A steel ball is traveling through water with a speed of x meters per second, where x is positive. The drag force, F, in newtons, N, is: F = 0.5 + 0.004(x + 50)(x-2.5). At what speed in meters per second does the ball have a force of 0.5 N, on it?

Answer:

x = 2.5m/s.

Step-by-step explanation:

Given that F = 0.5 + 0.004(x + 50)(x – 2.5), where x is the speed in m/s and F is the force in N. To know the speed, x, with F = 0.5N, we have:

0.5 = 0.5 + 0.004(x + 50)(x – 2.5)

This gives

0.004(x + 50)(x – 2.5) = 0 (after adding –0.5 to both sides).

For the multiplication to be 0, (x + 50)(x – 2.5) = 0 because 0.004 is not equal to 0.

Hence

x = –50 or x = 2.5

Since it is said from the question that x is positive then x = 2.5m/s.

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HELPPPPPPPP PLZZZZZ 50PTS

A high school surveyed students to determine if new foreign language classes should be added to the course offerings for the next school year. The two-way frequency table below shows the interest of next year's underclassmen in the new courses. German Mandarin Neither Total Freshmen 30 80 230 340 Sophomores 15 65 200 280 Total 45 145 430 620 Approximately what percentage of the underclassmen have an interest in taking a Mandarin course next year? 44.83% 33.72% 55.17% 23.39%

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