A shipping container is in the shape of a right rectangular prism with a length of 5 feet, a width of 12.5 feet, and a height of 14 feet. The container is completely filled with contents that weigh, on average, 0.78 pound per cubic foot. What is the weight of the contents in the container, to the nearest pound?

Answer:

0.00923077

Step-by-step explanation:

thats it

Answer:

Your answer is 0.000096 if your question was 0.96÷10 with a power of 4.

Answer:

infinite number of solutions

Answer:

What’s the answer

Step-by-step explanation:

Answer: 15000 millimeters

Step-by-step explanation:

Since David David made a batch of 5 liters of blue liquid everyday. The number of liters that'll be made for 3 days will be:

= 5 liters × 3

= 15 liters

We should note that 1000 millimeters = 1 liter. Therefore, 15 liters will be converted to millimeters which will be:

= 15 × 1000

= 15000 millimeters

Answer:i think D

Step-by-step explanation:

Answer: 5n = 35

Step-by-step explanation:

The product of a number n and the number 5 is 35. This statement can be formed into an equation as:

n × 5 = 35

5n = 35

The equation is 5n = 35

If we want to get the value of the number, it'll be:

5n = 35

n = 35/5

n = 7

The number is 7

Answer:

Hello.

The answer to this question is  

− √ 2 − √ 3 /2

And in Decimal Form: − 0.25881904

Step-by-step explanation:

Give brainliest :)

Step-by-step explanation:

x+5Y=13...... 1

4x +7y=0..... 2

from eqn 1

x =13-5y

substitute into eqn 2

[tex]4(13 - 5y) + 7y = 0[/tex]

52-20y +7y=0

52-13y=0

52=13y

y=52÷13

y=4

substitute Y into eqn 2

x +5y=13

x + 5(4)= 13

x+ 20=13

x=13-20

x=-7

Answer:

8 is the length

Step-by-step explanation:

The length of AD is 9 units from the given right triangle ABC.

A right angled triangle is a triangle with one of the angles as 90 degrees. A 90-degree angle is called a right angle, and hence the triangle with a right angle is called a right triangle.

Given right triangle ABC with altitude BD drawn to hypotenuse AC.

Given that, AB = 18 and AC = 36

Using Pythagoras theorem

AC²=AB²+BC²

⇒ 36²=18²+BC²

⇒ BC²=1296-324

⇒ BC²=972

⇒ BC=31.18 units

We know that, area of a triangle =1/2 × Base × Height

= 1/2 × 31.18 × 18

= 280.62 square units

Now, area of a triangle ABC with base AC and height BD

That is, Area = 1/2 ×36×BD

⇒ 18BD=280.62

⇒ BD=280.62/18

⇒ BD=15.6

Consider ΔBDA

AB²=AD²+BD² (Pythagoras theorem)

18²=x²+15.6²

⇒ x²=18²-15.6²

⇒ x=9 units

Therefore, the length of AD is 9 units from the given right triangle ABC.

To learn more about the right angle visit:

https://brainly.com/question/3770177.

#SPJ2

Answer:

B. -2_x_4÷3 this answer are not sure

Answer:

D

Step-by-step explanation:

-5 < 6x +3

-8 < 6x

-(4/3) < x

I use < to represent 'no no smaller than'

Answer:

[tex]b_1 \approx 7.2[/tex]

[tex]b_2 \approx 14.4[/tex]

Step-by-step explanation:

Given

[tex]Area = 65cm^2[/tex] --- Area of the triangle

[tex]b_2 = 2b_1[/tex] --- the bases of the trapezoid

The missing parameters is:

[tex]h=6 cm[/tex] --- Trapezoid height

Required

Determine b1 and b2

Since the areas of the trapezoid and the triangle are the same, then:

[tex]Area = \frac{1}{2}(b_1 + b_2) *h[/tex]

So, we have:

[tex]65 = \frac{1}{2}(b_1 +b_2) * 6[/tex]

Substitute[tex]b_2 = 2b_1[/tex]

[tex]65 = \frac{1}{2}(b_1 +2b_1) * 6[/tex]

[tex]65 = \frac{1}{2}(3b_1) * 6[/tex]

[tex]65 = 3b_1 * 3[/tex]

[tex]65 = 9b_1[/tex]

Solve for [tex]b_1[/tex]

[tex]b_1 = \frac{65}{9}[/tex]

[tex]b_1 \approx 7.2[/tex]

Substitute [tex]b_1 \approx 7.2[/tex] in [tex]b_2 = 2b_1[/tex]

[tex]b_2 \approx 2 * 7.2[/tex]

[tex]b_2 \approx 14.4[/tex]

Answer:

12=4 3          4=2 2

Step-by-step explanation:

9514 1404 393

Answer:

  boat speed: (7t -95)/(6t² -110t +500)

  stream speed: (37t -345)/(6t² -110t +500)

Step-by-step explanation:

The relation between time, speed, and distance is ...

  time = distance/speed

The boat speed (b) is added to the stream speed (s) going downstream. The stream speed is subtracted going upstream. The given relations tell us ...

  25/(b-s) +44/(b+s) = t

  15/(b-s) +22/(b+s) = 5

This gives us 2 equations in 3 unknowns, so we can only provide a solution in terms of one of the unknowns. Since we are asked for the speeds, they will be provided in terms of t.

