Assume a density of water of 1.00 g/mL, and calculate the mass of water in the solution

Answers

Answer 1

Answer:

1g or 10^-3kg

Explanation:

as you know , the density =mass \volume

so  you have the mass from the number it self

[tex]\frac{1g}{1 ml}[/tex] so from this equation, you will get 1 g and you can to SI to be [tex]10^{-3}[/tex]kg

Related Questions

Pre-Lab Questions
Which of the following are considered matter?
electricity
fire
air
water

Answers

Answer:

Fire, Air, Water.

Explanation:

Matter is anything that has mass and occupies space. However, not all form of matter are visible. Air is an example of invisible matter.

Note, electricity does not have mass or does not occupy space. Therefore, electricity is not a matter.

Answer:

Fire, Air, Water

Explanation:

Electricity is the of charged particles conducting medium. However, it is the electrons that are matter, not their movement.

Matter is anything that has mass and occupies space. The flame itself is a mixture of gases and so is matter. The light and heat produced are energy not matter.

Like solids and liquids, air is matter. It has a weight and it takes up space.

Water is a liquid and liquids are one of the four fundamental states of matter.

Which relation is correct
E ᾳ ѵ
ѵ = c / λ
both are correct
none

Answers

Answer:

geruow0irghvn3p0unhie0ghik

Explanation:

to make a solute dissolve more quikly in a solvent wich whould you do? a. stir it in cold water b.stir it in warm water c.solvent d.lets the solute settle down d. nothing to do with the solute?​

Answers

Answer:

b.stir it in warm water

Explanation:

the slobility will be faster in the high temperture

Plz what’s the answer to this

Answers

Answer: E

Explanation:hope this helps you out

Write the balanced equation for the neutralization reaction between H3PO4 and NaOH in an aqueous solution.

Answers

Answer:

H3PO4 + 3NaOH ==> Na3PO4 + 3H2O

The balanced equation for the given reaction is [tex]3NaOH+H_3PO_4---- > Na_3PO_4+3H_2O[/tex]

What is neutralization reaction?

A chemical reaction in which an acid and a base react quantitatively with each other is known as neutralization.

In a water reaction, neutralization means that there is no excess of hydrogen or hydroxide ions in the solution.

A neutralization reaction occurs when an acid and a base react to form water and a salt through the combination of H+ ions and OH- ions. The pH of neutralization of a strong acid and a strong base is 7.

Three moles of sodium hydroxide are required for one mole of phosphoric acid. The balanced equation tells us the following: 1 mol of H3PO4 reacts with 3 mol of NaOH.

It can be written as

[tex]3NaOH+H_3PO_4---- > Na_3PO_4+3H_2O[/tex]

Thus, this is the balanced equation for the given neutralizing reaction.

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Suppose of sodium chloride is dissolved in of a aqueous solution of silver nitrate. Calculate the final molarity of chloride anion in the solution. You can assume the volume of the solution doesn't change when the sodium chloride is dissolved in it. Be sure your answer has the correct number of significant digits.

Answers

Suppose of sodium chloride is dissolved in of a aqueous solution of silver nitrate. Calculate the final molarity of chloride anion in the solution. You can assume the volume of the solution doesn't change when the sodium chloride is dissolved in it. Be sure your answer has the correct number of significant

What is the IUPAC name of this compound?  ________ CH3-CHCl-CH2-CH2-Cl​

Answers

Answer:

The prefixes are fluoro-, chloro-, bromo-, and iodo-. Thus CH 3CH 2Cl has the common name ethyl chloride and the IUPAC name chloroethane. Alkyl halides with simple alkyl groups (one to four carbon atoms) are often called by common names.05‏/06‏/2019

The IUPAC name of this compound is 2,3- dichlorobutane.

What is compound?

Compound is defined as a chemical substance made up of identical molecules containing atoms from more than one type of chemical element.

