a trapezoid was transformed on a coordinate grid using the rule (x, y) → (–x, y). which of the following describes this transformation?

the minimum possible number of rows of zeros in any row echelon form is 2

If a matrix in linear algebra has the structure that comes from a Gaussian elimination, it is said to be in echelon form. The bottom row has solely zeros, as do all other rows. A nonzero row's pivot, also known as the leading coefficient, is always located strictly to the right of the leading coefficient of the row above it.

The row echelon form of 5 × 3 matrix is given by -

                                        [tex]\left[\begin{array}{ccc}1&a&b\\0&1&d\\0&0&1\\0&0&0\\0&0&0\end{array}\right][/tex]

As we can see, the number of rows containing zeros are 2.

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Answer:

Step-by-step explanation:

C

Answer:

85

Step-by-step explanation:

To find the mean, you have to add all the scores up and divide it by how many scores there are. In this case, there are seven scores, so we first add them up.

70+75+80+85+90+95+100=595

Now, we divide 595 by 7.

595/7=85

Hope this helps!

Have a wonderful day! :D

Answer: It is 5.3 based by rounding by it's tenth

Step-by-step explanation:

1. Add it all, in this case (3*2) + (7*2) + (8*2) + 1 which equals to 6 + 14 + 16 + 1

2. This then becomes 20 +17, which is 37, which we then divide by 7 becomes 5.285, or 5.3

Answer:

the number which has no factors is known as prime number

Answer: numbers that have only 1 and itself as factors.

Step-by-step explanation:

Answer:

Step-by-step explanation:

its 30.8. this is because .7 + .1 = .8 . Now just add that to the 30 and you get 30.8

Answer:

30.8

Step-by-step explanation:

All you have to do is take the 0.1 and add it to the 30.7 so you would add it to the .7 which gives you 8 and now just put the 30 back with your decimal

Suni needs to deposit $12,304.45 semiannually to have $100,000 to repay the loan at 0.9% interest.

Periodic payments are equal payments made periodically to settle a mortgage loan.

The periodic payment for a loan can be computed using an online finance calculator.

N (# of periods) = 8 times (4 years x 2)

I/Y (Interest per year) = 0.9%

PV (Present Value) = $0

FV (Future Value) = $100,000

Results:

PMT = $12,304.45

Sum of all periodic payments = $98,435.60 ($12,304.45 x 8)

Total Interest $-1,564.40

Thus, the periodic deposit that Suni needs to make semiannually to have $100,000 to repay the loan at 0.9% interest is  $12,304.45.

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Answer:

both are rational numbers

Step-by-step explanation:

Answer:

both are irrational numbers.

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Answer: -1

Step-by-step explanation:

Multiply -3 to (1+6r)

-3 - 18r = 14 - r

Then, group like terms and change the signs

-18r + r = 14 + 3

Add

-17r = 17

Divide 17 by 17 to solve for r

r = 17/-17

r = -1

To find the average rate of speed per miles an hour, do the following equation: miles ÷ hour = miles per hour.

So, we divide 3,000 ÷ 7 = 428.5714285714 but we can make round it to 429.

The airliners average rate of speed in miles per hour is 429 miles per hour.

The number of gasolines is 1,800,000 miles driven.

­Gas is known as an aliphatic hydrocarbon. All in all, gas comprised of particles made out of nothing, yet hydrogen and carbon organized in chains. Fuel particles have from seven to 11 carbons in each chain. Gas or petroleum is a straightforward, oil determined combustible fluid that is utilized principally as a fuel in most flash touched off gas powered motors. Fuel is as of now thought to be frozen in the event that it transforms into a thick slop or wax. To absolutely keep away from frozen gas inside the vehicle, center around forestalling the fuel line from freezing during winter. Fuel fumes are heavier than air, so they choose the ground and travel like a fluid. Along these lines, they frequently track down their direction into channels, storm cellars, and sewer lines.

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Rewriting 15 1/6 as a decimal, rounded to the nearest thousandths, is: 1,516.667.

