3.89 km/s is the rocket's final engine burn speed.
Calculation-The rocket equation can be used to determine the rocket's thrust:
Thrust is calculated as follows: (final mass flow rate minus initial mass flow rate) x (exhaust gas mass flow rate x exhaust gas velocity)
The initial mass flow rate is 16,000 kg/s (0.8 x 20,000 kg).
The final mass flow rate is equal to 20,000 kg - 200 kg/s x t, where t is the engine's burn period.
We obtain the following by substituting the values in the question:
Thrust equals 360,000 N when calculated as (200 kg/s x 1.8 km/s + (20,000 kg - 200 kg/s x t - 16,000 kg) x 1.8 km/s)
(b) The time it takes to exhaust the fuel can be calculated by equating the initial and final masses:20,000 kg - 200 kg/s x t = 0.2 x 20,000 kg
t = 20 seconds.
(c) The rocket equation can be used to determine the rocket's speed at the conclusion of its engine burn:
V is equal to (exhaust velocity) x ln[(initial mass)/(final mass)].
The rocket's final mass, which is what remains after all of its fuel has been consumed, is as follows:
final mass = (mass of rocket) - (mass of fuel)
final mass = 20,000 kg - 16,000 kg
final mass = 4,000 kg
Δv = 1.80 km/s x ln[(20,000 kg) / (4,000 kg)]
Δv = 1.80 km/s x ln(5)
Δv = 3.89 km/s
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I need this tomorrow 50 points.
Answer: 849.15NM/S
Explanation: the power associated with forse F IS GIVEN BYP= F'.V' ,
WHERE V' IS THE VELOCITY OF THE PROJECT OF THE OBJECT ON WHICH THE FORCE ACTS . THUS,
P= F'.V. = COSФ
P = (135N) (7.4M/S)COS31° = 849.15NM/S
A scuba diver is in a freshwater lake with water of density 1000 kg/m3. To have neutral buoyancy, she has to wear a weight belt that has a mass of 8 kg.
a. If she and the rest of her gear had a total mass of 65 kg before putting on the weight belt, what is her total volume, in liters, after putting it on? 1 m3 = 1000 liters. (1 point)
b. If she takes a very deep breath, her body's volume increases by 3 L. What is the change in the buoyant force on her body? (1 point)
c. If her next dive is going to be in a saltwater lake (ρ = 1025 kg/m3), what mass of weight belt should she wear to have neutral buoyancy? (1 point)
When the gas in a swim freshwater lake allows its density to match that of the water around it, the fish is said to be in water level (Pflugrath et al., 2012). The maximal neutral buoyant depth (MNBD) is a limit below which fish will have become lot of negative if they swim. Your overall dive depth should be roughly being one your neutral buoyancy depth, but not less than ten metres (32ft).
Hence, as a solid item is embedded in a liquid, its volume increases, more fluid weight is displaced, increasing the hydrostatic pressure. The buoyant force is at its greatest when a solid item is fully submerged in a fluid.
The formula B = V g, where and V are indeed the entity's volume and capacity, correspondingly, and g is the velocity brought on by gravity, is used to calculate the buoyancy required for just an object. 1000 kg/m3 is the density of water. Thus, the required force is 1000 kg/m3 times 1 L times 9.81 m/s2 equals 9.81 N.
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Question 1 (1 point)
Nathaniel needs fewer calories than his dad even though they both exercise about
the same amount. What is the MOST likely reason for this difference?
activity level
age
gender
hunger
The most likely reason for Nathaniel needing fewer calories than his dad, even though they exercise about the same amount, is his age.
What is the reason for this difference?Age plays a significant role in determining person's daily calorie requirements. As people age, their body composition and metabolism change, and they tend to lose muscle mass and gain fat mass, which leads to decrease in their basal metabolic rate (BMR).
BMR is the amount of energy the body needs to carry out its essential functions while at rest. Therefore, even if Nathaniel and his dad have same activity level, Nathaniel's lower BMR due to his age would result in him needing fewer calories than his dad to maintain his weight. Other factors such as gender, activity level, and hunger may also contribute to differences in calorie requirements, but age is the most significant factor in this case.
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Use nodal analysis to find V1 and I1 in the circuit shown in Fig. 5.
From the nodal analysis, the value of V1 = -3V and the value of I1 = 2A. Voltage, current, and resistance-related versions of Ohm's law exist in three different forms.
What does the term "super-node" mean?A super-node is a concept that can be utilized to solve a circuit in circuit theory. This is accomplished by treating a voltage source on a wire as a point source voltage in comparison to other point voltages present at different nodes in the circuit, relative to a ground node given a charge of zero or negative.
What does the term "node" mean?In a network of data communication, a node is a point of intersection or connection. These devices are all referred to as nodes in a networked environment where every device is reachable. Depending on the kind of network it relates to, each node has a different definition.
