A wheel has a radius of r = 2.0 m and it rolls down a smooth incline. The height of the incline is h = 8.0 m . What is the angular velocity ω of the wheel at the bottom of the incline?
Express your answer in radians per second.

Answers

Answer 1

The angular velocity of the wheel at the bottom of the incline is 4.429 rad/sec

The angular velocity (ω) of an object is the rate at which the object's angle position is changing in relation to time.

For a wheel attached to an incline angle, the angular velocity can be computed by considering the conservation of energy theorem.

As such the total kinetic energy (K.E) and rotational kinetic energy (R.K.E) at a point is equal to the total potential energy (P.E) at the other point.

i.e.

P.E = K.E + R.K.E

[tex]\mathbf{mgh = \dfrac{1}{2}m(r \times \omega)^2 + \dfrac{1}{2}\times I \times \omega^2}[/tex]

[tex]\mathbf{gh = \dfrac{1}{2}(r \times \omega)^2 + \dfrac{1}{2}\times r^2 \times \omega^2}[/tex]

[tex]\mathbf{2 \times \dfrac{gh}{r^2} =\omega^2 + \omega^2}[/tex]

[tex]\mathbf{2 \omega^2=2 \times \dfrac{9.81 \times 8 m }{2.0 ^2} }[/tex]

[tex]\mathbf{\omega^2=\dfrac{39.24 }{2}}[/tex]

[tex]\mathbf{\omega=\sqrt{19.62 } \ rad/sec}[/tex]

[tex]\mathbf{\omega=4.429 \ rad/sec}[/tex]

Therefore, we can conclude that the angular velocity of the wheel at the bottom of the incline is 4.429 rad/sec

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Answer 2

The angular velocity of the wheel depends on the mass, radius and the

mode of rotation of the wheel (with or without slipping).

The angle velocity at the bottom of the incline, ω ≈ 4.43 rad/sec

Reasons:

The given parameters are;

Radius of the wheel, r = 2.0 m

Height of the incline, h = 8.0 m

Required:

Angular velocity of the wheel at the bottom of the incline.

Solution:

The potential energy of the wheel at the top of the hill, P.E. = m·g·h

[tex]Sum \ of \ the \ kinetic \ energy \ of \ the \ wheel, \ K.E. = \mathbf{\displaystyle \frac{1}{2} \cdot m \cdot v^2 + \frac{1}{2} \cdot I \cdot \omega ^2}[/tex]

Where;

v = The translational velocity of the wheel = ω·r

I = The moment of inertia of the wheel = m·r²

Therefore'

[tex]Sum \ of \ K.E. = \displaystyle \frac{1}{2} \cdot m \cdot (\omega \cdot r)^2 + \frac{1}{2} \cdot m \cdot r^2 \cdot \omega ^2 = \mathbf{m \cdot r^2 \cdot \omega^2}[/tex]

At the bottom of the hill, the potential energy is converted to kinetic energy

Therefore;

P.E. = Sum of K.E.

m·g·h = m·r²·ω²

g·h = r²·ω²

[tex]\displaystyle \omega = \sqrt{ \frac{g \cdot h}{r^2} } = \mathbf{ \frac{\sqrt{g \cdot h} }{r}}[/tex]

Where;

g = Acceleration due to gravity ≈ 9.81 m/s²

Therefore;

[tex]\displaystyle \omega = \frac{\sqrt{9.81 \times 8} }{2} \approx \mathbf{ 4.43}[/tex]

The angular velocity of the of the wheel at the bottom of the incline, ω ≈ 4.43 rad/sec

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A Wheel Has A Radius Of R = 2.0 M And It Rolls Down A Smooth Incline. The Height Of The Incline Is H

Related Questions

Zoe is setting up a track for a toy car. The track has a ramp that is 32° above horizontal. If Zoe wants the car to travel as a projectile for 1.0 seconds, how fast does the toy car need to be moving as it leaves the ramp?
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Answer:

Explanation:

Not enough information.

IF we ASSUME she wants the car to be at LAUNCH LEVEL after 1 second of flight.

THEN

The highest point will have zero vertical velocity and will have taken ½ second to get there. This means that the initial vertical velocity was

v = gt

vy₀ = 9.8(0.5)

vy₀ = 4.9 m/s

vsinθ = vy₀

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objects want to ______ ___________ doing what they're __________ ____________ because they are "lazy." This is called __________.

Answers

Answer:

Explanation:

Objects want to continue doing what they're already doing because they are "lazy." This is called inertia.

