An electric charge at rest produce

Answers

Answer 1

Answer:

Charge at rest only produces electric field. Moving charge produces both electric field and magnetic field.

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Related Questions

When the material in the mantle cools off near the surface then sinks
down towards the core and get heated again and rises back towards the
surface it is called?
Condensation
О
The water cycle
O
Convection currents
О
Apples and Bananas.
PLEASE HELP THIS IS URGENT ITS FOR A TEST

Answers

I’m guessing convection currents since you mention mantle and core, reminds me of heat

Answer:

convection currents

Explanation:

Peter, a 100 kg basketball player, lands on his feet after completing a slam dunk and then immediately jumps up again to celebrate his basket. When his feet first touch the floor after the dunk, his velocity is 5 m/s downward; when his feet leave the floor 0.50 s later, as he jumps back up, his velocity is 4 m/s upward. a. What is the impulse exerted on Peter during this 0.50 s

Answers

Answer:

Explanation:

Impulse = change in momentum

Initial momentum = mass x initial velocity = 100 x 5 = 500 kg m/s

final momentum = mass x final velocity = 100 x - 4 = -400 ( - ve sign due to reversal of direction )

change in momentum = final momentum - initial momentum

= - 400 - 500 = - 900 kg m/s .

As it is - ve , it acts upwards .

So magnitude of  impulse on Perter = 900 kg m/s

A warm hockey puck has a coefficient of restitution of 0.50, while a frozen hockey puck has a coefficient of restitution of only 0.35. In the NHL, the pucks to be used in games are kept frozen. During a game, the referee retrieves a puck from the cooler to restart play but is told by the equipment manager that several warm pucks were just put into the cooler. To check to make sure he has a game-ready puck, the referee drops the puck on its side from a height of 2 m. How high should the puck bounce if it is a frozen puck

Answers

Answer:

the required height is 0.2449 m only

Explanation:

Given the data in the question;

Initial height = 2m

so speed of the puck before hitting the ground will be;

u² = 2gh

Initial speed u_ball = √2gh

u_ball = √( 2 × 9.8 × 2 )

u_ball =  √39.2

u_ball = 6.26 m/s

given that; FOR THE FROZEN PUCK, coefficient of restitution = 0.35 only

R = - (v_ball - v_ground / u_ball - u_ ground)

so

0.35 = - (v_ball - 0 / 6.26 - 0)

0.35 = -v_ball / - 6.26

-v_ball = 0.35 × (- 6.26)

-v_ball = -2.191 m/s

v_ball = 2.191 m/s

to get the height;

v² = 2gh

h = v² / 2g

we substitute

h = (2.191)² / 2×9.8

h = 4.800481 / 19.6

h = 0.2449 m

Therefore, the required height is 0.2449 m only

Which subatomic particle is NOT found in the nucleus of an atom? *

protons
neutrons
electrons

Answers

Answer:

Electrons

Explanation:

Only Protons and Neutrons are found in the nucleus

electrons, only protons and neutrons are found within the nucleus.

Describe the political actions that led to successful conservation in both stories.

Answers

Answer:

The political actions that led to successful conservation in both stories were what they call an FC company that makes the forest industry true. They make it out of a factory and it can make it very successful and accomplished.

Explanation:

a. Use the graph and the element made in question 2 to determine the mass of the star.

Answers

Black balls with blue waffles

How much force does it take to give a 70 kg object an acceleration of 20 mls2

Answers

Answer:

heyy

Explanation:how r uuu

a sensor light installed on the edge of a home can detect motion for a distance of 50 feet in front and with a range of motion of 200 degrees. what is the arc length of the area covered

Answers

Answer:

4363.3231 feets²

Explanation:

Given that :

Distance, r = 50 ft

θ = 200°

The arc length of area covered :

Arc length = θ/360° * πr²

Arc length = (200/360) * 50 ft ^2 * π

Arc length = 0.5555555 * 2500 * π

Arc length = 4363.3231 feets²

50 points Two waves combine with constructive interference. What must be true of the
combined wave that forms?
A. It has a lower frequency than that of the original waves.
B. It has a higher amplitude than that of the original waves.
C. It has a higher frequency than that of the original waves.
D. It has a lower amplitude than that of the original waves.