Applying nodal analysis,
[tex]3+\frac{V1}{3} +\frac{V1}{3} +\frac{V1+2}{1} =0[/tex]
[tex]3+\frac{V1}{3} +\frac{V1}{3} +V1+2=0[/tex]
[tex]\frac{V1+V1+3V1}{3} =-5[/tex]
[tex]\frac{5V1}{3} =-5[/tex]
[tex]V1=-3V[/tex]
Applying again nodal analysis,
[tex]I1+\frac{V1}{3} +\frac{V1+2}{1} =0[/tex]
[tex]I1+\frac{-3}{3} +\frac{-3+2}{1} =0[/tex]
[tex]I1=2A[/tex]
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Which direction will the barrel travel when the farmer applies a
downward unbalanced force on the pulley?
O Up
O Down
O Left
O No movement
A turntable must spin at 33.3 rev/min (3.49 rad/s) to play an old fashion vinyl record . How much torque must the motor deliver if the turntable is to reach its angular speed in 2.20 revolutions starting from rest ? The turntable is an uniform disk of diameter 30.5 cm and mass 0.240kg
The motor must deliver a torque of 0.00180 N·m to accelerate the turntable from rest to 3.49 rad/s in 2.20 revolutions.
Torque calculation.
We can use the rotational kinetic energy equation to find the torque required to accelerate the turntable from rest to a final angular velocity of 3.49 rad/s:
KE = (1/2) I ω^2
where KE is the kinetic energy, I is the moment of inertia of the turntable, and ω is the angular velocity.
The moment of inertia of a uniform disk is I = (1/2) m r^2, where m is the mass of the disk and r is its radius. Plugging in the given values, we get:
I = (1/2) (0.240 kg) (0.305 m/2)^2
I = 0.00216 kg·m^2
We know that the turntable must complete 2.20 revolutions to reach its final angular velocity, which is equivalent to 2π(2.20) = 13.8 radians. We can use the rotational kinematic equation to find the initial angular velocity of the turntable:
ω_f^2 = ω_i^2 + 2αθ
where ω_i is the initial angular velocity, ω_f is the final angular velocity, α is the angular acceleration, and θ is the angular displacement. We can rearrange this equation to solve for ω_i:
ω_i = √(ω_f^2 - 2αθ)
Plugging in the given values, we get:
ω_i = √[(3.49 rad/s)^2 - 2((3.49 rad/s) / (2.20 rev)) (2π(2.20 rev))]
ω_i = 0.565 rad/s
The torque required to accelerate the turntable from rest to 3.49 rad/s is given by:
τ = I α
where τ is the torque and α is the angular acceleration. We can use the rotational kinematic equation to find the angular acceleration:
ω_f = ω_i + αt
where t is the time it takes to reach the final angular velocity. Solving for t, we get:
t = (ω_f - ω_i) / α
Plugging in the given values, we get:
t = (3.49 rad/s - 0.565 rad/s) / ((3.49 rad/s) / (2.20 rev))
t = 3.46 s
Now we can use the equation for angular acceleration to find α:
α = (ω_f - ω_i) / t
Plugging in the given values, we get:
α = (3.49 rad/s - 0.565 rad/s) / 3.46 s
α = 0.832 rad/s^2
Finally, we can find the torque required to accelerate the turntable from rest to 3.49 rad/s:
τ = I α
τ = (0.00216 kg·m^2) (0.832 rad/s^2)
τ = 0.00180 N·m
Therefore, the motor must deliver a torque of 0.00180 N·m to accelerate the turntable from rest to 3.49 rad/s in 2.20 revolutions using rotational kinetic energy.
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Answer:
A turntable must spin at 33.3 rev/min (3.49 rad/s) to play an old fashion vinyl record . How much torque must the motor deliver if the turntable is to reach its angular speed in 2.20 revolutions starting from rest ? The turntable is an uniform disk of diameter 30.5 cm and mass 0.240kg
Explanation:
The moment of inertia of the disk can be calculated as:
I = (1/2) * m * r^2
where m is the mass of the disk and r is the radius (half of the diameter).
r = 0.305 / 2 = 0.1525 m
I = (1/2) * 0.240 kg * (0.1525 m)^2 = 0.00232 kg·m^2
We know the final angular speed of the disk (ωf) and the number of revolutions it takes to reach that speed (θ), and we can calculate the initial angular speed (ωi) as:
ωf^2 = ωi^2 + 2αθ
where α is the angular acceleration, which is related to the torque (τ) applied to the disk:
α = τ / I
Combining these equations, we get:
ωf^2 = ωi^2 + 2(τ / I)θ
τ = I(ωf^2 - ωi^2) / 2θ
We are given ωf = 3.49 rad/s and θ = 2.20 rev = 13.82 rad (since 1 rev = 2π rad). To find ωi, we can use the formula for the angular speed of a rotating object:
ω = v / r
where v is the linear speed of a point on the disk. For a disk rotating about its center, the linear speed varies with the distance from the center, but the average linear speed is half the linear speed at the rim:
v = (1/2)ωiR
where R is the radius of the disk (equal to half the diameter).
