The correct option is A: the force exerted on the wall by the sledgehammer is - 1000 N
Newton's third lawNewton's third law of motion states that for every action or force, there is an equal but oppositely directed force.
Application of the newton's third lawForce with which the sledgehammer hits the wall = 1000 N
From the Newton's third law, an equal but oppositely directed force is exerted on the sledgehammer by the wall.Thus, the force exerted by the sledgehammer on the wall = -1000 N
The negative sign indicates that the force acts in a direction opposite to that of the sledgehammer.Thus, the correct option is A: the force exerted on the wall by the sledgehammer is - 1000 N
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why can you predict how the moon will change appearance from day to day
As the Moon orbits our planet, its varying position means that the Sun lights up different regions, creating the illusion that the Moon is changing shape over time. This is because it rotates once on its axis in exactly the same time it takes to orbit Earth – 27 days and seven hours
How many kilojoules are in 1,967,256J? Round your answer to the nearest whole number.
Answer:
1,967 kilojoules.
Explanation:
1 kilo = a thousand.
There are 1.967 kilojoules in 1,967,256 joules.
What is law of energy conservation?Energy can neither be created nor destroyed.It is only get transfered from one form to another form.What is the SI unit of energy?Joule is a SI unit of energy.There are 1000 joules in 1 kilojoules .learn more about unit of energy here - https://brainly.com/question/3012083
#SPJ2
Which is the United States Space Shuttle-derived heavy expendable launch vehicle being designed by NASA?
Answer:
Space Launch System (SLS)
Explanation:
Space Launch System (SLS) is the United States Space Shuttle-derived heavy expendable launch vehicle being designed by NASA.
-TheUnknownScientist 72
A 5kg ball is on top of the school building at a height of 40m above the ground.
A. calculate the potential energy of the ball at that height.
B. How much power would it take to get the ball from the ground to that height in 1 minute.
C. If it is dropped what type of energy will the ball have as it approaches the ground.
D. What speed will the ball hit the ground
Answer:
A-Caclcuate the potential energy of the ball at that height
Explanation:
(a). Mass of the Body = 10 kg.
Height = 10 m.
Acceleration due to gravity = 9.8 m/s².
Using the Formula,Potential Energy = mgh
= 10 × 9.8 × 10 = 980 J.
(b). Now, By the law of the conservation of the Energy, Total amount of the energy of the system remains constant.
∴ Kinetic Energy before the body reaches the ground is equal to the Potential Energy at the height of 10 m.
∴ Kinetic Energy = 980 J.
(c). Kinetic Energy = 980 J.
Mass of the ball = 10 kg.
∵ K.E. = 1/2 × mv²
∴ 980 = 1/2 × 10 × v²
∴ v² = 980/5
⇒ v² = 196
∴ v = 14 m/s.
A billiard ball with a speed of 5 m/s strikes another stationary billiard ball in a perfectly elastic collision.
After the collision, the first ball has a speed of 4.35 m/s and is traveling at an angle of 30° below its original line of motion.
Find the speed and angle of the second ball, with respect to the initial line of motion, after the collision.
Assuming both billiard balls have the same mass, conservation of momentum says
[tex]m\vec v_1 + m\vec v_2 = m{\vec v_1}\,' + m{\vec v_2}\,'[/tex]
where m = mass of both billiard balls, and v₁ and v₂ = their initial velocities, and v₁' and v₂' = their final velocities. The masses are the same so the exact value of m is irrelevant. The first ball has initial speed 5 m/s and the second is at rest, so
[tex]\left(5 \dfrac{\rm m}{\rm s}\right) \, \vec\imath = {\vec v_1}\,' + {\vec v_2}\,'[/tex]
After the collision, the first ball has speed 4.35 m/s and is moving at angle of 30° below the original path, so
[tex]{\vec v_1}\,' = \left(4.35\dfrac{\rm m}{\rm s}\right)\left(\cos(30^\circ) \, \vec\imath + \sin(30^\circ) \, \vec\jmath\right) \approx \left(3.77 \dfrac{\rm m}{\rm s}\right) \vec\imath + \left(-2.18 \dfrac{\rm m}{\rm s}\right) \vec\jmath[/tex]
Then the second ball has final velocity vector
[tex]{\vec v_2}\,' \approx \left(1.23 \dfrac{\rm m}{\rm s}\right) \vec\imath + \left(2.18 \dfrac{\rm m}{\rm s}\right) \vec\jmath[/tex]
so it moves with speed
[tex]\left\|{\vec v_2}\,'\right\| \approx \sqrt{\left(1.23\dfrac{\rm m}{\rm s}\right)^2 + \left(2.18\dfrac{\rm m}{\rm s}\right)^2} \approx \boxed{2.50 \dfrac{\rm m}{\rm s}}[/tex]
at an angle of
[tex]\theta \approx \tan^{-1}\left(\dfrac{2.18}{1.23}\right) \approx \boxed{60.5^\circ}[/tex]
or about 60.5° above the original line of motion.
