Answer:
C7H6O2
Explanation:
Let;
68.8% of Carbon represents 68.8g
4.95% of Hydrogen represents 4.95g
26.25% of Oxygen represent 26.25g
Next, we convert each gram value to mole value by dividing by their respective molar mass {C = 12, H = 1, O = 16}
C = 68.8/12 = 5.73 mol
H = 4.95/1 = 4.95 mol
O = 26.25/16 = 1.64 mol
Next, we divide each mole value by the smallest (1.64mol)
C = 5.73 ÷ 1.64 = 3.49
H = 4.95 ÷ 1.64 = 3.02
O = 1.64 ÷ 1.64 = 1
Next, we multiply each ratio by 2 to obtain our simplest whole number ratio (empirical formula)
C = 3.5 × 2 = 7
H = 3.02 × 2 = 6
O = 1 × 2 = 2
Hence, the ratio of C, H and O is 7:6:2 and the empirical formula of benzoic acid is C7H6O2
How can I express the composition of a solution?
Answer:
It can be expressed in several ways: molarity (moles of solute per liter of solution); mole fraction, the ratio of the number of moles of solute to the total number of moles of substances present; mass percentage, the ratio of the mass of the solute to the mass of the solution times 100; parts per thousand (ppt), grams ...
Explanation:
It can be expressed in several ways: molarity (moles of solute per liter of solution); mole fraction, the ratio of the number of moles of solute to the total number of moles of substances present; mass percentage, the ratio of the mass of the solute to the mass of the solution times 100; parts per thousand (ppt), grams ...
8. Of what importance is a smoker to a person keeping bees?
Answer:
they help to calm the bees when the person keeping the bees inspects there hives.
If I add 25mL of water to 125 mL of 0.25 M NaOH solution, what will the molarity of the diluted solution be?
Answer:
0.208333 M
Explanation:
M2=M1V1/V2=(0.25 M)(125mL)/(125mL+25 mL)= 0.208333 M
The acidic ingredient in vinegar is acetic acid. The pH of vinegar is around 2.4, and the molar concentration of acetic acid in vinegar is around 0.85 M. Based on this information, determine the value of the acid ionization constant, Ka, for acetic acid.
Answer: The value of acid ionization constant [tex]K_a[/tex] for acetic acid is [tex]1.87\times 10^{-5}[/tex]
Explanation:
[tex]CH_3COOH\rightarrow H^+CH_3COO^-[/tex]
cM 0 0
[tex]c-c\alpha[/tex] [tex]c\alpha[/tex] [tex]c\alpha[/tex]
So dissociation constant will be:
[tex]K_a=\frac{(c\alpha)^{2}}{c-c\alpha}[/tex]
Give c= 0.85 M and [tex]pH[/tex] = 2.4
[tex]pH=-log[H^+][/tex]
[tex][H^=}=c\times \alpha=10^{-2.4}=3.98\times 10^{-3}[/tex]
[tex]K_a=?[/tex]
Putting in the values we get:
[tex]K_a=\frac{(3.98\times 10^{-3})^2}{(0.85-3.98\times 10^{-3})}=1.87\times 10^{-5}[/tex]
Thus the value of acid ionization constant [tex]K_a[/tex] for acetic acid is [tex]1.87\times 10^{-5}[/tex]
One major problem with wind and solar energy is that they are conditional. Explain how hydroelectric pumped storage could be used to eliminate this
obstacle? *
Link to the article https://thinkprogress.org/the-inside story-of-the-worlds-biggest-battery-and-the-future-of-renewable-energy-8984c81283c/
Answer:
Hydroelectric pumped storage can be used to eliminate the conditional nature of wind and solar energy. At times of peak production of energy from either solar or wind (during summer and windy days), the excess electrical energy produced can be stored using hydroelectric pumped storage methods. When conditions no longer favour energy production from either wind or solar sources, these stored energy can then be regenerated for use.
Explanation:
Pumped-storage hydroelectricity is a type of hydroelectric energy storage used by electric power systems to store excess electrical power during periods of low demand for later release at periods when demand for energy rises again. It stores energy in the form of gravitational potential energy of water, pumped from a lower level reservoir to a higher level reservoir.
At times of low electrical demand, excess generated energy is used to pump water into the upper reservoir. When there is higher demand, water is released back into the lower reservoir through a turbine, generating electricity.
This form of energy storage is useful in circumventing the conditional nature of renewable energy sources such as wind and solar energy. At times of peak production of energy from either solar or wind (during summer and windy days), the excess electrical energy produced can be stored using hydroelectric pumped storage methods. When conditions no longer favour energy production from either wind or solar sources, these stored energy can then be regenerated for use.