A student pushed a box 27.0 m across a smooth, horizontal floor using a constant force of 113 N. If the force was applied for 9.00 s, how much power was developed, to the nearest watt? Round your answer to the nearest whole number.

Answers

Answer 1
339 Watts

Nm/s=Watts.
113N * 27m / 9s
339 Watts
Answer 2

The power is a dependent parameter on work done for a given interval of time. The magnitude of power developed due to the applied force is 339 W.

What is power?

The rate of doing work is known as Power. Mathematically, the power is equal to the ratio of work and time interval.

Given data -

The distance covered by the box is, d = 27.0 m.

The magnitude of the constant force is, F = 113 N.

The time interval for the application of force is, t = 9.00 s.

The expression for the power developed is given as,

P = W/t

here, W is the work done and its value is, W = F × d.

Solving as,

P = F × d/t

Solving as,

P = 113 × 27.0/9.0

P = 339 W

Thus, we can conclude that the magnitude of power developed due to the applied force is 339 W.

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Related Questions

A 10.0kg box sits at rest on ramp that has an incline of 20.0° from the horizontal. What is the force of gravity acting on the box?

A. -98.0N

B. 98.0N

C. -92.1N

D. -33.5N

Answers

I think it would be d

Answer:

98.0N

Explanation:

6. A hockey player skates ten meters to the goal.
What term is used to describe the hockey
player's process of changing position?

Answers

Answer:

Displacement

Explanation:

Displacement is a term used to represent change in position.

Jackson throws a football 30 meters at a speed of 15 m/s. How long was the football in the air before Laurence caught it for touchdown

Answers

Answer:

2s

Explanation:

Given parameters:

Distance  = 30m

Speed  = 15m/s

Unknown:

Time before Laurence caught it = ?

Solution:

To solve this problem;

    Speed  = [tex]\frac{disance }{time}[/tex]  

 Time taken  = [tex]\frac{distance }{speed }[/tex]   = [tex]\frac{30}{15}[/tex]  = 2s

The time it takes is 2s

Given:

30 metersSpeed of 15 m/s

We will solve:

Speed  = [tex]\frac{distance}{time}[/tex]

Time taken  = [tex]\frac{distance}{time}[/tex] = [tex]\frac{30m}{15m/s}[/tex] = 2s

The time it takes is 2s

What is your average speed if you walk 2 kilometers in 20minutes

Answers

Answer:

12 km/hr

Explanation:

Speed= Distance/Time

Answer:

12km/h

Explanation:

average speed= Distance covered /time taken

average speed=2km/20minutes

=but 1 minutes is 60 seconds

=2km/60minutes

=12km/h

PLEASE HELPP
Look at the picture

Answers

answer: It’s c
explaining: i guessed
It’s either C. Or B. but it’s most probably B. Sorry if I’m incorrect.

In water, sound travels 1500 m/s. A whale sings at a frequency of 17 Hz. What will be the length of the sound wave?

Answers

Answer:

A 20 Hz sound wave is 75 m long in the water (1500/20 = 75) whereas a 20 Hz sound wave in air is only 17 m long (340/20 = 17) in air. As we descend below the surface of the sea, the speed of sound decreases with decreasing temperature.

Which of these would be the most efficient means to transmit light pulses over long distances?

Answers

Answer: It’s fiber optics so B

IS IT B!! if not pls helpp!

Answers

Answer:

I believe you are correct but we just started this unit

Explanation:

What is the distance traversed by the particle between 0 seconds and 6 seconds?

Answers

Answer:

I dont know to be honest

Explanation:

i dont know to be honest

1. A net force of 13 Newtons acting north on an object for 4.0 seconds will produce an impulse of?

Answers

Answer:

48 kg m/s north

Explanation:

This is not the exact answer but if there's something really close choose that answer

Body Systems Directly Involved (Give at Least 2)
Cartoon
13. Ouch! You step on a tack and jump away without even thinking. Then you decide to pick up the tack and place it back in a desk drawer.
I need the second one the nervous system and...

Answers

Answer:

Nervous system and immune system

Explanation:

The nervous system is involved because you immediately jumped away, that ur brain and nerves initiating the fight or flight response. The immune system is involved because the tack most likely pierced your skin, so your immune system needs to work to make sure the wound does not get infected.