Which is true for the motion of the car during its journey along OAB?
12)
A) The velocity of the car remains constant throughout the journey.
B) The change in speed alone causes the velocity of the car to vary.
C) The change in direction alone causes the velocity of the car to vary.
D) The velocity of the car changes due to the change in speed and dir
Answer:
D
Explanation:
A is wrong as the direction of the car changes, implying velocity is changing and not constant.
B and C are wrong as both the change in speed and direction contribute to the change in velocity
2. The _____ investigate crimes anywhere in the state.
Answer:
State Police
the police organized and maintained by a state as distinguished from those of a lower subdivision (such as a city or county) of the state government.
A car accelerates at a constant rate of 3 m/s2 for 5 seconds. If it reaches a velocity of 27 m/s, what was its initial velocity?
A
15 m/s
B
42 m/s
C
12 m/s
D
2.1 m/s
The initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.
CALCULATE INITIAL VELOCITY:
The initial velocity of the car can be calculated by using one of the equation of motion as follows:
V = u + at
Where;
V = final velocity (m/s)u = initial velocity (m/s)a = acceleration due to gravity (m/s²)t = time (s)According to this question, a car accelerates at a constant rate of 3 m/s² for 5 seconds. If it reaches a velocity of 27 m/s, its initial velocity is calculated as follows:
u = v - at
u = 27 - 3(5)
u = 27 - 15
u = 12m/s.
Therefore, the initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.
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> what are the four states of matter? how are they defined?
Answer:
In physics, a state of matter is one of the distinct forms in which matter can exist. Four states of matter are observable in everyday life: solid, liquid, gas, and plasma.
...
To From Gas
Solid Deposition
Liquid Condensation
Plasma Ionization
The smallest possible particle of complete matter is the atom. True or false?
true
false
Answer:
TRUE !!
Explanation:
An atom is the smallest particle of an element
Which is the correct answer
Answer:
C
Explanation:
All of the other options are affecting the gravitational force and opposing force that pushed upwards, the diagram represents an object that is not moving up or down.
whats 10x10 PLEASE I NEED THIS
Answer:
100
Explanation:
if vector b is added to vector a under what conditions does the resultant vector has magnitude a+b?
Explanation:
hope it's useful for you knows
A 50 kg pitcher throws a baseball with a mass of 0. 15 kg. If the ball is thrown with a positive velocity of 35 m/s and there is no net force on the system, what is the velocity of the pitcher? â’0. 1 m/s â’0. 2 m/s â’0. 7 m/s â’1. 4 m/s.
The velocity of the pitcher at the given mass is 0.1 m/s.
The given parameters:
Mass of the pitcher, m₁ = 50 kgMass of the baseball, m₂ = 0.15 kgVelocity of the ball, u₂ = 35 m/sLet the velocity of the pitcher = u₁
Apply the principle of conservation of linear momentum to determine the velocity of the pitcher as shown below;
m₁u₁ = m₂u₂
[tex]u_1 = \frac{m_2 u_2}{m_1} \\\\u_1 = \frac{0.15 \times 35}{50} \\\\u_1 = 0.105 \ m/s\\\\u_1 \approx 0.1 \ m/s[/tex]
Thus, the velocity of the pitcher at the given mass is 0.1 m/s.
