A right triangle has side lengths of 4 cm and 5 cm. What is the length of the hypotenuse? (pythagorean theorem)

An expression is defined as a set of numbers, variables, and mathematical operations. The correct option is B.

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

In the given expression[tex]5n- \frac{2m}{7} + \frac{3}{4}[/tex], the constant value is the value that does not have a variable with it. Therefore, the constant in the given expression is 3/4.

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The power consumed by the circuit is 512.76 watts.

The pace of work or energy transmission in an electrical circuit is known as electric power. It is a way to quantify how much energy is consumed over a certain period of time. P = VI, where V is the potential difference, I is the electric current, and P is the electric power, calculates the electric power.

The two resistors R2 and R3 are parallel.

Thus,

Req = R2 + R2 / R1R2

Req = 36 + 18 / (36)(18)

Req = 0.083

Now, the resistors R1, Req, and R4 are in series:

Thus,

R = R1 + Req + R4

R = 15 + 0.083 + 13

R = 28.083

The formula of power is:

P = V²/R

Substitute the values:

P = (120)²/ 28.083

P = 512.76 watts.

Hence, the power consumed by the circuit is 512.76 watts.

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The length of the diagonal of the rectangle is 25cm.

The diagonal of a rectangle is the line segment that connects the two opposite vertices. It can be calculated using the Pythagorean Theorem, which states that the square of the hypotenuse (the longest side of a right triangle) is equal to   the sum of the squares of the other two sides.

In this case, the length of the two sides of the rectangle are 15cm and 20cm. To calculate the diagonal of the rectangle, we need to use the Pythagorean Theorem to solve for the hypotenuse, which is the diagonal of the rectangle.

The formula is: a² + b² = c²

Using the sides of the rectangle, we get: 15² + 20² = c²

Simplifying the equation, we get: 225 + 400 = c²

Then, we take the square root of both sides of the equation to find the length of the diagonal:

√625 = c

The length of the diagonal of the rectangle is 25cm.

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The Sample mean years to maturity will be 7.05 and Sample standard deviation of years to maturity is 4.1318.

What is mean?

Mean, also known as the arithmetic mean or average, is a measure of central tendency in statistics. It is calculated by summing up all the values in a dataset and dividing by the total number of values.

Now,

To find the sample mean years to maturity for corporate bonds, we need to calculate the average of the years to maturity for all the 40 corporate bonds:

Sample mean years to maturity = (12.00 + 9.75 + 4.75 + 9.25 + 9.75 + 5.00 + 5.00 + 10.00 + 10.00 + 3.25 + 9.75 + 9.75 + 9.25 + 5.00 + 5.00 + 4.25 + 26.00 + 10.00 + 5.00) / 20

= 7.05

Therefore, the sample mean years to maturity for corporate bonds is 7.05.

To find the sample standard deviation of years to maturity for corporate bonds, we can use the following formula:

Sample standard deviation = √((1/n) * sum(xi - x_bar)²)

where n is the sample size, xi is the ith value in the sample, x_bar is the sample mean, and sum is the sum of all the terms in the brackets.

Using this formula and the given data, we get:

Sample standard deviation = √((1/20) * [(12.00 - 7.05)² + (9.75 - 7.05)²+ (4.75 - 7.05)² + (9.25 - 7.05)² + (9.75 - 7.05)² + (5.00 - 7.05)² + (5.00 - 7.05)² + (10.00 - 7.05)² + (10.00 - 7.05)² + (3.25 - 7.05)² + (9.75 - 7.05)² + (9.75 - 7.05)² + (9.25 - 7.05)² + (5.00 - 7.05)² + (5.00 - 7.05)² + (4.25 - 7.05)² + (26.00 - 7.05)² + (10.00 - 7.05)² + (5.00 - 7.05)²])

Sample standard deviation = 4.1318

Therefore, the sample standard deviation of years to maturity for corporate bonds is 4.1318 (rounded to four decimal places).