Molecule consisting atoms of only one element is not called compound.It is transformed into new substances during chemical reactions. There are four major types of compounds depending on chemical bonding present in them.They are:

1)Molecular compounds where in atoms are joined by covalent bonds.

2) ionic compounds where atoms are joined by ionic bond.

3)Inter-metallic compounds where atoms are held by metallic bonds

4) co-ordination complexes where atoms are held by co-ordinate bonds.

They have a unique chemical structure held together by chemical bonds Compounds have different properties as those of elements because when a compound is formed the properties of the substance are totally altered.

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Which process is shown in the diagram?
0,
ing
CO, +H,0
Chloroplast
Mitochondrion
Sugar
Heat
o
ATP
Respiration

Answers

I don’t see any diagram

The cellular respiration process, which generates ATP as the final result, employs oxygen and sugar as reactants. So, the correct option is A.

What is Cellular respiration?

Cellular respiration is the process by which organisms combine oxygen with food molecules, channeling the chemical energy from those resources into life-sustaining activities while eliminating carbon dioxide and water as waste.

Both oxygen and glucose are reactants in the mobile respiratory system. ATP is the primary component of mobile respiration; waste products include carbon dioxide and water.

Oxygen might be present or absent while cells are respiring. Nonetheless, the activity is essentially known as "cellular respiration" because the cell seems to "respire" by consuming molecular oxygen (as an acceptor of electron) and exhaling carbon dioxide (as an end product).

Therefore, the correct option is A.

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Your question is incomplete, most probably the complete question is:

The process shown in the diagram produces oxygen and sugar. Which

process uses oxygen and sugar as reactants?

Chloroplast

Mitochondrion

Sugar

CO, +H,0

ATP

Heat

Respiration

A. Cellular respiration

B. Water cycle

c. Transpiration

D. Photosynthesis

Now consider a sample of the gas at 33 deg C, 744 mm Hg, and 450 mL. If the pressure is decreased to 725 mm Hg and the temperature raised to 66C. What is the new volume of the gas? New volume =​

Answers

Answer:

V₂ =  511.59mL

Explanation:

Given data:

Initial volume = 450 mL

Initial pressure = 744 mmHg

Initial temperature = 33°C (33 +273 = 306 K)

Final temperature = 66°C (66+273 = 339 K)

Final pressure = 725 mmHg

Final volume =?

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 744 mmHg × 450 mL × 339 K / 306 K ×725 mmHg

V₂ = 113497200 mmHg .mL. K / 221850 K.mmHg

V₂ =  511.59mL

a human skull is ?????

Answers

Answer:

part of the skeleton that supports the structure of face and forms a cavity from bone.

Hope it help u.

Explanation:

hope it is helpful to you

How does temperature effect the molecules of a substance that is dissolved. ​

Answers

Explanation:

Generally, temperature increases the rate of any chemical reaction considerably.

In a dissolution process, the solute is solvated in the solvent. Solutes are usually the solids or liquids being dissolved in the solution.

When temperature increases, the average kinetic energy of the solvent molecules increase also. The indicator of the average kinetic energy in a body is heat. As molecules begins to move rapidly, it brings both the solvent and solute in contact faster with each other.

Demonstrate how you can prepare 250ml 0.25M hydrogen peroxide from a solution of 20g/100ml of hydrogen peroxide.​

Answers

To prepare 250 ml 0.25 M hydrogen peroxide, 10.63 ml of 20g/100 ml hydrogen peroxide has been taken and made up the volume to 250 ml.

The dilution of the sample can be prepared with the help of expression:

M1V1 = M2V2

M1 = molarity of the concentrated solution

V1 = volume of concentrated solution

M2 =  molarity of diluted solution

V2 = volume of diluted solution.