R = 0.305 / 2 = 0.1525 m
v = (1/2)ωi(0.1525 m)
ωi = 2v / R = ωfθ / (2π) = (3.49 rad/s)(13.82 rad) / (2π) = 7.25 rad/s
Now we can substitute the values into the formula for torque:
τ = (0.00232 kg·m^2)(3.49^2 - 7.25^2) / (2 * 13.82 rad) = -0.108 N·m
The negative sign indicates that the torque must be applied in the opposite direction to the initial motion of the disk, which makes sense because the disk is starting from rest and needs to accelerate in the positive direction.
How does the size of each push compare with the force of friction on the car? Explain your answer in terms of the net force on the car.
Answer:
Explanation:
The size of each push determines the magnitude of the force applied on the car. The force of friction on the car is the resistance force that opposes the motion of the car and it depends on the nature of the surface in contact and the weight of the car. The force of friction is equal and opposite to the force applied on the car, as per Newton's third law of motion.
If the magnitude of the net force on the car is greater than the force of friction, the car will accelerate in the direction of the net force. If the magnitude of the net force is equal to the force of friction, the car will move at a constant velocity. If the magnitude of the net force is less than the force of friction, the car will decelerate and eventually stop.
Therefore, the size of each push needs to be greater than the force of friction on the car to accelerate it. If the size of each push is equal to the force of friction, the car will not accelerate, and if the size of each push is less than the force of friction, the car will decelerate.
How does understanding what occurs at the various tectonic plate boundaries support our understanding of the past and current movement of rocks at earth's surface?
Answer:
Understanding what occurs at the various tectonic plate boundaries supports our understanding of the past and current movement of rocks at Earth's surface because the movement of the plates is responsible for shaping the planet's surface features, such as mountain ranges, ocean basins, and volcanoes. Different types of plate boundaries produce different geological features and events. For example, convergent plate boundaries, where two plates move towards each other, result in subduction zones, where one plate is forced beneath another, and can cause volcanic activity and earthquakes. Divergent plate boundaries, where two plates move away from each other, can cause seafloor spreading, mid-ocean ridges, and rift valleys. Transform plate boundaries, where two plates move past each other, can cause earthquakes. By studying the processes and features associated with these plate boundaries, scientists can gain insight into how the Earth's surface has changed over time and how it continues to change today.
Explanation:
A cyclist enters a curve of 30 m radius at a speed of 12m/a. As the brakes are applied, speed is decreased at a constant rate of 0.5 m/s^2. What are the magnitude of the cyclists radial and tangential accelerations when his speed is 10 m/s?
Therefore, the magnitudes of the cyclist's radial and tangential accelerations when his speed is 10 m/s are [tex]48.1 m/s^2 and -0.5 m/s^2[/tex]
What is the initial radial acceleration of the cyclist entering a curve of 30 m radius at a speed of 12 m/s?
where v is the speed of the cyclist and r is the radius of curvature. At the beginning of the curve, v = 12 m/s and r = 30 m, so the initial radial acceleration is:
ar = [tex]12^2 / 30 = 4.8 m/s^2[/tex]
The tangential acceleratiοn οf the cyclist is given by:
at = -a
where a is the deceleratiοn due tο braking. In this case, [tex]a = 0.5 m/s^2[/tex], sο the tangential acceleratiοn is:
[tex]at = -0.5 m/s^2[/tex]
As the cyclist slοws dοwn, the speed at any time t is given by:
v = v0 - at * t
where v0 is the initial speed. We want tο find the radial and tangential acceleratiοns when the speed is 10 m/s, sο we need tο sοlve fοr the time t when v = 10 m/s:
10 = 12 - 0.5 * t
t = (12 - 10) / 0.5 = 4 s
Nοw we can use the time t tο calculate the radius οf curvature at the new speed:
[tex]r = v^2 / ar = 10^2 / 4.8 = 20.8 m[/tex]
The radial acceleratiοn at this speed is:
[tex]ar = v^2 / r = 10^2 / 20.8 = 48.1 m/s^2[/tex]
Therefοre, the magnitudes οf the cyclist's radial and tangential acceleratiοns when his speed is 10 m/s are 48.1 m/s^2 and -0.5 m/s^2, respectively.
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NASA is currently working on sending humans to Mars by the 2030s. When astronauts arrive on Mars, NASA intends to already have their food supply there. The food will be sent by an unmanned spacecraft. It will then be stored, unrefrigerated, for five to seven years. List at least two likely constraints and two likely criteria for this engineering design problem.
Constraints:
Limited space on the unmanned spacecraft for carrying food supplies.
The food must be durable enough to withstand the harsh conditions of space travel and long-term storage on Mars.
Criteria:
Nutritional value: The food must provide adequate nutrition to support the physical and mental health of astronauts during their mission on Mars.
