Based on your data, what is the experimental probability that the family has two dogs or two cats? (Heads= dogs and tails=cats)

My table:

Heads, Heads
15
Heads, Tails
9
Tails, Heads
16
Tails, Tails
10
Total
50
Also, please explain your answer.

Answers

Answer 1

Answer:

Two dogs: 30%

Two cats: 20%

Two dogs OR two cats: 50%

Step-by-step explanation:

Since the total is 50, we have to multiply all the numbers by two. The total will then 100, so one unit in each category will represent one percent. For example, 15 x 2 = 30, so the chance for two dogs is 30%.

If your question meant two dogs OR two cats as a single probability - not the individual probabilities of two dogs and two cat - then it is 50%, because 30 (two dogs) + 20 (two cats) = 50 (two dogs OR cats). I hope this helps! Sorry if my explanation doesn’t make lots of sense, I’m typing this off my phone. Feel free to ask any questions!


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Answer:

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What is the result when 3/8x + 2 1/5 is subtracted from 3 1/2x - 4 1/10?

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Answer:

Option 3 3 1/8x - 6 3/10

Step-by-step explanation:

(3 1/2x - 4 1/10) - (3/8x + 2 1/5)

Divide it into parts:

(3 1/2x - 3/8x) + (-4 1/10 - 2 1/5)

3 1/2x - 3/8x = 3 4/8x - 3/8x = 3 1/8x

-4 1/10 - 2 1/5 = -4 1/10 - 2 2/10 = -6 3/10

So we get:

2 1/4x - 6 3/10

trying to cheat on a performance matter test but the answer is the last one -3 1/8 x + 6 3/10