a tube of constant circular cross-section, sealed at on end, contains an ideal gas trapped by a cylinder of mercury of length 0.035m. The whole arrangement is in the Earth's atmosphere. The density of mercury is 1.36*10^4, more details provided in the images.

A Tube Of Constant Circular Cross-section, Sealed At On End, Contains An Ideal Gas Trapped By A Cylinder
A Tube Of Constant Circular Cross-section, Sealed At On End, Contains An Ideal Gas Trapped By A Cylinder

Answers

Answer 1

Answer:

P V = N R T      ideal gas equation

V = .19 * A      volume of enclosed gas

.19 P = N R T / A      using volume of enclosed gas

P = Po + Phg       pressure on gas = atmospheric (Po) + Phg pressure due to column of mercury

.19 (Po + Phg) = N R T / A which is what was asked

Note Phg = density of Hg * height of Hg * acceleration due to gravity

Answer 2

A tube of constant circular cross-section, sealed at on end, contains an ideal gas trapped by a cylinder of mercury of length 0.035m. There will atmospheric pressure and pressure due to mercury column on trapped gas column  having length 0.19m which is given by,

(p₀+pm)×0.190 = nRT÷A.

What is Pressure?

Pressure is defined as force per unit area. i.e. P = F/A it gives the force on unit area.  its SI unit is Pascal (Pa) which is equal to N/m².  is a scalar quantity. its dimensions are [M¹ L⁻¹ T⁻²].

Looking at the figure from top to bottom, we can see the top end of the tube is opened. There is 0.035m of mercury column below which we have a air 0.190m of gas column.

We can feel the physics behind this figure what is happening here, top of the tube is open so there is atmospheric pressure acting on the mercury column and mercury column is above the gas column, it means that both atmospheric pressure and mercury pressure will act on gas column.

i.e.  (p₀+pm) = pressure on the air column

this (p₀+pm) is downward pressures, hence gas inside the tube gets compressed due to this pressure because bottom end is closed. it means that back pressure will be created inside the gas in upward direction and both pressures becomes equal at equilibrium.

i.e. (p₀+pm) = back pressure inside the gas column......1)

according to ideal gas equation, PV=nRT

pressure inside the air column is P = nRT÷V

where V is volume of gas that is A×0.190.

P = nRT÷(A×0.190).....( back pressure inside the gas column).

equation 1 becomes

(p₀+pm) = nRT÷(A×0.190).

Hence we get

(p₀+pm) ×0.190= nRT÷(A).

Hence proved.

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Answer:

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Hi there!

We know that:

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Hi there!

[tex]\boxed{\text{Her angular velocity decreases.}}[/tex]

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When this person extends her arms, her moment of inertia increases.

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Answer:

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i hope i understood this question and answered it correctly XD

PLS, NO SPAM!!

How can athletes benefit from feedback given using the feedback sandwich technique?

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Answer:

The key benefits to this is the athlete thinks and reflects for themselves which is a vital part of the Learning Styles Model. This technique is most useful for more experienced athletes who like to have involvement and their own opinions about their performance.

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Answers

Rogue waves are unpredictable and sudden waves that appear as surface waves and that have the ability to make ships capsize. For a wave to be a non-linear equation it means that it is unpredictable. What is expected does not actually happen. The resulting wave is often chaotic in nature.

In mathematics, a non-linear equation is one in which the input does not equal the output. This makes it more difficult to predict the outcome of variables.

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Answers

Answer:

Explanation:

The three things that occur naturally everyday and how science has had an impact on what we think or do about them is

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O D= m
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m
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Answers

It is P=M/V but I guess you could change the P with a D depending on what year group you are in. So it’s D=M/V.

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Answers

Answer:

a) Gradient = rise/run = mass/volume

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Answers

The empirical formula of the compound is Li₂CO₃

First, we will determine the respective number of moles of each element present in the compound by dividing by their atomic masses

Lithium                      Carbon                          Oxygen

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0.9006                      0.4496                          1.35

Now, divide through by the smallest number of moles, that is, 0.4496

Lithium                      Carbon                          Oxygen

0.9006÷0.4496        0.4496÷0.4496            1.35÷0.4496

2                                      1                                    3

Hence, the empirical formula of the compound is Li₂CO₃

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Answers

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Answers

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