Guidewords for the word “serpent” may be
a.
Serbia and service
c.
Seltzer and Saturday
b.
Seattle and section
d.
Solitude and second
THE CORRECT ONE IS A!!!!!!!!

Answers

Answer:

A. Serbia and service

Explanation:

A guide word is a word written on top of a page to indicate the first or last word entry on that page. For example in a dictionary, they indicate the alphabetical first and last words on the page.

In this example; the word ' serpent ' note the first three letters to guide you in the words that are on that page;

In this case : Serbia  and Service.


An Olympic athlete threw a javelin at the following angles, 30°, 40°, 60°, and 70°. All at the
same speed. Which two angles resulted in the same distance?

Answers

Answer:

30 and 60 degrees

Explanation:

Select the true statements.
The interquartile range of A is 1 less than the interquartile range of B.
Including the runs allowed in the tenth game does not cause the spread of the data to change
The median of A is the same as the median of B.
The interquartile range of B is greater than the interquartile range of A.
The median of B is 1 run more than the median of A.
M

Answers

Answer:

The true statements are;

The median of A is the same as the median of B

The interquartile range of B is greater than the interquartile range of A

Explanation:

The given parameters are;

The set of the number of runs, A = {1, 4, 2, 2, 3, 1, 1, 2, 1}

The number of runs the pitcher allows in the tenth game = 9 runs

The set of the number of runs allowed in 10 games B = {1, 4, 2, 2, 3, 1, 1, 2, 1, 9}

Rearranging the data, we get  

A = 1, 1, 1, 1, 2, 2, 2, 3, 4

B = 1, 1, 1, 1, 2, 2, 2, 3, 4, 9

For the set A, we have;

Q₁ = 1, Q₂ = 2, Q₃ = 2

Therefore, the interquartile range of A = Q₃ - Q₁ = 2.5 - 1 = 1.5

For the set B, we have;

Q₁ = 1, Q₂ = 2, Q₃ = 2

Therefore, the interquartile range of A = Q₃ - Q₁ = 3.25 - 1 = 2.25

Therefore, the correct answers with regards to the two data are;

The median of A is the same as the median of B

The interquartile range of B is greater than the interquartile range of A

Which of the following quantities are vectors?
charges
electric fields
energy
potentials

Answers

Answer:

electric fields

Explanation:

Which of the following statements is TRUE concerning forces?
A. Forces in the same direction are added together
B. Forces in the opposite direction are subtracted from one another
C. An overall net force must be present in order for movement to occur
D. All of the above

Answers

The answer is d I took the test

what are 3 chemical properties to plastic

Answers

Answer:

holla at me!!!!!!!!!!????

organic chemistry of the polymer
resistance and reaction to various chemical products and process.

10 POINTS QUESTION: Why both are models for monomers, polymers, and cross-linked polymers

Answers

Answer:

Because both monomers and polymers and cross linked polymers are mers with physically properties which is good for applycations

Explanation:

because they are good for using and not using

also, this is a 5 point question, you are not  fooling anyone. thx for 5 points tho

A 5.00 kg crate is on a 21.0° hill.
Using X-Y axes tilted down the
plane, what is the y-component
of the weight?
(Unit = N)

Answers

Answer:

17.56 N

Explanation:

Given that,

Mass of a crate, m = 5 kg

It is on a 21.0° hill

We need to find the y component of the weight.

y component = mgsinθ

Put all the values,

y-component = 5×9.8×sin(21)

= 49×sin(21)

= 17.56 N

So, the y-component of the weight is 17.56 N.

Answer:

-45.745

Explanation:

it is negative because it is downwards.

A student is leaving the lesson and walking to Maths at a speed of 1m/s. He notices that he is late for the lesson and speeds up to 3 m/s. It takes him 4 seconds to speed up. Calculate his acceleration.

Answers

Answer:

Acceleration = 0.5 m/s²

Explanation:

Given the following data;

Initial velocity, u = 1m/s

Final velocity, v = 3m/s

Time, t = 4 seconds

To find acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]

[tex]a = \frac{v - u}{t}[/tex]

Substituting into the equation, we have;

Acceleration = (3 - 1)/4

Acceleration = 2/4

Acceleration = 0.5 m/s²

A vertical spring with a force constant of 26 N/m has a relaxed length of 35 cm. A 200 g mass is then
attached to the end of the spring and is allowed to come to rest. (a) Find the length of the stretched spring.
(b) How much elastic potential energy is stored in the spring?

