Amanda inserted the gel tray with the well towards the red ( ) end of the chamber during gel electrophoresis and carefully pipetted her samples into the wells as indicated in the lab directions. After viewing her gel under UV light, she did not find bands in the regions that she was expecting. What did she most likely see in her gel results and why

Answers

Answer 1

Answer:

hello the options related to your question is missing attached below is the complete question with the options

answer:

Any visible bands were found in the small area above the wells instead in the expected large bottom area of the gel, because Amanda should have placed the wells into the black (-) end of the chamber for DNA to move towards the opposite red (+) end of the gel.   (  2 )

Explanation:

Why Amanda did not see any bands in the region that she was expecting is because during electrophoresis ( which allows the distinguishing of various lengths of DNA fragments on a gel )  the DNA been negative will migrate to the positively charged  electrodes and  The shorter brands will move faster through the gel, providing DNA fragments arrangements on the gel according to size.

Amanda Inserted The Gel Tray With The Well Towards The Red ( ) End Of The Chamber During Gel Electrophoresis

Related Questions

is oxygen a beginning substance or ending substance?​

Answers

it’s a beginning substance i think

what makes up the cell menbrane

Answers

With few exceptions, cellular membranes — including plasma membranes and internal membranes — are made of glycerophospholipids, molecules composed of glycerol, a phosphate group, and two fatty acid chains. Glycerol is a three-carbon molecule that functions as the backbone of these membrane lipids.

Explanation:

the principal components of plasma membrane are lipids phospholipid and cholesterol proteins and carbohydrates

If anyone could help I’d appreciate it

Answers

Answer: 2.00 mol

Explanation:

The balanced chemical equation is:

[tex]2H_2(g)+O_2(g)\rightarrow 2H_2O(g)[/tex]  

According to stoichiometry :

2.00 moles of [tex]H_2[/tex] require = 1.00 moles of [tex]O_2[/tex]

Thus 2.00 moles of [tex]H_2[/tex] will require=[tex]\frac{1}{2}\times 2.00=1.00moles[/tex]  of [tex]O_2[/tex]

Thus both will act as limiting reagents and will be fully consumed.

2.00 moles of [tex]H_2[/tex] will form = 2 moles of [tex]H_2O[/tex]

Thus 2.00 moles of [tex]H_2[/tex] will form = [tex]\frac{2}{2}\times 2.00=2.00moles[/tex]  of [tex]H_2O[/tex]

  Thus 2.00 moles of [tex]H_2O[/tex] will be produced from the given masses of both reactants.

What is the other product for this reaction? Hbr + NaOH —> ( select 2)

Answers

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Answer: HBr + NaOH = nabr + h2o

Explanation:

I hope this helped!

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which answer? Is this

Answers

Answer:

law of segregation

have a good day!

Explanation:

Identify the type of reaction.

Al + MgSO4 = Al2(SO4)3 + Mg

Answers

Answer: its combustion

Explanation:

Mass of watch glass + filter paper = 105.98 g
Mass of watch glass + filter paper + crystallized product = 109.03 g
Mass of uncrystallized product (show work) =
Mass of methyl benzoate = 3.08 g
Volume of nitric acid used = 2.0 mL

Theoretical yield based on each of the starting materials

(Please use two Dimensional Analysis (DA) equations, one for the maximum amount of product obtainable from the amount of methyl benzoate you used and the other from the concentrated nitric acid, then use the lesser of the two to determine the Limiting Reagent; you must determine the number of moles in 2.00 mL of concentrated nitric acid [concentration 69.0% (w/w), and density (1.42 g/mL)].

