A new version of the Medical College Admissions Test (MCAT) was introduced in spring 2015 and is intended to shift the focus from what applicants know to how well they can use what they know. One result of the change is that the scale on which the exam is graded was modified, with the total score of the four sections on the test ranging from 472 to 528. In spring 2015, the mean score was 500.0 with a standard deviation of 10.6.

Required:
What are the median and the first and third quartiles of the MCAT scores?

Answers

Answer 1

Answer:

The median of the MCAT scores was of 500.

The first quartile of MCAT scores was of 492.845.

The third quartile of MCAT scores was of 507.155.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The mean score was 500.0 with a standard deviation of 10.6.

This means that [tex]\mu = 500, \sigma = 10.6[/tex]

Median:

In a normal distribution, the median is the same as the mean, so the median of the MCAT scores was of 500.

First quartile:

This is the 100*(1/4) = 25th percentile, which is X when Z has a pvalue of 0.25. So X when Z = -0.675.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-0.675 = \frac{X - 500}{10.6}[/tex]

[tex]X - 500 = -0.675*10.6[/tex]

[tex]X = 492.845[/tex]

The first quartile of MCAT scores was of 492.845.

Third quartile:

This is the 100*(3/4) = 75th percentile, which is X when Z has a pvalue of 0.75. So X when Z = 0.675.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]0.675 = \frac{X - 500}{10.6}[/tex]

[tex]X - 500 = 0.675*10.6[/tex]

[tex]X = 507.155[/tex]

The third quartile of MCAT scores was of 507.155.


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Answers

Step-by-step explanation:

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Hence our exponential base should be 0.92, indicating exponential decay. (A)

Answer:

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Answers

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Answers

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Answers

Answer:

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Answers

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Answers

Answer:

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Answers

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Step-by-step explanation:

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abcdefghijklmnopqrstuvwxyz

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A orange chew was selected 5 times.
A apple chew was selected 23 times.
A lime chew was selected 18 times.

Based on these results, express the probability that the next chew Kylie removes from the bag will be a flavor other than lime as a decimal to the nearest hundredth.

Answers

Answer:

The probability is 0.609

Step-by-step explanation:

Out of 46 times that the experiment was performed:

A orange chew was selected 5 times.

A apple chew was selected 23 times.

A lime chew was selected 18 times.

We can find the relative frequency of each one of them as the quotient between the number of times that a particular chew was selected, and the total number of chews.

Then for the orange ones we have a relative frequency (that can be thought as the probability) of:

Po = 5/46

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Pa = 23/46

For Lime we get:

Pl = 18/46

We want to find the probability that the next chew Kylie removes from the bag will be a flavor other than lime (so this is equal to the probability of getting orange plus the probability of getting apple):

P = Po + Pa = 5/46 + 23/46 = 0.609

Answer:

0.61

Step-by-step explanation:

Kylie has a bag that contains orange chews, apple chews, and lime chews. She performs an experiment. Kylie randomly removes a chew from the bag, records the result, and returns the chew to the bag. Kylie performs the experiment 46 times. The results are shown below:

A orange chew was selected 5 times.

A apple chew was selected 23 times.

A lime chew was selected 18 times.

Based on these results, express the probability that the next chew Kylie removes from the bag will be a flavor other than lime as a decimal to the nearest hundredth.

The experiment occured 46 times, a flavor other than lime was selected 5+23=28 times.

Probability the next chew will be a flavor other than lime:

\frac{\color{steelblue}{28}}{\color{indianred}{46}}=

46

28

=

\,\,0.608695...

0.608695...

\approx

\,\,0.61

0.61

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Answers

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Answers

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Answer:

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Answers

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Answers

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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