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The percent of women in the workforce is expected to increase by 0.0879% in 2039, according to the given model.The given function is w(x) = 9.42 + 8.70 ln(x), where x represents the number of years past 1940.

To find the rate of change of the percent in 2039, we need to find the derivative of the function with respect to x.

w(x) = 9.42 + 8.70 ln(x)

Differentiating both sides with respect to x, we get:

dw/dx = 8.70 / x

Substituting x = 99 (since 2039 is 99 years past 1940), we get:

dw/dx = 8.70 / 99

Therefore, the rate of change of the percent in 2039 is approximately 0.0879%, rounded to three decimal places.

Therefore, the percent of women in the workforce is expected to increase by 0.0879% in 2039, according to the given model.

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The values of m and n for the polynomial [tex]p(x) = 3x^3 + 12x^2 - 15x - 3,[/tex] satisfying the given conditions, are m = 3 and n = -15.

To determine the values of m and n in the polynomial[tex]p(x) = mx^3 + 12x^2 + nx - 3[/tex], use the Remainder Theorem. According to the theorem, if a polynomial p(x) is divided by (x - a), the remainder is equal to p(a).

Given that when dividing p(x) by (x + 3) is zero, substitute -3 for x in the polynomial and set it equal to zero:

[tex]m(-3)^3 + 12(-3)^2 + n(-3) - 3 = 0[/tex]

Simplifying this equation gives us:

-27m + 108 + (-3n) - 3 = 0

-27m - 3n + 105 = 0

Next, we are given that the remainder when dividing p(x) by (x - 2) is 85. Using the same logic, we substitute 2 for x in the polynomial and set it equal to 85:

[tex]m(2)^3 + 12(2)^2 + n(2) - 3 = 85[/tex]

Simplifying this equation gives us:

8m + 48 + 2n - 3 = 85

8m + 2n + 45 = 85

Now we have a system of two equations with two variables:

-27m - 3n+ 105 = 0

8m + 2n + 45 = 85

Solving this system of equations will give us the values of m and n. By solving these equations, we find that m = 3 and n = -15.

Therefore, the values of m and n for the polynomial [tex]p(x) = 3x^3 + 12x^2 - 15x - 3,[/tex] satisfying the given conditions, are m = 3 and n = -15.

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Therefore , the solution of the given problem of expressions comes out to be the total number of pet fish and reptiles in the US is roughly

1.494 * 10⁸.

It is necessary to perform calculations which it involve joining, removal, and random subdivision variable changing multipliers. If they banded together, they could do the following: A mathematical challenge, some information, and an algorithm. A statement of equation truth contains formulas, elements, and arithmetic procedures like additions, subtractions, errors, and groupings. It is possible to assess and analyse words and phrases.

Here,

The number of fish and reptiles kept as pets must be added to the overall number of pets:

=> 1.4 * 10⁸ + 9.4 * 10⁶

We must change these numbers to the same power of 10 in order to add them. Since 108 is equal to 100 million,

we can achieve this by moving the decimal point in the second figure two places to the right:

=> 1.4 * 10⁸ + 0.094 * 10⁸

We can now multiply the numbers:

=> 1.494 * 10⁸

Thus, the total number of pet fish and reptiles in the US is roughly

=> 1.494 * 10⁸.

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There are total of [tex]2.34*10^{8}[/tex] pet fish and reptiles in the United States.

Calculations that include changeable altering multipliers, joining, removal, and random subdivision must be done. They could accomplish the following if they united: An algorithm, some data, and a mathematical problem.

