Answer:
Follows are the solution to this question:
Explanation:
In Time = 22:
The P5 and P8 are in the ready/running state, and the P1, P3, P7 are into the block state for Input/output.
In Time = 37:
The P1, P3, P8 are in the ready/running state, P5 is in the block state. It suspends or swapped out, and P7 is on the block state for Input/output.
In Time= 47:
The P1, P3, and P5 are in the ready/running state, P7 is on the block state for Input/output, and P8 is in the exit state.
Can someone tell me why this code in Java won't run?
if (s.toLowerCase().equals(s.toUpperCase()))
{
System.out.println("*");
}
Answer:
try typing the following:
String lc = s.toLowerCase();
String uc = s.toUpperCase();
if(lc == uc){
System.out.println("*")
}
Write a program with a car's miles/gallon and gas dollars/gallon (both floats) as input, and output the gas cost for 10 miles, 50 miles, and 400 miles. Ex: If the input is 20.0 3.1599, the output is: 1.57995 7.89975 63.198 Note: Small expression differences can yield small floating-point output differences due to computer rounding. Ex: (a + b)/3.0 is the same as a/3.0 + b/3.0 but output may differ slightly. Because our system tests programs by comparing output, please obey the following when writing your expression for this problem. First use the dollars/gallon and miles/gallon values to calculate the dollars/mile. Then use the dollars/mile value to determine the cost per 10, 50, and 400 miles. Note: Real per-mile cost would also include maintenance and depreciation.
Answer:
The Following are the code to this question:
def cost(miles, milesPerGallon, dollarsPerGallon):##defining a method cost that accepts three parameter
return miles / milesPerGallon * dollarsPerGallon# calculate cost and return it value
milesPerGallon = float(input('Enter miles/Gallon value: '))#defining variable milesPerGallon for user input
dollarsPerGallon = float(input('Enter dollars/ Gallon value: '))#defining variable dollarsPerGallon for user input
print('{:.5f}'.format(cost(10, milesPerGallon, dollarsPerGallon)))#call method and print its value
print('{:.5f}'.format(cost(50, milesPerGallon, dollarsPerGallon)))#call method and print its value
print('{:.3f}'.format(cost(400, milesPerGallon, dollarsPerGallon)))#call method and print its value
Output:
Enter miles/Gallon value: 20.0
Enter dollars/ Gallon value: 3.1599
1.57995
7.89975
63.198
Explanation:
In the above-given code, a method "cost" is defined, that accepts three value "miles, milesPerGallon, and dollarsPerGallon" in its parameter, and use the return keyword for calculating and return its value.
In the next step, two variable "milesPerGallon, and dollarsPerGallon" is declared, that use the input method with float keyword for input floating-point value.
After input value, it uses a print method with different miles values, which are "10,50, and 400", and input value to pass in cost method to call and print its return value.
Why are floppy disks obsolete ?
Answer:
they don't have enough space on them to carry useful information, and because most computers no longer have a drive for them. This is true for most legacy items
Adding a rock or stone looking characteristic to a background is which element of design?
Answer:
Explanation:
ejhdkl;xs
'
Choose the terms that best complete the sentence.
For users to be able to communicate with a large number of other people around the world, their
___needs to be connected to a_____
which has
an almost unlimited geographical distance.
Answer: For users to be able to communicate with a large number of other people around the world, their LAN needs to be connected to a WAN, which has an almost unlimited geographical distance.
Explanation: Correct on Edg 2020/2021.
The Beaufort Wind Scale is used to characterize the strength of winds. The scale uses integer values and goes from a force of 0, which is no wind, up to 12, which is a hurricane. The following script first generates a random force value. Then, it prints a message regarding what type of wind that force represents, using a switch statement. You are to rewrite this switch statement as one nested 150 CHAPTER 4: Selection Statements if-else statement that accomplishes exactly the same thing. You may use else and/or elseif clauses.
ranforce = randi([0, 12]); switch ranforce case 0 disp('There is no wind') case {1,2,3,4,5,6} disp('There is a breeze') case {7,8,9} disp('This is a gale') case {10,11} disp('It is a storm') case 12 disp('Hello, Hurricane!') end
Answer:
ranforce = randi([0, 12]);
if (ranforce == 0)
disp('There is no wind')
else if(ranforce>0 && ranforce <7)
disp('There is a breeze')
else if(ranforce>6 && ranforce <10)
disp('This is a gale')
else if(ranforce>9 && ranforce <12)
disp('It is a storm')
else if(ranforce==12)
disp('Hello, Hurricane!')
end
Explanation:
Replace all switch case statements with if and else if statements.
An instance is:
case {7,8,9}
is replaced with
else if(ranforce>9 && ranforce <12)
All other disp statements remain unchanged
what are the steps to troubleshoot a frozen computer
The trigonometry book says: sin^2(t) + cos^2(t) = 1 Write a Python program that verifies the formula with the help of the Python Math module. Note that the trigonometric functions in the module act on the angles in radians. Your program should perform the following steps 3 times: 1. Pick a random number between 0 and 180 degrees representing an angle in degrees, say Dangle 2. Convert the angle from degrees to radians, say Rangle 3. Use the Math module to find and print the values of sin(Rangle) and cos(Rangle), and 4. Compute and print the value of the above expression: sin^2(Rangle) + cos^2(Rangle). You can then visually verify if the result printed is 1 (or close to it).
Answer:
If you open your python-3 console and execute the following .py code you will have the following output. (Inputing 20 e.g)
Write the angles in degrees: 20
radian angles is: 0.3490658503988659
cosene( 0.3490658503988659 ) = 0.9396926207859084
sine( 0.3490658503988659 ) = 0.3420201433256687
sin^2( 0.3490658503988659 ) + cos^2( 0.3490658503988659 ) = 1.0
Explanation:
Code
import math
for i in range(1,4):
angle = int(input('Write the angles in degrees: '))
#mat library better works with radians
angle_radians = (angle*math.pi)/180
#print output
print('radian angles is: ',angle_radians)
print('cosene(',angle_radians,') = ',math.cos(angle_radians))
print('sine(',angle_radians,') = ',math.sin(angle_radians))
res = (math.sin(angle_radians))**2 + (math.cos(angle_radians))**2
print('sin^2(',angle_radians,') + cos^2(',angle_radians,') = ',res)
Assume a 64KB cache with four-word block size (a word is 4 bytes) and a 32-bit address. If a block has 28 tag bits, what is the type of this cache
Answer:
Fully associative
Explanation:
Fully associative cache is a type of cache in which after retrieving the data from memory, it subsequently allows data to be deposited in the available but unused cache block. This is to ensure that the storage of cache is done without forcing each memory address into one specific block.
Given the following
address = 32 bits,
tag = 28 bits, as a block is 4 words that are, 4x4 bytes,
offset = 4 bits, which equates to index = 0 bits.
Hence, it can be concluded that the type of cache is FULLY ASSOCIATIVE.