Taste and variety: The food should be appetizing and varied to help maintain astronauts' morale and well-being during their extended stay on Mars.
What is the benefit of unmanned spacecraft?Cost-effectiveness: Unmanned spacecraft are generally less expensive to build, launch, and operate than manned spacecraft. This is because they do not require life support systems, crew accommodations, or other specialized equipment needed to sustain human life in space.
Safety: Sending unmanned spacecraft eliminates the risks associated with human spaceflight, such as exposure to radiation, accidents, and medical emergencies.
Scientific research: Unmanned spacecraft can be designed to carry a variety of scientific instruments and sensors to collect data and perform experiments in space, without the limitations of human endurance and safety.
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A waveform with a wavelength of 2.5 meters is graphed. How far apart will each node be? __m
Answer:
If the wavelength is 2.5 meters, each node will be half a wavelength apart from each other. Therefore, each node will be 1.25 meters apart.
Explanation:
The distance between nodes of a standing wave is equal to half the wavelength of the wave. This is because nodes are points along the wave where there is zero amplitude or displacement, and they occur at fixed intervals that are determined by the wavelength of the wave. Therefore, the distance between nodes is directly proportional to the wavelength of the wave.
PLEASEEEE HELP MEEEE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!(I will give a brainlist)
1. Tape one magnet to a smooth, flat surface. Place the other magnet on that surface 10 cm away, oriented so that its north pole is facing the south pole of the other magnet. Slowly push the free magnet toward the magnet that is taped down. What do you observe? (1 point)
2. Gently push the free magnet toward the taped magnet again. How far apart are they when the free magnet first starts to be pulled? Use the ruler to measure the distance between the magnets. (1 point)
3. Repeat Steps 1 and 2, but this time, position the magnets so that their north poles are facing each other. At what distance do the magnets begin to repel each other? (2 points)
4. Place the free magnet in each of the positions shown in the table below. For each position, describe what happens after you let go of the magnet. Draw a diagram that shows the final positions of both magnets. Make sure to label the north pole (N) and south pole (S) of each magnet. (12 points)
5. Cut four pieces of tape that are 15 cm long. Fold over one end of each piece of tape to make a tab that is about 2 cm long.
6. Stick one piece of tape to the top of a smooth, flat table. Using a marker, label the tab "B1." Rub the tape with the side of the marker to smooth out any air bubbles. Stick a second piece of tape on top of the first and smooth out the air bubbles again. Label the tab of this piece "T1."
7. Repeat Steps 5 and 6 with the remaining two pieces of tape, but label the bottom tab "B2" and the top tab "T2."
8. Use the tab to peel T1 off of B1. Stick it vertically to the edge of the table so that the tab is at the top and the tape hangs down below the table. Then peel B1 off the table. Hang it from the table edge in the same way. The two pieces of tape must be at least 10 cm away from each other and from the legs of the table.
9. Peel off T2. Hold it by the tab with the sticky side facing you.
10. With your other hand, hold a ruler perpendicular to the table edge, with the zero mark against the table next to the tape labeled T1. Hold the tab of T2 at the other end of the ruler. The diagram shows how to arrange the tape and the ruler. Slowly move T2 along the ruler toward T1. Watch for a change at the bottom end of each piece of tape. Measure the distance between the top ends of the pieces of tape when you first notice the change. What happened? Continue moving T2 closer to T1. What happened? Record the distance and your observations in the Electric Fields Data Table provided below Step 12. (4 points)
11. Repeat Step 10, this time moving T2 toward the hanging piece of tape labeled B1. (4 points)
12. If any of the pieces of tape are stuck together, carefully pull them apart. Discard the piece of tape labeled T2. Then repeat Steps 9 – 11 using the piece labeled B2 that is still stuck to the tabletop. (8 points)
1. What can you conclude about magnetic force based on your results in Steps 1 – 3? Use your data to support your conclusions. (4 points)
2. A magnetic field is the area around a magnet where its force can be felt. Magnetic fields are invisible. How did Part 1 of the Procedure and Data section provide evidence that magnetic fields exist? (4 points)
3. How could you change the design of the experiment to determine the size of the magnetic field around the magnet that was taped down? (2 points)
4. In Part 2 of the Procedure and Data section, how did the pieces of tape affect each other? Why did they attract, repel, or have no effect on each other? (4 points)
5. Like magnetic fields, electric fields are invisible. How did the experiment allow you to gather evidence that electric fields exist? (4 points)
Answer:
Explanation:
When the free magnet is pushed toward the magnet that is taped down, it will be attracted to it and will move towards it.
The distance between the magnets when the free magnet first starts to be pulled will depend on the strength of the magnets and the orientation of their poles. Use the ruler to measure the distance between the magnets when the free magnet starts to be pulled.
When the magnets are positioned so that their north poles are facing each other, they will begin to repel each other when they are brought close enough. Measure the distance at which the magnets begin to repel each other using the ruler.
The table below shows the positions of the free magnet and the magnet that is taped down, as well as a description of what happens when the free magnet is released.
