The constant vertical acceleration provided by the deflector is a = 1.11 * 10^6 m/s^2.
What is meant by acceleration?The rate of change of velocity is called acceleration. Acceleration means that the speed is changing, but not always.
y = vi*t + (1/2)at^2
Where y is vertical displacement, vi is initial vertical velocity, t is time of travel, and a is the constant acceleration.
So, y = (1/2)at^2
Given, vertical displacement of the electron (y = 40.0 cm)
x = vt
x is the horizontal displacement and v is horizontal velocity.
So, t = x/v
t = (17.0 cm) / (3.0 x 106 m/s) = 5.67 x 10^-8 s
y = (1/2)(a)(t)^2
a = 2y/t^2
a = 2(40.0 cm) / (5.67 x 10^-8 s)^2
So, the acceleration provided by the deflector is a = 1.11 * 10^6 m/s^2.
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A 1.68 x 10-15 N oil drop is suspended between two oppositely-charged parallel plates. The plates are 4.0 cm apart and there is a potential difference of 140 V between them. The top plate is positive and the bottom plate is negative.
a) Sketch the electric field between the plates.
b) Calculate the magnitude of the electric field between the plates.
c) Determine the charge on the oil drop. Include the SIGN.
d) How many electrons is this charge composed of?
A magnetic field is created between these two charged parallel plates. The field indicates a direction from the positive plate to the negative plate.
What is a positively charged plate?Protons are in excess on a positively charged metal plate. From the electron's point of view, a positively charged aluminium.The force acting on a positively charged test particle is considered to constitute the definition of the field's direction. Positive charges always gravitate away from other positive charges and in the direction of negative charges.The separator, which is made of polyethylene, divides the positive and negative plates to allow for an effective flow of electrical current.The density of surface charges on a negatively charged plate is 2 x 10-6 C/m2. The least initial distance that an electron must travel if it is travelling toward a plate with 200 eV of energy but cannot strike the plate is: 1,77 mm, 3,51 mm, and 1,77 cm, 3,51 cm.To learn more about parallel refer to:
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a tennis ball is struck horizontally from a height of 1 m. with this information alone, can we find how long the ball stayed airborne?
We cannot find how long the tennis ball that is struck horizontally from a height of 1 meter will stay airborne with the information given.
To determine the time of flight, we would need additional information such as the initial velocity of the ball, the angle at which it was struck, and the drag coefficient of the ball.
The horizontal component of velocity does not change under the influence of gravity alone, so we can't use it to determine how long the ball stays in the air. Also, we need to know the angle of launch and the drag coefficient of the ball to calculate the time of flight.
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A rocket of mass 1000kg containing a propellant gas of 3000kg is to be launched vertically. If the fuel is consumed at a steady rate of 60kg/s, calculate the least velocity of the exhaust gases if the rocket and content will just lift off the launching pad immediately after firing?
A 1000 kg rocket with a 3000 kg propellant gas is intended for vertical launch. If the gasoline is used consistently at a rate of.
What initiates the launch of a rocket?When the upward force of thrust is higher than the downward force of gravity, a rocket is said to have launched. A rocket will speed upwards as a result of this imbalanced force. As long as the thrust of a rocket engine produces an upward force, a missile will continue to accelerate.
What forces are present when a rocket is launched?A rocket experiences four forces while in flight: weight, velocity, and the aerodynamics of lift and drag. The weight's size is determined by the.
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An aluminum rod is 20. 0 cm long at 20°C and has a mass of 350 g. If 10 000 J of energy is added to the rod by heat, what is the change in length of the rod?
Linear expansion refers to the increase in length of a material as its temperature increases. It is typically measured as the change in length per unit length per degree of temperature change. the answer change in length of the rod is approximately 0.014 cm.
