A solar collector for a hot water system absorbs solar radiation at the rate of 660 W/m^2
. Its collecting area is 3.8m^2 . Cold water at 15degrees enters the collector. What volume of
water per minute at an output temperature of 60 degrees can this collector deliver?

Answer:

Heterotrophic requiring complex organic compounds of nitrogen and carbon (such as that obtained from plant or animal matter) for metabolic synthesis.

Answer -:

⟹ It is a mode of nutrition in which organism are unable to synthesize organic substance by themselves and obtain part of whole of organic substance from external environment. the organism that obtain their food by this method are called heterotphs.

On the basis of types of food and feeding habit's nutrition classified into following group -:

(1) Holozoic Nutrition -:

nutrition and animal consumes a plant or an animal us whole or a part of it in solid or liquid form most of free living a cellular protist and all animal show Holozoic Nutrition

(2) Herbivores -:

animal eating grass or other plant material are called Herbivores.

(3) Carnivorous

flesh eating animal are called carnivorous.

(4) Omnivorous

animal eating food or plant us well us animal origin are called omnivorous.

(5) Insectivorous

insect eating animal are calledinsectivorous .

(6) Frugivores

animal which mainly depend on fruit are called frugivores.

The magnitude of the total initial velocity of the rocket is determined as 9.82 m/s.

The magnitude of the total initial velocity of the rocket is calculated as follows;

V = D/T

where;

V = (54)/(5.5)

V = 9.82 m/s

Thus, the magnitude of the total initial velocity of the rocket is determined as 9.82 m/s.

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#SPJ2

Answer:

Explanation:

Echo is caused by sound energy reflecting off of "hard" surfaces. It could be as simple as a change in density of the material the sound is traveling through.

In 0.8 s, the sound has traveled 0.8(1500) = 1200 m.

That means the object that reflected the sound is 600 m below the boat. The sound took 0.4 s to reach the object and another 0.4 s to return the echo.

Answer:

Explanation:

s = s₀ + v₀t + ½at²

assuming that the acceleration is in the direction of initial velocity.

(it would not have to be so)

s = 0 + 10(8) + ½(3.5)(8²)

s = 192 m

Km values are standardized because half the Vmax (Vmax/2) is more informative than Vmax. This value (Km) can be used to calculate the affinity of the enzyme by a given substrate.

The Km (Michaelis constant) of the enzyme refers to the value in which the concentration of substrate is equal to half of its maximum velocity (Vmax/2).

This value (Km) is inversely proportional to the affinity of an enzyme by a given substrate.

An enzyme showing a high Km also exhibits a low affinity for its specific substrate, and thereby this enzyme requires a high concentration of the substrate to reach its maximum velocity (Vmax).

In consequence, the Km value is a more informative value than the maximum velocity (Vmax), which only indicates the concentration of an enzyme catalyzing a reaction under ideal conditions.

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Addition of a proton to germanium  will convert it to arsenic (element 33) having different properties.

The atomic number of an atom is the number of protons in the nucleus of the atom. The atomic number serves as the identity of an atom. If the atomic number is changed by adding or removing protons, the identity of that atom changes.

Hence, when a proton is added to germanium, the  atom would become arsenic (element 33) and have different properties.

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Answer: Its B and D

I had the same question on usatestprep

Explanation:

The initial kinetic energy [tex]KE_0[/tex] is

[tex]KE_0 = \frac{1}{2}mv_0^2 = \frac{1}{2}(400\:\text{kg})(10\:\text{m/s})^2[/tex]

[tex]\:\:\:\:\:\;\:= 2×10^4\:\text{J} = 20\:\text{kJ}[/tex]

The final kinetic energy [tex]KE[/tex] is

[tex]KE = \frac{1}{2}mv^2 = \frac{1}{2}(400\:\text{kg})(30\:\text{m/s})^2[/tex]

[tex]\:\:\:\:\:\:\:= 1.8×10^5\:\text{J} = 180\:\text{kJ}[/tex]

The work done W on the car is

[tex]W = \Delta{KE} = KE - KE_0[/tex]

[tex]\:\:\:\:\:\:\:= 180\:\text{kJ} - 20\:\text{kJ} = 1.6×10^5\:\text{J}[/tex]

The power expended P is

[tex]P = \dfrac{W}{t} = \dfrac{1.6×10^5\:\text{J}}{15\:\text{s}} = 10667\:\text{Watts}[/tex]

[tex]\:\:\:\:\:= 10.7\:\text{kW}[/tex]

Answer:

a thing or event that evokes a specific functional reaction in an organ or tissue.

or

a thing that rouses activity or energy in someone or something; a spur or incentive.