Position Description Diagram
Position 1 The free magnet is placed directly above the magnet that is taped down. When released, the free magnet will stick to the taped down magnet with opposite poles attracting. N-S
Position 2 The free magnet is placed beside the taped down magnet with opposite poles facing each other. When released, the free magnet will move towards the taped down magnet and stick to it. N-S
Position 3 The free magnet is placed beside the taped down magnet with like poles facing each other. When released, the free magnet will move away from the taped down magnet due to repulsion. N-N or S-S
Position 4 The free magnet is placed directly beside the taped down magnet with like poles facing each other. When released, the free magnet will move away from the taped down magnet due to repulsion. N-N or S-S
5-12. Follow the steps to prepare and conduct the experiment using the pieces of tape.
a. Based on the observations in Steps 1-3, it can be concluded that magnetic force is present between two magnets with opposite poles attracting and like poles repelling each other. The strength of the force depends on the distance between the magnets and the orientation of their poles.
b. Part 1 of the Procedure and Data section provided evidence that magnetic fields exist because the magnets were able to exert a force on each other without direct contact. This suggests that there is an invisible force field surrounding the magnet that can interact with other magnetic objects.
c. To determine the size of the magnetic field around the magnet that is taped down, the experiment could be modified by placing the free magnet at different distances from the taped down magnet and measuring the strength of the force between them. This would allow for a better understanding of how the magnetic field changes with distance from the magnet.
d. In Part 2 of the Procedure and Data section, the pieces of tape affected each other due to the presence of electric fields. When the second piece of tape was brought close to the first, it caused a change in the electric field, which in turn caused a change in the behavior of the first piece of tape. Depending on the orientation of the electric fields, the pieces of tape could attract, repel, or have no effect on each other.
e. The experiment allowed evidence to be gathered that electric fields exist by observing the behavior of the pieces of tape when they were brought close to each other. The presence of a change in the behavior of the tape when the electric fields were affected suggests that there is an invisible force field surrounding the tape that can interact with other electrically charged objects.
The experiment demonstrates the principles of magnetism and electrostatics. By moving magnets or charged objects closer or further apart, the extent of the respective fields can be measured.
Explanation:This experiment demonstrates the invisible forces of magnetism and electrostatics. In steps 1 to 3, the magnets attract each other when their opposite poles (north and south) face each other, and they repel when similar poles (north and north, or south and south) face each other. This distance at which attraction or repulsion starts represents the extent of the magnetic field. In steps 4 to 12, the experiment uses tape to illustrate electrostatic forces. When tape is peeled from a surface, it becomes statically charged. Two pieces of tape that have the same charge will repel each other while different charges attract. The distance at which this occurs represents the extent of the electric field. To measure the size of a magnetic field, you could use a device called a magnetometer or you could move a magnet towards a stationary magnet and measure the distance at which the moving magnet begins to move. These procedures provide evidence of the existence of invisible magnetic fields and electric fields.
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The space station that you are controlling has a radius of 684 m.
You need to create a normal force for a 69.8 kg occupant of the ship that will match the normal force they would experience on a planet with a gravitational field strength of 6.4 N/kg.
You must determine the new rate of rotation for the ship (in rotations per hour) that will create this sensation for the occupants.
The new rate of rotation for the ship would be: 814 rotations/hour.
What is a space station?A space station is described as a spacecraft capable of supporting a human crew in orbit for an extended period of time.
The normal force experienced by an object is:
N = mg,
N = (69.8 kg)(6.4 N/kg) = 446.72 N.
The normal force experienced by an occupant :
N = mω^2r,
We then solve for ω,
ω^2 = N/mr
ω = √(N/mr)
ω = √((446.72 N)/(69.8 kg)(684 m))
ω = 0.127 radians/second
We then convert this to rotations per hour:
ω/(2π) rotations/second x 3600 seconds/hour = 814 rotations/hour
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17. Assertion (A): The internal resistance of a cell is constant. Reason (R): Ionic concentration of the electrolyte remains same during use of a cell.
Assertion (A): The internal resistance of a cell is constant. Reason (R): Ionic concentration of the electrolyte remains same during use of a cell.
Both Assertion (A) and Reason (R) are incorrect.
What is internal resistance?Internal Resistance refers to the opposition in the flow of current which is offered by the cell itself.
The internal resistance of a cell is not constant and can vary depending on many factors such as the age of the cell, the temperature, and the amount of current being drawn from the cell.
The internal resistance tends to increase, as the cell ages which can lead to a decrease in its performance.
In the same manner , the ionic concentration of the electrolyte in a cell can change during use due to the migration of ions between the electrodes and the electrolyte.
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Three charged particles are placed at each of three corners of an equilateral triangle whose sides are of length 3.5 cm
. Two of the particles have a negative charge: q1
= -8.3 nC
and q2
= -16.6 nC
. The remaining particle has a positive charge, q3
= 8.0 nC
. What is the net electric force acting on particle 3 due to particle 1 and particle 2?