Answers

Answer:

it has a higher amplitude than that of the original waves

Explanation:

trust me its right

The two waves combined with constructive interference have a higher amplitude than the original wave.

Which wave has the highest amplitude?

High energy waves are characterized by high amplitude. Low energy waves are characterized by their small amplitude. As explained in Lesson 2, wave amplitude is the maximum amount of particle movement on a medium from a resting position.

What are superposition and interference?

Superposition is a combination of two waves in the same place. Constructive interference occurs when two identical waves interfere in phase. Destructive interference occurs when two identical waves are exactly out of phase and overlap.

Learn more about higher amplitude waves at

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The Moon has a smaller mass than the Earth. If you were to travel to the moon your weight would....
A Increase
B Decrease
C Stay the Same
D Vary with day and night

Answers

Answer:The Moon has a smaller mass than the Earth. If you were to travel to the moon your weight would..

Explanation: It would decrease.

The Moon has a smaller mass than the Earth. If you were to travel to the moon your weight would decrease because the acceleration due by gravity on the moon is less than the acceleration due to gravity on the earth, therefore the correct answer is option C.

What is gravity?

It can be defined as the force by which a body attracts another body towards its center as the result of the gravitational pull of one body and another.

In comparison to the Earth, the Moon is less massive. Your weight would drop if you traveled to the moon because the acceleration caused by gravity there is lower than that caused by gravity here on Earth.

As a result of the less gravity on the moon, the weight would decrease.

Thus, the correct answer is option C.

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A wheelbarrow is pushed 10 meters with a force of 75 N for 30 seconds. What is the work done?
How much power is needed?

Answers

I’ll figure this out just give me 5 minutes
Work done= force(N) x distance moved in the direction of force. (m)
Power= work done/ time taken.
Work done = 75N x 10m
= 750Nm/ 750J( Joules)* joules is the SI unit of work.

Power is the rate at which work is done. Suppose two men were carrying a heavy box, man A has a force of 10N , man B has a force of 10N and both carries the box of a distance 3m. Both have done the same work. But if suppose man A takes 2 seconds to carry the box while man B takes 3 seconds, their power needed are different.
Man A , power= 30J/ 2s which is 15 joules per second ( SI unit of power is “watts”)
Man B, power= 30J/ 3s which is 10 joules per second. MAN A HAS MORE POWER.

so, the work done for the wheelbarrow is 750J, divide it by the time taken( 30 seconds) 750J/30s= 25 J/s. <— this is the power needed.

20 points!!!! A 2,00ON steel rod that is 5 meters long is placed in a corner between the floor and a wall, and balanced at an angle using a cord attached to the wall The rod is balanced such that its top end is 2.38 meters away from the wall, The cord is 40 cm long, and it is attached to the wall at a height of 75 cm above the floor. The diagram to the right shows the situation If the lower end of the rod does not slip from the corner, what is the tension in the cord?

Answers

Answer:

WE NEED TO ADD ALL 40+2.38 +75+5

Explanation:

PLSE GIVE SOME POINTS DUDE

Which is an advantage of storing data digitally?
A. It is easy to change the data if you have the right computer
programs.
B. It is easy to copy a computer virus to a device along with the data.
C. The quality of copies decrease as more copies are made.
D. Other people can access personal data from unsecured devices.

