Steam
To save money for his daughter's college tuition, All Invests $250 every quarter in an annuity that pays 6.2% Interest, compounded quarterly
Payments will be made at the end of each quarter. Find the total value of the annuity in 22 years
Do not round any intermediate computations, and round your final answer to the nearest cent. If necessary, refer to the list of financial formulas

Answer:

B

Step-by-step explanation:

Answer:

22:2, 55:5, 1:11

Step-by-step explanation:

Answer:

22:2 55:5 and no others

Step-by-step explanation:

Answer:

Hello!!! Princess Sakura here ^^

Step-by-step explanation:

The answer to [tex]2^{5} *3^{2} *5[/tex] is 1440.

I believe she is correct because 1440 can be divided by another number without any remainders.

Step-by-step explanation:

7y=4x-5

y=(4/7)x-5/7

slope is equal to m where m is

y=mx+b

in this case m is 4/7

so slope =4/7

Answer:

y-2x -8

Step-by-step explanation:

your jus gonna right it back because it's parallel which means it's the same thing.

Since Kyle invested $500 and received $650 after three years, the value of Kyles's interest rate is 43.3%.

Given the following data:

To calculate the value of Kyles's interest rate:

Mathematically, simple interest is given by the formula:

[tex]S.I = \frac{PRT}{100}[/tex]

Where:

Making R the subject of formula, we have:

[tex]R = \frac{100S.I}{PT}[/tex]

Substituting the given parameters into the formula, we have;

[tex]R = \frac{100 \times 650}{500 \times 3}\\\\R = \frac{65000}{1500}[/tex]

Interest rate, R = 43.3%

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Answer:

21.97025026/250

Answer:

0

Step-by-step explanation:

Order of operation:

P-parenthesis

E-exponents

M-multiplication

D-division

A-addition

S-subtraction

Follow this order of operation in order.

If there are parenthesis when solving an equation, do the parenthesis first, if there are exponents and multiplication, do exponents before you do multiplication.

14 + 5(-3) + 1

Multiply 5 * -3

14 + -15 + 1

Add 14 + (-15)

-1 + 1

Add -1 + 1

0

Hope this helps and pls do mark me brainliest:)

Answer:

0

I hope this helps!

Answer:

[tex]\mathbf{y(x) = \dfrac{(c_1 + c_2) \ cos (x)}{e^{6x} }+ \dfrac{i(c_1 -c_2) \ sin (x)}{e^{6x}}+ c_3e^{3\ x}}[/tex]

Step-by-step explanation:

The objective of this question is to solve:

[tex]\dfrac{dy(x)}{dx}+ 9\dfrac{d^2y(dx)}{dx^2}+\dfrac{d^3y(x)}{dx^3}-111y(x) = 0 :[/tex]

Suppose the general solution is proportional to [tex]e^{\lambda x}[/tex] for [tex]\lambda[/tex] is constant; Then:

Let's replace [tex]y(x) = e^{\lambda\ x}[/tex] into the above equation:

i.e.

[tex]\dfrac{d^3}{dx^3}(e ^{\lambda x} )+ 9 \dfrac{d^2}{dx^2}(e ^{\lambda x} ) + \dfrac{d}{dx}(e ^{\lambda x} )- 111 \ e ^{\lambda x} = 0[/tex]

To Replace:

[tex]\dfrac{d^3}{dx^3}(e ^{\lambda x} )[/tex] with [tex]\lambda^3 e ^{\lambda x }[/tex]

[tex]\dfrac{d^2}{dx^2}(e ^{\lambda x} ) \ with \ \lambda^2 e^{\lambda\ x}[/tex]

[tex]\dfrac{d}{dx}(e ^{\lambda x} ) \ with \ \lambda e ^{\lambda \ x}[/tex]

Thus;

[tex]\lambda^3 e ^{\lambda x }[/tex] + [tex]9 \lambda^2 e^{\lambda\ x}[/tex] + [tex]\lambda e ^{\lambda \ x}[/tex] - 111 [tex]e ^{\lambda \ x}[/tex] = 0

[tex]e ^{\lambda \ x} (\lambda ^3 + 9 \lambda ^2 + \lambda - 111 )= 0[/tex]

∴

In as much as [tex]e^{ \lambda x}\neq 0[/tex] for any finite [tex]\lambda[/tex]; Then:

[tex]\lambda ^3 + 9 \lambda ^2 + 111 = 0[/tex]

By Factorization:

[tex](\lambda - 3) ( \lambda ^2 + 12 \lambda + 37) = 0[/tex]

[tex]\lambda = -6 + i \ or\ \lambda = -6 - i \ or \ \lambda = 3[/tex]

However;

The root [tex]\lambda = -6 \pm i[/tex] yield;

[tex]y_1 = (x) = c_1 e ^ {(-6+i)x}[/tex]

[tex]y_2 (x) = c_2e^{(-6-i)x}[/tex]

The root [tex]\lambda = 3[/tex] yield;

[tex]y_3(x) = c_3 e^{3x}[/tex]

∴

The general solution is:

[tex]y(x) = y_1(x) + y_2(x) + y_3(x) = \dfrac{c_1}{c^{(6-i)}x}+\dfrac{c_2}{c^{(6+i)}x}+ c_3e^{3x}[/tex]

Using Euler's Identity ;

[tex]e^{\alpha+i \beta} = e^\alpha \ cos (\beta ) + i \ e^\alpha \ sin ( \beta)[/tex]

[tex]y(x) = c_1 ( \dfrac{cos (x) }{e^{6x}}+ \dfrac{i \ sin x }{e^{6x} }) + c_2 ( \dfrac{cos (x)}{e^{6x}}- \dfrac{-i \ sin (x)}{e^{6x}})+c_3 e^{3x}[/tex]

[tex]\mathbf{y(x) = \dfrac{(c_1 + c_2) \ cos (x)}{e^{6x} }+ \dfrac{i(c_1 -c_2) \ sin (x)}{e^{6x}}+ c_3e^{3\ x}}[/tex]

Answer:

x=12

Step-by-step explanation:

multiply 2 from both sides to isolate x

then u should end up with 1x=12

Answer:

This is what internet says. Maybe this helps.