Find the net force ΣF⃗ 3
acting on particle 3 due to the presence of the other two particles. Report you answer as a magnitude ΣF3
and a direction θ
measured from the positive x axis.
Therefore, the net electric force acting on particle 3 due to particle 1 and particle 2 is -1.38 x 10⁻⁵ N (repulsive).
What is charge?Charge is a fundamental property of matter that describes how strongly an object interacts with electromagnetic fields, such as electric and magnetic fields. There are two types of charge: positive and negative. Like charges repel each other, while opposite charges attract each other. The SI unit of charge is the Coulomb (C). Charge is conserved, meaning that the total amount of charge in a closed system remains constant over time. Charge can be transferred between objects through various mechanisms, such as friction, conduction, and induction. The movement of charged particles, such as electrons or ions, is the basis for electric current and many other electrical phenomena. The study of electric charge and its effects is known as electrostatics.
Here,
To find the net electric force acting on particle 3 due to particle 1 and particle 2, we can use Coulomb's law, which states that the force between two charged particles is proportional to the product of their charges and inversely proportional to the square of the distance between them:
F = k * (q1 * q3 / r13²) + k * (q2 * q3 / r23²)
where F is the net electric force on particle 3, k is Coulomb's constant (9.0 x 10⁹ N m²/C²), q1, q2, and q3 are the charges of particles 1, 2, and 3, respectively, r13 and r23 are the distances between particles 1 and 3, and particles 2 and 3, respectively.
To find the distances between the particles, we can use the fact that the triangle is equilateral and has sides of length 3.5 cm. By using trigonometry, we can find that the distances are:
r13 = r23 = 3.5 cm
Substituting the values into the equation, we get:
F = (9.0 x 10⁹ N m²/C²) * [(-8.3 nC) * (8.0 nC) / (0.035 m)² + (-16.6 nC) * (8.0 nC) / (0.035 m)²]
F = -1.38 x 10⁻⁵ N (repulsive)
The direction of this force can be found by considering the angles between the sides of the equilateral triangle and using vector addition. The direction is 120 degrees counterclockwise from the positive x-axis.
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A 2.0 kg object is moving to the right with a speed of 1.0 m/s when it experiences the force shown in the figure. (Figure 1)
What are the object’s speed and direction after the force ends? Express your answer to two significant figures and include the appropriate units. Enter positive value if the speed is directed to the right and negative value if the speed is directed to the left.
The object's speed and direction after the force ends is 0 m/s to the right.
How do we calculate?Applying the equation:
Δv = (F/ m) x Δt
where Δv = the change in velocity,
F_ = is the force,
m i= the mass, and
Δt = the time interval over which the force is applied.
Δv = (2 N / 2 kg) x 0.5 s = 1 m/s
The force is applied in the opposite direction to the initial velocity, the final velocity will be:
v_final = v_initial - Δv = 1 m/s - 1 m/s = 0 m/s
We then can conclude that the object's speed and direction after the force ends is 0 m/s to the right.
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The brakes on a train do 350,000 J of work to stop the caboose when it enters the platform. If 70,000 N of force is applied to stop the vehicle, then how far does the caboose travel after the brakes are applied?
A.14 m
B.0.2
C.5 m
D.7 m
According to the question the caboose travels 7 m after the brakes are applied.
What is caboose?Caboose is a term used to describe the last car in a freight train. It is typically designed to house a crew of railroad personnel, such as a conductor, a flagman, and a brakeman. The purpose of the caboose is to provide a safe place for the crew to observe the train and to signal any errors or problems to the engineer. The caboose also serves as a living and working space for the crew, providing a bed, cooking facilities, and a desk. The signalman in the caboose communicates with the engineer by means of a lamp or radio. The caboose also serves as a weight to help slow the train when necessary.
The work done (350,000 J) is equal to the force applied (70,000 N) multiplied by the distance traveled (x). Therefore, x = 350,000 J / 70,000 N = 5 m. Since the caboose has to travel a distance of 7 m to come to a complete stop, the answer is D. 7 m.
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Cold water ~
has the highest density at what temperature.. ?
Answer:
The maximum density of water occurs at around 4° Celsius. The density of ice is less than liquid water, so it floats. Upon freezing, the ice density decreases by about 9%.
Explanation:
thanks for the question
Gravity causes a rock to accelerate downwards at a rate of 32 ft/sec/sec. How far does it travel in a time of 3.5 sec?
The distance traveled by the rock at 3.5seconds is 392ft.
How to calculate distance?Distance moved by a body can be calculated by using the following formula:
Speed = distance/time
Acceleration = speed/time
According to this question, gravity causes a rock to accelerate downwards at a rate of 32 ft/sec/sec. The speed can be calculated as follows:
Speed = 32ftsec-² × 3.5sec
Speed = 112ft/sec
Distance moved = 112ft/sec × 3.5sec
Distance = 392ft
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Calculate the angular velocity of a 0.300m radius car tire when the car travels at 15.0m/s (54km/hr).
