Answer:
14.8J
Explanation:
PE=MGH
M=0.21
G=9.8m/s
H= 7.2 m
0.21x7.2x9.8= 14.8176 J
Suppose that two objects attract each other with a gravitational force of 16 units. If the mass of both objects was tripled, and if the distance between the objects was doubled, then what would be the new force of attraction between the two objects?
Answer:
The new force of attraction would be 36 units
Explanation:
Law of Universal Gravitation
Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.
This statement can be expressed with the formula:
[tex]\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]
Where:
m1 = mass of object 1
m2 = mass of object 2
r = distance between the objects' center of masses
G = gravitational constant: [tex]6.67\cdot 10^{-11}~Nw*m^2/Kg^2[/tex]
Now suppose two given objects attract with a force of F=16 units, thus:
[tex]\displaystyle G{\frac {m_{1}m_{2}}{r^{2}}}=16[/tex]
And now the masses of both objects is tripled, i.e., m1'=3m1, m2'=3m2, and the distance between them is doubled, r'=2r. The new force is:
[tex]\displaystyle F'=G{\frac {3m_{1}3m_{2}}{(2r)^{2}}}[/tex]
Operating:
[tex]\displaystyle F'=G{\frac {9m_{1}m_{2}}{4r^{2}}}[/tex]
[tex]\displaystyle F'=\frac{9}{4}G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]
Substituting the value of the initial force:
[tex]\displaystyle F'=\frac{9}{4}\cdot 16[/tex]
[tex]F'=36\ units[/tex]
The new force of attraction would be 36 units
Problems - Show all work.
1. A carnival ride has a radius of 10.00 m and rotates at a speed of 3.00 m/s. Find the period of one complete revolution.
Given:
r=
v=
Unknown:
T=?
Equation:
v=2*pi*r/T
Answer:
21s
Explanation:
Given parameters;
Radius = 10m
Speed or velocity = 3m/s
Unknown:
Period = ?
Solution:
To solve this problem, use the expression:
v = [tex]\frac{2\pi r}{T}[/tex]
r is the radius
T is the unknown
Input the parameters and solve for T;
3 = [tex]\frac{2 x \pi x 10}{T}[/tex]
62.84 = 3T
T = 21s
current is a ______ quantity.
scalar or vector
Answer:
vector quantity............
Explanation:
Mark me braimlist
Answer:
scalar
Explanation:
why does the fire snake weight less than it was when it was on fire
Answer:
When Zoe weighs the ingredients (sugar and baking soda), it weighs 25 grams in total. When she weighs the “snake” it weighs 23 grams. This is because some carbon dioxide gas produced during the chemical reaction escapes into the air.
a ball is thrown vertically upwards from the ground. The ball rises and falls back to the ground. Describe the changes in the mechanical energy of the ball as it rises.
Answer:
as the ball is thrown, the enegry rises up, when it falls, the ball relseases all energy
Explanation:
if a 60 kg person was standing on a platform at the surface of saturn and they jumped, they would have to push with a force greater than..?
Answer:
A 60 kg person standing on a platform at the surface of Saturn and they jumped, they would have to push with a force greater than 540 N
Explanation:
The gravitational attraction between an object on the surface of a planet and the planet is given by the weight of the object
Therefore the force needed to be applied for an object to lift off the surface of a planet = The weight of the object
The weight of the object on the surface of a planet = m × g
Where;
m = The mass of the object
g = The strength of gravity on the planet's surface in N/kg
The given parameters are;
The mass of the person standing on a platform at the surface of Saturn, m = 60 kg
The strength of gravity on the surface of Saturn = 9 N/kg
Therefore, we have;
The weight of the person = The force greater than which the person would have to push on the surface of Saturn so as to Jump = The weight of the person on the surface of Saturn = 60 kg × 9 N/kg = 540 N
Therefore, for a 60 kg person standing on a platform at the surface of Saturn and they jumped, they would have to push with a force greater than 540 N.
Given the impulse acting on an object and the impact time which equation can be used to calculate the force applied to an object
Answer is D
Ndmdjdndbdjdkskd
The impulse acting on an object and the impact time, the equation F= I / Δt can be used to calculate the force applied to an object, therefore the correct answer is D.
What is impulse?The product of the average applied force and the time for which it is exerted is known as an impulse.
the mathematical relation for impulse is
Impulse = F * Δt
where F represents the force applied and Δt represents the time for which the force is applied
Thus, the correct equation that can be used to calculate the force applied to an object is F = I /Δt and the correct option is D.
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A bungee jumper starts with 1000 J in their GPE store. After they jump they fall and are brought to a stop with the bungee cord. With the cord fully stretched what is the energy in the EPE store?
Answer:
energy is equal to 1000 J
Explanation:
When the jumper is in the tent, he has a given height, this height gives him a gravitational potential energy, which forms his initial mechanical energy of 1000 J. After jumping, this energy is converted into elastic energy of the rope plus a remainder of potential energy gravitational, it does not reach the ground, but as the friction is negligible the total mechanical energy is conserved, therefore its energy is equal to 1000 J
This is a case of energy transformation, but the total value of mechanical energy does not change
How can we transfer a table of motion data into a line graph?
