An arborist examined trees in an orchard to see if they were infected with a virus. 21 out of 28 trees were infected with the virus. What percentage of the trees were infected?

Answer:

Volume is dependent on how hard the air is pushed through. Sound travels more slowly than light. Sound waves travel at the same speed, but vibrate in different ways. Some vibrate quickly and have a high frequency or pitch, while others vibrate slowly and give a lower pitch.

Step-by-step explanation:

I hope this helps :)

Answer: look up alaskan pipeline

Step-by-step explanation:

Answer:

3x+48

add 3+45=48

Step-by-step explanation:

Hope this helps! Please consider marking brainliest! I hope you have an amazing day. Always remember, your smart and you got this! -Alycia :)

Answer:

3(x+16)

Step-by-step explanation:

45+3=48

3x/3=x

48/3=16

3(x+16)

Answer:

(-2, -4)

Step-by-step explanation:

I Hope this helps you out!

Answer:

(-2,-4)

Answer:

n <−4

42 - 28n + 4n >138

42 - 24n >138

-24n > 138 - 42

-24n >96

n <−96/24

N <−4

Answer:

the answer is E because the shape is still in the same directions, so it wasn't reflected it was just translated

Step-by-step explanation:

Answer:

5.5

Step-by-step explanation:

Answer: actually 5.504 rounded to 5.5

Step-by-step explanation:

Answer:

it will be C) SAS(side angle side)

I did 40+32 in got 72

Or 40-32=8

Answer:

0.222 as a decimal

111/500 as a fraction

22.2 as a %

The properties of items in a question can be used to simplify the solution to the questions

The area of triangle ΔABD is 20 - 4·√3

The reason the above value for the area of ΔABD is correct is as follows:

The given parameters are;

AB = AD, BC = CD, BE = 2, BC = 4, AC = 10

Given that AB = AD, and BC = CD, we have that the figure ABCD is a kite

∴ AC is perpendicular to BD by properties of the diagonals of a kite

ΔBCE is a right triangle

By Pythagoras' theorem, [tex]\overline{CE}[/tex]² = [tex]\overline{BC}[/tex]² - [tex]\overline{BE}[/tex]²

Which gives;

[tex]\overline{CE}[/tex]² = 4² - 2² = 12

[tex]\overline{CE}[/tex] = 2·√3

Given that AC is the perpendicular bisector of BD, by the properties of a kite, we have;

BD = BE + DE, where BE = DE definition of bisected line

∴ BD = BE + BE = 2·BE

Area of a triangle = (1/2) × Base length × Height

AE = The altitude (height) of the ΔABD = AC - CE

∴ AE = 10 - 2·√3

BD = The base length of ΔABD = 2·BE (Length of BE = 2)

∴ BD = 2 × 2 = 4

The area of triangle ΔABD = (1/2) × BD × AE

∴ The area of triangle ΔABD = (1/2) × 4 × (10 - 2·√3) = 20 - 4·√3

The area of triangle ΔABD = 20 - 4·√3

Learn more about the properties of a kite here:

https://brainly.com/question/24110637

Answer:

boop boop beep bop

Step-by-step explanation:

Im nice heheh

roight?

Answer:

Yes, they do.

Step-by-step explanation:

They both pass through the same points of -2 on the x and y axis.

Answer:

38 inches

Step-by-step explanation:

just add them all together.

Answer:

75 single servings

Step-by-step explanation:

First multiply

40*5/8

You’ll get 25

now 40-25=15

Using 15

15 divided by 1/5

15÷1/5

keep change flip

15*5

75

Answer:

75 servings

Step-by-step explanation:

1. Form an equation

As per the given information;

- starts with 40 cups of juice

- uses 5/8 of the juice

-Splits the remaining serving amongst people, giving each person (1/5) of a cup

Hence the equation is;

(40 - [tex]\frac{5}{8}[/tex](40)) ÷ [tex]\frac{1}{5}[/tex]

2. Solve the equation

(40 - [tex]\frac{5}{8}[/tex](40)) ÷ [tex]\frac{1}{5}[/tex]

Simplify;

(40 - 25) ÷ [tex]\frac{1}{5}[/tex]

Dividing by a fraction is the same as multiplying by the fraction's reciprocal;

(40 - 25) * 5

Follow the order of operations, remember the order of operations are;

1. parenthesis

2. exponents

3. multiplication, division

4. addition, subtraction

Parenthsis first

(40 - 25) * 5

15 * 5

Multiply next

15 * 5

75

Answer:

[tex]\cos(A + B) = \frac{23}{265}[/tex]

Step-by-step explanation:

Given

[tex]\tan A=\frac{28}{45}[/tex]

[tex]\cos B=\frac{3}{5}[/tex]

Required

[tex]\cos(A+B)[/tex]

In trigonometry:

[tex]\cos(A+B) = \cos\ A\ cosB - sinA\ sinB[/tex]

We need to solve for cosA, sinA and sinB

Given that:

[tex]\tan A=\frac{28}{45}[/tex] and the tangent of an angle is a ratio of the opposite side (x) to the adjacent side (y),

So, we have:

[tex]x =28[/tex] and [tex]y = 45[/tex]

For this angle A, we need t calculate its hypotenuse (z).

Using Pythagoras,

[tex]z^2 = x^2 + y^2[/tex]

[tex]z = \sqrt{x^2 + y^2[/tex]

[tex]z = \sqrt{28^2 + 45^2[/tex]

[tex]z = \sqrt{2809[/tex]

[tex]z = 53[/tex]

From here, we can calculate sin and cos A

[tex]\sin A= \frac{opposite}{hypotenuse}[/tex] and [tex]\cos A= \frac{adjacent}{hypotenuse}[/tex]

[tex]\sin A= \frac{x}{z}[/tex]

[tex]\sin A= \frac{28}{53}[/tex]

[tex]\cos A= \frac{y}{z}[/tex]

[tex]\cos A= \frac{45}{53}[/tex]

To angle B.

Give that

[tex]\cos B=\frac{3}{5}[/tex] and the cosine of an angle is a ratio of the adjacent side (a) to the hypotenuse side (c),

So, we have:

[tex]a = 3[/tex] and [tex]b = 5[/tex]

For this angle B, we need to calculate its opposite (b).

Using Pythagoras,

[tex]c^2 = a^2 + b^2[/tex]

[tex]5^2 = 3^2 + b^2[/tex]

[tex]25 = 9 + b^2[/tex]

Collect like terms

[tex]b^2 = 25 - 9[/tex]

[tex]b^2 = 16[/tex]

[tex]b = \sqrt{16[/tex]

[tex]b = 4[/tex]

From here, we can calculate sin B

[tex]\sin B= \frac{opposite}{hypotenuse}[/tex]

[tex]\sin B = \frac{b}{c}[/tex]

[tex]\sin B = \frac{4}{5}[/tex]

Recall that:

[tex]\cos(A+B) = \cos\ A\ cosB - sinA\ sinB[/tex]

and

[tex]\cos B=\frac{3}{5}[/tex]      [tex]\sin B = \frac{4}{5}[/tex]       [tex]\sin A= \frac{28}{53}[/tex]      [tex]\cos A= \frac{45}{53}[/tex]

[tex]\cos(A + B) = \frac{45}{53} * \frac{3}{5} - \frac{28}{53} * \frac{4}{5}[/tex]

[tex]\cos(A + B) = \frac{135}{265} - \frac{112}{265}[/tex]

[tex]\cos(A + B) = \frac{135-112}{265}[/tex]

[tex]\cos(A + B) = \frac{23}{265}[/tex]

The value of [tex]\cos (A+B)[/tex] is [tex]-\frac{96}{265}[/tex].

Trigonometrically speaking, the sine, cosine and tangent of an angle are described by the following formulas:

[tex]\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}}[/tex] (1)

[tex]\cos \theta = \frac{x}{\sqrt{x^{2}+y^{2}}}[/tex] (2)

[tex]\tan \theta = \frac{y}{x}[/tex] (3)

Where:

And we have the following trigonometric identity for the cosine of the sum of angles:

[tex]\cos (A+B) = \cos A\cdot \cos B - \sin A \cdot \sin B[/tex] (4)

By (1) and (2), we rewrite (4):

[tex]\cos (A+B) = \frac{x_{A}\cdot x_{B}}{\sqrt{x_{A}^{2}+y_{A}^{2}}\cdot \sqrt{x_{B}^{2}+y_{B}^{2}}} - \frac{y_{A}\cdot y_{B}}{\sqrt{x_{A}^{2}+y_{A}^{2}}\cdot \sqrt{x_{B}^{2}+y_{B}^{2}}}[/tex]

If we know that [tex]x_{A} = 28[/tex], [tex]y_{A} = 45[/tex], [tex]x_{B} = 3[/tex] and [tex]y_{B} = 4[/tex], then the cosine for the sum of angles is:

[tex]\cos (A+B) = \frac{28\cdot 3}{\sqrt{28^{2}+45^{2}}\cdot \sqrt{3^{2}+4^{2}}}-\frac{45\cdot 4}{\sqrt{28^{2}+45^{2}}\cdot \sqrt{3^{2}+4^{2}}}[/tex]

[tex]\cos (A+B) = -\frac{96}{265}[/tex]

The value of [tex]\cos (A+B)[/tex] is [tex]-\frac{96}{265}[/tex].

We kindly invite to check this question on trigonometric identities: https://brainly.com/question/24836845

Answer:

48.75

Step-by-step explanation:

The customer will save interest by paying off a credit debt is $1,800 at the end of 1 year instead of at the end of 3 years

Simple interest is the concept that is used in many companies such as banking, finance, automobile, and so on.

A customer has a credit card that charges 18% simple interest every year.

The customer saves by paying off a credit card debt of $5,000 at the end of 1 year instead of at the end of 3 years.

Interest for three years will be

[tex]\rm A_3 = \dfrac{PRT}{100}\\\\\\A_3= \dfrac{5000*18*3}{100}\\\\\\A_3= 2700[/tex]

Interest for one year will be

[tex]\rm A_1 = \dfrac{PRT}{100}\\\\\\A_1= \dfrac{5000*18*1}{100}\\\\\\A_1= 900[/tex]

The saved amount will be

A = A₃ - A₁

A = 2700 - 900

A = 1800

The customer will save interest by paying off a credit debt is $1,800 at the end of 1 year instead of at the end of 3 years

More about the simple interest link is given below.

https://brainly.com/question/2793278

Given :

Amount, A = 5760 Rs.

Interest in the amount, I = 1526 Rs.

To Find :

We need to find the % rate of interest.

Solution :

Let, us assume it is simple interest.

So,

[tex]Interest = \dfrac{price \times rate \times time}{100}\\\\1526 = \dfrac{5760 \times r \times m}{100}\\\\r = \dfrac{152600}{5760m}\\\\r = \dfrac{26.5}{m}[/tex]

Hence, this is the required solution.

Answer:

A is a function

Step-by-step explanation:

Hope the image helps.

Answer:

B.

Step-by-step explanation:

Subtract 45 from both sides first. Then divide by 4.

Answer:

Subtract 45 from both sides to eliminate that number

Step-by-step explanation:

Answer:

Step-by-step explanation:

jordan traveled 255 miles out of 340 miles

340 miles.........................100 %

255 miles..........................   ?

255*100=2500/340=73%

See attachment for math work and answer.

Answer:

clockwise

Q= (5,-2)

R= (-1,-3)

S= (0,0)

T= (3,-2)

counterclockwise

Q= (-5,2)

R= (1,3)

S= (0,0)

T= (-3,-2)

Step-by-step explanation:

this might not be right im a little rusty on my transformations but here goes nothing.

i dont know if this is a clockwise or a counter clockwise rotation so ill do both options.

clockwise (x,y) - (y,-x)

q=(2,5) - (5,-2)

r=(3,-1) - (-1,-3)

s=(0,0) - (0,0)

t=(-2,3) - (3,2)

counterclockwise (x,y) - (-y,x)

q=(2,5) - (-5,2)

r=(3,-1) - (1,3)

s=(0,0) - (0,0)

t=(-2,3) - (-3,-2)