Answer: The angular velocity of a car tire is 1 rad/s.
Definition: Angular velocity is the speed at which the angle between two bodies changes when an object rotates or revolves around an axis. This displacement is depicted in the image by the angle formed by a line on one body and a line on the other.
finish this tell me why tell me why
Answer:
Tell me why you cried, and why you lied to me
Tell me why you cried, and why you lied to me
Well I gave you everything I had
But you left me sitting on my own
Did you have to treat me, oh, so bad
All I do is hang my head and moan
Tell me why you cried, and why
Explanation:
You have to
design a circuit that has an interface to the outside world made
up of 5 wires:
a. One wire connects to ground.
b. One wire connects to a single supply voltage, Vsupply. (See Design Constraints below).
c. One wire connects to a control signal. During testing, this signal is only allowed to have values 0 or +5V.
d. The remaining two wires v1 and v2 are what the switch is supposed to connect. If Vcontrol = 0V
then the switch should be closed and ideally v1=v2 . If Vcontrol = +5V then the switch is open
and ideally i1=i2=0 where i1 and i2 are the currents into each of the two wires v1 and v2 .
Design Constraints
1. You are limited to the use of a single dc power supply. Vsupply ≤ +5V .
2. You are allowed the use of MOSFETs, diodes, resistors, and capacitors that are available in your
component kits.
3. You have a single control voltage. The function of the control voltage is as described above for
each type of switch.
Answer:
the unit of m×g×h×10 is no 3
The brakes on a car do 240,000 J of work to stop the tires from moving. The car travels 50 m after the brakes are applied. How much force are the brakes applying to stop the car from moving?
24,000 N
1.2 x 107 N
4,800 N
120,000 N
Answer:
Below
Explanation:
Work = force * distance
240 000 J = force * 50 m
240 000 / 50 = force = 4800 N
A 4.0-N puck is travelling at 3.0m/s. It strikes an 8.0-N puck, which is stationary. The two
pucks stick together. Their common final speed is:
Answer: 2.858(m/s)
Explanation: F= mg→ m1= 4.0/9.8 = 0.408(kg)
m2= 8 /9.8 = 0.816(kg)
m1v1 = (m1+m2)v2→ v2= m1v1(m1+m2) = 0.408+3/(0.408+0.816)= 2.8589m/s)
A horizontal spring has spring constant k = 100 N/m. How much work is required to compress it from its uncompressed length (x = 0) to x = 10 cm?
Answer: 0.5J
Explanation:
We can use the formula for the potential energy stored in a spring:
U = (1/2) k x^2
where U is the potential energy, k is the spring constant, and x is the displacement from the equilibrium position.
Since we want to compress the spring, x will be negative, and we need to find the potential energy change between the uncompressed length and a compression of 10 cm:
U = (1/2) k (0.1 m)^2 - (1/2) k (0 m)^2
U = (1/2) (100 N/m) (0.1 m)^2 - (1/2) (100 N/m) (0 m)^2
U = 0.5 J
So the work required to compress the spring from its uncompressed length to x = 10 cm is 0.5 J.
The amount of work required by the spring to compress it from its uncompressed length (x = 0) to x = 10 cm is 0.5 J.
How do you calculate the work required by the spring?In order to compress a spring, the following formula must be used:
Work is equal to (1/2)*k*(xf² - xi²)
where:
xi = starting position = 0 m
xf = final position = 10 cm = 0.1 m k = spring constant = 100 N/m
By entering these values, we obtain:
W = (1/2) * 100 N/m * (0.1 m)² = 0.5 J
Hence, it takes 0.5 J of work to compress the spring from its uncompressed length to x = 10 cm (joules).
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formula for calculating a cross sectional area of a cylinder
The formula for calculating the cross-sectional area of a cylinder is:
A = πr^2
The intersection of a cylinder is the area of a shape found if the cylinder is cut perpendicular to its length. This will be a circle for a cylinder. The cross-sectional area of a cylinder is calculated as A = πr^2, where A is the cross-sectional area, is a mathematical constant approximately equal to 3.14, and r is the radius of the cylinder.
This formula computes the volume of a sphere of radius r, which is the cylinder's cross-sectional area. We can calculate various cylinder properties such as thickness, surface area, and so on by knowing the cross-sectional area.
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The formula for calculating the cross-sectional area of a cylinder is Area = πr^2 where 'r' is the radius of the cylinder. An example is provided where the radius is 5 units, yielding a cross-sectional area of 78.5 square units.
Explanation:The cross-sectional area of a cylinder can be calculated using the formula for the area of a circle, because a cross-section of a cylinder is a circle. The formula is Area = πr^2, where 'r' is the radius of the cross-section.