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In a game of pool, a cue ball rolls without slipping toward the stationary eight ball with a momentum of 0.23 kg m/s. After the two balls collide, the final momentum of the cue ball is 0.01 kg m/s
Answer: 0.22
Explanation: Subtract 0.01kg from 0.23kg
How fast would a(n) 75 kg man need to run in order to have the same kinetic energy as an 8.0 g bullet fired at 420 m/s ?
[tex] = \frac{1}{2} \times 0.008 \times 420J \\ = 1.68J[/tex]
So, the kinetic energy of the bullet is 1.68 J. It is said that the man's kinetic energy should be same as that of the bullet.Mass of the man (m2) = 75 KgLet the velocity of the man be v2.Therefore,[tex]1.68J = \frac{1}{2} \times 75 \: kg \times v2 \\ = > v2 = \frac{1.68 \times 2}{75} m {s}^{ - 1} \\ = 0.0448 \: m \: {s}^{ - 1} [/tex]
Answer:
0.0448 m/s
Hope you could get an idea from here.
Doubt clarification - use comment section.
Please help is any one know Its correct answer
Answer:
a=Head
b=Tip
c=South pole of the magnet
d=North pole of the magnet
train travels 1/4of its total distance over half of its time with a constant velocity of 5m/s. calculate the average velocity
Let D be the total distance (say in meters) traveled by the train and T the time (say in seconds) it takes to do so. (Assume the train moves in a straight line in only one direction.) Then the average velocity of the train as it covers this distance is
v (ave) = D/T
We're told the train can traverse a distance of D/4 in a matter of T/2 seconds if it moves at a speed of 5 m/s. This means
D/4 = (5 m/s) (T/2)
⇒ 5 m/s = 1/2 D/T
⇒ v (ave) = D/T = 10 m/s
when do magnets have the most potential energy
Answer:
Explanation:
Permanent magnets do have potential energy, stored in their magnetic field. That energy can be compared to the potential energy of some compressed spring. See the picture below, representing the magnetic field lines of a magnetized sphere : These lines are compressed inside the magnet.
can somebody explain it to me please?
Range be R and height be h
[tex]\boxed{\sf R=\dfrac{u^2sin2\theta}{g}}[/tex]
[tex]\boxed{\sf h=\dfrac{u^2sin^2\theta}{2g}}[/tex]
u=initial velocity
theta is angle of projection.
g=acceleration due to gravity
ATQ
[tex]\\ \sf\longmapsto R=2h[/tex]
[tex]\\ \sf\longmapsto \dfrac{u^2sin2\theta}{g}=\dfrac{2u^2sin^2\theta}{2g}[/tex]
Cancelling required ones
[tex]\\ \sf\longmapsto sin^2\theta=sin2\theta[/tex]
sin2O=2sinOcosO
[tex]\\ \sf\longmapsto sin^2\theta=2sin\theta cos\theta [/tex]
[tex]\\ \sf\longmapsto \dfrac{sin^2\theta}{sin\theta cos\theta=2[/tex]
[tex]\\ \sf\longmapsto \dfrac{sin\theta}{cos\theta}=2[/tex]
[tex]\\ \sf\longmapsto tan\theta=2[/tex]
[tex]\\ \sf\longmapsto \theta=tan^{-1}(2)[/tex]
[tex]\\ \sf\longmapsto \theta=63.4°[/tex]
Done
Option B is correct
Objects 1 and 2 attract each other with a gravitational force
of 18.0 units. If the mass of Object 1 is doubled mass of object 2 is tripled AND the
distance separating Objects 1 and 2 is halved, then the gravitational force will be
new gravitational force will be
units.
The new gravitational force of the two objects will be 432 N.