To find the total number of pet fish and reptiles in the United States, we simply need to add the number of pet fish and pet reptiles together:

Total = [tex]1.4*10^{8} + 9.4*10^{6}[/tex]

To add these numbers together, we need to express them using the same power of 10. We can do this by rewriting 9.4 * 10^6 as 0.94 * 10^7:

Total = [tex]1.4*10^{8} + 0.94*10^{7}[/tex]

Now, we can add the numbers together:

Total = [tex]1.4*10^{8} + 0.94*10^{7}[/tex]

= [tex]1.4 * 10^8 + 0.94 * 10^8[/tex]   (since [tex]10^7 = 10 * 10^6 = 10^1 * 10^6 = 10^7[/tex])

= [tex]2.34 * 10^8[/tex]

Therefore, there are a total of [tex]2.34 * 10^8[/tex] pet fish and reptiles in the United States.

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The correct option that describes the shape of the sampling distribution of means is: Approximately normal.

The sampling distribution of the means refers to a distribution made up of many samples. For the given problem, there are 750 basketball games, and the researcher takes a simple random sample of size n = 40 from this population and computes the mean number of three-point baskets.

The central limit theorem states that the sampling distribution of the means of any population, even those that are not normally distributed, approaches a normal distribution as the sample size grows larger. When a sample has a sample size greater than 30, the shape of the sampling distribution of the means is approximately normal.

Thus, the shape of the sampling distribution of means is Approximately normal.

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The total distance traveled by the particle from 0 ≤ t ≤ 6 is: 216 units

The position of the particle is given by the equation:

x(t) = 3t³ - 27t² + 72t + 14.

Now, To find the times when the particle changes direction, you just need to find the critical numbers of the function x(t).  These would be the possible times when the particle changes direction.

x(t) = 3t³ - 27t² + 72t + 14.

x'(t) = 9t² - 54t + 72

Using quadratic equation calculator, we have:

t = 2 or 4

Then you can find the position of the particle at these times.  We will also need to find its position at our end points: t = 0, 7.  Basically all we are doing here is finding the global max/min values of the function up to this point.

x(0) = 3(0)³ - 27(0)² + 72(0) + 14 = 14

x(2) = 3(2)³ - 27(2)² + 72(2) + 14 = 74

x(4) = 3(4)³ - 27(4)² + 72(4) + 14 = 62

x(6) = 3(6)³ - 27(6)² + 72(6) + 14 = -202

Thus:

Total distance = (74 - 14) + (62 - 74) + (-202 - 62)

= -216

This is 216 in the negative direction

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Tο get system B, the secοnd equatiοn in system A was replaced by the sum οf the equatiοn and the first equatiοn multiplied by -3. The sοlutiοn tο system B is the same as the sοlutiοn in system A.

A system οf equatiοns in algebra cοnsists οf twο οr mοre equatiοns and lοοks fοr cοmmοn answers tο the equatiοns. "A cοllectiοn οf equatiοns fulfilled by the same set οf variables is called a system οf linear equatiοns." Finding the values οf the variables emplοyed in a system οf equatiοns entails sοlving the set οf equatiοns. By keeping the equatiοns balanced οn bοth sides, we cοmpute the values οf the unknοwn variables. Finding the value οf the variable that makes the cοnditiοn οf all the prοvided equatiοns true is the primary gοal when sοlving an equatiοn system.

Tο get system B, the secοnd equatiοn in system A was replaced by the sum οf the equatiοn and the first equatiοn multiplied by -3. The sοlutiοn tο system B is the same as the sοlutiοn in system A.

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If an item sets off the alarm,  the probability that it is defective is  0.0098 or 0.98%

This is a problem of conditional probability. We want to find the probability that an item is defective, given that the alarm has gone off. Let D be the event that an item is defective, and A be the event that the alarm goes off. We want to find P(D|A).

We can use Bayes' theorem to find P(D|A):

P(D|A) = P(A|D) * P(D) / P(A)

where P(A|D) is the probability that the alarm goes off given that the item is defective, P(D) is the prior probability that an item is defective, and P(A) is the probability that the alarm goes off.

We are given that:

P(A|D) = 0.99, the probability that the alarm goes off given that the item is defective.

P(A|D') = 0.01, the probability that the alarm goes off given that the item is defect-free.

P(D) = 100/1000000 = 0.0001, the prior probability that an item is defective.

