Hi there!
There are two torques acting on the system:
τ (Arthur) = RW = R(790N)
τ (Violet) = RW = 4(500N) = 2000N
∑τ = 0 = τ(Violet) - τ(Arthur)
Thus:
τ(Violet) = τ(Arthur)
2000 = 790R
R ≈ 2.53m
How can you find the mass of an object that is broken into parts?
Find the weight of the parts, and then add those weights together.
Find the weight of the whole.
Find the mass of the whole.
Find the mass of the parts, and then add those masses together.
The mass of an object broken into parts can be determined by finding the mass of the parts, and then add those masses together.
To total mass of an object broken into parts can be determined by adding the mass of different parts together.
[tex]M_t = m_1 + m_2 +\ ---[/tex]
where;
[tex]M_t[/tex] is the total mass of the objects[tex]m_1 , \ m_2[/tex] masses of the broken partsThus, we can conclude that the mass of an object broken into parts can be determined by finding the mass of the parts, and then add those masses together.
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A block of wood mass 0.60 kg is balanced on top of a vertical port 2.0 m high. A 10 gm
bullet is fired horizontally into the block and the embedded bullet land at a 4.0 m from
the base of the port. Find the initial velocity of the bullet.
A. 10 3 m/s B. 8.32 m/s C. 3.82 m/s D. 1.0 m/s
Answer:
m V1 = (m + M) V2 conservation of momentum
T = time to fall 2 m
2 = 9.8 / 2 T^2 initial vertical velocity zero
T^2 = 4/9.8 T = .639 sec
Sx = V2 * .639 sec distance traveled horizontally
V2 = 4 /.639 = 6.26 m/sec
V1 = (m + M) / m * 6.26 m/sec from first equation
V1 = (600 + 10) / 10 * 6.26 m/s = 382 m/s
There seems to be some confusion on units
Note that 382 m/s is a reasonable answer for speed of bullet
1100 ft/sec is reasonable for a .22 cal bullet
1100 ft/sec / 3.28 ft/m = 335 m/sec
More potential energy can be stored by moving against the magnetic force closer to a magnet?
Answer:
if your saying can it? then yes or if you are asking what type of magnetic force then its fr its actual self magnetic force
Explanation:
a trip from Austin to Dallas takes about 3 hours going 65 mi/hr north is this speed, velocity, or acceleration?
Answer:volocity
Explanation:
Two conditions must
be met for work to be done, what are they?
The two conditions are:
1) Application of-force on the body.
2) Displacement of the body in the direction of force.
Hope this helps!
How do you change an object's motion?
Please help thank you!
Answer:
mass, weight
Explanation:
mass is constant, and weight is dependant on your location
Answer:
I think d
Explanation:
because distance j
has to be the last one that's the only one with distance
A 4.6 kg bucket of water is raised from a well by a rope. The acceleration of gravity is 9.8 m/s 2 . If the upward acceleration of the bucket is 3 m/s 2 , find the force exerted by the rope on the bucket. Use g
Hi there!
If we sum the forces acting on the bucket:
∑F = T (upward) - Mg (downward)
Thus:
ma = T - mg
We can rearrange for T:
ma + mg = T
Plug in the given values:
4.6(3 + 9.8) = T = 58.88 N
plzz explain how it is 66 m
i know that distance =speed × time so how it is 66 m not a
0.4 and if there us another rule plz explain like if u day that 1/2 ×speed ×time plz explain why u used 1/2 or when do I use the 1/2 rule
Hi there!
For someone to hear an echo, the sound must echo and bounce back to the person.
Thus, the sound travels TWICE the distance from the person to the wall (to the wall and back).
We know that:
d = st (distance = speed × time)
Let L = distance from person to wall
Thus:
2L = st
2L = 330 × 0.40
2L = 132
L = 66 m
how does the hypothesis of inflation account for the existence of the seed of density from which galaxies and other large structures formed
about how much more energy is released in a 6.5 richter magnitude earthquake than in one with magnitude 5.5?
Answer:
For example, an earthquake of magnitude 5.5 releases about 32 times as much energy as an earthquake measuring 4.5. Another way to look at this is that it takes about 900 magnitude 4.5 earthquakes to equal the energy released in a single 6.5 earthquake.