The molarity of concentrated solution has been:

Molarity = [tex]\rm \dfrac{weight}{molecular\;weight}\;\times\;\dfrac{1000}{Volume\;(ml)}[/tex]

The 20g/100 ml Hydrogen peroxide has molarity:

Molarity = [tex]\rm \dfrac{20}{34.0147}\;\times\;\dfrac{1000}{100}[/tex]

Molarity of Hydrogen peroxide = 5.879 M

The volume of 5.879 M hydrogen peroxide is required to prepare 0.25 M hydrogen peroxide has been:

Volume of Hydrogen peroxide (20g/100 ml) [tex]\times[/tex] 5.879 = 250 ml [tex]\times[/tex] 0.25 M

Volume of Hydrogen peroxide (20g/100 ml) = 10.63 ml.

To prepare 250 ml 0.25 M hydrogen peroxide, 10.63 ml of 20g/100 ml hydrogen peroxide has been taken and made up the volume to 250 ml.

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1. Is it possible to distinguish DNA and RNA structures by using Bial’s Test? Explain.

2. What are the functions of orcinol and FeCl3 in Bial’s Test.

Answers

Answer:

yes and thats all i know

Explanation:

How do the physical and chemical properties the halogens compare with those of the noble gases? ​

Answers

Explanation:

To form bonds with noble gases, a lot of energy is required to form those bonds. Halogens, on the other hand, are extremely reactive. ... The halogens tend to be very reactive, while the noble gases are in no way reactive and don't bond easily, if at all.

Dbdnsa sksksbs slashed djdheveje skeleton endings snslshsbsmsldi s dlddibslss hsos bask

3. Find
out the initial energy level (n) of an electron that results in the emi ssion of light of
wavelength 486 nm in the Balmer series?​

Answers

Answer:

4

Explanation:

The Balmer series refers to a series of spectral emission lines of the hydrogen atom arising from electronic transitions from any higher level and terminating at the the energy level n= 2.

Using the relation;

1/λ = 1.09737*10^7 (1/2^2 -1/n^2initial)

We now have;

1/486 *10^-9 = 1.09737*10^7 (1/2^2 -1/n^2initial)

0.1875 = 1/2^2 -1/n^2initial

1/n^2initial = 1/2^2 - 0.1875

1/n^2initial = 0.0625

n^2initial = 16

ninitial = 4

A car's fuel efficiency is 39.0 miles per gallon. What is its fuel efficiency in kilometers per liter? (1.6094 km=1 mile)(1 gallon=3.79 L)

Answers

Answer:

the fuel efficiency in kilometers per liter is 16.561 kilometer per liter

Explanation:

The computation of the full efficiency in kilometers per liter is shown below:

39.0 miles ÷ gallon = (39.0 miles ÷ gallon) × (1.6094 km ÷ 1 miles)  × (1 gallon ÷ 3.79 L)

Now cut the opposite miles and gallons

So, the fuel efficiency would be

= 16.561 kilometers per liter

Hence, the fuel efficiency in kilometers per liter is 16.561 kilometer per liter


22. Metallic compounds
a. are poor conductors of electricity
b. dissolve in water
c. have low melting points
d. can be hammered into sheets

Answers

B is the awnser to that question

What is the compound name for HgCl2

Answers

Answer:

Mercury Chloride

Explanation:

Trust me, this answer is correct.

Which of the following statements correctly describes the function of cell parts?

A. The cell membrane determines which type of cell will develop.
B. The nucleus contains all the nutrients that the cell needs.
C. The mitochondria are the power plants of the cell.
D. The genes contain hemoglobin.

Answers

The answer is c because mitochondria powers the cell it makes all the functions work

The statements correctly describes the function of cell parts is the mitochondria are the power plants of the cell. Therefore, option C is correct.

What do you mean by the mitochondria ?

The cytoplasm of a cell contains tiny structures (fluid that surrounds the cell nucleus). The majority of a cell's energy is produced by mitochondria, which also have unique genetic material distinct from that present in the nucleus.