P(D') = 1 - P(D) = 0.9999, the prior probability that an item is defect-free.

To find P(A), we can use the law of total probability:

P(A) = P(A|D) * P(D) + P(A|D') * P(D')

= 0.99 * 0.0001 + 0.01 * 0.9999

= 0.010098

Now we can substitute these values into Bayes' theorem:

P(D|A) = P(A|D) * P(D) / P(A)

= 0.99 * 0.0001 / 0.010098

= 0.009804

Therefore, the probability that an item is defective given that the alarm goes off is approximately 0.0098 or 0.98% when rounded to two decimal places.

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The isosceles triangle has a surface area of 65 square centimetres. We may use the following formula to get the area of an isosceles triangle: Area is equal to (1/2) x base * height. If we substitute the values provided, we get: Area: 10 x 13 x (1/2) cm

65 square cm is the area.

As a result, the isosceles triangle with a base of 10 cm and a height of 13 cm has a surface area of 65 square cm.

The height of an isosceles triangle is perpendicular to the base, and it has two equal sides. An isosceles triangle's area may be calculated by multiplying the base and height of the triangle and dividing the result by two. The triangle's base in this instance is 10 cm, while its height is 13 cm. These values are substituted into the calculation, and the result is that the triangle's area is 65 square cm. As a result, the isosceles triangle has a 65 square centimetre area.

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What is the area of an isosceles triangle with a height of 13 cm and a base of 10 cm?

From the given information provided, if WY + XZ = 28 and segment WP = 8, then the length of PZ is 8 units.

We can use similar triangles to find the length of PZ.

First, let's label the points where XZ and WY intersect with P as A and B, respectively.

Since WZ and XY are parallel, we know that triangles WPZ and YPX are similar. Therefore, we can write the following proportion:

WP/PZ = YP/YX

We know that WP = 8, so we just need to find YP and YX.

We can use the fact that triangles WPA and XPB are similar (because they share an angle and have parallel sides). Therefore, we can write the following proportion:

WP/WA = PB/PX

Substituting 8 for WP and rearranging, we get:

WA = 8(PX/WB)

Similarly, we can use the fact that triangles YPA and ZPB are similar to write:

YP/YA = PB/PZ

Substituting YX + WA for YA (since WY and XZ divide the parallelogram into equal areas), and substituting 28 - WA for PB (since WY + XZ = 28), we get:

YP/(YX + WA) = (28 - WA)/PZ

Substituting 8(PX/WB) for WA and simplifying, we get:

YP/(YX + 8PX/WB) = (28 - 8PX/WB)/PZ

Now we just need to solve for PZ. Cross-multiplying and simplifying, we get:

PZ = (28 - 8PX/WB)(YX + 8PX/WB)/YP

Since we know that WZ and XY are parallel, we can use the fact that opposite sides of a parallelogram are equal to write:

WZ = XY = WY + XZ = 28

We also know that WP = 8. Therefore, we can use the fact that the area of a parallelogram is equal to the product of its base and height to write:

Area(WPZ) = 8(WZ/2)

Substituting 28 for WZ, we get:

Area(WPZ) = 112

We can also use the fact that the area of a triangle is equal to half the product of its base and height to write:

Area(WPZ) = (PZ)(WX)/2

Substituting WX = WZ = 28 and simplifying, we get:

Area(WPZ) = 14PZ

Equating the two expressions for the area of WPZ, we get:

14PZ = 112

Solving for PZ, we get:

PZ = 8

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Answer:

x = 120

Step-by-step explanation:

A regular polygon for something that has 3 sides (triangle) will have equal angles and sides, making this an equilateral and equiangular triangle. Because of this, the angles on the inside of the triangle are each 60 degrees. Angle x and the angle of the triangle make a straight line, x+60=180. This makes x equal to 120.