Answers

Answer:

A

Explanation:

Because I said so

Answer:

A

Explanation:

i took the test and got it right please mark me ❤️

What inspired Ronald McNair to do science

Answers

Answer:

While working as a staff physicist at hughes Research Laboratories McNair learned that the National Aeronautics and Space Administration (NASA) was looking for scientist to join the shuttle program;)

There is a very long straw of charge that is uniformly charged in electro static equilibrium. It has a charge per unit length of 4.0E-9 C/m (4.0 nC/m) and a radius of 0.5 m. What is the strength of the electric field a distance of 10.0 m from its center outside the straw

Answers

Answer:

2880 N/c

Explanation:

Given that:

Charge per unit length ; λ = 4 * 10^-9

radius, r = 10

Radius, R = 0.5m

Using the relation :

2λr / 4πE0R²

Columb's constant, k = 1/4πE0 =. 9* 10^9Nm²/C²

Hence, we have :

2λrk/ R²

(2 * 4 * 10^-9 * 10 * 9 * 10^9) / 0.5^2

(720 ÷ 0.25)

= 2880 N/c

Which of these is an effect of gravity?
А
A cup placed on a table won't float away.
B
You can throw a ball or a rock up.
С
The brakes on a bike can make it stop.
D
Liquid water can become a gas.

Answers

Answer:

(A)

A cup placed on a table won't float away

Which of the following variables can be measured in joules?
A. momentum
B. Energy
C. Power
D. Work

Answers

Answer:

The variables that can be measured in joules are

B. Energy

D. Work

Hope it will help :)

Orion, also called the Hunter, has three stars that make up Orion's belt.

Which star is at the tip of the arrow? PLEASE HELP I NEED THIS FAST


A. Sirius


B. Betelgeuse


C. Rigel


D. Polaris

Answers

Answer - B. Betelguese.

I really hope this helps!!

A ball is rolling with a constant acceleration of 13 m/s starting from rest. How long will it take to increase its velocity to a final speed of 62 m/s? ​

Answers

Time taken : 4.77 s

Further explanation

Given

a = 13 m/s²

vf = final velocity = 62 m/s

Required

time taken

Solution

An equation of uniformly accelerated motion  

[tex]\large {\boxed {\bold {x=xo+vo.t+\frac {1} {2} at ^ 2}}}[/tex]

vf = vo + at  

vf² = vo² + 2a (x-xo)  

x = distance on t  

vo / vi = initial speed  

vt / vf = speed on t / final speed  

a = acceleration  

Input the value :

vo =0 ⇒from rest

vf=at

62 m/s = 13 m/s².t

t = 62 : 13

t = 4.77 s

Thomas knows that many machines transform electrical energy into other forms of energy

Answers

Question:-
So? Gd for him though

Answer:

Only the car transforms electrical energy into more than one form of energy.

Explanation:

The motion of the car is mechanical energy but it can also transform into another energy witch is electrical energy

Suppose a car is traveling at 22.8 m/s, and the driver sees a traffic light turn red. After 0.404 s has elapsed (the reaction time), the driver applies the brakes, and the car decelerates at 9.00 m/s2. What is the stopping distance of the car, as measured from the point where the driver first notices the red light?

Answers

Answer:

38.09 m

Explanation:

We'll begin by calculating the distance travelled by the car during the reaction time. This can be obtained as follow:

Reaction time (tᵣ) = 0.404 s

Initial velocity (u) = 22.8 m/s,

Distance travelled during the reaction time (sᵣ) =?

sᵣ = utᵣ

sᵣ = 22.8 × 0.404

sᵣ = 9.21 m

Next, we shall determine the distance travelled by the car when the brake was applied. This can be obtained as follow:

Initial velocity (u) = 22.8 m/s

Acceleration (a) = –9 m/s² (since the car is decelerating)

Final velocity (v) = 0 m/s

Distance travelled when the brake was applied (s₆) =?

v² = u² + 2as₆

0² = 22.8² + (2 × –9 × s₆)

0 = 519.84 – 18s₆

Collect like terms

0 – 519.84 = –18s₆

–519.84 = –18s₆

Divide both side by –18

s₆ = –519.84 / –18

s₆ = 28.88 m

Finally, we shall determine the stopping distance of the car, as measured from the point where the driver first notices the red light. This can be obtained as follow:

Distance travelled during the reaction time (sᵣ) = 9.21 m

Distance travelled when the brake was applied (s₆) = 28.88 m

Stopping distance =?