Answer:

Explanation:

v = √(25² + 8.5²) = 26.40549... = 26 m/s

θ = arctan(8.5/25) = 18.77803... = 19° S of E

Answer:

Explanation:

If we assume the rod and sphere are of uniform construction so that their individual centers of mass are at their geometric centers, and that the rod end is attached to the surface of the sphere.

Balance moments about the rod free end of the assembly with its parts

(M + m)Cx = M(L/2) + m(L + R)

Cx = (M(L/2) + m(L + R)) / (M + m)

Answer:

Explanation:

s = s₀ + v₀t + ½at²

if the throw point is origin and UP the positive direction and ignoring air resistance.

s = 0 + (-5)(7) + ½(-10)(7²)

s = 0 - 35 - 245

s = - 280 m

Answer:

0.80 kN

Explanation:

Hope you understood it

Answer:

Explanation:

Initial velocity 25 m/s

final velocity 0 m/s

The ratio of the two is undefined as dividing by zero is wonky.

Explanation:

Fgravity = G*(mass1*mass2)/D².

G is the gravitational constant, which has the same value throughout our universe.

D is the distance between the objects.

so, if you triple one of the masses, what does that do to our equation ?

Fgravitynew = G*(3*mass1*mass2)/D²

due to the commutative property of multiplication

Fgravitynew = 3* G*(mass1*mass2)/D² = 3* Fgravity

so, the right answer is 3×12 = 36 units.

Answer:

D = 25g/cm³

Explanation:

1ml = 1cm³

D = m/V

D = 500g/20cm³

D = 25g/cm³

Answer:

A. Determine the equation of constraints

Hi there!

We can begin by finding the period of the pendulum.

[tex]T = \text{ # of complete swings / seconds} = 12 / 8 = \boxed{\text{1.5 sec}}[/tex]

The frequency is simply the reciprocal of the period, so:

[tex]f = \frac{1}{T} = \frac{1}{1.5} = \frac{2}{3}Hz \text{ or } \boxed{0.67 Hz}[/tex]

Explanation:

a. (i) When the variable resistor is set at zero, the only resistance in the circuit is due to the lamp. So the current flowing through the circuit is

[tex]I = \dfrac{V}{R} = \dfrac{220\:\text{V}}{440\:Ω} = 0.5\:\text{A}[/tex]

(ii) The power output P of the lamp is given by

[tex]P = I^2R = (0.5\:\text{A})^2(440\:Ω) = 110\:\text{W}[/tex]

b. (i) The variable resistor is in a series connection to the lamp so when its value is set to its maximum value of 660 Ω, the total resistance of the circuit is simply the sum of the two resistances:

[tex]R_T = R_{vr} + R_L = 660\:Ω + 440\:Ω = 1100\:Ω[/tex]

Therefore, the current through the circuit is

[tex]I = \dfrac{V}{R_T} = \dfrac{220\:\text{V}}{1100\:Ω} = 0.20\:\text{A}[/tex]

(ii) Using the result in Part (ii), we can solve for the potential difference across the lamp as follows:

[tex]V_L = IR_L = (0.20\:\text{A})(440\:Ω) = 88\:\text{V}[/tex]

(iii) The power output of the lamp is

[tex]P = I^2R_L = (0.20\:\text{A})^2(440\:Ω) = 17.6\:\text{W}[/tex]

(iv) The rate at which electrical energy is supplied, i.e., the power output of the circuit is equal to the square of the current multiplied by the total resistance of the circuit:

[tex]P = I^2R_T = (0.20\:\text{A})^2(1100\:Ω) = 44\:\text{W}[/tex]

Answer:

Explanation:

s = s₀ + v₀t + ½at²

ASSUMING the acceleration is in the direction of initial motion.

s = 0 + 3.3(10) = ½(3.7)(10²)

s = 218 m

The equation of the progressive wave is y = 12 cos(40t - 4x)

The general wave equation is given by:

y = A sin(ωt - kx)

Where A is the amplitude, ω is the angular frequency = 2πf, f is the frequency, k is the wave number and y, x is the displacement.

Given the equation for a progressive wave is y=6 cos⁡(20t-4x). Hence:

The amplitude A = 6,

ω = 20 = 2πf

f = 20/2π = 3.183 Hz

Twice the amplitude = 2 * 6 = 12, twice the frequency = 2 * 3.183.

ω = 2π(3.183*2) = 40

Therefore the other progressive wave has an equation of:

y = 12 cos(40t - 4x)

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Explanation:

here the file has everything

Explanation:

In this chapter, we will study the important concepts of kinetic energy and the

closely related concept of work and power.

A- Kinetic Energy

Kinetic energy is a physical quantity, which is associated with the moving objects

and defined as:

K = ½ mv2

If the body is stationary (v=0), its kinetic energy is zero. The SI unit of kinetic

energy is kg.m2

/s2

or Joule (J), where 1 J=1 kg.m2

/s2

. Kinetic energy is a scalar

quantity.