1. An airplane flies with an airspeed (speed relative to the air) of 215
km/h. The wind is blowing at 45.0 km/h. Find the velocity of the
plane (relative to the ground) if the plane is pointed straight west and
the wind is:

A. blowing toward the
west (3 points)

B. blowing toward the east (3 points)

C. blowing toward the south (4 points)
(For part C be sure to calculate the angle as well.)

Answers

Answer:

Explanation:

A) 215 + 45.0 = 260 km/h West

B) 215 - 45.0 = 170 km/h West

C) √(215² + 45.0²) = 219.6588... 220 km/h

θ = arctan(45.0/215) = 11.8214... 11.8° S of W

The airplane's ground velocity is westward at 170 km/h regardless of wind direction. The south wind does not affect the plane's westward velocity in component C.

Vector addition will determine each scenario's plane velocity relative to the ground. We'll simplify by assuming a consistent horizontal breeze.

Let's divide the airplane's velocity and wind velocity into westward (negative) and eastward (positive) components.

Data: Plane airspeed = 215 km/h.

45 km/h wind.

A. West wind:

The airplane's westward (negative) ground velocity:

West aeroplane velocity = -215 km/h

-45 km/h west wind.

Find Vg when the wind blows west:

Vg (west) = Aeroplane velocity + Wind velocity (west)

Vg(west) = -215 km/h - (-45 km/h)

Vg (west)=-170 km/h

B. East wind: 2. Westward (negative) aeroplane velocity relative to the ground:

West aeroplane velocity = -215 km/h

Wind velocity (east) = 45 km/h (because the wind is blowing eastward)

Find Vg when the wind blows east:

Vg (west) = Aeroplane velocity (west) + Wind velocity (east).

Vg (west) = -215 + 45 km/h

Vg (west)=-170 km/h

C. Southerly wind: 3. Westward (negative) aeroplane velocity:

West aeroplane velocity = -215 km/h

Wind velocity (south) = 0 km/h (no effect since wind is not moving westward)

Find Vg when the wind blows south:

Vg (west) = Aeroplane velocity (west) + Wind velocity (south).

Vg (west) = -215 + 0 km/h.

Vg (west)=-215 km/h

All resultant velocities are westward and 170 km/h.

Part C's plane's westward velocity is unaffected by the south wind. The plane's ground velocity remains -215 km/h (westward). Since the heading is westward, no angle is needed.

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What capacitance is needed to store 3μC of charge at a voltage of 120V?

Answers

Answer:

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Explanation:

Charge =q=3×[tex]10^{-6}[/tex]C

Voltage=V=120V

Q=CV

C=Q/V

   =3×[tex]10^{-6}[/tex]/120

   =1/40×[tex]10^{-6}[/tex]

        C = 0.025F

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There are more dissolved solids within the cell than outside thecell.

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[tex] \large \bf{Answer:-}[/tex]

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Please help me answer the following question!

What is the momentum of a 750-kg Volkswagen Beetle when at rest?
Please give the Value and Unit

Answers

Answer:

P = 0

Explanation:

Momentum is defined as the quentity of motion contained in a body. Mathematically, it can be defined as the product of mass and velocity. So, in order to determine the Volkswagen Beetle, at rest, we can use the simple formula, as follows:

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Answers

The new oscillation frequency of the pendulum clock is 1.14 rad/s.

     

The given parameters;

Mass of the pendulum, = M Length of the pendulum, = LInitial angular speed, [tex]\omega _i[/tex] = 1 rad/s

The moment of inertia of the rod about the end is given as;

[tex]I_i = \frac{1}{3} ML^2[/tex]

The moment of inertia of the rod between the middle and the end is calculated as;

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Apply the principle of conservation of angular momentum as shown below;

[tex]I _i \omega _i = I _f \omega _f\\\\\frac{ML^2}{3} (1 \ rad/s)= \frac{7ML^2}{24} \times \omega _f\\\\\frac{24 \times ML^2}{3 \times 7 ML^2} (1 \ rad/s)= \omega _f\\\\1.14 \ rad/s = \omega _f[/tex]

Thus, the new oscillation frequency of the pendulum clock is 1.14 rad/s.

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Answer:

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WILL GIVE BRAINLY best answer with steps

Answers

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s3 = 1/2·(1/2m/s²)·(30s)² = 225m.

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Answers

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The change in state of every matter is accompanied by lost or gained of energy.

Example is water.