Stopping distance = sᵣ + s₆

Stopping distance = 9.21 + 28.88

Stopping distance = 38.09 m

On a level test track, a car with antilock brakes and 90% braking efficiency is determined to have a theoretical stopping distance (ignoring aerodynamic resistance) of 408 ft (after the brakes are applied) from 100 mi/h. The car is rear-wheel drive with a 110-inch wheelbase, weighs 3200 lb, and has a 50/50 weight distribution (front and back), a center of gravity that is 22 inches above the road surface, an engine that generates 300 ft-lb of torque, and overall gear reduction of 8.5 to 1 (in first gear), a wheel radius of 15 inches and a driveline efficiency of 95%. What is the maximum acceleration from the rest of this car on this test track

Answers

Answer:

a = 30.832 ft/s²

Explanation:

To solve this problem let's start by finding the braking acceleration using kinematics, where the distance is x = 408 ft, the initial velocity vo = 100 mi / h and the final velocity is zero v = 0

           v² = v₀² - 2 a x

           0 = v₀² - 2ax

           a = [tex]\frac{v_o^2}{2x}[/tex]

Let's start by reducing the magnitudes to ft / s              

            v₀ = 100 mi / h (5280 foot / 1 mile) (1h / 3600 s) = 146.666 ft / s

           

let's calculate

         a = [tex]\frac{146.66^2}{2 \ 408}[/tex]

         a = 26.36 ft / s²

Let's call this acceleration a_effective, this acceleration is in the opposite direction to the speed of the vehicle.  

Let's use a rule of three (direct proportions) to find the acceleration applied by the brake system (a1) which has an efficiency of 95%. or 0.95

                 a₁ = [tex]\frac{a_e}{0.95}[/tex]

Let's use another direct proportion rule If the acceleration of the brake system (a₁) for an applied acceleration (a) with an efficiency of 0.90

           a = [tex]\frac{a_1}{0.90}[/tex]

we substitute

           a = [tex]\frac{a_e}{0.95 \ 0.90}[/tex]

           

let's calculate

           a = [tex]\frac{26.36}{ 0.95 \ 0.90}[/tex]

           a = 30.832 ft/s²

This is the maximum relationship that the vehicle can have for when it brakes to stop at the given distance

A 200-N force acts on a 10-kg object. The acceleration of the object is

Answers

200N/10kg = 20 m/s^2

You are inside the Great Hall, 15 m from the north wall with the doors to the RMC, and centered between two open doors that are 3 m apart. Someone is blairing a 200 Hz tone outside the Great Hall so that it enters the doors as a plane wave. You hear a maximum intensity in your current position. As you walk along the direction of the wall with the doors (but maintain a distance 15 m from the wall), how far will you walk (in m) to hear a minimum in the sound intensity

Answers

Answer:

Δr = 0.425 m

Explanation:

This is a sound interference exercise, the expression for destructive interference is

          Δr = (2n + 1) λ / 2

in this case the movement is in the same direction as the sound, therefore the movement is one-dimensional

let's use the relationship between the speed of sound and its frequency and wavelength

          v = λ f

          λ = v / f

the first minium occurs for n = 0

           Δr = λ / 2

            Δr = v / 2f

            Δr = [tex]\frac{340}{2 \ 400}[/tex]

             Δr = 0.425 m

this is the distance from the current position that we assume in the center of the room

A clump of soft clay is thrown horizontally from 9.80 m above the ground with a speed of 20.0 m/s. Assume it sticks in place when it hits the ground At what time will the clay hit the ground

Answers

Answer:

Explanation:

The time to hit the ground will be same as time taken to fall from the height of 9.8 m with initial vertical velocity of zero .