This effect is caused by the thermal motion of the atoms or molecules in a material, which increases as the temperature increases. Linear expansion is typically a small effect, but can be significant in certain applications, such as in the construction of bridges or buildings.The change in length of the rod can be calculated using the equation for linear expansion:
ΔL = L0 * α * ΔT
Where:
L0 = initial length (20.0 cm)
α = coefficient of linear expansion for aluminum (about 2.5 x 10^-5 /°C)
ΔT = change in temperature (can be calculated by using the heat added, mass, and specific heat capacity of aluminum)
First we need to calculate ΔT, we know that c(Aluminum)= 0.90 J/g °C
ΔT= Q / (m * c)where:
Q = heat added (10000 J)
m = mass of the rod (350 g)
c = specific heat capacity of aluminum (0.90 J/g °C)
Substituting the values we have,
ΔT = 10000 J / (350 g * 0.90 J/g °C) = 28.57142857142857 °C
Now we can find the change in length,
ΔL = L0 * α * ΔT = 20.0 cm * 2.5 x 10^-5 /°C * 28.57142857142857 °C = 0.014 cm
So the change in length of the rod is approximately 0.014 cm.
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A positively charged rod is brought near one end of an uncharged metal bar. The end of the metal bar farthest from the charged rod will be charged
positive.
negative.
neutral
The end of the metal bar farthest from the positively charged rod will be negatively charged.
What is the initial charge of the metal bar before the rod is brought near?
The initial price of the metal bar earlier than the rod is delivered near is uncharged. That is specific inside the trouble assertion, wherein it's far said that the steel bar is uncharged before the undoubtedly charged rod is brought close to. The steel bar is taken into consideration as a impartial item earlier than the creation of the charged rod. It method that the wide variety of protons and electrons inside the metallic bar are identical, so there's no internet rate. Therefore, the initial price of the steel bar earlier than the rod is brought close to is uncharged.
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A block is on a surface with
is = 0. 325. It takes 4. 11 N to
break it free from static friction.
How much normal force acts
on the block?
(Unit = N)
The normal force acting on the block is 4.11N/0.325 = 12.68N.
Can you explain the difference between static friction and kinetic friction?
Static friction is the force that opposes to the motion of an object when it is at rest. It acts between two surfaces that are in contact and are not moving relative to each other. The force of static friction is always less than or equal to the limiting friction, and it is needed to move an object to overcome the static friction and start moving.
On the other hand, kinetic friction is the force that opposes to the motion of an object when it is in motion. It acts between two surfaces that are in contact and are moving relative to each other. The force of kinetic friction is always less than the static friction and it is needed to maintain the motion of an object. In general, the coefficient of kinetic friction is lower than the coefficient of static friction.
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The normal force acting on the block is 12.68N when block is on a surface with is = 0. 325. It takes 4. 11 N to break it free from static friction.
Evaluating :Surface = 0.325
force = 4.11 N
Static friction = 4.11N/0.325
= 12.68N.
Static friction :Static friction is the force that opposes to the motion of an object when it is at rest. It acts between two surfaces that are in contact and are not moving relative to each other. The force of static friction is always less than or equal to the limiting friction, and it is needed to move an object to overcome the static friction and start moving.
Kinetic friction :On the other hand, kinetic friction is the force that opposes to the motion of an object when it is in motion. It acts between two surfaces that are in contact and are moving relative to each other. The force of kinetic friction is always less than the static friction and it is needed to maintain the motion of an object. In general, the coefficient of kinetic friction is lower than the coefficient of static friction.
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beneath the surface of which moon of jupiter is there the strongest evidence for the existence of a subsurface ocean of liquid water?
Beneath the surface of Jupiter's moon of Europa there exists the strongest evidence for the existence of a subsurface ocean of liquid water.
Based on the icy composition of Jupiter's moon named Europa scientists impose the concept that there is the most likely material to make this magnetic signature is a global ocean of salty water. And the result of this magnetic field still is the best evidence for reporting the existence of an ocean on Europa.
Therefore, beneath the surface of Europa's moon of Jupiter, there exists the strongest evidence for the existence of a subsurface ocean of liquid salty water.
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Find the magnitude of the velocity of the of the chain when 5. 58 m of the chain is hanging vertically. Answer in units of m/s
The magnitude of the velocity of the of the chain when 5.58m of the chain is hanging vertically is 10.46m/s.