I just need the work please the answers is
(a) 45.2 J
(b) 0.0739

Answers

Answer:

(a) The length of the stretched string is approximately 42.53846 cm

(b) The elastic potential energy stored in the string is approximately 0.073877 Joules

Explanation:

(a) The given parameter are;

The force constant of the vertical spring, k = 26 N/m

The relaxed length of the spring, L = 35 cm = 0.35 m

The mass attached to the end of the spring, m = 200 g = 0.2 kg

By Hooke's law, we have;

F = k·x

Where;

F = The applied force on the sting = The weight of the attached mass, W

∴ F = W

The weight of the attached mass, W = m × g

Where;

g = The acceleration due to gravity ≈ 9.8 m/s²

Therefore, F = W = 0.2 kg × 9.8 m/s² = 1.96 N

From Hooke's law, we have;

x = F/k = 1.96 N/(26 N/m) ≈ 0.0753846 m

The extension of the stretched spring, x ≈ 0.0753846 m

The length of the stretched string, L[tex]_{stretched}[/tex] = L + x

∴ L[tex]_{stretched}[/tex] ≈ 0.35 m + 0.0753846 m ≈ 0.4253846 m

0.4253846 m = 42.53846 cm

The length of the stretched string ≈ 42.53846 cm

(b) The elastic potential energy stored in the string, U = 1/2·k·x²

By substituting the known values, we get;

U = 1/2 × 26 N/m × (0.0753849 m)² ≈ 0.073877 Joules

4) Which is the BEST description of a tectonic plate? *
O A. Tectonic plates consist of the lithosphere and part of the asthenosphere.
O B.Tectonic plates are large pieces of mesosphere that never move.
C. Tectonic plates are large pieces of lithosphere that move on tope of the
asthenosphere.
O D. None of these answers is correct.

Answers

Using process of elimination the answer is D

Answer:

The answer is A

Explanation: i took k12

Four velcro-lined air-hockey disks collide with each other in a perfectly
inelastic collision. The first disk has a mass of 50.0 g and a velocity of
0.80 m/s to the west, the second disk has a mass of 60.0 g and a velocity of
2.50 m/s to the north, the third disk has a mass of 100.0 g and a velocity of
0.20 m/s to the east, and the fourth disk has a mass of 40.0 g and a
velocity of 0.50 m/s to the south. What is the final velocity of the disks
after the collision?

Answers

Answer:

The magnitude of the final velocity is approximately 0.526 m/s in approximately the direction of 8.746° East of South

Explanation:

The given collision parameters are;

The kind of collision experienced by the four velcro-lined air-hockey disk = Inelastic collision

The mass of the first disk, m₁ = 50.0 g

The velocity of the first disk, v₁ = 0.80 m/s West = -0.8·i

The mass of the second disk, m₂ = 60.0 g

The velocity of the second disk, v₂ = 2.50 m/s North = 2.5·j

The mass of the third disk, m₃ = 100.0 g

The velocity of the third disk, v₃ = 0.20 m/s East = 0.20·i

The mass of the fourth disk, m₄ = 40.0 g

The velocity of the fourth disk, v₄ = 0.50 m/s South = -0.50·j

Therefore, the total initial momentum of the four velcro-lined air-hockey disk, [tex]\Sigma P_{initial}[/tex] is given as follows;

[tex]\Sigma P_{initial}[/tex] = m₁·v₁ + m₂·v₂ + m₃·v₃ + m₄·v₄ = 50.0×(-0.80·i) + 60.0×(2.50·j) + 100 × (0.20·i) + 40.0 × (-0.50·j)

∴ [tex]\Sigma P_{initial}[/tex] = -40·i + 150·j + 20·i - 20·j = -20·i + 130·j

∴ [tex]\Sigma P_{initial}[/tex] = -20·i + 130·j

By the law of conservation of linear momentum, we have;

[tex]\Sigma P_{initial} = \Sigma P _{final}[/tex] = -20·i + 130·j

Therefore, given that the collision is perfectly inelastic, the disks move as one after the collision and the four masses are added to form one mass, "m", m = m₁ + m₂ + m₃ + m₄ = 50.0 + 60.0 + 100.0 + 40.0 = 250.0

∴ m = 250.0 g

Let, "v" represent the final velocity of the four disks moving as one after the collision

We have;