Explanation:
A system releases 622 kJ of heat and does 105 kJ of work on the surroundings. What is the change in internal energy of the system
Answer:
Δ-727 or -7.27x10²kJ
Explanation:
ΔV=q-w
(q)= -622
(w)= -105
(both negative because it indicate loss of energy)
ΔV= -622+(-105)
ΔV= -727 kJ
The change in internal energy of the system when it released a heat of 622 kJ and does a work of 105 kJ on the surroundings is -727 kJ.
What is change in internal energy?Internal energy is all the energy contained in an object.
To calculate the change in internal energy of the system, we use the formula below.
Formula:
ΔU = Q-W............. Equation 1Where:
ΔU = Change in internal energy of the system,W = work done by the systemQ = Heat released by the system.From the question,
Given:
Q = - 622 kJ ( released of heat)W = 105 kJ.Substitute these values into equation 1
ΔU = -622-105ΔU = -727 kJHence, the change in internal energy of the system when it released a heat of 622 kJ and does a work of 105 kJ on the surroundings is -727 kJ.
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The table shows the diameters of the planets in our solar system. Assume that a basketball whose diameter is 25
centimeters represents the planet Jupiter. Find the scale (ratio) between Jupiter and the basketball. Then use this ratio to
find the scaled diameter of the other planets. Enter these numbers into the table. (Saturn has been done for you.) Finally,
choose a real-world spherical or nearly spherical object that matches the scaled diameter of each planet.
Saturn is shown as an example. To find what Saturn's size would be after adjusting it to scale, follow these steps. Let the
scaled diameter of Saturn be d centimeters. If Jupiter's diameter, 142,984 kilometers, is scaled to 25 centimeters, Saturn's
diameter of 120,536 kilometers will be scaled to about 21 centimeters:
120,536
d
120,536x25
142,984
d ~ 21 cm
Use this process to complete the table.
142,984
25
Answer:
Mercury:
.85
pea
Venus:
2.1
gumball
Earth:
2.2
gumball
Mars:
1.2
marble
Uranus:
9
grapefruit
Neptune:
8.6
softball
Explanation:
I have no clue if I'm right but hopefully, I am
ignore this i put the wrong grade sorry
Answer:
Oh its fine i am not in college but its still fine
Explanation:
2. What is the period of 350 waves passing a point in 5 seconds?
Answer:
IF SHE BREATHS SHES A T.H.OT
Explanation:
Pls dont hate me its meme k ,_.
A ball of mass 2.0 kg is travelling at a speed of 12 m/s. It moves towards an object of mass 3.0 kg which is at rest.
The ball hits the object and sticks to it.
Which row gives the total momentum, and the speed of both objects immediately after the collision?
total momentum (kg m/s)
A- 0
B- 0
С- 24
D- 24
AND..
speed (m/s)
A- 4.8
B- 8.0
C- 4.8
D- 8.0
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
The velocity for the entire trip is 0.4 m/s as It takes her 500 seconds to make the round trip and 60 kg • m/s2 = (45 kg • v) + (20 kg • 3 m/s).
Path 1 = 400 m В B. A Path 2 = 200 m Path 3 = 300 m. Thus, option C is correct.
What is velocity?A particle's settling velocity known as the rate at which is travels through a still fluid. The specific gravity of the particles, their size, and their shape all have an impact on settling velocity.
A particle in still air will gravitationally settle and reach its terminal velocity fairly quickly. A particle's terminal velocity in a still fluid is referred to as the settling velocity (also known as the "sedimentation velocity").
Understanding variations in the hydraulic regime and interactions between sediment and fluid in the surf zone depends heavily on the particle settling velocity at the foreshore region. In contrast to sedimentation, which is the end product of the settling process, settling is the movement of suspended particles through the liquid.
Therefore, Thus, option C is correct.
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Copper is a type of metal.
A block of copper has a mass of 2.0kg.
The block of copper absorbs 12000J of thermal energy.
The specific heat capacity of copper is 385J /(kg°C).
What is the temperature rise of the copper?
A 15.6°C B 31.2°C C 46.8°C D 62.4°C
The temperature rise in the copper is. I think its 0.393
The temperature rise in the copper is. I think its 0.393. Copper is a chemical element with the symbol Cu (from Latin: cuprum) and atomic number 29.
