a quadratic function has a discriminant with a value of -4 what type of solution does the quadratic equation have ?

Answer:

8.9 g/cm^3

Step-by-step explanation:

Volume = 5 x 2 x 6 = 60 cm^2

density = m/V = 534/60 = 8.9 g/cm^3

Answer:

We can use the Pythagorean theorem to solve this problem. Let's assume that Cari's house is at point A, the airport is at point B, and her grandparents' house is at point C. We know that the distance from A to B is 45 miles and the distance from A to C is 45 miles. We want to find the distance from B to C, which we can call x.

We can form a right triangle with sides AB, AC, and BC. The distance we want to find, x, is the length of the hypotenuse of this triangle (side BC).

Using the Pythagorean theorem, we know that:

AB^2 + AC^2 = BC^2

Substituting in the values we know:

45^2 + 45^2 = x^2

Simplifying:

2025 + 2025 = x^2

4050 = x^2

Taking the square root of both sides:

x = sqrt(4050)

x is approximately equal to 63.64 miles (rounded to two decimal places).

Therefore, the direct distance from the airport to Cari's grandparents' house is approximately 63.64 miles.

Answer:

To calculate the range of inferences, we need to find the minimum and maximum percentages based on the results of the three surveys.

Desiree's survey found that 48 out of 60 students prefer to listen to music while completing homework, which is 80%.

Marina's survey found that 39 out of 60 students prefer to listen to music while completing homework, which is 65%.

Raúl's survey found that 42 out of 60 students prefer to listen to music while completing homework, which is 70%.

To find the minimum percentage, we can take the lowest value of the three surveys, which is 65%. To find the maximum percentage, we can take the highest value of the three surveys, which is 80%. Therefore, a reasonable range of inferences is:

From 65% to 80% of the school population prefers to listen to music while completing homework.

Answer: Let's call the height of the steeple "h". We can use the tangent function to set up an equation involving the angles of elevation:

tan(40°) = h / x

tan(49° 40') = (h + y) / x

where "x" is the distance from the point to the base of the steeple, and "y" is the height of the point above the ground.

We are given that the distance from the point to the church is 48 feet, so we can use the Pythagorean theorem to find the value of "y":

y^2 = x^2 - 48^2

We can substitute this expression for "y" into the second equation above:

tan(49° 40') = (h + √(x^2 - 48^2)) / x

We can now solve this equation for "h":

h = x tan(49° 40') - x √(1 + tan^2(49° 40')) + 48 tan(40°)

Plugging in the values for the angles and solving for "h", we get:

h ≈ 83.9 feet

Therefore, the height of the steeple is approximately 83.9 feet.

Step-by-step explanation:

Answer:

72 degrees

Step-by-step explanation:

If a complete angle is 360 degrees, one-fifth of a complete angle would be:

Therefore one-fifth of a complete angle is 72 degrees.

Answer:

X=60

Step-by-step explanation:

Firstly you must know that a triangle has 180° angle in it's all side.. so in this case you can say x+½x+(1,5)x= 180°

here x equal to 60°

this is a simple way to expres how can find the x angle

And to second way about how to find the x we have to know the lineer algebra. so lineer algebra is a strong way and useful to not only geometric shapes and for all mathematic calculate..

Answer:

the velocity of the man is 5 m/s.

Step-by-step explanation:

The kinetic energy of a moving object is given by the equation:

K.E. = 0.5 * m * v^2

where

K.E. is the kinetic energy

m is the mass of the object

v is the velocity of the object

In this problem, we are given that the man has a mass of 60 kg and a kinetic energy of 750 J.

So,

750 J = 0.5 * 60 kg * v^2

Solving for v:

v^2 = (2 * 750 J) / 60 kg

v^2 = 25 J/kg

v = sqrt(25 J/kg)

v = 5 m/s

Therefore, the velocity of the man is 5 m/s.

The x-intercepts are approximately (-1.08, 0) and (-0.42, 0), and the y-intercept is (0, -5).

To find the x-intercepts of a parabola, we set y = 0 and solve for x. Similarly, to find the y-intercept, we set x = 0 and solve for y.

