ASAP
A train is travelling at 100 m/s when it receives an alert: “Brake! 600 meters ahead, the rails are broken”. The highest acceleration that the train can produce is 10 m/s^2. If the train slows down with a constant acceleration of 10 m/s^2
How long will it take for the train to stop?
How many meters will it travel before it stops?
Botcookiemaster please don't use a file just give me the answer

Answers

Answer 1

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Let's consider the given terms ~

Initial velocity (u) = 100 m/s

Acceleration (a) = - 10 m/s²

(Acceleration is negative bbecause train slows down)

Final velocity (v) = 0 m/s

(final velocity is 0, because train stops)

Now, let's find the time taken (t) by using the first equation of motion ~

[tex]v = u + at[/tex]

[tex]0 = 100 + ( - 10 \times t)[/tex]

[tex]0 = 100 - 10t[/tex]

[tex]10t = 100[/tex]

[tex]t = 100 \div 10[/tex]

[tex]t = 10[/tex]

The train will take 10 secs to stop,

Now, let's find how much distance (s) it will cover before it stops using second equation of motion ~

[tex]s = ut + \dfrac{1}{2} at {}^{2} [/tex]

[tex]s = (100 \times 10) + ( \dfrac{1}{ 2} \times - 10 \times 10 \times 10)[/tex]

[tex]s = 1000 + ( - 500)[/tex]

[tex]s = 1000 - 500[/tex]

[tex]500 \: \: m[/tex]

It will cover 500 meters before coming to rest ~


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Explanation:

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Answer:

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Hi there!

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Geometric optics allows you to find which the correct answer about which false statement is:

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Answers

Answer:

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Answers

Answer:

a balance and a beaker of water

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What average force magnitude is required to stop a 15,000 kg train in 12.1 s if the train is traveling at 86 km/hr

Answers

Answer:

Explanation:

Givens

m = 15000 kg

t = 12.1 seconds

vi = 86 km / hr

vf =0

Formula

F = m*a

a = (vf - vi)/ t

vi has to be converted to m/s

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86 * 1000 / 3600 = 23.89 m/s

Solution

a = (vf - vi) / t

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Answers

Answer:

62.5 J

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From the question

m = 20 kg

v = 2.5 m/s

From the question we have

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We have the final answer as

62.5 J

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Answers

Answer:

It should be mentioned that an efficient way to work this vector addition problem is with the cosine law for general triangles (and since  

a

,

b

 and  

r

 from an isosecles triangle, the angles are easy to figure). However, in the interest of reinforcing the usual systematic approach to vector addition, we note that the angle  

b

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0

+105

0

=135

0

(a) The x component of  

r

x

=(10.0m)cos30

0

+(10.0m)cos135

0

=1.59m

(b)  the y component of  

r

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y

=(10.0m)sin135

0

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(c) the magnitude of  

r

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r

∣=

(1.59m)

2

+(12.1m)

2

=12.2m

(d) The angle between  

r

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−1

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0

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Answer:

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Answer:

whats the question

Explanation:

Find the work done while lifting a 115 kg sofa 1.5 m off the ground.
Find the weight first

Answers

P= 10m = 10 x 115 = 1150 N

work done while lifting a 115 kg sofa 1.5 m off the ground :

A= Ph = 1150 x 1.5 = 1725 J

P/s: I think the weight first is 115kg

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