[tex]\Sigma P _{final}[/tex] = m × v = 250.0 × v = -20·i + 130·j

∴ v = -20·i/250 + 130·j/250 = -0.08·i + 0.52·j

The final velocity of the four disks after collision, v = -0.08·i + 0.52·j

The magnitude of the final velocity, [tex]\left | v \right |[/tex] = √((-0.08)² + (0.52)²) ≈ 0.526

[tex]\left | v \right |[/tex] ≈ 0.526 m/s

The direction of the final velocity, θ = arctan(0.52/(-0.08)) ≈ -81.254°

The direction of the final velocity, θ ≈ -81.254° which is 8.746° East of South

4. A toy car travels 60 m during 5.7 s at a constant speed. What is the speed of the toy car?
15.556
13.526
6.116
10.526
None of these is correct.

Answers

Answer: 10.526m/s

Explanation:

The speed of the toy car would be calculated as the distance travelled by the toy card divided by the time taken. This will be:

= Distance travelled / Time taken

= 60/5.7

= 10.526m/s

The speed of the toy car is 10.526 meters per second.

Who is the father of Nuclear Physics?​

Answers

Answer:

Ernest Rutherford, 1st Baron Rutherford of Nelson

Is work being done on a barbell when a weight lifter is holding the barbell
over his head?

Answers

I don’t see any picture sorry I wish I can help tho

whats the result of rounding 52.8015 into five significant figures​

Answers

Answer:

52.802

Explanation:

"Significant figures" in Mathematics refer to the digits that give accuracy to the value of a measurement. There are specific rules when it comes to determining the significant figures. For example, all non-zero digits are considered significant and zeroes located in-between non-zero numbers are significant. In the number given above, the digit "0" is located between "8" and "1," therefore, it is significant. All the digits above are significant.

The problem is only asking for "five" significant figures. We can do this by counting from the left to the right. By this means, we know that the number will be rounded off to the nearest thousandths, which is "1." The number after 1 is 5, which means that 1 digit will be added to number 1, thus, making the digit into "2." The last digit (5) will then be removed.

Explanation:

five significant of 52.8015=52.801 ..

which wave carries the highest energy?​

Answers

Answer:

Gamma rays

Explanation:

The highest wave of energy is gamma ray.

A vector
of magnitude 5 units and another vector ū of magnitude 3 units point in directions
differing by 60°. Find out (a) the scalar product of the two vectors and (b) the vector product of the two vectors​

Answers

Answer:

7.5 units

13 units

Explanation:

[tex]|v|=5\ \text{units}[/tex]

[tex]|u|=3\ \text{units}[/tex]

[tex]\theta[/tex] = Angle between the vectors = [tex]60^{\circ}[/tex]

Scalar product is given by

[tex]u\cdot v=|u||v|\cos\theta\\ =3\cdot 5\cdot \cos60^{\circ}\\ =7.5\ \text{units}[/tex]

The scalar product of the vectors is 7.5 units.

Vector product is given by

[tex]u\times v=|u||v|\sin\theta\\ =3\times 5\sin60^{\circ}\\ =13\ \text{units}[/tex]

The vector product of the vectors is 13 units.

Which type of matter is likely to absorb the most sound waves? A. Metal door B. Loudspeaker C. Hot air O D. Foam wall​

Answers

Answer:

its either A or D

Explanation:

They use foam walls in like asylums but in the movies all the bad guys say "They can't hear you the metal is too thick" so its either one of those, hope it helped

Sound absorbing foams are typically softer and more lightweight than their sound blocking counterparts. This open and flexible cell structure acts as a natural soundwave absorber and prevents noises from reverberating off hard surfaces like walls, floors and ceilings.

What are sound waves ?

"A sound wave is the pattern of disturbance caused by the movement of energy traveling through a medium (such as air, water, or any other liquid or solid matter) as it propagates away from the source of the sound. The source is some object that causes a vibration, such as a ringing telephone, or a person's vocal chords."

What is sound ?

"Sound is a vibration that propagates as an acoustic wave, through a transmission medium such as a gas, liquid or solid. In human physiology and psychology, sound is the reception of such waves and their perception by the brain."

What is noise ?

Sound is defined as vibrations that travel through air or another medium that can be heard when they reach a person's or animal's ears. Noise is defined as unwanted sound. In engineering, noise has the additional connotation of signals varying over time without meaning, whereas sound connotes meaningful signals.

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