Setting y = 0 in the given equation, we get,

0 = −10x^2 − 16x − 5

We can solve for x by using the quadratic formula:

x = [-(-16) ± sqrt((-16)^2 - 4(-10)(-5))] / (2(-10))

Simplifying, we get,

x = [-(-16) ± sqrt(256 - 200)] / (-20)

x = [-(-16) ± sqrt(56)] / (-20)

x = [8 ± 2sqrt(14)] / (-10)

So the x-intercepts are:

x = [8 + 2sqrt(14)] / (-10) ≈ -1.08

x = [8 - 2sqrt(14)] / (-10) ≈ -0.42

To find the y-intercept, we set x = 0 in the given equation:

y = −10(0)^2 − 16(0) − 5

y = -5

So the y-intercept is -5.

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Answer:

In the equation X + y = 9, X and y are variables. Variables are used to represent unknown quantities or quantities that can vary. In this case, X and y represent two unknown numbers whose sum is equal to 9. We can use algebraic techniques to solve for either X or y, or both, depending on the situation. The values of X and y could represent anything, such as the number of apples and oranges in a basket, the length and width of a rectangle, or the ages of two people.

The company would use 19.5 yards of blue fabric when 63 yards of red fabric are used, according to the given ratio and diagram.

Word problems are mathematical problems expressed in words, often used to apply mathematical concepts to real-life situations.

To find the number of yards of blue fabric used when 63 yards of red fabric are used, we can use the given ratio of 9 yards of red fabric to 17 yards of blue fabric.

To determine the number of units of red fabric needed for 63 yards divide the number of yards of red fabric by the scale factor for red fabric, which is 3. So, 63 yards ÷ 3 units per yard = 21 units of red fabric.

Use the ratio to determine the number of units of blue fabric needed. Since the ratio of red to blue fabric is 9:17.So, to find the number of units of blue fabric needed for 21 units of red fabric, we can multiply 21 by 17/9, which gives us 39 units of blue fabric.

So, 39 units of blue fabric ÷ 2 units per yard = 19.5 yards of blue fabric.

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Thus, cos x/2 = (sqrt(2))/2 has the solution for x =  4kx ± π/2 in the intervals  [0, 2pi).

The ratio of the hypotenuse to the side adjacent to the acute angle together in right triangle is the cosine function, which is a trigonometric function.

This cosine function for only a specified range of angles is represented graphically by the cos graph. A trigonometric graph's horizontal axis is the angle, which is typically denoted by the symbol, and the y-axis is really the sine function of just that angle. The maximum and minimum values are 1 and 1.

There are amplitudes for both the sine and cosine functions. This is due to the scope limitations of each function. Both functions typically have an amplitude of 1, though this can vary depending on the way the function is constructed.

Given function:

cos x/2 = (sqrt(2))/2

OR,

cos x/2 = √2/2

cos x/2 = cos (2kx ± π/4) , k ∈ R (real number)

x/2 = 2kx ± π/4

x =  4kx ± π/2

Thus, cos x/2 = (sqrt(2))/2 has the solution for x =  4kx ± π/2 in the intervals  [0, 2pi).

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Answer: y=mx+b

Step-by-step explanation:

To change the equation into slope-intercept form, we write it in the form y=mx+b .

Answer:

1582÷

Step-by-step explanation:

because u haven't told to divide wth any number

Answer:

Your question isn't complete. Kindly correct it.

Answer:

[tex]\large\boxed{\mathtt{x = 10}}[/tex]

Step-by-step explanation:

[tex]\textsf{We are asked for the value of x.}[/tex]

[tex]\textsf{Because E is a Midpoint,} \ \overline{DE} \cong \ \overline{EF}.[/tex]

[tex]\textsf{Let's set them equal to each other.}[/tex]

[tex]\mathtt{45=3(x+5)}[/tex]

[tex]\large\underline{\textsf{Begin Solving:}}[/tex]

[tex]\mathtt{45= ( 3 \times x ) +(3 \times 5)}[/tex]

[tex]\mathtt{45= 3x+15}[/tex]

[tex]\large\underline{\textsf{Subtract 15 from Both Sides:}}[/tex]

[tex]\mathtt{3x=30}[/tex]

[tex]\large\underline{\textsf{Divide by 3:}}[/tex]

[tex]\large\boxed{\mathtt{x = 10}}[/tex]

Answer:

x = 10

Step-by-step explanation:

To find:-

Answer:-

We are here given that, E is the midpoint of DF. The value of DE is 45 and that of EF is 3(x+5) . We are interested in finding out the value of "x" .