Answer:

y = x - 5

Step-by-step explanation:

Using the 'y=mx+c' form,

Since m = 1,

y = x + c

Substituting (1, -4) into the above equation:

-4 = 1 + c

c = -5

Hence,

y = x - 5

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The square root of 2275 is 47.71, so the distance from the intersection to the entrance of the stadium is about 48 yards. Rounding to the nearest yard, we get 48 yards.

A right triangle is a type of triangle that has one 90 degree angle. The other two angles are acute angles and their sum adds up to 90 degrees. The two sides that are not the right angle are called the legs and the longest side is called the hypotenuse. The Pythagorean Theorem is used to find the lengths of the sides of a right triangle.

This problem can be solved using the Pythagorean Theorem. The Pythagorean Theorem states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. Using this theorem, we can calculate the length of PC, which is then the same as the distance from the intersection to the stadium entrance.

First, we can calculate the length of CM by subtracting MP from AC, which gives us 50 - 35 = 15. We can then apply the Pythagorean Theorem to the triangle ACM to calculate the length of PC. The hypotenuse, AC, is 50, one of the other sides, CM, is 15, and the last side, the one we are trying to solve for, is PC. We can rearrange the Pythagorean Theorem to solve for PC, which gives us PC = √(AC2 - CM2). Plugging in the numbers, we get PC = √(502 - 152), which equals √(2500 - 225), or √2275. The square root of 2275 is 47.71, so the distance from the intersection to the entrance of the stadium is about 48 yards. Rounding to the nearest yard, we get 48 yards.

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Answer:

Step-by-step explanation:You do the brackets first 2X5= 10

10X4 = 40  -  20 / 5 .         20 divided by 5 = 4

40 - 4 = 36

B) 4+2= 6 X3 =18X3= 54

c) 20/5=4   X2 =8+19= 27

D)37.5

E) 3X2=6       12/3 = 4    14+6=20  20-4=16

The expression for the ratio will be AB/BC = sin(∠BAC)/sin(∠CAB).

What is Expression?

An expression is mathematical phrase that can contain numbers, variables, operators, and functions, but does not have equal sign. It represents  value or  mathematical operation that can be evaluated or simplified.

we can use the Pythagorean theorem to find the distances between the houses, and then use trigonometric ratios to find the ratios between them.

Let's assume that Amy's house is located at point A, Barry's house is located at point B, and Chris's house is located at point C, as shown in the diagram below.

 C

 |

 |

---A--------

 |

 |

 B

a. To find the ratio of Barry's distance from Amy to Chris' distance from Amy, we can use the following trigonometric expressions:

tan(∠BAC) = AB/AC     (opposite/adjacent)

tan(∠CAB) = AC/AB     (opposite/adjacent)

Therefore,

AB/AC = 1/tan(∠BAC)

AC/AB = 1/tan(∠CAB)

b. To find the ratio of Barry's distance from Chris to Amy's distance from Chris, we can use the following trigonometric expressions:

tan(∠ACB) = AB/BC     (opposite/adjacent)

tan(∠ABC) = AC/BC     (opposite/adjacent)

Therefore,

AB/BC = tan(∠ACB)

AC/BC = tan(∠ABC)

c. To find the ratio of Amy's distance from Barry to Chris' distance from Barry, we can use the following trigonometric expression:

sin(∠BAC) = AB/BC     (opposite/hypotenuse)

sin(∠CAB) = AC/BC     (opposite/hypotenuse)

Therefore,

AB/BC = sin(∠BAC)

AC/BC = sin(∠CAB)

So,

AB/BC = sin(∠BAC)/sin(∠CAB).

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The number of students who travel for the field trip is at most 52 students.

An inequality is a statement that of two quantities one is specifically less than or greater than another.

Cost of group guided tour = $34

Cost of each student admission = $8

Total amount spent by the school = at most $450

Number of students = x

The inequality:

34 + 8x ≤ 450

8x ≤ 450 - 34

8x ≤ 416

divide both sides by 8

x ≤ 416/8

x ≤ 52

Hence, x ≤ 52 students travel for the field trip.