To rewrite the percentage, 15 1/6% as a decimal do the following as shown below:

Convert 15 1/6 from mixed number to an improper fraction:

91/6

Multiply 91/6 by 100:

91/6 × 100

= 9,100/6

Divide

9,100/6 = 1,516.667

Thus, rewriting 15 1/6 as a decimal, rounded to the nearest thousandths, is: 1,516.667.

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Nepali rupees that the person requires to exchange $4500 will be equal to NRs. 555,022.8.

We know that:

$ 1 = NRs. 120.92

We are also given that a person needs $ 4500 to visit foreign countries.

Also, for the conversion, bank charges commission as 2 %

Now, $ 4500 in NRs. will be calculated by multiplying 120.92 with $ 4500.

$ 4500 = NRs. 120.92 × 4500

$ 4500 = NRs. 544,140

Now the commission charged by the bank will be:

2 % of 544,140

Commission = 2 / 100 × 544,140

Commission = NRs. 10,882.8

So, the amount the person will require to get $ 4500 will be = NRs. 544,140 + 10,882.8

= NRs. 555,022.8

Therefore, Nepali rupees that the person requires to exchange $4500 will be equal to NRs. 555,022.8.

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Answer:

94800

Step-by-step explanation:

Answer:

94,800

Step-by-step explanation:

Well semimonthly means 2 times a month

If you multiply 3,850 by 2 you get 7,900

Then simply multiply 7,900 by 12 (12 months in a year) and you get 94,800

The answer is u = (10, 5)

Step-by-step explanation:

Imagine u = (x, y)

10 = x/2 + 10/2

10 = x/2 + 5

20 = x + 10

x = 20 - 10

x = 10

u = (10, y)

6 = y/2 + 7/2

6 = y/2 + 3.5

12 = y + 7

y = 5

u = (x, 5)

Thus, u = (10, 5)

Hey there!

b(9 - c) / a^2

= 6(9 - 8) / 4^2

= 6(1) / 4^2

= 6/4 * 4

= 6/16

= 6 ÷ 2 / 16 ÷ 2

= 3/8

Therefore, your answer should be:

3/8

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

The distance between the cars changes by 60.42mph.

Distance is a measurement of how far apart two objects or locations are. Distance in physics or common language can refer to a physical length or an assumption based on other factors. |AB| is a symbol that can be used to represent the distance between two points. "Distance from A to B" and "Distance from B to A" are frequently used interchangeably. A distance function or metric is a technique to describe what it means for elements of some space to be "close to" or "far away" from each other in mathematics. It is a generalization of the idea of physical distance. Through dimensions like time, space, and isolation, an object may be psychologically distanced from itself.

Calculations:

[tex]d=\sqrt{80^{2}+50^{2} } \\[/tex]

d=94.34

1st car -- 40mph/hr

2nd car-- 50 mph/hr

The positions of cars at 4pm

Distance travelled by 1st car = 80m

Distance travelled by 2nd car = 50m

[tex]d^{2}=a^{2} +b^{2}[/tex]

2d.dd/dt=2a(da/dt) +2b(db/dt) =d(dd/dt) =a(da/dt)+b(db/dt)=94.34(dd/dt)=50*50+80*40

dd/dt=(2500+3200)(94.34)  =60.419

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The value of probability density function in the interval between 2 and 10 is 0.125.

A probability density function (PDF), also referred to as the density of a continuous random variable (CRV), is a mathematical function whose value at any particular sample (or point) in the sample space (the range of possible values that the RCV can take), can be interpreted as providing a relative likelihood that the RCRV's value would be close to that sample. Since there are an infinite number of possible values to begin with, the probability per unit length for a continuous random variable to take on any particular value is 0, but the value of the PDF at two different samples can be used to infer, in any given draw of the random variable, even though the absolute likelihood is zero.

Given the assembly time for a product is uniformly distributed between 2 to 10 minutes.

The Probability density function in the internal between 2&10

pdf=1/10-2      = 1/8pdf = 0.125

The probability density function in the interval between 2 and 10 is 0.125.