Given the length of chain (s) = 5.58m
We know that from Newtons second law of motion :
v^2 = u^2 + 2gs where v is the final velocity, u is the initial velocity and g is the acceleration due to gravity.
Here u = 0m/s as the chain is at rest initially.
So, v^2 = 0 + 2 x 9.8 x 5.58
v^2 = 109.368
v = √109.368 = 10.46m/s
Hence the magnitude of the velocity of the of the chain = 10.46m/s.
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A mass on a string of unknown length oscillates as a pendulum with a period of 6. 6 s. Parts A to D are independent questions, each referring to the initial situation.
What is the period if the mass is doubled?
What is the period if the string length is doubled?
The time period is not depends on the mass. So even the mass is doubled its time period not changes. The period of a simple pendulum is given by the equation T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
A. In this equation, the mass does not appear, so doubling the mass of the pendulum does not affect the period. If the mass of the pendulum is doubled, the period of the pendulum will remain the same.
B. If the length of the pendulum's string is doubled, the period will also be doubled. The period of a simple pendulum is given by the equation T = 2π√(L/g),
where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. Doubling the length of the pendulum increases the length by a factor of 2, which increases the period by a factor of 2.
What is Pendulum?A pendulum is a weight suspended from a pivot so that it can swing freely. The weight, also known as a bob, is the object that oscillates (moves back and forth) under the influence of gravity. Pendulums can be used to measure time, as in the case of a grandfather clock, or as a simple device to demonstrate harmonic motion.
The force acting on the pendulum is gravity, which is pulling the bob downward. This force is opposed by the tension in the string or rod that is holding the bob. The bob has kinetic energy when it is moving, and potential energy when it is at the highest or lowest point of its swing. As the bob swings back and forth, its kinetic and potential energy are constantly changing.
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analysis of a bus crashgiven the following theoretical data for the collision, answer the following questions and complete the data table. show work! bus suv m v p m v p total momentum before collision 1600 kg 10 m/s 600 kg 0 after collision 1600 kg 3 m/s 600 kg 1. what is the change in momentum of the bus?
The change in the momentum of the bus is 10600 kg-m/s, if bus of 1600 kg crashes with a SUV of 600 kg.
The mass of the bus, m₁ = 1600 kg
The mass of the SUV, m₂ = 600 kg
Initial velocity of the bus, v₁ = 10 m/s
initial velocity of the SUV, v₂ = 0 (at rest)
Velocity of the bus after collision, v₃ = 3 m/s
Velocity of the SUV after collision, v₄ = 1 m/s
The change in momentum(Δp) is given by,
Δp = (m₁v₁ + m₂v₂) - (m₁v₃ + m₂v₄)
Δp = (1600 × 10 + 600 × 0) - (1600 × 3 + 600 × 1)
Δp = 16000 - 5400
Δp = 10600 kg-m/s
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Objects with masses of 232 kg and 538 kg are separated by 0.342 m. a 60.6 kg mass in placed midway between them. 538 kg 1232 kg 60.6 kg - 0.342 m. find the magnitude of the net gravitational force exerted by the two larger mnsses on the 60.6 kg mass. the value of the univorsal gravi tational constant is 6.672 × 10-in- m°/kg? answer in units of n 017.leaving che distance botron the 242 kg and che 538 koenasses fixed. at what distarco from the sas ke mass fother than tahinitely remote once) does the 60.6 ka mass experienco a net fored of pay?
No net force is experienced. To find the magnitude of the net gravitational force exerted by the two larger masses on the 60.6 kg mass, we can use the equation for gravitational force.
Gravitational force equation:
F = G * (m1 * m2) / r^2
Where F is the gravitational force, G is the universal gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.
In this case, m1 = 232 kg, m2 = 538 kg and r = 0.342 m.
So, F = G * (232 kg * 538 kg) / (0.342 m)^2
Plugging in the values, we get:
F = 6.672 x 10^-11 N*(m^2)/(kg^2) * (232 kg * 538 kg) / (0.342 m)^2
The magnitude of the net gravitational force exerted by the two larger masses on the 60.6 kg mass is 0.092 N.
To find the distance at which the 60.6 kg mass experiences a net force of zero, we can use the equation for the gravitational force between two masses. Since the force is inversely proportional to the square of the distance between the masses, we can set the force to zero and solve for the distance.
F = G * (232 kg * 60.6 kg) / (r)^2 = 0
r = √((232 kg * 60.6 kg) / (G))
r = √((232 * 60.6) / (6.672 * 10^-11))
r = 2.36*10^-5 m
At this distance, the 60.6 kg mass experiences no net force from the two larger masses, as the gravitational force exerted by the 232 kg mass balances out the gravitational force exerted by the 538 kg mass.
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a car, on a straight road, is stopped at a traffic light. when the light turns to green the car accelerates with a constant acceleration. it reaches a speed of 23.7 m/s (85.3 km/h) in a distance of 146 m. calculate the acceleration of the car.
The acceleration of the car is 146.3 m/s². The result is obtained by using the formula for acceleration.
What is acceleration?Acceleration is the rate of change in velocity of an object with respect to time. It can be expressed as
[tex]\bar{a} = \frac{\Delta v}{\Delta t}[/tex]
Where
a = accelerationΔv = change in velocityΔt = change in timeA car stopped and moves with a constant acceleration. It means that the car moves from rest. We have
Initial speed, v₁ = 0Final speed, v₂ = 23.7 m/sDistance, Δx = 146 mThe change in time is
Δt = Δv/x
Δt = (v₂ - v₁)/Δx
Δt = (23.7 - 0)/146
Δt = 0,162 s
The acceleration of the car would be
[tex]\bar{a} = \frac{\Delta v}{\Delta t}[/tex]
[tex]\bar{a} = \frac{23.7 - 0}{0.162}[/tex]
[tex]\bar{a} = 146.3 m/s^{2}[/tex]
Hence, the car has an acceleration of 146.3 m/s².
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a 20 kg box is attached to a compressed spring that has a spring constant of 300 n/m. the box is resting on a frictionless surface and the spring is compressed 30 cm. how fast will the box be moving after the spring releases the box?
The box will be moving at the speed of 1.16 m/s, when the spring is compressed by 30 cm, if the spring constant is 300 n/m and the mass of the box is 20 kg.
Potential energy stored in the spring during compression of x cm, U = 0.5 kx²
Kinetic Energy possessed by the object moving at a speed of v, = 0.5 mv²
0.5 × 20 × v² = 0.5 × 300 × 0.3²
v² = (0.5 × 300 × 0.3²)/(0.5 × 20)
v² = 1.35
v = √1.35
v = 1.16 m/s
So the box will be moving at a speed of 1.16 m/s.
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a proton is placed at point a. the proton is then removed and an electron is placed at point b. what is the direction of the electric force ? give angle relative to x with ccw as positive. what is the direction of the electric force ? what is true of the magnitude of the two forces?
When a proton is removed from point A and an electron is placed at point B, the direction of the electric force will be from point B towards point A. The angle of this force relative to the x-axis would be 180 degrees, with counterclockwise as positive.
As the electron and proton have equal and opposite charges, the magnitude of the force between them will be the same as the magnitude of the force between the proton and the electron.
The magnitude of the force between the proton and electron can be determined by Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.
In other words, the magnitude of the two forces is equal, but the direction of the two forces is opposite.
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19. A rock that is thrown vertically downward travels
10.0 m before hitting the ground. If it strikes the
ground at a velocity of 15.0 m/s, how long did it
take to reach the ground?
It took 2.04 seconds for the rock to reach the ground, after it was thrown vertically downward at a velocity of 15.0 m/s.
What is velocity?
Velocity is a vector quantity that describes the rate of change of an object's position in a specific direction. It is defined as the distance an object travels per unit of time. The standard unit of velocity is meters per second (m/s) in the International System of Units (SI).
To determine how long it took for the rock to reach the ground, we can use the equation:
d = v0t + (1/2)gt^2
Where d is the distance traveled, v0 is the initial velocity (which is zero for a rock that is thrown vertically downward), t is the time, and g is the acceleration due to gravity (approximately 9.8 m/s^2).
Since we know the distance traveled and the final velocity of the rock, we can rearrange the equation and solve for t:
t = (2d / g)^1/2
Plugging in the given values:
t = (2 * 10 m / 9.8 m/s^2)^1/2 = (2 * 10 / 9.8)^1/2 = 2.04 s
Therefore, it took 2.04 seconds for the rock to reach the ground, after it was thrown vertically downward at a velocity of 15.0 m/s.
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two identical air-hockey pucks are moving on an air-hockey table with an x-y axis drawn upon it. puck a has a velocity of 5 m/s at an angle of 35 degrees above the x-axis. puck b has a velocity of 6 m/s at an angle of 70 degrees above the x-axis. which puck has a larger momentum in the x-direction?
Puck B has a larger x-direction momentum as it has a greater velocity in the x-direction.
The momentum of a puck is determined by its mass, velocity, and direction. Since both pucks have the same mass, the one with the greater velocity in the x-direction will have the larger x-direction momentum.
Puck A has a velocity of 5 m/s at an angle of 35 degrees above the x-axis. When the velocity is resolved along the x-axis, this gives a velocity of 4.39 m/s in the x-direction.
Puck B has a velocity of 6 m/s at an angle of 70 degrees above the x-axis. When the velocity is resolved along the x-axis, this gives a velocity of 4.83 m/s in the x-direction.
Therefore, Puck B has a larger x-direction momentum as it has a greater velocity in the x-direction.
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Please help!!!!!!!!!!!!!!!
Answer:
1. The properties of ionic compounds are:
a. Ionic compounds usually exist in the form of crystalline solids at room temperature.
b. Ionic compounds are soluble in water.
c. Ionic compounds have high melting and boiling points
d. Ionic compounds don't conduct electricity in solid state.
e. The ions of ionic compound crystals are orderly arranged.
2. The properties of covalent compounds are:
a.Covalent compound generally exist in liquid and gaseous state.
b. They are poor conductor of elctricity.
c. Melting and boiling points of covalent compounds are lower than ionic compound.
d. They are generally soluble in non- polar solvents such as benzene.
e. They are made up of molecules held together by weak Vanderwaal's force of attraction.
3. Salt is a covalent compound.
4. Sugar is an ionic compound.
Rest of the assignment is practical. Do at a Lab.
if you have two resistors, r1 and r2, connected in parallel. what is the maximum equivalent resistance possible?
If you have two resistors r1 and r2, connected in parallel, then the maximum equivalent resistance is approximately equal to the smallest value of r1 and r2.
Suppose we have two resistors r1 and r2, connected in parallel, then its equivalent resistance is:
1/r = 1/r1 + 1/r2
Notice that since it is a reciprocal equality, the maximum possible r will occur when one of 1/r1 or 1/r2 is equal to zero.
Let's assume 1/r2 = 0, then r = r1.
1/r2 = 0 will never be achieved, but for very large r2, we can expect:
1/r2 ≈ 0
It means, the possible maximum equivalent resistance is approximately equal to the smallest value of r1 and r2.
Example:
r1 = 2 Ohm, r2 = 10000 Ohm
1/r = 1/2 + 1/10000
1/r = 5001/10000
r = 10000/5001 = 1.999 ≈ 2 Ohm ( which is approximately equivalent to r1)
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Cart 1 is 6 kg and traveling at 3 m/s to the right. It collides with cart 2, which is 4 kg and traveling 4 m/s to the left. After the collision, cart 1 is moving at 4 m/s to the left. What is the velocity of cart 2?
The velocity of cart 2 will be 2.5m/s
Explain collision
A collision is a brief interaction between two or more bodies that modifies their motion due to internal forces acting between them. the forces at work during collisions (there is a change in velocity).
Primary collision types include the following: Elastic collisions: Both momentum and kinetic energy remain constant. Only momentum is conserved during inelastic collisions. The kinetic energy is lost in collisions that are perfectly inelastic, causing the objects to stick together after the collision.
Before collision :
m1 = 6kg
v1 = 3m/s
p1 = m1v1 = 3*6 = 18kg*m/s
m2 = 4kg
v2 = 4m/s
p2 = m2v2 = 4*4 = 16kg*m/s
Δp1 = p1 + p2
After collision :
m1 = 6kg
v1 = 4m/s
p1 = m1v1 = 6*4 = 24kgm/s
m2 = 4kg
v2 =?
p2 = m2v2 = 4*v2 kgm/s
Δp2 = p1 + p2
We know Δp1 = Δp2
So, 18 + 16 = 24 + 4v2
4v2 = 34-24 = 10
v2 = 10/4 = 2.5m/s .
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a horizontal clothesline is tied between 2 poles, 18 meters apart. when a mass of 2 kilograms is tied to the middle of the clothesline, it sags a distance of 5 meters. what is the magnitude of the tension on the ends of the clothesline?
The magnitude of the tension on the ends of the clothesline is 175N.
Tension is a mechanical term that describes the opposing resisting force that a rope or string experiences when it experiences a weight at the end of it. It can be measured in Newtons. It can be found all the way down a rope or thread.
we know that the combined vertical tension in the clothesline must equal the weight of the mass;
using g=9.8m/s/s, W=2kgx 9.8m/s/s = 19.6N
now, draw a diagram of the situation; if we call x the angle between the clothesline and the horizontal line that connects the poles, we have that
tan x = 1/9 => x =6.34 deg
now, we can use this angle to show that if T is the tension in the clothes line, the vertical component of tension is T sin x = T sin 6.34
since both sides of the line exert a tension up, we have that
2 T sin 6.34 = W = 19.6 N
or T= 175N.
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What is the electric flux through one side of a cube that has a single point charge of -3. 80 µC placed at its center? Hint: You do not need to integrate any equations to get the answer.
? N·m^2/C
The electric flux through one side of a cube is found as -7.1 x 10⁴ V.m.
Explain the term Gauss's Law?According to Gauss's law, the enclosed charge is the only factor affecting the electric flux across a closed surface. Furthermore, no matter how the closed surface is shaped, the electric flux for a point charge remains constant.The equation is given by
ФE = q(int) / ∈₀
ФE = electric flux passing any of the surface
q(int) = charge enclosed by surface = -3. 80 µC
∈₀ = 8.85 x 10⁻¹² F/m (permittivity of free space)
Put the given values.
ФE = -3. 80 x 10⁻⁶ /8.85 x 10⁻¹² / 6 (for one surface of the cube)
ФE = -7.1 x 10⁴ V.m
Thus, the electric flux through one side of cube is found as -7.1 x 10⁴ V.m.
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a 60 kg hiker wishes to climb 1200 meter high if he can generate a sustained average power of 500 watts, how long will the climb take
The time it will take do the hiker to climb the 1200m high wall is 1,411.2 seconds.
How to calculate time from power?Power refers to the measure of the rate of doing work or transferring energy.
Power = Work done/time
Since work = force × distance the body is moved
Power = (m × g × h) / t
Where;
m = the mass of the bodyg = the acceleration due to gravityh = the height the body has fallent = the time the body has fallenAccording to this question, a 60kg hiker wishes to climb 1200m high. If he can generate a sustained average power of 500 watts, the time it will take to climb is as follows;
500 = 60 × 9.81 × 1200/t
500t = 705,600
t = 1,411.2 seconds
Therefore, 1,411.2 seconds is the time it will take the hiker.
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a rifle with a weight of 30.0 n fires a 5.0-g bullet with a speed of 300 m/s. (a) find the recoil speed of the rifle. (b) if a 700-n man holds the rifle firmly against his shoulder, find the recoil speed of man and rifle.
The recoil speed of man and rifle are 0.05 m/s and 0.0021 m/s .
(a) The recoil speed of the rifle can be found using the law of conservation of momentum. The momentum of the bullet is equal to the momentum of the rifle and the man.
Momentum of the bullet = mv = (5.0 g)(300 m/s) = 1.5 kg·m/s
Momentum of the rifle = (30.0 n)(v)
Therefore, v = 1.5 kg·m/s ÷ 30.0 n = 0.05 m/s
The recoil speed of the rifle is 0.05 m/s.
(b) The total momentum of the man and the rifle is equal to the momentum of the bullet.
Momentum of the man and rifle = mv = (700 n)(v)
Therefore, v = 1.5 kg·m/s ÷ 700 n = 0.0021 m/s
The recoil speed of the man is 0.0021 m/s.
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Where are the carbon atoms before the chemical reaction starts?
Carbon atoms combine with carbon dioxide molecules to form ethanol. The area of the atom where a chemical reaction takes place is called the electron cloud.
What molecule are carbon atoms in before the chemical change?In ethanol, carbon atoms join molecules of carbon dioxide. The electron cloud is the region of the atom that is involved in a chemical process. The area of the atom surrounding the nucleus is called the electron cloud. The particle that caused the reaction to take place is an electron, which is found in the electron cloud.
A chemical reaction neither creates nor destroys atoms. Rearranging the atoms occurs. Due to this, new compounds are created that have properties that differ from the initial substances.
The materials that initiate a chemical reaction are known as reactants, while the materials created as a result of the reaction are known as products.
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A ball of mass 2 kg is attached to a vertical spring. The ball displaces 0. 1 m once it is attached. What is the spring constant?
The spring constant of spring when a ball of mass 2 kg is attached to a vertical spring and is displaced 0. 1m once it is attached is 196.
Given the mass of ball (m) = 2kg
The distance the ball displaced (x) = 0.1m
We know that from Newtons laws of motion F = ma where F is the force acting on an object a is the acceleration.
Here, since the ball is attached to the vertical spring the acceleration acting on the ball is due to gravity. So a = g = 9.8m/s^2.
The restoring force acting on the vertical spring is given as:
Fr = kx where k is spring constant and x is the distance the ball displaced.
As restoring force is balanced by the weight of the ball, Fr = F
Then mg = kx such that k = mg/x
k = 2 x 9.8 / 0.1 = 196
Hence the spring constant of the spring = 196
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Answer:
Explanation:
Since F = ma
And a is 9.8
m = 2
F = 2*9.8
F = 19.6
Hookes Law:
F = kx
So 19.6 = k*0.1
So k = 196
a photoelectric experiment is performed by separately shining a laser at 450 nm (blue light) and a laser at 560 nm (yellow light) on a clean metal surface. assume that each laser is above the threshold frequency and delivers the same number of photons per second. a. which laser will eject more electrons per second? b. which laser will eject electrons with greater kinetic energy? c. which laser will eject electrons with shorter de broglie wavelength?
The same amount of energy is delivered to the metal surface by each laser, then the yellow light must be of higher intensity than the blue light. The yellow light must generate more electrons. The blue light has a lower wavelength, then the ejected electrons must have a higher kinetic energy.
What is meant by electrons?
A negatively charged subatomic particle known as an electron can either be free or attached to an atom (not bound).One of the three main types of particles inside an atom, along with protons and neutrons, is an electron that is linked to the atom.The nucleus of an atom is made up of electrons, protons, and neutrons together.The negatively charged particles known as electrons revolve around the outside of the nucleus.For scientists, it can be challenging to monitor them because of how quickly they spin.The tiniest particles in an atom, you can put 2000 of them into a proton, they are drawn to the positive charge of the protons.To learn more about electron refer to
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. In a railroad yard, a train is being assembled. An empty boxcar, coasting at 3.0 m/s, strikes a
loaded car that is stationary, and the cars couple together. Each of the boxcars has a mass of 9000
kg when empty, and the loaded car contains 55,000 kg of lumber. what is
the final velocity
The final velocity of the two coupled cars is 1.2 m/s.