The given parameters:
Force between object 1 and object 2, F = 18 NLet the mass of object 1 = m1Let the mass of object 2 = m2Let the distance between the two object = rThe gravitational force between the two objects is calculated by applying Newton's law of universal gravitation;
[tex]F = \frac{Gm_1m_2}{r^2} \\\\G = \frac{Fr^2}{m_1m_2}\\\\G = \frac{Gm_1m_2}{r^2} \\\\G = \frac{18r^2}{m_1m_2}[/tex]
when the mass of the object 1 = 2m1mass of the object 2 = 3m2distance between the two object = ¹/₂r[tex]\frac{18r^2}{m_1 m_2 } = \frac{F_2(\frac{1}{2}r)^2 }{2m_1 \times 3m_2} \\\\\frac{18r^2}{m_1 m_2 } = \frac{F_2 \times r^2}{4 \times 2m_1 \times 3m_2} \\\\\frac{18r^2\times 4 \times 2m_1 \times 3m_2}{m_1 m_2\times r^2 } = F_2\\\\432 \ N = F_2[/tex]
Thus, the new gravitational force of the two objects will be 432 N.
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Calculate amount of current flowing in wire if number of charge is 8 and e = 1.69 x10^-19 , t= 8millsec
The amount of current flowing in the wire is 1.69 × 10⁻¹⁶ A
From the question,
We are to calculate, the amount of current flowing in the wire.
From the formula,
[tex]I =\frac{nQ}{t}[/tex]
Where I is the current
n is the number of charge
Q is the quantity of charge
t is the time
From the given information
n = 8
Q = e = 1.69 × 10⁻¹⁹ C
t = 8 msecs = 8 × 10⁻³ sec
Putting the parameters into the formula, we get
[tex]I = \frac{8 \times 1.69 \times 10^{-19} }{8\times 10^{-3} }[/tex]
[tex]I = 1.69 \times 10^{-16} \ A[/tex]
Hence, the amount of current flowing in the wire is 1.69 × 10⁻¹⁶ A
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A 3.1 kg carton's GPE was increasing by 7.8 J as it was lifted above the ground. How high was it lifted?
Answer:it was lifted
Explanation:
by me lifting it because i can life it very high
how is the rate of evporation of a liquid affected by temperature, the surface area of a liquid exposed to air
a q deben los cambios de la materia??
Answer:
wat
Explanation:
What force is responsible for how magma flows and rocks stack up on top of one another?
Question 6 options:
Electroweak and Strong
Nuclear
Electromagnetic
Gravitational
Gravitational Force
Explanation:-
The magma flows through the gap between the rocks which are stacked up on top of one another.
The gravity attracts the magma to do that.
Also the rocks are stacked because of the gravitational force between them
Hence Option D is correct
Hope it helps
Answer:
pls mark me as brainliest
Explanation:
last one
If a rock weighing 3.5 newtons is resting on cliff's ledge 12 meters from the canyon floor, what is its potential energy?
Group of answer choices
87 joules
4.5 joules
42 joules
142 joules
Answer:
42 Joules
Explanation:
Potential energy
= weight × height
= (3.5)(12)
= 42 joules
____________ is a medium-sized flat-topped hill with cliff-face sides that is taller than it is wide.
Answer:
mesa
Explanation:

A mesa is a flat-topped mountain or hill. It is a wide, flat, elevated landform with steep sides. ... Spanish explorers of the American southwest, where many mesas are found, used the word because the tops of mesas look like the tops of tables.
What force is responsible for how magma flows and rocks stack up on top of one another?
Question 6 options:
Electroweak and Strong
Nuclear
Electromagnetic
Gravitational
Gravitational force is responsible for how magma flows and rocks stack up on top of one another.
Gravitational force is the force hat attracts all objects to the center of the earth. The force of gravity accounts for the fact that when an object is thrown up, it falls back to the earth.The force that is responsible for how magma flows and rocks stack up on top of one another is the gravitational force.Hence, it is the gravitational force that is responsible for how magma flows and rocks stack up on top of one another.
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A concrete block (B-36 x10 °C-') of volume 100 mat 40°C is cooled to
-10°C. What is the change in volume? *
A. It will increase by 0.18 m
B. It will decrease by 0.18 m'
C.It will increase by 0.05 m
D. It will decrease by 0.05 mº
Applying Charles law
[tex]\\ \sf\Rrightarrow \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]
[tex]\\ \sf\Rrightarrow \dfrac{100}{313}=\dfrac{V_2}{263}[/tex]
[tex]\\ \sf\Rrightarrow V_2=\dfrac{26300}{313}[/tex]
[tex]\\ \sf\Rrightarrow V_2=84.02ml[/tex]