B- Work

The work is defined as the ability to perform a force along a certain displacement.

There are different types of work as follows:

1- Work done by a constant force

The work done by the constant force F is given by the scalar product of the force F

and the displacement d.

WF = F.d = Fd cosθ

where θ is the angle between the force and displacement. The above equation means

that the work is the product of the displacement magnitude by component of the

force parallel to the displacement. Therefore, work is a scalar quantity (only

magnitude, no direction) and can be positive, negative, or zero. The SI unit of work

is (N.m) or joule (J) where 1 N.m = 1 J.

Special cases and remarks:

• If the angle between the force and displacement is zero (parallel), the work is

WF = F d (maximum work)

Hi there!

Since the collision is elastic, we must also satisfy the following condition:

Ei = Ef, or:

KEi = KEf

Begin by writing an expression for momentum. (p = mv) Remember that one ball's direction is negative; in this instance, we can let the second ball be moving LEFT.

mv1 + mv2 = mvf1 + mvf2

0.220(1.84) + 0.220(-.530) = 0.220(vf1 + vf2)

0.2882/0.220 = vf1 + vf2

1.31 = vf1 + vf2

Now, we can express this as a conservation of energy:

1/2mv1² + 1/2mv2² = 1/2mvf1² + 1/2mvf2²

Plug in values and simplify:

0.403315 = 1/2m(vf1² + vf2²)

Simplify further:

3.6665 = vf1² + vf2²

Use the equation derived from momentum above and solve for one variable:

vf2 = 1.31 - vf1

Plug in this expression for vf2:

3.6665 = vf1² + (1.31 - vf1)²

Expand:

3.6665 = vf1² + 1.7161 - 2.62vf1 + vf1²

Simplify:

1.9504 = -2.62vf1 + 2vf1²

Solve for vf1 using a graphing calculator:

vf1 = -0.53 m/s or 1.84 m/s; we must figure out which one is correct.

Since v1 is heading to the right initially with a velocity of 1.84 m/s, we know that the ball's velocity could not have stayed the same in both magnitude and direction, so the final velocity must be -0.53 m/s.

Now, we can solve for the velocity of the other ball (initial of 0.53 m/s):

vf2 = 1.31 - (-0.53) = 1.84 m/s.

Now, you could have also made the connection that when two balls of the SAME MASS experience an ELASTIC collision, the velocities are simply "exchanged" from one to another. I just used this more "extensive" method to prove this.

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Acceleration due to gravity on that planet is half than that of om earth ~

that is ~

And it's weight is equal to ~

now, As we know ~

here ,

let find the mass of stone ~

Mass of the stone is 100 kg ~

I hope it helped

The characteristics of the expression of the simple harmonic motion allows to find the results for the expression of the mass- block system are:

     A) The constant Ces: C = xinit

     B) The ocsntna S is: S = 0

     C) The equation of the system is: x = xinit cos wt

     D) If the reference system is at some extreme, the equation is:

              [tex]L - x_{init} = x_{init} \ cos \ wt[/tex]  

The simple harmonic movement is an oscillatory movement where the restoring force is proportional to the displacement, the general equation that describes this movement is indicated.

          x = C cos wt + S sin wt

Where x is the displacement C and S are constants. W the angular velocity and t the time.

A) The initial position of the body occurs when the time is zero, t = 0

We substitute.

           x = C cos 0 + S sin 0

           [tex]x_{init}[/tex] = C

B) The velocity of the particle is defined.

          [tex]v= \frac{dx}{dt} \\ v= C w \ sin \ wt - Sw \ cos \ wt[/tex]  

The initial velocity occurred for time zero t = 0

          v = - S w

It indicates that the initial velocity is zero, since the angular velocity must be different from zero, it implies that the constant is valid.

          S = 0

C) The equation for the block remains.

           x (t) = [tex]x_{init} \ cos \ wt[/tex]  

D) In ​​some cases it is measured with respect to another reference system, the most common are:

In these cases, the change that must be made is

          x =  [tex]L - x_{min}[/tex] t

we substitute

          [tex]L - x_{init} = x_{init} \ cos \ wt[/tex]  

          L = [tex]x_{init}[/tex]  (1 + cos wt)

In conclusion, using the characteristics of the expression of the simple harmonic motion we can find the results for the expression of the mass- block system are:

    A) The constant Ces: C = xinit

     B) The ocsntna S is: S = 0

     C) The equation of the system is: x = xinit cos wt

     D) If the reference system is at some extreme, the equation is:

              [tex]L - x_{init} = x_{init} \ cos \ wt[/tex]  

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Answer:

the one in which the fluid has the lowest density

Answer:

4600kg

Explanation:

Density=mass÷volume

920=m/5

m=920×5=4600kg