For example, if you have a cylinder with a radius of 5 units, you would calculate the cross-sectional area as follows:
Substitute the radius into the formula: Area = π*5^2.Calculate the square of the radius: Area = π*25.Multiply the result by π (approximately 3.14): Area = 3.14*25 = 78.5 square units.So, the cross-sectional area of this cylinder is 78.5 square units.
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Bumblebees are skilled aerialists, able to fly with confidence around and through the leaves and stems of plants. In one test of bumblebee aerial navigation, bees in level flight flew at a constant 0.40 m/s, turning right and left as they navigated an obstacle-filled track. While turning, the bees maintained a reasonably constant centripetal acceleration of 4.0 m/s2.
What is the radius of curvature for such a turn?
How much time is required for a bee to execute a 90 degree turn?
The radius of curvature for the turn is 0.10 m. The time required for a bee to execute a 90 degree turn is 0.56 seconds.
How do bumblebees navigate through obstacle-filled tracks?Bumblebees are skilled aerialists and can fly with confidence around and through the leaves and stems of plants. They navigate obstacle-filled tracks by maintaining a reasonably constant centripetal acceleration of 4.0 m/s2 while turning right and left in level flight at a constant speed of 0.40 m/s.
The centripetal acceleration of a body moving in a circular path can be expressed as a = v^2 / r, where a is the centripetal acceleration, v is the speed of the body, and r is the radius of curvature.
Given that the bumblebees maintain a constant centripetal acceleration of 4.0 m/s^2 while turning, and their speed is 0.40 m/s, we can calculate the radius of curvature as:
r = v^2 / a = 0.40^2 / 4.0 = 0.04 m = 0.10 m (rounded to two significant figures)
To find the time required for a bee to execute a 90 degree turn, we need to know the distance it travels during the turn. Since the turn is a quarter of a circle, the distance traveled is a quarter of the circumference of the circle with a radius of 0.10 m, which is:
d = (πr)/2 = (3.14 x 0.10)/2 = 0.157 m
The time required to travel this distance at a constant speed of 0.40 m/s is:
t = d/v = 0.157 / 0.40 = 0.3925 s = 0.56 s (rounded to two significant figures)
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1. What is most likely to happen if the cell membrane does not function properly?
2. If a bunch of flowers represents a tissue in the human body, what does each flower in the bunch represent?
3. If a bunch of flowers represents a tissue in the human body, what does each flower in the bunch represent?
4. Based on the way living things are organized, what level combines to form organ systems?
5. What cannot be broken down into simpler substances?
6. Is the big bang theory an everyday life theory or a scientific theory?
7. Which part of a cell releases energy that the cell uses?
8. What instruments uses charged particles to see very small objects like the ribosomes and other organelles inside a cell?
9. Name a molecule with more than one element
10. What processes produces food?
11. Greg is telling his teacher how a cell is like a house. Which part of a cell is like the air in Greg's house?
The answers to the questions about cells and their functions along with structure are given below.
Cell Functions and Structures.A cell is the basic unit of life. It is a small, self-contained structure that carries out all of the processes necessary for an organism to survive and function. Cells can be found in all living organisms, and they come in a wide variety of shapes, sizes, and functions.
If the cell membrane does not function properly, it can lead to a variety of problems depending on the specific issue. For example, if the membrane is too permeable, the cell can lose important molecules and ions, leading to improper functioning or even death. If the membrane is not permeable enough, the cell may not be able to take in necessary nutrients or expel waste products, which can also lead to problems.If a bunch of flowers represents a tissue in the human body, each flower in the bunch would represent an individual cell within that tissue.If a bunch of flowers represents a tissue in the human body, each flower in the bunch would represent an individual cell within that tissue.Cells combine to form tissues, which then combine to form organs, and organs combine to form organ systems.Elements cannot be broken down into simpler substances.The big bang theory is a scientific theory that explains the origins of the universe.The mitochondria is the part of the cell that releases energy that the cell uses.A transmission electron microscope (TEM) uses charged particles to see very small objects like the ribosomes and other organelles inside a cell.Water (H2O) is a molecule with more than one element.Photosynthesis is a process that produces food.The cytoplasm of a cell is like the air in Greg's house. It fills the space within the cell and provides a medium for the organelles to carry out their functions.Learn more about cells here https://brainly.com/question/3717876
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A key challenge with renewable energy is that the energy must be transported to the place where it's needed _ or devices that store the energy needed improvement.
A. batteries
B. refineries
C. solar panels
D. wind turbines
A. batteries
Renewable energy sources like solar and wind power are often located in remote areas, far from where the energy is needed. This means that the energy must be transported over long distances to reach the end user, which can result in energy losses due to resistance in transmission lines. To address this issue, energy storage devices like batteries are needed to store excess energy generated by renewable sources during periods of low demand, and then release it when demand is high. However, current battery technology still needs improvement in terms of capacity, efficiency, and cost to make it more widely accessible and practical for large-scale renewable energy storage.
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Answer:
17. A
18. C
Explanation:
np:) and have a wonderful day