Answer:

-3.21

Step-by-step explanation:

If you pay close attention the numbers are 5 points away from each other, so after -3.2 is -3.21! Hope that helped love :)

Answer:

270 miles and 180 minutes

Step-by-step explanation:

Answer:

The answer is 11

hence 5 + 6 = 11

Answer:

hi

Step-by-step explanation:

[tex]5 + 3(2) = 11[/tex]

probably…

Answer:

x=20°

Step-by-step explanation:

1.) m<DOB = m<DOE + m<BOE (or m<EOB)    

2.) m<DOB = 90°+x

3.) m<AOC = m<DOB

4.) 110° = 90° + x

5.) x = 20°

1.) given

2.) substitution

3.) vertical/reflexive

4.) substitution

5.) algebra

The possible third side to a triangle is 12.

Given that,

Based on the above information, the calculation is as follows:

Here we use the pythagoras theorem.

[tex]= \sqrt{13^2 - 4^2} \\\\= \sqrt{169-16} \\\\= \sqrt{153}[/tex]

= 12.37

= 12

Learn more: brainly.com/question/17429689

Subtract the [tex]x^2[/tex] terms from each other, then the [tex]x[/tex] terms, then the ones without any [tex]x[/tex] whatsoever.

[tex](12x^2 - 8x + 12) - (9x^2 +22x-46)[/tex]

First, we'll subtract [tex]9x^2[/tex] from [tex]12x^2[/tex]

[tex]12x^2-9x^2- = 3x^2[/tex]

Result: [tex]3x^2[/tex]

Next, we'll subtract [tex]22x[/tex] from [tex]-8x[/tex]

[tex]-8x - 22x = -30x[/tex]

Result: [tex]-30x[/tex]

Finally, we'll subtract [tex]-46[/tex] from [tex]12[/tex]

[tex]12-(-46) = 12+46 = 58[/tex]

Result: [tex]58[/tex]

Now, we can add these 3 results together.

First, we had [tex]3x^2[/tex], then [tex]-30x[/tex], and finally [tex]58[/tex].

Thus, our subtraction of

[tex](12x^2 - 8x + 12) - (9x^2 +22x-46)[/tex]

equals

[tex]3x^2-30x+58[/tex]

Answer:

11.8% Decrease

Step-by-step explanation:

I googles it i am sorry if it's not right

Answer:

Step-by-step explanation:

13/16 dived by 5/6 = 9/40

7 dived by 1/6 = 42

2 1/5 dived by 1 1/3 = 1 13/20

2 1/7 dived by 3/28 = 20

1280 cones because you would add 60 +4 and multiply by 20, and would get 1280 cones.

Answer:

x = 39

Step-by-step explanation:

A circle is made up of 360 degrees

235+ 54+ x+32 = 360

Combine like terms

x+321=360

Subtract 321 from each side

x+321-321 = 360-321

x = 39

9514 1404 393

Answer:

  31

Step-by-step explanation:

The relationship between sides and the sum of angles is ...

  sum of angles = (sides - 2)·180°

Filling in the given value and solving for "sides", we get ...

  5220 = (sides -2)180

  29 = sides -2 . . . . . . . . . divide by 180

  31 = sides . . . . . . . . . . . . add 2

The polygon has 31 sides.

Answer:

31

Step-by-step explanation:

5220/180=29+2=31

Answer:

Not 100% sure on this make sure you double check

Step-by-step explanation:

X- 10          

Y- 10

Slope- (-1)

like I said this could be wrong  

Answer:

As

Step-by-step explanation:

Aaa

Answer:

bout 7

Step-by-step explanation:

Answer:3.049533e+44 to be exact

Step-by-step explanation:

Answer:

-

Step-by-step explanation:

I took the test

The correct operator that enters a circle is a subtraction sign.

Given the expressions

[tex](4x^5-8x) ()(3x^2-8x+9)[/tex]

We need to know which sign goes into the bracket that will give a trinomial when simplified.

A trinomial is a function containing 3-terms.

Using the subtraction sign.

[tex](4x^5-8x) - (3x^2-8x+9)[/tex]

Expand

[tex]= 4x^5-8x - 3x^2+8x-9\\= 4x^5-3x^2-8x+8x-9\\=4x^5-3x^2+0-9\\=4x^5-3x^2-9[/tex]

Since the resulting term is a trinomial (3 terms), hence the correct operator that enters a circle is a subtraction sign.

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Answer:

70 is the answer to the question

Answer:

[tex]70^{o}[/tex]

Step-by-step explanation:

Opposite angles in a parallelogram are equal. The opposite angle to A is C and we are trying to find angle C. Therefore, <C = <A, therefore, <c= 70 degrees

It's easier to eliminate x because when you add both equations -4x +4x would be zero