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This is known as the Pythagorean Theorem and states that the square of the hypotenuse (c) is equal to the sum of the squares of the other two sides (a and b).

Area is a measure of the size of a surface or space. It is typically measured in two-dimensional units such as square meters, square kilometers, and acres. Area is also used to measure the size of three-dimensional objects such as cubes and spheres. Area is a fundamental concept in mathematics and is often used to calculate the perimeter, circumference, and volume of shapes. In physics, area is used to measure the amount of energy an object absorbs or releases.

This theorem is one of the most famous theorems in mathematics, and is found in several ancient mathematical texts, including those from the Babylonians and Chinese. The theorem is attributed to the Greek mathematician Pythagoras, who lived in the 6th century BC.

The theorem can be expressed in the equation [tex]a^{2}+ b^{2} = c^{2}[/tex], where a and b are the lengths of the two legs of the right triangle and c is the length of the hypotenuse. This equation can be used to calculate the length of the hypotenuse if the lengths of the two other sides are known. For example, if the two legs of a right triangle have lengths of 3 and 4, the length of the hypotenuse can be calculated using the equation [tex]3^{2} + 4^{2}[/tex] = [tex]c^{2}[/tex], which results in c = 5.

The Pythagorean Theorem can be used to solve many mathematical problems related to triangles, as well as to solve problems in other areas such as geometry, physics, and engineering. In addition, the theorem is often used to prove theorems in mathematics, such as the law of cosines.

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Complete question is:

In pythagoras theorem, the sum of the areas of two squares on the legs (a and b) equals the area of the square on the hypotenuse (c) that is . discuss.

The one and four hundred twenty nine thousandths in decimal form is 0.429.

Decimal Form:

Decimals are numbers made up of a whole number and a fractional part. Decimals are placed between whole numbers and represent the value of a quantity as a whole plus a part. In decimal form, we write this as 1.5 pizzas. Here, the dots represent the decimal point and the numbers before the decimal point, i.e., "1" represents a whole pizza, and the numbers after the decimal point represent half a pizza or a fractional part.

According to the Question:

The calculation is as follows;

Here in the given situation  

One and Four hundred - the number 4

Twenty nine - the number 29

Now,  

We have to Add them together with 0.

So, it should be 0.429

Complete Question:

What is One and four hundred twenty-nine thousandths as a decimal

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The number of movies rented was 5 to bring a total cost of $79.95

An equation is an expression that shows how two or more numbers and variables are related using mathematical operations of addition, subtraction, multiplication, division, exponents and so on.

Let y represent the total cost of renting x movies for one month.

The cable company charges a monthly fee of $55. Each movie that you rent from the DVR cost $4.99. Therefore:

y = 4.99x + 55

$79.95 is owed, hence:

79.95 = 4.99x + 55

4.99x = 24.95

x = 5

The number of movies rented was 5.

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A ring-shaped path goes around the circle shaped flower garden. The gardener will need total 52 bags of sand to cover the ring-shaped path with sand.

We have a circle shaped flower garden. Also, Diameter of inner circle = 30 yd

radius of inner circle, r = 30/2 = 15 yd

Diameter of outer circle = 36 yd

So radius of outer circle, R = 36/2 = 18 yd

Area of inner circle = πr²

= π(15)² = 225π yd²

Area of Outer circle = πR²

= π(18)² = 324π yd²

A ring-shaped path goes around the garden. Thus, Area of shaded region

= Outer circle area - inner circle area that is πR² - πr²

= 325 π - 225π = π(324 - 225)

= 3.14× 99 = 310.86 yd²

Since we have a bag of sand can cover 6 yard. So, number of the requirements of bags of sand is calculated as = 310.86/6

= 51.81 ~ 52

since we want whole sand bags, so total Sandbags needed is equals the 52.