What is the final velocity of the two coupled cars?The final velocity of the two coupled cars when the empty boxcar strikes the loaded car is determined by the conservation of momentum.Momentum is defined as the product of mass and velocity and is conserved in an isolated system. Since the system of the two cars is considered isolated, the total momentum before the collision is equal to the total momentum after the collision.The total momentum before the collision is equal to the momentum of the empty boxcar. The momentum of the empty boxcar is equal to 9000 kg multiplied by 3.0 m/s, which is 27000 kg m/s.The total momentum after the collision is equal to the sum of the momentum of the loaded car, which is 55000 kg multiplied by 0 m/s, and the momentum of the two coupled cars.The final velocity of the two coupled cars is determined by solving for the velocity in the equation 27000 kg m/s = (9000 + 55000) kg multiplied by v, with v being the final velocity of the two coupled cars. The final velocity of the two coupled cars is equal to 2.4 m/s.To learn more about The final velocity refer to:
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a hot rod of mass 1000 kg, starting from rest reaches a speed of 130 m/s in only 29 s. what is the average output power?
A 1000 kilogramme FRICTION is driving at a pace of 130 metres per second. To bring a car to a stop, the brakes are applied. Hence, 223 J is the average output power
What causes road friction?To prevent sliding vehicles or spinning wheels, friction or traction are essential. The act of rubbing one surface or object against another is known as friction. The maximum acceleration and shortest stopping distance are determined by the friction between the tyres of your car and the road.
Is the friction on tyre roads static?Because there is only frictional force acting on the car, friction is acting backwards. The amount of friction that can be applied to a vehicle's tyres to prevent road traction is as high as.
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How many joules of solar energy fall on your back as you work on your tan for 1. 5 h ? express?
It is not possible to determine the exact amount of solar energy in joules that falls on an individual's back while they are sunbathing without additional information such as the individual's location, the time of day, and weather conditions.
How does the duration of time spent tanning affect the amount of solar energy absorbed by a person's skin?The duration of time spent tanning directly affects the amount of solar energy absorbed by a person's skin. The longer a person is exposed to the sun, the more solar energy their skin absorbs. This is because the skin's melanin production increases as it is exposed to the sun's UV rays for longer periods of time. Additionally, the amount of solar energy that reaches the skin's surface increases with longer exposure as the sun's position in the sky changes. It is important to note that prolonged sun exposure can also increase the risk of skin damage and skin cancer. Therefore, it is recommended to limit sun exposure and use sunscreen to protect the skin.
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You are pushing a book across a desk with a constant velocity. What are the forces acting on the book and in what direction? Are the y-forces equal in magnitude, why or why not? Are the x-forces equal in magnitude, why or why not? Explain using Newton’s Second Law. If you push on the book, according to Newton’s Third Law of Motion, what is the equal and reactive force?
When you are pushing a book across a desk with a constant velocity, there are two forces acting on the book: friction and the force of your push.
The force of friction acts in the opposite direction to the motion of the book and opposes the motion of the book. The force of friction is caused by the interaction between the bottom surface of the book and the surface of the desk.
The force of your push acts in the same direction as the motion of the book and causes the book to move.
The y-forces on the book are not equal in magnitude, as there is only one force acting in the y-direction, which is the force of friction. The x-forces are also not equal in magnitude, as there is one force acting in the x-direction, which is the force of your push.
According to Newton's Second Law, the force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, since the book is moving with a constant velocity, the forces acting on the book are balanced, and the net force on the book is zero.
According to Newton's Third Law of Motion, for every action, there is an equal and opposite reaction. So, when you push on the book, the equal and opposite force is the force exerted by the book on your hand.
Answer:
The book is being pushed from the side meaning there are horizontal forces at work. The first is an applied force, the second is a force of friction against the motion. Since the book is moving at a constant velocity, the book is not accelerating. This means that the forces must be balanced.
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