What is Capacity of copper?The chemical element copper (Cu) is a reddish, incredibly ductile metal belonging to Periodic Group 11 (Ib) that has an exceptional ability to conduct heat and electricity.
In nature, copper can be found in its free metallic state. Neolithic (New Stone Age) humans originally utilised this local copper (about 8000 BCE) as a substitute for stone.
Around 4000 BCE, Mesopotamia saw the beginning of metallurgy as copper was cast into molds, reduced to metal from ores with fire and charcoal, and purposefully alloyed with tin to form bronze (c. 3500 BCE).
Therefore, The temperature rise in the copper is. I think its 0.393. Copper is a chemical element with the symbol Cu (from Latin: cuprum) and atomic number 29.
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one end of a light inextensible string is attached to a tool box of mass 2.5 kg which is lying on a horizontal table. The string passing over a smooth pulley and is tied at the other end to a bag of mass 1.4kg as shown in the diagram
a. If the toolbox on the point of sliding, find the value for μ, the coefficient of friction.
b. Supposing the coefficient of friction between the tool boxe and the table is 0.20, calculate the acceleration of the system and the tension in the string gravity as 10 m per second square
Answer:
the answer is A
Explanation:
10. Which of the following will happen to the respiratory-associated muscles if you were to blow up a balloon?
A. Diaphragm contracts, Internal intercostal would relax
B. Diaphragm would contract, external intercostal would relax
C. Internal intercostal and abdominal muscles would contract
D. External intercostal would contract and diaphragm would relax
Answer:
C
for sure
go for it
..............
calculate the relative density of a block having dimension 4m x 3m x 2m given its mass in 48000g
Answer:
in the picture
Explanation:
CARRY ON LEARNING
Select two of Earth's spheres and explain how they interact with each other.
atmosphere, biosphere, cryosphere, geosphere and hydrosphere
HELPPPPPPPP!!!!!
Answer and Explanation: The geosphere interacts with the cryosphere when glaciers and sheets of ice from the cryosphere erode the rocks located on the geosphere. This happens as ice passes over the land and carries eroded rocks to new locations. The cryosphere can also cause soil to become icy and take hold of greenhouse gases from the atmosphere. The geosphere is the part of the Earth that has rocks, minerals, sand, and lava. The cryosphere has frozen water, ice, and glaciers. The cryosphere also interacts frequently with the hydrosphere because it draws water from the hydrosphere and freezes it during cold temperatures. Warmer temperatures cause the cryosphere to melt and release water back to the hydrosphere.
Sachi wants to throw a water balloon to knock over a target and win a prize. The target will only fall over if it is hit with a force of 0. 035 N. The water balloon has a mass of 11. 4 grams. How fast will Sachi have to make the water balloon accelerate to hit the target with enough force and win the prize? Round the answer to the nearest one tenth m/s2. The water balloon must accelerate m/s2.
Hi there!
We can use the following equation (Newton's Second Law):
∑F = ma
m = mass of object (kg)
a = acceleration (m/s²)
We can rearrange to solve for 'a':
F/m = a
Remember to convert grams to kg.
1000g = 1 kg
0.035/(0.0114) = 3.07 m/s²
4. A force of 50 Newtons is applied to a mass resulting in an acceleration of 8 m/s2. What force would need to be applied to this mass to cause an acceleration of 25 m/s??
Answer:
125N
Explanation:
force =mass×acceleration
50 =mass×8m/s2
mass=6.25kg
6. Explain a change that you can make in your diet to further your overall health.
Answer:
“Eat more delicious whole-food plants at every meal and snack. Fruits, vegetables, whole grains, nuts and seeds are packed with nutrients and contain satisfying fiber that is good for digestion, disease prevention and sustained energy.
Explanation:
v=VyV67.2 -8.2 m/s
Part B
Now let's see if your prediction agrees with the experimental results. There isn't any data at y=-3.5 m, so you'll need to interpolate by zooming in
on the relationship between y velocity (W) and y displacement. You'll use Tracker's Data tool to help with this analysis. Follow these steps:
• Change the vy versus t graph to a vy versus y graph. (Click the t label on the horizontal axis and select y. position y-component from the
menu.)
• It's a little hard to see what's going on with this graph at y = -3.5, so zoom in. Double-click on the graph to open it up in the Data tool.