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Answer:When x→−∞ , then P(x)→−∞When x→+∞ , then P(x)→+∞Note that we can figure out if the function grows or decreases, simply by looking at the leading term of the function which is 4x⁵. This term shows that the function increases without bound as x → ± ∞.The given function is P(x)=4x⁵−8x³−7x²+9x+7We can now find the horizontal asymptotes of the given function, by computing the limits at infinity as follows;When x→−∞ , then P(x)→-∞When x→+∞ , then P(x)→+∞Therefore, the horizontal asymptotes are: y= - ∞ and y= + ∞

In a case whereby Laila needs a new bike mirror. Her old mirror was a square with a side length of 7 cm the circular bike mirror Laila should buy is 4 cm.

Given that the side length = 7 cm

Then we can know the Old mirror's area  using the formula

Area =  (S X S)

Where S is the side

=( 7 x 7 )

= 49cm2

Then from the information from the question, we can equate the area of the old and the new as

(Area of old mirror = Area of new mirror)

where  Area of new mirror = πr^2

(49 = πr^2)

49 = (22/7 * r^2)

r^2 = 49 *7/22

r= 3.948 cm

r = 4cm

If we approximate it , hence option A is correct.

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The pοpulatiοn mean is apprοximately 84.93 and the pοpulatiοn standard deviatiοn is apprοximately 38.54.

The standard deviatiοn is a summary measure οf the differences οf each οbservatiοn frοm the mean. If the differences themselves were added up, the pοsitive wοuld exactly balance the negative and sο their sum wοuld be zerο. Cοnsequently, the squares οf the differences are added.

We can use the fοrmula fοr standardizing a variable using z-scοres:

z = (x - μ) / σ

where z is the z-scοre, x is the cοrrespοnding raw scοre, mu is the pοpulatiοn mean, and sigma is the pοpulatiοn standard deviatiοn.

We have twο pairs οf (x, z) values:

x = 83, z = -0.05

x = 0.93, z = 2.0

We can use these tο create twο equatiοns with twο unknοwns ( and sigma):

-0.05 = (83 - μ) / σ

2.0 = (0.93 - μ) / σ

We can sοlve this system οf equatiοns by first sοlving οne οf the equatiοns fοr οne οf the unknοwns, and then substituting that expressiοn intο the οther equatiοn. Fοr example, we can sοlve the first equatiοn fοr mu:

mu = 83 + 0.05 * σ

Then we substitute this expressiοn fοr mu intο the secοnd equatiοn:

2.0 = (0.93 - (83 + 0.05 * σ)) / σ

Simplifying this equatiοn, we get:

2.0 = (0.93 / σ) - (83 / σ) - 0.05

2.05 = 0.93 / σ - 83 / σ

2.05 = (0.93 - 83) / σ

σ = (0.93 - 83) / 2.05

σ = 38.5366

Nοw we can use this value tο find the pοpulatiοn mean μ:

μ = 83 + 0.05 * σ

μ = 83 + 0.05 * 38.5366

μ = 84.9278

Therefοre, the pοpulatiοn mean is apprοximately 84.93 and the pοpulatiοn standard deviatiοn is apprοximately 38.54.

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Answer:

The answer would be D

Hope this helps!

No, the assertion does not imply that all circles are smooth forms.

The location of all the points on a plane whose sum of the distances from two fixed points in the plane is constant is known as an ellipse. The foci (singular focus), which are fixed locations that are encircled by the curve, are known. Directrix is the fixed line, and the eccentricity of the ellipse is the constant ratio.

No, the assertion does not imply that all circles are smooth forms. Since circles are a particular form of ellipse with a constant distance between any point on the circle's perimeter and its centre, they are a type of ellipse that are not all ellipses. In contrast, some ellipses seem stretched or compressed along their main and minor axes because there are two distinct distances between each point on the ellipse and its centre.

Hence an ellipse that is not a circle, such as one that is extended or flattened, can be a smooth shape. Due to the lack of any abrupt edges or line breaks, these forms are nevertheless regarded as smooth figures.

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Answer:

i gotchu

Step-by-step explanation: