A box contains 4 pair of sunglasses. How many outcomes are in the sample space for pulling out a single pair, not returning it, then drawing out a second set of glasses.
a. 8
b. 12
c. 6
d. 9
Answer:
B.12
Step-by-step explanation:
For your first draw you have 4 possible options, then on your second draw you have 3 possible options since you took out a pair. So to figure out the number of possible outcomes you simply multiply the possibilities by each other to get the number of possible outcomes.
Can someone pls helpppp ASAP this is due in 25 min :(
For the right triangles below, find the values of the side lengths d and a.
Round your answers to the nearest tenth.
Answer:
a = 1.4 and d = 6.9
Step-by-step explanation:
To get the value of d and a, we will use the SOH CAH TOA identity
For the first tringle;
Opposite = d ((opposite angle 60 degrees)
Adjacent = 4
Tan theta = opp/adj
Tan 60 = d/4
d = 4tan60
d = 4(1.732)
d = 6.9
For the second triangle;
Opposite = a
Hypotenuse = 2
Since sin theta = opp/hyp
Sin45 = a/2
a = 2sin45
a = 2(0.7071)
a = 1.4
Hence a = 1.4 and d = 6.9
Given that the diameter of a circle is 5 mm, find the radius of the circle.
Answer:
r=2.5mm
Step-by-step explanation:
Using the formula
[tex]\huge\underline{ \sf \: Formulae \: to \: remember \: for \: solving \: the \: question:}[/tex]
[tex] \\{ \sf radius \: of \: a \: circle = \frac{d}{2} where \: d \: is \: the \: diameter \: of \: the \: circle}[/tex]
[tex]\huge\underline{\sf Given:}[/tex]
[tex] \ \: { \sf The \: diameter \: of \: a \: circle \: is \: 5 mm.}[/tex]
[tex]\huge\underline{\sf To \: find \: out:}[/tex]
[tex] \ { \sf Radius \: of \: the \: circle}[/tex]
[tex]\huge\underline{\sf Solution:}[/tex]
[tex] \\{ \sf The \: diameter \: of \: the \: circle \: is \: 5 \: mm.}[/tex]
[tex] \\{ \sf Therefore \: radius \: of \: the \: circle}[/tex]
[tex]\\{ \sf = \frac{5}{2} \: mm} [/tex]
[tex] \\{ \sf = 2.5 \: mm}[/tex]
[tex]\huge\underline{\sf Answer:}[/tex]
[tex]\\{\sf The \: radius \: of \: the \: circle \: is \: 2.5 \: mm.}[/tex]
which are the complementary angles?
Answer:
Two angles are called complementary when their measures add to 90 degrees. Two angles are called supplementary when their measures add up to 180 degrees.
Step-by-step explanation:
please amrk this answer as brainliest
Evaluate the function.
Answer:
Step-by-step explanation:
Nothing further can be done with this topic.
f ( x ) = 3 x 2 − 10 x − 9
A shoe store donated a percent of every sale to charity. a the total sales were $9,800 so the store donated $588. What percent of $9,800 was donated to charity?
Answer:
They donated 6%.
Step-by-step explanation:
The total sales were $9800.
The amount donated is $588.
We want to know what percent of 9800 is 588.
Let's make an equation.
what percent of 9800 is 588
x/100 • 9800 = 588
Divide by 9800.
x/100 = 0.06
Multiply by 100.
x = 6
They donated 6%.
Hope this helps!
You wash 12 cars on Friday and 10 cars on Saturday for our fund-raiser you were also given a $40 donation from somebody who didn't want a car wash if you raised a total of $370 how much money did you earn per car wash
Answer:
$15
Step-by-step explanation:
370-40=330
12+10=22
330÷22=15
15*22=330
The temperature startedat 10 degrees F. The temperature dropped 5
degrees every hour. What was the temperature after 3 hours?
Answer:
-5FStep-by-step explanation:
10-5x3=-5 F
plz hurry!! A person standing close to the edge on top of a 108-foot building throws a ball vertically upward. The quadratic function h ( t ) = − 16 t 2 + 132 t + 108 h ( t ) = - 16 t 2 + 132 t + 108 models the ball's height above the ground, h ( t ) h ( t ) , in feet, t t seconds after it was thrown. a) What is the maximum height of the ball?
Answer:
The maximum height of the ball is 380.25 feet in the air.
Step-by-step explanation:
The quadratic function:
[tex]h(t)=-16t^2+132t+108[/tex]
Models the ball's height h(t), in feet, above the ground t seconds after it was thrown.
We want to determine the maximum height of the ball.
Note that this is a quadratic function. Therefore, the maximum or minimum value will always occur at its vertex point.
Since our leading coefficient is leading, we have a maximum point. So to find the maximum height, we will find the vertex. The vertex of a quadratic equation is given by:
[tex]\displaystyle \left(-\frac{b}{2a},f\left(\frac{b}{2a}\right)\right)[/tex]
In this case, a = -16, b = 132, and c = 108. Find the t-coordinate of the vertex:
[tex]\displaystyle t=-\frac{132}{2(-16)}=-\frac{132}{-32}=\frac{33}{8}=4.125[/tex]
So, the maximum height occurs after 4.125 seconds of the ball being thrown.
To find the maximum height, substitute this value back into the equation. Thus:
[tex]h(4.125)=-16(4.125)^2+132(4.125)+108=380.25\text{ feet}[/tex]
The maximum height of the ball is 380.25 feet in the air.
Sum of 23 and y please help
Answer:
I think it’s -5
2. At Best Buy, two flash drives and one new mouse for your
computer cost $55.00. How much does one flash drive cost?
(Mouse cost 22.00)
Answer:
I believe one flash drive would cost $16.50.
Step-by-step explanation:
55=2x+22
-22 -22
33=2x
/2 /2
16.50=x
Hope this helps! Have an Amazing day!!