Oxidative phosphorylation, which produces ATP using the energy generated during the oxidation of the food we ingest, is the traditional function of mitochondria.

For the majority of biochemical and physiological activities, including growth, mobility, and equilibrium, ATP is used as the main energy source in turn.

Thus, option C is correct.

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Calculate the internal energy of a system (in kiloJoules) that absorbs 14.73 kJ while being compressed with a pressure of 1.54 atm from 5.72 L to 1.0 L. Answer to one decimal space.

Answers

The internal energy of a system : 21.9 kJ

Further explanation  

The laws of thermodynamics 1 state that energy can be changed but cannot be destroyed or created  

The equation is:  

ΔU=Q+W    

Energy owned by the system is expressed as internal energy (U)  

The sign rules for heat and work are set as follows:  

• The system receives heat, Q +  

• The system releases heat, Q -  

• The system does work, W -  

• the system accepts work, W +  

The system absorbs 14.73 kJ⇒Q=+14.kJ

The system compressed⇒work done on the gas⇒W=+

W=-PΔV

[tex]\tt W=-1.54(1-5.720)\\\\W=7.2688[/tex]

[tex]\tt internal~energy(\Delta U)=Q+W\\\\\Delta U=14.73+7.2688\\\\\Delta U=21.9[/tex]

state the difference between spermatozoon and spermatogonium​

Answers

Answer:

spermatozoon:A spermatozoon is a motile sperm cell or moving from of the haploid cell that is the male gamete.

spermatogonium : A cell produced at an early stage in the formation of spermatozoa, formed in the wall of a seminiferous tuble and giving rise by mitosis to spermatocytes.

A compound of copper and sulfur contains 76.84 g of metal and 38.53 g of nonmetal. How many grams of copper are in 3801 kg of the compound? How many grams of sulfur?

Answers

Answer:

There are:

2'531,500 g Cu1'269,500 g S

Explanation:

First calculate the percentage of Cu and S in the compound:

Total mass = 76.84 g + 38.53 g = 115.37 g% metal (Cu) = 76.84/115.37 * 100% = 66.6%% metal (S) = 38.53/115.37 * 100% = 33.4%

These percentages will remain the same no matter how much of the compound we analyze.

Now we calculate the grams of Cu and S in 3801 kg of the compound:

kg Cu = 3801 kg * 66.6/100 = 2531.5 kg Cug Cu = 2531.5 kg * 1000 = 2531500 g Cukg S = 3801 kg * 33.4/100 = 1269.5 kg Sg S = 1269.5 kg * 1000 = 1269500 g S

how to do question no 17

Answers

Explanation:

even I don't know this answer

but maybe you can solve it by putting the formula

The energy level diagram shown below represents a fictional gas. What is the energy of a photon that would move an electron from level 2 to level 5?
A. 5.8 eV
B. 4.8 eV
C. 4.2 eV
D. 2.65 eV

Answers

The energy of a photon that would move an electron from level 2 to level 5 : B. 4.8 eV

Further explanation

The electron energy at the nth shell can be formulated:

En = -Rh / n²

Rh = constant 2.179.10⁻¹⁸ J

So the electron transfer energy (ΔE)

ΔE = E final- E initial

energy at n=2(level 2) = -5.3 eV

energy at n=5(level 5) = -0.5 eV

So the energy absorbed :

[tex]\tt \Delta E=-0.5-(-5.3)=-0.5+5.3=4.8`eV[/tex]

The energy required to move an electron from level 2 to level 5 is 4.8 eV.

According to the Bohr model of the atom, an electron moves from a lower to a higher energy level when it absorbs energy. The same energy is released when the atom returns to ground state.

When an electron from level 2 to level 5, the energy of the photon required is;

ΔE = E5 - E2 = -0.5eV - (-5.3eV)

ΔE = 4.8eV

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A competitive high school swimmer takes 56.7 seconds to swim 100. yards. What is his rate in m/min?

m

min

Answers

Answer:

96.72 m/min

Explanation:

The following data were obtained from the question:

Time (t) = 56.7 s

Distance (d) = 100 yard

Rate (R) =?