Required:
a. Identity of the Limiting reagent (LR) based on the above two DA equations = __________
b. Max amount of product obtainable from the LR = ___________
c. Mass of the product you obtained: ____________

Answers

Answer:

Explanation:

Mass of uncrystallized product = (Mass of watch glass + filter paper + crystallized product) - (Mass of watch glass + filter paper)  

Mass of uncreystaliized product = 109.03 gm - 105.98 gm

Mass of uncrystaliized product = 3.05 gm

For methyl benzoate;

mass = 3.08 g

no of moles = 3.08 g/ 136.15 g/mol = 0.0226 mole

It is possible for the formation of 1 mole of nitro methyl benzoate from a mole of methyl benzoate.

moles of nitro methyl benzoate that can be formed from 0.0226 moles of methyl benzoate = 0.0226 moles

mass of nitro methyl benzoate = 0.0226 mol × 181.15 gm /mol

mass of nitro methyl benzoate = 4.098 gm

For HNO_3 solution:

mass = 1.42 gm/ml × 2.0 ml

mass = 2.84 gm

Mass of HNO3 in 2.84 gm solution[tex](69\% w/w)= 2.84 gm * \dfrac{69}{100 }[/tex]

= 1.9596 gm

Moles of HNO3 = [tex]\dfrac{ 1.9596 \ gm }{ 63.01 gm /mol}[/tex]

= 0.0311 mole

1 mol of HNO_3 can be formed from 1 mole of nitro methyl benzoate

Thus; moles of nitro methyl benzoate that can be formed from 0.0311 mole of HNO_3 = 0.02256 mole

The mass for nitro methyl benzoate can now be determined as:

= 0.0311 mole × 181.5 gm/mole

= 5.634 gm

Since the mass formed from methyl benzoate is lesser, then methyl benzoate serves as the limiting reagent.

The mass obtainable from the LR = 4.098 gm

A student places 2 mL of 2% ethanolic silver nitrate solution into test tube. They add 2 drops of an unknown compound into the test tube while gently mixing. After five minutes, the student heated the test tube in a water bath and a white precipitate formed. They added 2 drops of 1 M nitric acid to the mixture which was cooled to room temperature and still noticed the precipitate did not dissolve in response to the nitric acid. What compound is most likely the unknown

Answers

Answer:

hi

Explanation:

i am smart but i need this app cuz some are realy hard

Which contains the greatest number of moles of oxygen atoms?

Answers

Answer:

B. OR C.

Explanation:

So, 1 mol of ethanol, C2H5OH contains 1 mol of atoms of O; 1 mol of formic acid, HCO2H contains 2 moles of atoms of O; and 1 mol of water, H2O contains 1 mol of atoms of O.

Answer: So, of the three compounds given, formic acid, HCO2H, contains the greatest number of moles of oxygen atoms.

How can you determine if elements have the same properties?

Answers

Answer:

You will know if elements have the same properties if they are in the same column (up and down) on the periodic table.

Explanation:

Ex: Lithium and a hydrogren has the same properites bcause they are both on the same line/column. Columns are up and down the table and rows are left and right. Hope this helps

A 20 mL sample of human urine was found to have 10 mg of
urea during analysis. The molar mass of urea is 60.1 g/mol.
Calculate the molarity of urea in the given sample.

Answers

0.008
Molarity=
Mw
2

×V
sol

(in mL)
W
2

×1000

⟹W
2

=5 mg =5×10
−3
g
∴M=
60×10
5×10
−3
×10
3


=0.008

If 220 mL of a 12.0 M HCl solution is diluted to 1000 mL, what will be the concentration of the new solution?

Answers

Answer:

2.64 M

Explanation:

Use the dilution equation M1V1 = M2V2, where:

M1 = 12.0 M HCl

V1 = 220 mL HCl

M2 = ?

V2 = 1000 mL HCl

(12.0 M HCl)(220 mL HCl) = M2(1000 mL HCl)

M2 = 2.64 M HCl

Solid iron is mixed with a solution of copper (I) nitrate to form iron (III) nitrate solution and metal copper. (what is the equation)

Answers

Answer:

Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu

Explanation:

Solid Iron = FeCopper (I) nitrate = CuNO₃ (Nitrate, NO₃⁻, always has a charge of -1).Iron (III) nitrate = Fe(NO₃)₃ (That way the compound has an overall neutral charge)Metal Copper = Cu

Writing the equation using symbols leaves us with:

Fe + CuNO₃ → Fe(NO₃)₃ + Cu

It is not balanced yet. Now we balance the NO₃ species on the left side:

Fe + 3CuNO₃ → Fe(NO₃)₃ + Cu

Finally we balance the Cu species on the right side:

Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu

1/5 divided by 3/4 fraction

Answers

Answer:

4/15

Explanation:

we can write out an equation by doing (1/5 ÷ 3/4) and then switch the sign to multiplication and we can keep the first fraction the same (in this case 1/5) and then we flip the second fraction BUT when we flip the second fraction upside-down we have to change the symbol to multiplication (1/5x4/3)

then after that all we do is multiply the denominators and numerators :)

1 x 4 = 4

_______

5 x 3 = 15

answer would be 4/15

What type of solution would have a pH of 8 ?

Answers

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Answer: Weak base

Explanation:

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Answer and Explanation:

Solutions that have a pH of 8 would be considered a Weak Base.

This is because a weak base is a base that, upon dissolution in water, does not dissociate completely.

Solutions/liquids that have a pH higher than a pH of 7 are basic solutions, while solutions/liquids that have a pH lower than a pH of 7 are acidic solutions.

When the pH level is closer to 7, it is weak, and when it is far from 7, like if it is 1 or 12, then it is a strong acid/base.

#teamtrees #PAW (Plant And Water)

Solution remained colorless.
During the experimentation, the test tube was gently heated in a Bunsen burner flame for 60 seconds. What was the reason for this specific
procedure?
A)
Heating was done to initiate the combustion of the metal in water.
B)
Heating was done to confirm that no chemical reaction would take
place in acid
0
Heating was done to precipitate the chemical change in each test
tube containing water
D)
Heating helped released the hydrogen contained in water
molecules so students would have a positive H+ test.

Answers

B because the others are not equal and if you add and then get the root it would be b

what is another name for horse

Answers

Answer:

Mount, Charger, Colt, Pony, and Folt

Explanation:

Answer:

A stallion or a mare

Explanation:

What substance is oxidized in the following reaction? 4HCl + MnO2 → Cl2 + 2H2O + MnCl2

Answers

Answer:

Cl⁻ was oxidized.

Explanation:

4HCl + MnO₂ → Cl₂ + 2H₂O + MnCl₂

Oxidation can be defined as the process in which the oxidation number of a substance increases.

On the left side of the equation, Cl has a charge of -1 (in HCl); while on the right side of the equation Cl has a charge of 0 in Cl₂.

Thus, Cl⁻ was oxidized.

Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the equation PV = C, where C is a constant. Suppose that at a certain instant the volume is 300 cm3, the pressure is 180 kPa, and the pressure is increasing at a rate of 30 kPa/min. At what rate is the volume decreasing at this instant?

Answers

Answer:

The gas is decreasing at a rate of 50 cubic centimeters per minute.

Explanation:

The Boyle's Law is represented by the following expression:

[tex]P\cdot V = k[/tex] (1)

Where:

[tex]P[/tex] - Pressure, in kilopascals.

[tex]V[/tex] - Volume, in cubic centimeters.

[tex]k[/tex] - Proportionality constant, in kilopascal-cubic centimeters.

By definitions of rate of change and implicit differentiation, we derive the following differential equation:

[tex]\dot P \cdot V + P\cdot \dot V = 0[/tex] (2)

Where:

[tex]\dot P[/tex] - Rate of change of the pressure, in kilopascals per minute.

[tex]\dot V[/tex] - Rate of change of the volume, in cubic centimeters per minute.