. Put your cursor on the point where the graph line intersects y = -3.5. Click and hold to read the vy at that point shown in a yellow box in the
bottom left comer).
What's the interpolated graph value of v, at y = -3.57 Comment on how well this value agrees with the value of v, that you calculated in part A of
this activity. Make a hypothesis about any notable difference.
Answer:
-3.5
Explanation:
b/c the distance is moving in to two A And B A +B or S1 +S2 that is it
Answer:
The interpolated velocity value from the graph is -8.1 meters/second. The calculated value based on the average acceleration is -8.2 meters/second. This is very good agreement.
Explanation:
A small ball is attached to one end of a spring that has an unstrained length of 0.201 m. The spring is held by the other end, and the ball is whirled around in a horizontal circle at a speed of 3.41 m/s. The spring remains nearly parallel to the ground during the motion and is observed to stretch by 0.0176 m.
Required:
By how much would the spring stretch if it were attached to the ceiling and the ball allowed to hang straight down, motionless?
The extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.
The given parameters;
unstrained length, l₁ = 0.201 mextension of the string, x = 0.0176 mspeed of the ball, v = 3.41 m/sThe radius of the circular path when spring is stretched is calculated as;
R = l₁ + x
R = 0.201 + 0.0176
R = 0.2186 m
The spring constant is calculated as follows;
[tex]F = ma\\\\Kx = \frac{mv^2}{R} \\\\K = \frac{mv^2}{Rx} \\\\K = \frac{(3.41)^2 m}{0.2186 \times 0.0176} \\\\K = 3,022.4 m \ N/m[/tex]
The extension of the spring when the ball is allowed to hang straight down, motionless;
[tex]F = mg\\\\Kx=mg\\\\x = \frac{mg}{K} \\\\x = \frac{9.8 m}{3022.4 m} \\\\x = 0.0032 \ m[/tex]
Thus, the extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.
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11. A box with a mass of 1.0 kg is resting on a horizontal surface and the coefficient of friction between the block and the surface is 0.20. It is accelerated by attaching a 1.5 kg mass, as shown in the diagram. Assume that the pulley is frictionless and that the cord has negligible mass.
a. What is the acceleration of the box? What is the tension?
Answer:
We know that the force pulling the box in the positive x direction has a magnitude of m g sin 30 . Using Newtons Second Law, F = ma , we just need to solve for a :
ma=mgsin30
a=gsin30
=(10m/s2)(0.500)
=5m/s2
Answer:
A force is applied acting to the right. Assume that friction is negligible. Ikg 0.5N. For each question, one or more features of the system.
Explanation:hope this helps
Plzzzz help mee plzzzz help meeee
Answer:
1 $1260.00-$700.00=$560.00
2 $700.00/$1260.00*100= approximately 55.6%
Explanation:
* this sign means Multiplication
A ____ is believed to occur when energy, stored in a twist in the solar magnetic field above a sunspot, is suddenly released.
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
A solar flare is believed to occur when energy, stored in a twist in the solar magnetic field above a sunspot, is suddenly released.
what is the magnitude of the torque that the axle must apply to prevent the disk from rotating?
The required torque at the axle, is given by the difference between the
moments of the applied forces.
The torque required is 19.62 N·m counterclockwise
Reasons:
The given parameters are;
Mass of the disk, m = 5.0 kg
Location of the axle = Half the radius of the disk
Diameter of the disk, D = 40 cm = 0.4 m
Applied mass, 0.1 m from the axle = 15 kg
Applied mass, 0.3 m from the axle = 10 kg
Required:
Magnitude of torque at the axle that prevent the disk from rotating
Solution:
Torque needed = Clockwise moment - Counterclockwise moment
Clockwise moment = (10 kg × 0.3 m + 5 kg × 0.1 m) × 9.81 m/s² = 34.335 N·m
Counterclockwise moment = 15 kg × 0.1 m × 9.81 m/s² = 14.715 N·m
τ + Counterclockwise moment = Clockwise moment
τ + 14.715 N·m = 34.335 N·m
Torque required, τ = 34.335 N·m - 14.715 N·m = 19.62 N·m
Torque required, τ = 19.62 N·m counterclockwise
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The probable question drawing obtained from a similar question online is attached