Next, we shall convert 56.7 s to minutes. This can be obtained as follow:

60 s = 1 min

Therefore,

56.7 s = 56.7 s × 1 min /60 s

56.7 s = 0.945 min

Next, we shall convert 100 yard to metre (m). This can be obtained as follow:

1 yard = 0.914 m

Therefore,

100 yard = 100 yard × 0.914 m /1 yard

100 yard = 91.4 m

Finally, we shall determine the rate of the swimmer as follow:

Time (t) = 0.945 min

Distance (d) = 91.4 m

Rate (R) =?

R = d/t

R = 91.4/0.945

R = 96.72 m/min

Thus the rate of the swimmer is 96.72 m/min

Where do karst regions occur?

Answers

Answer:

Image result for Where do karst regions occur?

Karsts are found in widely scattered sections of the world, including the Causses of France; the Kwangsi area of China; the Yucatán Peninsula; and the Middle West, Kentucky, and Florida in the United States.

Explanation:

Answer:

Middle West Kentucky.

Explanation:

Karst are found in widely scatter sections of the world.

A solution of cough syrup contains 5.00% active ingredient by volume. If the total volume of the bottle is 80.0 mL , how many milliliters of active ingredient are in the bottle?

Answers

Answer:

someone is in my mind and it is telling me 5.55m

Explanation:

Answer:

4 mL

Explanation:

4mL is 5% of 80mL. Therefore my answer is right.

A carbocation is an example of a(an) ____. Does a carbocation accept a pair of electrons, or does it donate a pair of electrons?
A. Electrophile. The carbocation accepts a pair of electrons.
B. Nucleophile. The carbocation accepts a pair of electrons.
C. Electrophile. The carbocation donates a pair of electrons.
D. Nucleophile. The carbocation donates a pair of electrons.

Answers

Answer:

Option A. The carbocation accepts a pair of electrons.

Explanation:

A carbocation is defined as a positively charged carbon, which is bound to 3 substituents. Since it has no electrons  nonbonding, it only has six electrons in its valence shell. With only six electrons in its valence shell, a carbocation is a powerful electrophile (and Lewis acid) and can react with any nucleophile that is found.

Carbocations are proposed as intermediates in many  organic reactions. They also work like free radicals, which are electron-deficient species.

Same as free radicals, the carbocations are stabilized by alkyl substituents.

How many centimeters are in .479 kilometers

Answers

Answer:

47900 cm

General Formulas and Concepts:

Chemistry

Base 10 Decimal SystemUsing Dimensional Analysis

Explanation:

Step 1: Define

0.479 km

Step 2: Identify Conversions

1 km = 1000 m

1 m = 100 cm

Step 3: Convert

[tex]0.479 \ km(\frac{1000 \ m}{1 \ km} )(\frac{100 \ cm}{1 \ m} )[/tex] = 47900. cm

Step 4: Check

We are given 3 sig figs. Follow sig fig rules.

47900. cm ≈ 47900 cm

A 0.2 g sample of pyrolusite is analyzed for manganese content as follows. Add 50.0 mL of 0.1 M solution of ferrous ammonium sulfate to reduce the MnO2 to Mn2 . After reduction is complete, the excess ferrous ion is titrated in acid solution with 0.02 M KMnO4, requiring 15.0 mL. Calculate the percent manganese in the sample as Mn3O4.