Answer:
A table of motion (for a moving object) usually is something like:
Time I Position:
0s 1m
1s 3m
2s 5m
etc...
Where time is the independent variable and position represents the position of the object at that given time.
We can think in these points as coordinate pairs, for example, we can wrote these 3 pairs as:
(0s, 1m)
(1s, 3m)
(2s, 5m)
Now that we have these points, we can go to a coordinate plane and find these points
(The time would be on the horizontal axis, and position in the vertical axis)
Once you found the points, to complete the graph you need to find a line that connects the points.
An example of this is shown below, where the points used are the ones above, and the line should be straight.
help plz will give brainliest and dont answer if u dont know
Answer:
is highly motivated
Explanation:
You serve a volleyball with a mass of 1.4 kg. The ball leaves with a speed of 13 m/s. Calculate KE
Answer:
118.3 J
Explanation:
Givens:
m = 1.4 kg
V = 13 m/s
Formula for kinetic energy:
KE = (1/2)*(m)*(v)^2
KE = .5*(1.4 kg)*(13 m/s)^2
KE 118.3 J
J = Joules
We emphasize performance over participation well before kids' bodies, minds, and interests mature. And we tend to value the child who can help win games or whose families can afford the rising fees." Take some time to think through your answer.
Answer:
Yes.
Explanation:
Yes, we emphasize performance over participation of kids in a competition which causes negative effect on kid's personality. We also prefer those children whose families can afford the fees which is our big failure. We should emphasize participation over performance and prefer those child who has the ability to win the game instead of those who can afford the fees.
Which of these force&mass pairs will result in the largest acceleration? *
50 N and 5 kg
60 N and 3 kg
30 N and 1 kg
25 N and 100 kg
10 N and 8 kg
Answer:
30N and 1 kg has largest acceleration
hope it helps youWrite down the factors on which moment depends upon ?
Answer:
The size of a forceThe perpendicular distance from the pivot the line of action of forceExplanation:
Factors that affect the moment of a force are;
The size of a forceThe perpendicular distance from the pivot the line of action of forceThe magnitude of force applied is directly proportional to the moment of force in that for a perpendicular distance d, increased in force applied will result to a higher moment of force. When the perpendicular distance from the pivot is decreased while the force applied remains constant, the moment of force decreases.
Which of the following statements about infrared telescopes is NOT true?
a. They are typically operated at lower temperatures.
b. They are especially helpful for viewing cool or obscured astronomical objects.
c. They were first built in the 1960s.
d. They are often placed on mountaintops.
e. They do not work well at high altitudes.
Answer:
a. They are typically operated at lower temperatures.
a. They are typically operated at lower temperatures.b. They are especially helpful for viewing cool or obscured astronomical objects.
Sam scored 98, 25, 105, 62 and 65 runs in 5 matches. What was the average score per match?
Answer:
71
Explanation:
answer if you want to
Answer:
C
Explanation:
think of a diffuser
Which lighting source has lower energy costs and a longer life but can be dangerous?
a. fluorescent
b. laser
c. incandescent
d. neon
Answer: I'm like 98% sure it's fluorescent cause it's got mercury
Explanation:
Two charged objects originally felt 12N of attraction. One charge is changed from to 3C to 6C and their distance changes from 15cm apart to 45cm apart. What is the new force of attraction ?
Given that,
Initial force, F = 12 N
First initial charge, q₁ = 3C
First new charge, q₁' = 6C
Initial distance, r = 15 cm
New distance, r' = 45 cm
To find,
The new force of attraction.
Solution,
The force between two charges is given by :
[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]
[tex]12=k\dfrac{3\times q_2}{15^2}\ ....(1)[/tex]
Let F' is the new force.
[tex]F'=k\dfrac{q_1'q_2'}{r'^2}[/tex]
[tex]F'=\dfrac{k\times 6\times q_2}{(45)^2}\ ...(2)[/tex]
As q₂ is same in this case.
Dividing equation (1) and (2) :
[tex]\dfrac{F}{F'}=\dfrac{k\dfrac{3q_2}{15^2}}{\dfrac{k\times 6\times q_2}{45^2}}\\\\\dfrac{12}{F'}=4.5\\\\F'=\dfrac{12}{4.5}\\\\F'=2.67\ N[/tex]
So, the new force of attraction is 2.67 N.
this is an area where two tectonic plates move towards each other with one going under the other plate?
Answer:Convergent boundaries are areas where plates move toward each other and collide. These are also known as compressional or destructive boundaries. Subduction zones occur where an oceanic plate meets a continental plate and is pushed underneath it. Subduction zones are marked by oceanic trenches.
pLS THANK ME AND VOTE ME BRAINLIEST ME
Explanation:
if an object with a mass of 248kg is lifted 76 meters in 18 seconds, how much power is used?
Explanation:
power = 1/2 mass × velocity^2 >>1
velocity = distance / time = 76 /18 = 4.2m
then power = 1/2 × 276 × (4.2)^2 = 138 × 17.64 = 2,434.3 jules.