According to Euclid's first axiom , Things which are half of the same thing are equal to one another. So here;

[tex]\sf:\implies DF = DF \\[/tex]

[tex]\sf:\implies \dfrac{DF}{2}=\dfrac{DF}{2} \\[/tex]

[tex]\sf:\implies DE = EF \\[/tex]

On substituting the respective values, we have;

[tex]\sf:\implies 45 = 3(x+5) \\[/tex]

[tex]\sf:\implies 45 = 3x + 15 \\[/tex]

[tex]\sf:\implies 3x = 45-15\\[/tex]

[tex]\sf:\implies 3x = 30 \\[/tex]

[tex]\sf:\implies x =\dfrac{30}{3}\\[/tex]

[tex]\sf:\implies \red{x = 10}\\[/tex]

Hence the value of x is 10 .

Answer:

Since the pole is in the shape of a cylinder, its volume can be calculated using the formula V = πr²h, where r is the radius and h is the height (or length in this case). We are not given the radius, so we cannot calculate the exact volume. However, we can use an approximation assuming a reasonable radius.

Let's assume a radius of 1 foot. Then, the volume would be V ≈ π(1)²(15) = 15π ≈ 47.1 cubic feet.

The closest answer choice to this approximation is D) 141 ft². However, note that volume is measured in cubic units (feet cubed or ft³), not square units (feet squared or ft²). Therefore, none of the answer choices are in the correct units for the volume of a cylinder.

The probability of 3 successes in 64 trials with a probability of 0.04 of success on a single trial is 0.375.

The probability of x successes in n trials with a probability p of success on a single trial can be calculated using the binomial probability formula. This formula is P(x successes) =[tex]nCx * (p^x) * (1-p)^(n-x)[/tex]. In this case, n = 64, x = 3, p = 0.04. Therefore, P(x successes) =[tex]64C3 * (0.04^3) * (1-0.04)^(64-3)[/tex]. Calculating this gives us P(x successes) = 0.375. Therefore, the probability of x successes in n trials with a probability p of success on a single trial is 0.375.

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In response to the stated question, we can state that here  Hence, the linear equation (6 2 • 35) 2 equals 1/4096

A linear equation is one that satisfies the algebraic formula y=mx+b. m is the y-intercept, while B is the slope. The foregoing sentence is sometimes referred to as a "linear equation with two variables" because y and x are variables. Bivariate linear equations are two-variable linear equations. Examples of linear equations include 2x - 3 = 0, 2y = 8, m + 1 = 0, x/2 = 3, x + y = 2, and 3x - y + z = 3. An equation is said to be linear if its formula is y=mx+b, where m denotes the slope and b the y-intercept. It is referred to as being linear when an equation has the form y=mx+b, where m stands for the slope and b for the y-intercept.

We must do the following operations in the correct order to simplify the formula (62 • 35)2:

To start, we must multiply 2 by 35, which results in the number 70.

The result is -64 when we remove 70 from 6.

The final step is to raise the unfavorable integer -64 to the power of -2.

Hence, we can write:

[tex](6-2 * 35)-2 = (-64)^{-2}[/tex]

To make this statement easier to understand, keep in mind that taking the reciprocal of a number raised to a positive power is the same as raising it to a negative power. With those words:

[tex]a^-n = 1/a^n\\(-64)^-2 = 1/(-64)^2\\1/(-64)^2 = 1/4096[/tex]

Hence, the expression (6 2 • 35) 2 equals 1/4096.

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The answer of the given question based on finding the new coordinate of c is  (1, 5). and to determine if the image of Triangle ABC is similar or congruent to the original triangle is AB / A'B' = BC / B'C' = CA / C'A' = √(2).