Answers

Answer:

66.7%

Explanation:

The reaction for the titration of the excess ferrous ion is:

5Fe⁺² + MnO₄⁻ + 8H⁺ → 5Fe³⁺ + Mn²⁺ + 4H₂O

We calculate the moles of Fe⁺² from the used moles of KMnO₄:

0.02 M * 15.0 mL = 0.30 mmol KMnO₄0.3 mmol KMnO₄ * [tex]\frac{5mmolFe^{+2}}{1mmolKMnO_4}[/tex] = 1.5 mmol Fe⁺²

Then we substract those 0.30 mmol from the original amount used:

0.1 M * 50.0 mL = 5.0 mmol Fe⁺²5.0 - 1.5 = 3.5 mmol Fe⁺²

The reaction between ferrous ammonium sulfate and MnO₂ is:

2Fe⁺² + MnO₂ + 4H⁺ → 2Fe³⁺ + Mn²⁺ + 2H₂O

So we convert those 3.5 mmol Fe⁺² that were used in this reaction to MnO₂ moles:

3.5 mmol Fe⁺²  * [tex]\frac{1mmolMnO_2}{2mmolFe^{+2}}[/tex]= 1.75 mmol MnO₂

Then we convert MnO₂ to Mn₃O₄, using the reaction:

3MnO₂ → Mn₃O₄ + O₂1.75 mmol MnO₂ * [tex]\frac{1mmolMn_3O_4}{3mmolMnO_2}[/tex] = 0.583 mmol Mn₃O₄

Finally we convert Mn₃O₄ moles to grams:

0.583 mmol Mn₃O₄ * 228.82 mg/mmol = 133.40 mg Mn₃O₄

And calculate the percent

0.2 g = 200 mg133.40 / 200 * 100% = 66.7%
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While Mr. Ridley was writing on the dry erase board, Margo threw a paper airplane at his back. The class giggled as Mr. Ridley spun around to see who had thrown the paper airplane. "Class! Throwing paper airplanes at a teacher is unacceptable and disrespectful. Who did that?" Mr. Ridley asked. The students kept their mouths closed and sat up straight in their chairs. No one volunteered any information. "Fine then, you will all stay in from recess until someone tells me who threw the airplane," Mr. Ridley said. Mercy wiggled in her seat. She wanted to tell the teacher who threw the airplane, but she was afraid that the other students would call her a tattle tale. Alan, the class clown, was thrilled that someone besides him had done something foolish. He would never tell. He would expect the same loyalty from his classmates. Margo felt nervous. She wanted to confess and apologize to Mr. Ridley, but she was afraid that she would receive a harsh punishment. She wondered how long her classmates would protect her. Jervis sat and drummed his fingers. He didn't see who threw the paper airplane, but he guessed that it had been Alan. He was tempted to raise his hand and tell the teacher that Alan was the responsible party, but he wasn't completely confident. He really wished that someone would tell who did it. It wasn't fair that the whole class was being punished for one person's mistake. Rosania was happy that the class wasn't going to recess. She had terrible allergies and wanted to stay inside. She hoped that no one would say a word until recess time was over. Mr. Ridley walked around the classroom looking at each student's face as he went by. He thought he detected sweat and shaking when he walked by Fred. He wondered if Fred was the culprit. However, Fred just needed to use the restroom but was afraid to ask. "Fred, you seem a bit anxious. What is it you want to tell me?" Mr. Ridley asked. "Nothing, sir. I-I need to use the restroom," Fred stammered. "No one is leaving this room until I find out who threw that airplane at me," Mr. Ridley said. Margo could not allow her classmates to suffer any longer. "It was me! I threw it! I'm sorry, Mr. Ridley," Margo said as she burst into tears. Mr. Ridley hated to see children cry. He rushed over to Margo and gently patted her back. "I forgive you. Don't cry," Mr. Ridley said. "I was just being silly. I didn't mean to disrespect you," Margo sniffled. "We will forget all about it. Let's enjoy the rest of our day together. Because you were honest, we will all play games for the rest of the day," Mr. Ridley announced.6In the passage, the author contrasts the points of view of the different characters by A. demonstrating the consequences of each character's actions. B. providing background information about each character. C. explaining how each character feels about the airplane incident. 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