Subtracting the first equation from 2 times the second gives ...

  2(15/(b-s) +22/(b+s)) -(25/(b-s) +44/(b+s)) = 2(5) -(t)

  5/(b-s) = 10 -t

  5/(10 -t) = b -s

Substituting for b-s in the second equation gives ...

  15/(5/(10-t)) +22/(b+s) = 5

  30 -3t +22/(b+s) = 5

  22/(b+s) = 3t -25

  22/(3t -25) = b+s

Adding the equations for the sum and difference of speeds, we get ...

  (b-s) +(b+s) = 5/(10-t) +22/(3t -25)

  2b = (5(3t -25) +22(10 -t))/((10-t)(3t-25)) = (95 -7t)/((10-t)(3t-25))

  b = (7t -95)/(6t² -110t +500)

Subtracting the equations for sum and difference of speeds, we get ...

  (b+s) -(b-s) = 22/(3t -25) -5/(10 -t)

  2s = (22(10-t) -5(3t -25))/((10-t)(3t-25))

 s = (37t -345)/(6t² -110t +500)

__

The speed of the boat in still water is (7t -95)/(6t² -110t +500) km/h.

The speed of the stream is (37t -345)/(6t² -110t +500) km/h.

__

Note that these solutions only make sense for values of t between 25/3 and 345/37, approximately 8.33 < t < 9.32. For t=9 hours, the boat speed is 8 km/h and the stream speed is 3 km/h.

Answer:

it can have any about 3 and up as long as it is a 2d shape and it has to have straight lines

Answer:

They all vary. All a polygon needs is straight sides, two dimensions, and equal length sides.

Step-by-step explanation:

Hope this helps!

Answer:

1.9%.

Step-by-step explanation:

Answer:

Step-by-step explanation:

It depends on what level you are. Logs are most easily developed by using a series for the natural logarithms (instead of base 10, you use base e). Even that is a difficult process using a series that you won't be introduced to until your second calculus course..

For now, I'd be content to use a calculator. The series does not converge terribly quickly.

Answer:

49/64 yd²

Step-by-step explanation:

since where finding a square we do

A = bxh

A = 7/8×7/8

A = 49/64

Answer:

The answer is the second one!

Have a wonderful day/night! <3

-41.2 minus (-37.4) is -3.8.

If this is incorrect, please, don't refrain to tell me. Thank you.

Answer: -3.8

Hope this helps!

Step-by-step explanation:

find the area as if it was a rectangle so do 14x12 then subtract the area of half a circle with a diamater of 12

Answer:

24.75 percents

Step-by-step explanation:

Answer: I think it’s False I’m not sure

Answer:

it's false because isosceles is convex quadrilateral with line of symmetry

Answer:

By 2020, there will be 1,147 species of birds left

Step-by-step explanation:

The general model for an exponential decrease is;

y = I(1 - r)^t

where in this case;

y is the number of bird species at a particular decade from the initial

I is the number of birds initially at 1990

r is the decrease percentage which is 1.5% per decade ; 1.5% = 1.5/100 = 0.015

t in this case will be the number of decades after the initial

Mathematically, a decade is 10 years

The difference between 2020 and 1990 is 30

The number of decades in 30 years is 30/10 = 3

so t will be 3 here

Substituting these values into the equation, we have

y = 1200(1-0.015)^3

y = 1200(0.985)^3 = 1,146.8

To the nearest whole number, this is 1,147

Answer:

A.  when an action causes something to come into effect

Step-by-step explanation:

Mark as brainliest please. Hope the answer helps :)

Answer:

1.) Hypotenuse.

The hypotenuse is the longer side.

2.)Leg

Answer:

1.) Hypotenuse

2.) Leg

Step-by-step explanation:

The legs or bases of a triangle are the sides connected to the right angle.

The hypotenuse is the side across from the right angle and is always the longest side.

Answer:

6chocolates

Step-by-step explanation:

Given

The total number of chocolate = 15chocolates

If it is divide into ratio 2:3

total ratio = 2+3

Total ratio = 5

Number of chocolate raju receives = 2/5 * 15

Number of chocolate raju receives = 2 * 3

Number of chocolate raju receives = 6chocolates

The number of chocolates that Raju received are; 6 chocolates

We are told that;

Number of chocolates distributed = 15

Ratio of sharing between Raju and sanju = 2:3

Thus, fraction to be received by both of them are;

Thus;

Amount of chocolates for Rajus = 2/5 × 15 = 6

In conclusion, Raju received 6 chocolates.

Read more about proportion at; https://brainly.com/question/1781657

Answer:

D.

Step-by-step explanation:

Hope this helps

~R3V0

[tex]\huge\red{\boxed{\tt{\colorbox{pink}{ANSWER:}}}}[/tex]

[tex] - 4(2w + 1)[/tex]

[tex]\huge\red{\boxed{\tt{\colorbox{pink}{Solution:}}}}[/tex]

[tex] - 8w - 4[/tex]

Bind the expression with the common factor -4

[tex] - 8w - 4[/tex]

Answer: −4(2w+1)

Step-by-step explanation: Hope this help :D