banana with an average mass of 0.15 kg and average specific heat of 3.35 kJ/kg · °C is cooled from 20°C to 5°C. The amount of heat transferred from the banana is

a.
62.1 kJ

b.
7.5 kJ

c.
None of these

d.
6.5 kJ

e.
0.85 kJ

f.
17.7 kJ

Answers

Answer 1

Answer:

The amount of heat transferred from the banana is (-)7.54 KJ

Explanation:

As we know,

[tex]Q = m*c*\Delta T[/tex]

Q = Amount of heat transferred

m = mass of banana

[tex]T_2 = 5[/tex] degree Celsius

[tex]T_1 = 20[/tex] degree Celsius

The amount of heat transferred from the banana =

[tex]0.15 * 3.35 * (5 -20)\\-7.54[/tex]KJ (negative sign represents reduction in heat energy)


Related Questions

If it took a 30m capacity tank mediated by 2cm waterproof water faucet for 10 hours, calculate the flow speed (exit) water from the

Answers

Complete question:

If it took a 30m³ capacity tank mediated by 2cm waterproof water faucet for 10 hours, calculate the flow speed (exit) of water from the tank.

Answer:

the flow rate of the water from the tank is 0.05 m³/min

Explanation:

Given;

volume of water in the tank, v = 30 m³

length of the waterproof faucet, L = 2cm = 0.02 m

duration of water flow through the tank, t = 10 hours

The flow rate of the water from the tank is calculated as;

[tex]Q = \frac{V}{t} = \frac{30 \ m^3}{10\ h \ \times \ 60 \min} = 0.05 \ m^3/ \min[/tex]

Therefore, the flow rate of the water from the tank is 0.05 m³/min

This is the top part of the picture. I need someone to put the correct letter by the word !

Answers

Answer:

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Explanation:

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