Congruent triangles are triangles that have the same shape and size. More specifically, if two triangles have exactly the same size and shape, then they are congruent triangles. This means that all the corresponding sides and angles of two triangles are equal. Congruent triangles can be thought of as being identical to each other, but they may be positioned and oriented differently in space.

To rotate a point 180° degrees counterclockwise about the origin, we can simply multiply its coordinates by the matrix:

[ -1  0 ]

[  0 -1 ]

So, the coordinates of the rotated point C would be:

[ -1  0 ]   [ 3 ]

[  0 -1 ]*[ 8 ] =[ -3 ]

           [  1 ]

we translate this point 4 units to the right and 4 units up by adding 4 to the x-coordinate and 4 to the y-coordinate:

[ -3 + 4 ]

[  1 + 4 ] = [ 1, 5 ]

Therefore, the new coordinates of point C are (1, 5).

To determine if the image of triangle ABC is similar or congruent to the original triangle, we can check if the ratios of the corresponding sides are the same. Let's calculate the lengths of the sides of the original triangle:

AB = √((8-3)² + (3-3)²) = 5

BC = √((3-8)² + (8-3)²) = 5*√(2)

CA = √((3-3)² + (3-8)²) = 5

Now, let's calculate the lengths of the sides of the image triangle, using the new coordinates:

A'B' = √((8-1)² + (3-5)²) = 5*√(2)

B'C' = √((1-1)² + (5-8)²) = 3

C'A' = √((1-8)² + (5-3)²) = 5*√(2)

We can see that the ratios of the corresponding sides are the same:

AB / A'B' = BC / B'C' = CA / C'A' = √(2)

Therefore, the image of triangle ABC is similar to the original triangle.

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The circumference and area of the circle with the arc of length 21 meters and a central angle of 287° are 4.35 meters and 1.16 square meters.

An arc of length 21 meters subtends a central angle of 287° in a circle. The circumference of the circle and area are required to be determined.

Here is the solution:

Let us suppose that the radius of the circle is r. Thus, we can write:

r = (L/θ) r = (21/287)

Let us substitute the values of r in the formulae of the circumference of the circle and area of the circle.

Circumference of the circle:

C = 2πr

C = 2π (21/287)

C ≈ 4.35 meters

Area of the circle:

A = πr²

A = π (21/287)²

A ≈ 1.16 square meters

Therefore, the circumference of the circle is 4.35 meters and the area of the circle is 1.16 square meters.

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if the vertex is at the origin, and the focus point horizontally to the right-side 1/8 units away from the vertex, well, that means is a horizontal parabola with a "p" value of +1/8, so

[tex]\textit{horizontal parabola vertex form with focus point distance} \\\\ 4p(x- h)=(y- k)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h+p,k)}\qquad \stackrel{directrix}{x=h-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{p~is~negative}{op ens~\supset}\qquad \stackrel{p~is~positive}{op ens~\subset} \end{cases} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\begin{cases} h=0\\ k=0\\ p=\frac{1}{8} \end{cases}\implies 4(\frac{1}{8})(~~x-0~~) = (~~y-0~~)^2\implies \cfrac{1}{2}x=y^2\implies \boxed{x=2y^2}[/tex]

The exact value of tangent of 11 times pi over 12 is  [tex]-2+\sqrt{3}[/tex].

We have to find the exact value of [tex]tan\frac{11\pi}{12}[/tex]

[tex]tan\frac{11\pi}{12}=tan\frac{6\pi+5\pi}{12}[/tex]

[tex]tan\frac{11\pi}{12}=tan(\frac{6\pi}{12}+\frac{5\pi}{12})[/tex]

[tex]=tan(\frac{\pi}{2}+\frac{5\pi}{12})[/tex]

We have [tex]tan(\frac{\pi}{2}+x)=-cotx[/tex]

[tex]tan\frac{11\pi}{12}=-cot(\frac{5\pi}{12})[/tex]

[tex]tan\frac{11\pi}{12}=-cot(\frac{2\pi+3\pi}{12})[/tex]

[tex]tan\frac{11\pi}{12}=-cot(\frac{\pi}{6}+\frac{\pi}{4})[/tex]

We have identity [tex]cot(x+y)=\frac{cotxcoty-1}{coty+cotx}[/tex]