I am giving 18 points. Please try and don’t just do it for the points.
They won’t let me shown the very last picture, it looks like the normal L shape that is in every picture, and just one straight line. L—
Like that.
Which of the following graphs below represents the motion of an object at variable speeds? (3 points)
Distance
(miles)
Time
(hours)
Distance
(miles)
Time
(hours)
Answer:Distance.
Explanation:
6. What charge is in the nucleus?
a. negative charge
b. positive charge
C. no charge
d. positive and negative charges
Which has the greatest amount of energy: ultraviolet rays, infrared rays, or
microwaves? (1 point)
Answer:
ultraviolet rays
Explanation:
It is because it have more photons.
Explain relative velocity with examples
Answer:
Velocity of the moving objects with respect to other moving or stationary object is called “relative velocity” and this motion is called “relative motion”.
Explanation:
For example, you are in a bus and it goes with the velocity of 50 m/s to the east, then a truck passes you with a velocity of 60m/s to the east.
a high school physics student with a mass of 68.18 KG is sitting in a seat reading this question the magnitude of the force with which the seat is pushing up upon the student is
A) 6.96 N
B) 66.82 N
C) 668.16 N
D) 1200 N
A horizontal net force is exerted on a 2.0 kg object at rest. The object starts at x=0 m and travels 8.0 m along a horizontal frictionless surface.
What is the velocity of the object
Round answer to 2 significant digits
____ m/s
There's a constant force of 35 N exerted on the object of mass 2.0 kg, so it undergoes an acceleration a of
35 N = (2.0 kg) a → a = 17.5 m/s²
The object travels 8.0 m, so that it attains a velocity v of
v ² = 2 (17.5 m/s²) (8.0 m) → v ≈ 16.73 m/s ≈ 17 m/s
The velocity of the 2 Kg object which travels 8 m along the horizontal frictionless surface is 17 m/s
How to determine the acceleration Force (F) = 35 NMass (m) = 2 KgAcceleration (a) =?a = F / m
a = 35 / 2
a = 17.5 m/s²
How to determine the velocity Initial velocity (u) = 0 m/sDistance (s) = 8 mAcceleration (a) = 17.5 m/s²Final velocity (v) =?v² = u² + 2as
v² = 0² + (2 × 17.5 × 8)
v² = 280
Take the square root of both side
v = √280
v = 17 m/s
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A 2.0 kg block is pulled across a horizontal surface by a 15 N force at a constant velocity.a. What is the net force acting on the block?
Answer:
0
Explanation:
the block is being pulled at a constant velocity meaning it has no acceleration. the rule is fnet=mass x acceleration so if theres no acceleration there is no force net!
A block of mass 2 kg is pulled across a surface with a force of 15 N then the net force acting on the block is 0.
What is Force?A force is an effect that can alter an object's motion according to physics. A force might cause an object has mass to accelerate when it changes its velocity, for, us when it moves away from rest. An obvious way to describe force is in terms of push or pull. A force is a vector quantity since it has equal magnitude and direction. It is calculated using the newton SI unit (N). Force is denoted by the letter F.
The net force exerted by an object was equal to the speed at which its velocity varies over time, according to Newton's second law in its original formulation.
The block has no acceleration because it is being pushed at a constant speed. If there is no acceleration, there is no force net because the formula is net force =mass × acceleration.
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Which of the following has zeros that are not significant?
2.05 m/s
10.0 J
1.30 N
100 kg
Answer: Either 10.0 J or 1.30 N
Explanation:
10.0 J
if it was 10.01 it would be significant, but its 10.0 which makes it a whole number
1.30 N
All zero's preceding the first integers are never significant. For example: 0.0078 has two significant figures. All zero's after the decimal point are always significant. For example: 4.500, 45.00 and 450.0 all have four significant figures
Answer:
100 kg
Explanation:
With the absence of a decimal point, only the 1 would be significant.
Calculate the volume of water in gallons that 4.1 mL of water takes up. Express your answer in scientific notation,
Explanation:
The unit of volume derived from SI units(1) is the cubic meter, m3.
Chemists in a laboratory usually deal with much smaller volumes than cubic meters and the metric but non-SI units of liter or litre (L) and milliliter or millilitre (mL or ml) are in common use.
In 1964 the litre was redefined as being equal to exactly 1 cubic decimetre:
1 L = 1 dm3
So 1 milliltre = 1 cubic centimetre
1 mL = 1 cm3 (= 1cc)
Other metric units of measuring volume are given in the table below:
large volume → → → → → → → → → → small volume
name teralitre gigalitre megalitre kilolitre hectolitre decalitre decilitre centilitre millilitre microlitre nanolitre picolitre femtolitre attolitre
symbol TL GL ML kL hL daL dL cL mL µL nL pL fL aL
volume (L) 1012 L 109 L 106 L 103 L 102 L 101 L 10-1 L 10-2 L 10-3 L 10-6 L 10-9 L 10-12 L