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If the snacks are to be identical without any food left over only one snack bags can  be made by Angela

The number of granola bars = 28

The number of pieces of dried fruit = 45

If the snack bags should be identical without any food left over, then we need to find out  the greatest number of snack bags, we should find out the Greatest common factor(GCF) or highest common factor(HCF) between 28  granola bars and 45 packages of string cheese

Since , factors of 28 = 1, 2, 4,7,14,28

Factors of 45 = 1, 3,5,9,15,45

Common factors of 28 and 45 = 1

Greatest Common factors of 28 and 45 = 1

Hence, the greatest common factor of 28 and 45 is 1 as only 1 is the common factor in the factors of 28 and the factors of 45.

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Answer: It is m<BAE or measure of angle BAE

Step-by-step explanation:

1. Based by the m<CAE, 135 - 45 equals to 90, so that is not an obtuse angle, m<BAD is the same thing, so those 2 aren't it

2. m<CAD is 65, which is way too low for an obtuse angle, and m<DAE is way too small as well since it's angle is 25, making m<BAE a correct answer

When the sum of the squared deviation scores is SS=20 for a population n=5 scores, then the variance for this population is 4

Given,

The sum of the squared deviation scores SS= 20

Population of n= 5

Then the variance = SS/n

Substitute the values in the equation

The variance = [tex]\frac{20}{5}[/tex]

=4

Hence, when the sum of the squared deviation scores is SS=20 for a population n=5 scores, then the variance for this population is 4

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The parametric equations for the line passing through the points p(2, 4, 2) and q(5, 5, 3) are x=2+5t, y=4+5t and z=2+3t.

The same values may be expressed by a variety of alternative parameterizations because parametric representations are typically non-unique (see the "Examples in two dimensions" section below).

In addition to curves and surfaces, higher dimensional algebraic varieties can also be described by parametric equations; in this case, the number of parameters is equal to the dimension of the manifold or variety, and the number of equations is equal to the dimension of the space in which the manifold or variety is taken into account (for curves the dimension is one and one parameter is used, for surfaces dimension two and two parameters, etc.).

In kinematics, where the motion of an object is represented by equations using time as the parameter, parametric equations are frequently utilized.

Calculations:

Parametric equation of line PQ is

x=2+5t,y=4+5t and z=2+3t

parametric equation of line AB is

x=x1+tx2, y=y1+ty2 and z=z1+tz2

Here as we have P(2,4,2) and Q(5,5,3)as two points,

parametric equation of line

PQ is x=2+5t, y=4+5t and z=2+3t

i.e.

x=2+5t, y=4+5t and z=2+3t

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Paulina is most likely assessing "Test-retest reliability", while Montrose is most likely assessing "Parallel forms reliability."

The consistency with which a method attempts to measure something is indicated by its reliability. The same method applied to the same sample in the same conditions should yield the same results. If not, the measurement method may be unreliable.

Some key points related to the reliability are-

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Certain polynomials with integer coefficients fall into the category of substantially prime polynomials in q[x] if and only if the ideal they create in z[x] contains a (nonzero) integer.

A polynomial is an expression in mathematics that consists of indeterminates (also known as variables and coefficients) that exclusively uses the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables. x2 4x + 7 is an illustration of a polynomial of one uncertain x.

In both mathematics and science, polynomials are widely used. For instance, they are used to define polynomial functions, which can be found in a variety of contexts, from basic chemistry and physics to economics and social science, and they are used in calculus and numerical analysis to approximate other functions. Polynomial equations are used to encode a wide range of problems, from simple word problems to complex scientific problems.

Calculations:

Let d=degP.

Then the Q-vector space V=Q[X]/(P) is d-dimensional.

The residue classes modulo (P) of X2,X3,X5,… are linearly dependent over Q, so there exist a2,a3,a5,…∈Z not all zero such that a2X2+a3X3+a5X5+⋯∈(P).

This shows that there is Q∈Z[X], Q≠0 such that PQ=a2X2+a3X3+a5X5+⋯.

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Transformations are used to move a function from one position to another. The function of g(x) is g(x) = | x/6|.

Given that:

f(x) = |x|

The rule of a horizontal stretch by factor k is:

(x, y) → (x/k,y)

This means that:

g(x) = f(x/k)

In this case, k = 6

So, we have:

g(x) = f(x/6)

Calculate f(x/6)

f(x/5) = |x/6|

Hence, the function of g(x) is

g(x) = |x/6|.