[tex]tan(\frac{\pi}{2}+x)= -\frac{cot\frac{\pi}{6}cot\frac{\pi}{4}-1}{cot\frac{\pi}{4}+ cot\frac{\pi}{6}}[/tex]

[tex]=\frac{-\sqrt{3}(1) - 1}{1+\sqrt{3}}[/tex]

Rationalize the denominator and simplify, we get:

[tex]=-2+\sqrt{3}[/tex]

Therefore, the exact value of  [tex]tan\frac{11\pi}{12}[/tex] is [tex]-2+\sqrt{3}[/tex].

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Complete question is:

Find the exact value of  [tex]tan\frac{11\pi}{12}[/tex] ?

One positive number is 5 more than another. The sum of their squares is 53. Then the larger number is 8.


Lets take x be the smaller number, then x + 5 = the larger number. Thus, we have the equation:
x2 + (x + 5)2 = 53
By Simplifying the equation, we get: 2x2 + 10x + 25 = 53
By Solving this quadratic equation, we get x = 3 and the larger number is 8.

Quadratic equations are the polynomial equations of degree 2 in one variable of type f(x) = ax2 + bx + c = 0 where a, b, c, ∈ R and a ≠ 0. It is the general form of a quadratic equation where 'a' is called the leading coefficient and 'c' is called the absolute term of f (x).

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Answer:

20

Step-by-step explanation:

you add them and divide by how ever many you added

The height of the cylinder is 27 yards.

To find the height of a cylinder, we need to use the formula V = πr^2h, where V is the volume, π is the constant pi (3.14), r is the radius, and h is the height.

In this problem, we know the radius is 5 yards, and the volume is 1,177.5 cubic yards. We can rearrange the formula to calculate the height as h = V / (πr^2). Substituting the given values into the equation, we get: h = 1177.5 / (3.14 * 25) = 27 yards. Therefore, the height of the cylinder is 27 yards.

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According to the given information, the function g(x) that represents a horizontal stretch of 3 on f(x) = 2x is [tex]\rm g(x) = \frac{2}{3}x$[/tex]. Thus, option A is correct.

A functiοn is a relatiοn between a set οf inputs and a set οf pοssible οutputs, with the prοperty that each input is related tο exactly οne οutput.

Tο create a hοrizοntal stretch οf 3 οn the functiοn f(x) = 2x, we can replace x in the functiοn with x/3, which will cause the οutput tο take three times the input value. This gives us the functiοn:

[tex]$$ g(x) = f\left(\frac{x}{3}\right) = 2\left(\frac{x}{3}\right) = \frac{2}{3}x $$[/tex]

Therefore, the function g(x) that represents a horizontal stretch of 3 on f(x) = 2x is [tex]g(x) = \frac{2}{3}x$.[/tex]

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Complete question:

Create a stretch of 3 on function f(x) = 2x to make g(x)

[Group of answer choices]

a. [tex]\rm g(x) = \tfrac{2}{3}x$[/tex]

b.  [tex]\rm g(x) = \tfrac{3}{2}x$[/tex]

c.  [tex]\rm g(x) = {2}x^3$[/tex]

d. [tex]$\rm g(x) = \sqrt[3]{{2}x} $[/tex]

The image of the point after the reflection is (-3, -6).

To reflect a point across the y-axis, we simply negate its x-coordinate while keeping the y-coordinate the same.

Thus, the image of point (3, -6) reflected across the y-axis would be (-3, -6).

We can visualize this by drawing a line passing through the point (3, -6) and the y-axis.

The reflection of the point will be at the same distance from the y-axis but on the opposite side.

So, the reflection of the point (3, -6) across the y-axis is (-3, -6).

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Answer:

To recoup the cost of buying 200 canned drinks, Jack needs to make a profit of zero, meaning that the revenue from selling the drinks needs to equal the cost of buying them.

Let's start by setting the profit equation equal to zero and solving for x:

0 = 1.25x - 100

1.25x = 100

x = 80

Therefore, Jack needs to sell 80 cans of drinks to recoup the cost of buying 200 canned drinks.

Step-by-step explanation: