.3370}[/tex]

[tex]Zn^{+2} + 2 e^- \to Zn \ \ \ \ \ \ E = -0.763[/tex]

[tex]Zn \to Zn^{+2} + 2 e^- \ \ \ \ \ \ E = +0.763[/tex]

Since the reduction potential of Cu is more; it means copper will go into reduction and zinc will undergo oxidation.

Standard Potential =[tex]E^0_{left} - E^0_{right}[/tex]

[tex]= -0.763 -0.337[/tex]  ( since both are reduction potential)

[tex]\mathbf{E^0_{cell} = -1.100 volt}[/tex]

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