Then, we clear the rate of change of the volume within (2):

[tex]P\cdot \dot V = -\dot P\cdot V[/tex]

[tex]\dot V = -\left(\frac{\dot P}{P} \right) \cdot V[/tex]

If we know that [tex]P = 180\,kPa[/tex], [tex]\dot P = 30\,\frac{kPa}{min}[/tex] and [tex]V = 300\,cm^{3}[/tex], then the rate of change of the volume is:

[tex]\dot V = -\left(\frac{\dot P}{P} \right) \cdot V[/tex]

[tex]\dot V = -50\,\frac{cm^{3}}{min}[/tex]

The gas is decreasing at a rate of 50 cubic centimeters per minute.

Potassium chlorate, a common oxidizing agent in fireworks and matchheads, undergoes a solid-state disproportionation reaction when heated:

4KClO3 (s) ⟶ Δ3KClO4 (s) + KCl (s).

Use ΔHf ° and S° values to calculate ΔG_sys ° (which is ΔGrxn °) in kJ at 25°C for this reaction.

Answers

Answer:

Explanation:

[tex]\text{From the information given:}[/tex]

[tex]\text{The chemical reaction is : } 4 KClO_{3(s)} \to 3 KClO_{4(s)} + KCl_{(s)}[/tex]

[tex]\text{To find} \ \Delta G^0_{rxn}\ \text{using the formula}: \\ \\ \Delta G^0_{rxn} = \sum n_p \times \Delta _f G^0 (Products) - \sum n_R \times \Delta _fG^0 ( Reactants) \\ \\ where; n_p = \text{no of moles of products } \ and; \\ \\ n_R = \text{no of moles of reactants }[/tex]

[tex]\implies G^0_{rxn} = 3 \times \Delta _fG^0 [KClO_4{(s)}] + \Delta_fG^0[KCl_{(s)}] - 4 \times \Delta _f G^0 [ KClO_3 (s) ][/tex]

[tex]\Delta _fG^0 \ values \ at \ 25^0 \ C (298 \ K) are\ given \ as:\\\\ \Delta _fG^0 [KClO_4(s)] = -303.09 \ kJ \\ \\ \Delta _fG^0 [KCl(s) ] = - 409.14 \ kJ \\ \\ \Delta_f G^0 [KClO_3_{(s)}] = -296.25 \ kJ \\ \\ replacing \ the \ above \ values \ into \ equation (1) ; then:\\ \\ \\\Delta G^0_{rxn} = 3 *(-303.09) + (-409.14) - 4*(-296.25) \ kJ \\ \\ = (-909.27 - 409.14 + 1185) \ kJ \\ \\ = -133.41 \ kJ \\ \\ \mathbf{\Delta G^0_{rxn} = -133.4 \ kJ }[/tex]

The standard free energy change of the reaction is -133 kJ.

From the reaction equation, we have; 4KClO3 ⇄ 3KClO4 (s) + KCl (s). The standard free energy of formation of each specie is given below;

ΔG°f KClO3 = -296.35 kJ

ΔG°f KClO4 = -303.09 kJ

ΔG°f KCl = -409.14 kJ

Hence;

ΔG°rxn = [3(-303.09)] + ( -409.14)] - [(4( -296.35))]

ΔG°rxn = (-909.27) + (-409.14) - (-1185.4)

ΔG°rxn = -133 kJ

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The correct value of m, n, x and y to obtain a balanced equation is?

m B2O3(s) + n HF(l) → x BF3(g) + y H2O(l)

a.
m=1, n=1, x=1 and y=1


b.
m=1, n=6, x=2 and y=3


c.
m=1, n=1.5, x=1 and y=1


d.
m=2, n=12, x=4 and y=6​

Answers

Answer:

d

Explanation:

answer d makes the equation balance

This timeline woulchre useful to someone who was writing a report titled

Answers

A la clase d no me voy al trabajo y me voy al colegio a las

What is the name of this molecule?

Answers

Answer:

pentanoic acid

Explanation:

it has 5 carbon atoms which gives it the parent name pent, and its attached to the ester group

What is the concentration of a solution with a
volume of 2.5 liters containing 660 grams of
calcium phosphate Ca3(PO4)2 ?

Answers

Answer:

660gx Imol = 2.1278 mol 310.189 2.5L 1.85 m).

Explanation:

The number of moles of 660 grams of calcium phosphate is 2.127. Then the molarity of the solution of 2.5 liter volume is 0.85 M.

What is molarity ?

Molarity is a common term used to express the concentration of a solution. It is the ratio of number of moles of solute particles to the volume of solution in liters. Hence, its unit is mol/L or molar.

The molarity of a solution is a colligative quantity as well as temperature dependent.

Given,

molar mass calcium phosphate,  Ca₃(PO₄)₂  =310.18 g/mol

Then,

no.of moles of calcium sulphate in 660 g = 660 g/310.18 g/mol = 2.127 moles

volume of solution = 2.5 L

Molarity = no.of moles of solute/ volume of solution in L

M = 2.127 moles/ 2.5 L

   = 0.85 M.

Therefore, the molarity of the given solution is 0.85 molar.

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Which of the different components of smog depicted in the graph are most likely released from automobile exhaust?
A
A and B
B
B and C
с
A, B, and C
D
B, C, and D

Answers

Answer:

B, B and C

Explanation:

The two components (AA, hydrocarbons and BB, nitrogen oxide) are most likely released from automobile exhaust.

What is Smog?

This is referred to a type of air pollution which could be from carbon emission etc and reduces the visibility.

(AA, hydrocarbons and BB, nitrogen oxide peaked midmorning when traffic is highest which means they were most likely released from automobile exhaust?.

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If a mechanical wave has a frequency of 0.147 Hz and a wavelength of 12.05 m, what is the velocity of the wave? (round to the hundredths place)

Answers

Answer:

0.147 Hz   because I took the test

The velocity of a wave is the product of its frequency and wavelength. The  velocity of wave with 0.147 Hz and 12.05 m is 1.77 m/s.

What is frequency ?

The frequency of a wave is the number of wave cycles per unit time. Frequency is the inverse of time period of the wave. It is inversely proportional to the wavelength. Unit of frequency is Hz which is equivalent to s⁻¹.

The wavelength of a wave is the distance between two consecutive crests or troughs. The wavelength λ, and frequency ν of a wave is related to the velocity  v of the wave as follows:

v = νλ

Given that,

frequency = 0.147 Hz

wavelength = 12.05 m

then, velocity = 0.147 Hz × 12.05 m = 1.77 m/s.

Therefore, the velocity of the mechanical wave is 1.77 m/s.

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What is 2AI(s) + FeO3(s) = Ai2O3(s) + 2Fe(s)

Answers

Answer:

it's a double displacement Reaction.

How can y’all do this

The molecular weight for the compound from the previous question is
64.07 g/mol. What is its molecular formula?

Answers

The molecular formula should have been give to you from ur teacher

Chromium is manufactured by heating a mixture of chromium(III) oxide with aluminium powder.
Cr2O3(s) + 2Al(s) → 2Cr(s) + Al2O3(s)

a=Calculate the mass of aluminium needed to react with 50 g of Cr2O3.
b=Calculate the mass of chromium produced from 50 g of Cr2O3.
c=Calculate the mass of chromium produced from 5 kg of Cr2O3.
d=Calculate the mass of chromium produced from5 tonnes of Cr2O3.

Note: 1 tonne = 1,000,000 g
Ar: Cr = 52, O = 16, Al = 27

Answers

I’m taking a good estimation and gonna say B but I’m torn between that and D

When sodium hydroxide NaOH dissociates in water, the oxygen atoms on the hydroxide anions will interact with:

Answers

Answer:

Hydroxide ions ( OH−) are negatively charged, and the formal negative charge is on the oxygen atom. Since opposite charges attract, the oxygen atoms will interact with the positive end of water's dipole.

Explanation:

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