A function is defined as a relation between a set of inputs, each with an output. Simply put, a function is a relationship between inputs, each associated with exactly one output. Each function has a domain and a codomain or scope. Functions are commonly denoted by f(x). x is the input.

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The minimum IQ score for the top 10% of the population is 0.0179.

Standard deviation:

Standard deviation means the root of the variance in the given grouped or ungrouped data.

The standardized value is the value decreased by the mean, divided by the standard deviation:

z =   (x- μ) / σ

where

x: the observation (a specific value that you are calculating the z-score for).

Mu(μ): the mean.

Sigma(σ): the standard deviation.

Given,

The human IQ scores are approximately normally distributed with a mean of 100 and a standard deviation of 15.

Here we need to find the minimum IQ score for the top 10% of the population.

We know that,

x = 131.5

μ = 200

σ = 15

So, when we apply the values on the formula,

Then we get,

=> z = 131.5 - 100 /15

=> z = 2 .10

Determine the corresponding probability using table A-2:

=> P(Z>2.10) = 1 − P(Z<2.10)

=> 1 − 0.9821

=> 0.0179

Therefore, the minimum IQ score for the top 10% of the population is 0.0179.

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The expressions that have numeric value of less than 2 when x = 5 are:

A. x to the power of zero divided by 4.

C. (50 divided by x to the power of 2) to the power of zero

E. x to the power of zero divided by x to the power of 2

To find the numeric value of a function, we replace each instance of the variable by the desired value.

For item a, the expression is:

x^0/4 = 1/4 < 2.

For item b, the expression is:

x/(7^0) = x.

When x = 5, the expression has a numeric value of 5 > 2.

For item c, the expression is:

(50/x^2)^0 = 1 < 2.

For item d, the expression is:

2(10/x)^0 = 2 x 1 = 2 = 2.

For item e, the expression is:

x^0/x^2 = 1/x^2.

When x = 5, the expression has a numeric value of 1/25 < 2.

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The statement lim infn sₙ > lim infn tₙ and lim sup sₙ ≤ lim sup tₙ is proved such that sₙ ≤ tₙ for all n≥n₀.

The biggest element in P, if one exists, that is less than or equal to each element of S is known as the infimum of a subset S of a partially ordered set P. As a result, the phrase largest lower bound is also frequently employed. A set's infimum is its highest upper bound, while its supremum is its lowest upper bound. The supremum is the smallest upper bound of a set, whereas the maximum is the largest member of a set. The largest number in one column that is less than or equal to the target value in the other column is found using the greatest lower bound (glb) operator. The smallest number that is larger than or equal to the target number is discovered using the least upper bound (lub) operator.

Let us suppose that sₙ ≤ tₙ if n≥N, but that

lim infn sₙ > lim infn tₙ.

Let [tex]E_{s}[/tex] denote the set of all subsequential limits of {sₙ}, and let [tex]E_{t}[/tex] denote the set of all subsequential limits of {tₙ}. Then

inf [tex]E_{s}[/tex] >inf [tex]E_{t}[/tex].

This implies that there exists some x∈[tex]E_{t}[/tex] such that inf [tex]E_{s}[/tex] >x>inf [tex]E_{t}[/tex]., since otherwise inf [tex]E_{t}[/tex]. would not be the greatest lower bound of [tex]E_{t}[/tex]. Hence some subsequence of {tₙ}, say {tₙ}, converges to x< inf [tex]E_{s}[/tex].

lim sup sₙ ≤ lim sup tₙ.

Let [tex]E_{s}[/tex] denote the set of all subsequential limits of {sₙ}, and let [tex]E_{t}[/tex] denote the set of all subsequential limits of {tₙ}. Then

sup [tex]E_{s}[/tex] ≤ sup [tex]E_{t}[/tex].

This implies that there exists some x∈[tex]E_{t}[/tex] such that sup [tex]E_{s}[/tex] ≤ x ≤ sup [tex]E_{t}[/tex]., since otherwise sup [tex]E_{t}[/tex]. would be the greatest lower bound of [tex]E_{t}[/tex]. Hence some subsequence of {tₙ}, say {tₙ}, converges to x< sup [tex]E_{s}[/tex].

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