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Answer:

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Explanation:

give me brain pls

Answer:

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Answer:

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Explanation:

Answer:

Explanation:

The shape of the horse's withers is also a determining factor in choosing a saddle. An adjustable hoop saddle allows you to choose with finesse the opening of the tree at the height of the withers, in order to best adapt to each horse. It is the size of the arch that determines the opening of the saddle.

English saddles are the main riding saddles used in equestrian disciplines around the world: Show jumping, endurance, require specific designs to meet specific needs. For example, dressage saddles are designed to bring the rider closer to the horse, allowing him to communicate very precisely with his horse.

A dwarf planet has a mass of 0.0045 times that of the Earth and a diameter on average 0.19 times that of the Earth. What is the escape velocity of the dwarf planet? (Type in the numerical answer and unit, e.g. 10m/s)

Answers

The escape velocity of the dwarf planet is 1,721.8 m/s.

The given parameters:

Mass of the dwarf planet, m = 0.0045 MMass of the Earth = 5.98 x 10²⁴ kgDiameter of the planet, d = 0.19 DDiameter of the Earth, D = 12,742 km

The mass of the of the dwarf planet is calculated as follows;

[tex]m = 0.0045 \times 5.98 \times 10^{24} \ kg\\\\m = 2.69\times 10^{22} \ kg[/tex]

The radius of the dwarf planet is calculated as follows;

[tex]r = \frac{0.19 D}{2} \\\\r = \frac{0.19 \times 12, 742, 000}{2} \\\\r = 1,210,490 \ m[/tex]

The escape velocity of the dwarf planet is calculated as follows;

[tex]v _e = \sqrt{\frac{2GM}{r} } \\\\v_e = \sqrt{\frac{2\times 6.67 \times 10^{-11} \times 2.69 \times 10^{22}}{1,210,490}}\\\\v_e = 1,721.8 \ m/s[/tex]

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A 4.0-mF capacitor initially charged to 50 V and 6.0-mF capacitor charged to 30 V are connected to each other with the positive plate of each connected to the negative plate of the other. what is the final charge of the 6.0-mF capacitor?

a. 20 mC
b. 8.0 mC
c. 10 mC
d. 12 mC
e. 230 mC

Answers

[tex]\huge\color{pink}\boxed{\colorbox{black}{Answer ☘}}[/tex]

12 mC

Explanation:

We are given that...

[tex]C_{1} = 4mF \\ V_{1} = 50v \\ C_{2} = 6mF \\ V_{2} = 30v \\ \\ we've \: to \: find \: the \: final \: charge \: on \: the \: 6mF \\capacitor \:- \\ \\ we \: know \: that ,\: \\ Q = CV \\ \\ using \: the \: formula \: \\ Q_{1} = 4 \times 50 = 200mC \\ Q_{2} = 6 \times 30 = 180mC \\ \\ total \: charge , \: Q_{1} - Q_{2} = 200 - 180 = 20mC \\ \\ let \: V \: be \: the \: final \: potential \: \\ 4V + 6V = 20mC\\ 10V = 20mC \\ V = \frac{20}{10} = 2V \\ final \: charge \: Q = CV = 6 \times 2 = 12mC[/tex]

therefore,

σptíσn ( d ) íѕ cσrrєct!

hope helpful~

~Be Brainly!

Which degree would a person most likely pursue if they are interested in how
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B. Mechanical engineering
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SUBMIT

Answers

Answer:

Computer science

Explanation:

You would get everything you need to know about computers if you took computer science. I hope this helps

Answer:

Computer science

Explanation:

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Answers

Explanation:

We use the Theorem of conservation of mechanical energy for finding the velocity when it strikes the ground:

Ei = Ef

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Ui = Kf

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So the momentum will be:

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Answer:

Neutrons

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Answer:

a. amount of time spent swimming

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Answers

Here

Acceleration and initial velocities are constant.

According to first equation of kinematics.

[tex]\\ \sf\longmapsto v=u+at[/tex]

[tex]\\ \sf\longmapsto v=0+at[/tex]

[tex]\\ \sf\longmapsto v=at[/tex]

[tex]\\ \sf\longmapsto v\propto t[/tex]

Time was t at velocity vTime will be 4t at velocity 4v

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Answers

Answer:

The triangle law of forces can also be stated as. if a body is in equilibrium under the action of three forces acting at a point, then the three forces can be completely represented by the three sides of a triangle taken in order. A body might be subjected to further than one force at a similar time.

Explanation:

Hope it's help

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