A toy gun uses a spring to shoot plastic balls (m = 50 g). The spring is compressed by 3.0 cm. Let k=2.22 × 105 N/m. (a) Of course, you have to do some work on the gun to arm it. How much work do you have to do? (b) Suppose you fire the gun horizontally. How fast does the ball leave the gun? (c) Now suppose you fire the gun straight upwards. How high does the ball go?

Answers

Answer 1

Answer:

Explanation:

Given that:

mass of the plastic ball = 50 g = 50 × 10⁻³ kg

spring constant (k) = 2.22 × 10⁵ N/m

compression of spring (x) = 3.0 cm = 3 × 10⁻² m

a) Work done:

[tex]= \dfrac{1}{2}kx^2 \\ \\ = \dfrac{1}{2}\times 2.22 \times 10^{5}\times (3 \times 10^{-2})^2 \\ \\ = 99.9 \ J[/tex]

b) When the gun is fired horizontally;

In the spring, the potential energy is changed to kinetic energy.

i.e.

[tex]\implies \dfrac{1}{2}kx^2 = \dfrac{1}{2}mv^2 \\ \\ 2.22 \times 10^5 \times (3\times 10^{-2}) ^2 =50 \times 10^{-3} \times v^2\\ \\ \mathbf{v= 63.2 m/s}[/tex]

c) The max height the bullet will reach if the gun is being shot upward is:

[tex]H_{max}= \dfrac{v^2}{2g} \\ \\ H_{max}= \dfrac{63.2^2}{2\times 9.8}[/tex]

[tex]\mathbf{H_{max}= 203.9 \ m}[/tex]


Related Questions

What is the momentum of a 200 kg truck travelling at 20 m/s?

Answers

Answer:

p = 4000 kg-m/s

Explanation:

Given that,

The mass of a truck, m = 200 kg

Speed of the truck, v = 20 m/s

We need to find the momentum of the truck. The formula for momentum is given by :

p = mv

so,

[tex]p=200\times 20\\\\p=4000\ kg-m/s[/tex]

So, the momentum of the truck is equal to 4000 kg-m/s.

Which equation could not be used to determine straight line acceration?

Answers

Answer:

the answer for the question is the last option

state and explain the disadvantages of anomalous expansion of water​

Answers

Answer:

я не знаю старайся изо всех сил

Explanation:

[tex]\huge{\mathbb{\tt { QUESTION↓}}}[/tex]

[tex]\color{green}{\tt State \: and \: explain \: the \: disadvantages}[/tex]

[tex]\color{green}{\tt { of \: anomalous \: expansion \: of \: water}}[/tex]

[tex]\huge{\mathbb{\tt {ANSWER↓}}}[/tex]

[tex]{\boxed{\boxed{\tt { DISADVANTAGES \: of \: anomolous \: expansion \: of \: water }}}}[/tex]

Since the maximum density can be found for a positive temperature, water's own weight will prevent it from freezing from the bottom up. However, the anomalous expansion of water has some negative consequences. ... As the water freezes it expands and can rip pipes open.

[tex]{\boxed{\boxed{\tt { What \: is \: the \: state \: of \: anomalous \: expansion \: of \: water? }}}}[/tex]

The anomalous expansion of water is an abnormal property of water whereby it expands instead of contracting when the temperature goes from 4o C to 0o C, and it becomes less dense. The density is maximum at 4 degree centigrade and decreases below that temperature as shown in graph

#CarryOnLearning

#JustEnjoyTheSummer

→XxKim02xX

A lightbulb has 25 W stamped on it. What does this mean?

Answers

Answer:

A lightbulb has 25 W stamped on it. What does this mean?:

These labels mean that each lightbulb has Its respective power delivered to It when It Is connected to a constant

Explanation:

A toy radio-controlled car races around a circular track in a time of 2 MINUTES, with a speed of 5.25 m/s. What is the radius of the
circular track? (will give brainliest)

Answers

Answer:

The radius will be "100.31 m". A further solving is given below.

Explanation:

The given values are:

Time,

T = 2 minutes

i.e.,

 = 120 seconds

Speed,

V = 5.25 m/s

As we know

⇒  [tex]T=\frac{2 \pi R}{V}[/tex]

then,

⇒  [tex]R=\frac{TV}{2 \pi}[/tex]

On substituting the given values, we get

⇒      [tex]=\frac{120\times 5.25}{2\times 3.14}[/tex]

⇒      [tex]=\frac{630}{6.28}[/tex]

⇒      [tex]=100.31 \ m[/tex]

A car increases from 15 km/s to 45 km/s in 5 seconds. Calculate the average acceleration of the car during these 5 seconds. (2 points) A. 6 km/s2 B. 12 km/s2 C. 30 km/s2 D. 60 km/s2​

Answers

A is the correct answer

Is telekinesis real??? I really wanna start learning it!

Answers

Answer:

if you only have to control your chakra and know how to get all your vibes to pass it to objects and it takes time to practice

An object is located 20.0 cm from a convex lens. The lens focuses light at a
distance of 10.0 cm. What is the image distance?

A. 6.67 cm
B. -6.67 cm
C. -20.0 cm
D. 20.0 cm

Answers

The Answer Is :  D. 20.0 cm

My Reason : These types of problems can all be solved using the lens or mirror equation.

1/20 +1/q= 1/10

q=20 cm

The image is formed behind the lens at 2f or the center of curvature.

It is real, inverted, and the same size as the object

The Answer Is: D. 20.0 cm

Explanation: I did the test :)

Which applications, either for diagnostic purposes or for therapeutic purposes, do not involve ionizing radiation? Check all that apply.

Answers

Answer: I do not know (is this an RP question? ;-;)

Explanation:

Answer:

Applications in which ionizing radiation are not used are  

MRI

ultrasound

laser surgery

Explanation:

hope its right

bestfriend

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Answer:

REVENGE

Explanation:

HAHAAHAHAAHAHAHA

Would Lincoln, Nebraska or San Diego, California have a smaller range in average monthly temperatures

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How fast is a 0.50 kg ball moving if it's kinetic energy is 400 j

Answers

Answer:

Correct 40 m/s

Explanation:

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