Considering vertical displacement

initial velocity u = 0

displacement s = 9.8 m

acceleration a = g = 9.8 m /s²

time t = ?

s = ut + 1/2 g t²

9.8 = 0 + .5 x 9.8 x t²

t² = 2

t = √2 = 1.4 s

a 90 kilogram dog runs across the dog park at a speed of 6.5 meters per second. what is the magnitude and direction of the average force required to stop the dog in .85 seconds?

Answers

Answer:

am not sure about the answer

Explanation:

you need to find out the amount of force it's going in for example 10n or 100n then you need to times it the distance then devide by the time

I have a massive rock weighing 3,000 Newtons but I can only accelerate it to 500 m/s2 what is its mass?

Answers

Answer:

6 kg

Explanation:

F=ma

F is Force(newtons)

m is mass(kg)

a is acceleration(m/s^2)

Plug in the numbers

3000 = m(500)

divide both sides by 500 to cancel out the 500.

3000/500=6

6 = m

6kg is the mass

which particles do not affect the stability of the atom

Answers

electrons


20charachters

Electrons are the particle pr4esent inside the atom that does not affect the stability of the atom,

What is radioactivity?

The ability of some unstable atoms to emit nuclear radiation spontaneously, typically in the form of alpha or beta particles frequently accompanied by gamma rays, is known as radioactivity.

An overabundance of neutrons or protons can make the nucleus of an atom unstable.

A radioactivity atom will try to become stable by extruding other particles, such as protons or neutrons, or by releasing energy in various ways.

Thus, Electrons are the particle present inside the atom that does not affect the stability of the atom,

To learn more about radioactivity here, refer to the link;

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A single, monochromatic indigo light source is shined through an etched, flat prism with a slit separation of .0250mm. The resulting interference pattern is viewed on a screen 1.25m away. The third maximum is found to be 6.6cm from the central maximum. What is the wavelength of the indigo light

Answers

Answer:

  λ = 440 nm

Explanation:

The phenomenon of constructive interference is described by the expressions

          d sin θ= m λ                    (1)

where d is the separation of the slits d = 0.0250 mm = 2.50 10⁻⁵ m, lam is the wavelength of the incident radiation and m is an integer indicating the order of interference

let's use trigonometry to find the angle

          tan θ = y / L

where L is the distance to the screen L = 1.25 m

in general interference experiments angles are very small

         tan θ = [tex]\frac{sin \ \theta }{cos \ \theta}[/tex]

         ten θ = sin θ

substituting

           

         sin θ = y / L

we substitute 1

          d y / L = m λ

          λ = [tex]\frac{ d \ y }{m \ L}[/tex]

in the exercise indicate

        m = 3

         y = 6.6 cm = 6.6 10-2 m

we calculate

          λ = 2.50 10⁻⁵ 6.6 10⁻² /( 3   1.25)

          λ = 4.4 10⁻⁷ m

let's reduce to nm

          λ = 4.4 10⁻⁷ m (10⁹ nm / 1 m)

          λ = 440 nm

Analyze the data to identify the mathematical relationship between the
amplitude and energy of a mechanical wave. If mechanical wave A has an
amplitude of 4 cm and mechanical wave B has an amplitude of 5 cm, what
will be the relationship between the energy carried by the two waves?
Amplitude
Energy
A. Wave A has about 1.25 times more energy than wave B.
ОО
B. Wave A has about 1.6 times more energy twan wave B.
C. Wave B has about 1.6 times more energy than wave A.
O D. Wave A has about 1.15 times more energy than wave B.

Answers

Answer:

Its C

Explanation:

Because I got it wrong for you

Wave B has about 1.6 times more energy than wave A.

What is energy?

Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.

The amplitude and energy of a mechanical wave. If mechanical wave A has an amplitude of 4 cm and mechanical wave B has an amplitude of 5 cm wave B has about 1.6 times more energy than wave A.

Wave B has about 1.6 times more energy than wave A.

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