A model rocket is launch from a platform 17 feet high in the initial velocity is 40 ft The path of the rocket is modeled by the equation 16x^2 +40X +17=0 When does the rocket land

Answer:

true

Step-by-step explanation:

.................

Answer:

28.3 (b)

Step-by-step explanation:

To solve circumference, you will need to use the equation C = 2 *pi* r

for this, we will use 3.14 for pi and the radius is 4.5 so this is how we need to solve it

C= 2 pi (4.5)             Solve 2*4.5

C= 9 pi                     Now we input 3.14 for pi and multiply

C= 9(3.14)

C= 28.26                  Now we round to the nearest tenth to get

C=28.3

Answer:

$68

Step-by-step explanation:

=> 20% 0f 340

=> (20/100) * 340

=> (1/5) * 340

=> (340/5) = 68

Sarah spends $68 dollar on transportation.

Thenks and mark me brainliest :)

Answer:

Here is the picture

Step-by-step explanation:

The number lies between x-values 4 and 6 and y-values 6 and 9.

Coordinates are a pair of integers (Cartesian coordinates), or occasionally a letter and a number, that identify a certain place on a grid, often referred to as a coordinate plane.

Given that scatter plot lies in quadrant 1 of a coordinate plane, and the 14 points are plotted in the first quadrant.

We need to find the range of x and y values for this scatter plot.

The x values of the 14 points are given as;

2, 4, 4,1, 5, 5, 5, 5, 6, 6, 7, 8, 9.5, 9.5

The y values of the 14 points are given as;

5, 6, 9, 7.2, 6, 6.8, 8, 9, 7, 8.5, 10, 10.5, 9.5, 11.4

We can conclude that that most of the points are clustered between x-values 4 and 6 and y-values 6 and 9.

Therefore, the points are clustered between the x-values 4 and 6 and y-values 6 and 9.

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The complete question is

Select the correct answer. Scatter plot in quadrant 1 of a coordinate plane. 14 points are plotted at (2, 5), (4, 6), (4, 9), (4.1, 7.2), (5, 6), (5, 6.8), (5, 8), (5, 9), (6, 7), (6, 8.5), (7, 10), (8, 10.5), (9.5, 9.5), and (9.5, 11.4). Between which x-values and y-values does the cluster in this scatter plot lie? A. It lies between x-values 2 and 4 and y-values 4 and 6. B. It lies between x-values 4 and 6 and y-values 9 and 10. C. It lies between x-values 4 and 6 and y-values 6 and 9. D. It lies between x-values 7 and 9 and y-values 10 and 11.

Answer:

1.004728

Step-by-step explanation:

Mark as brainllest

Answer:

1², 2²,3², 4², 5², 6², 7², 8², 9², 10², 11², 12², 13², 14², 15², 16², 17², 18², 19², 20²,........

Each number is multiplied by itself.

Answer:

28 in.

Step-by-step explanation:

Since the right portion of the figure is a square, the unlabeled bottom must be the same as the top or 6 in., therefore just add up the pieces starting on the right side. (5 + 6 + 2 + 5 + 4 + 6 = 28)

Answer:

C. -1

Step-by-step explanation:

I calculated it logically

Answer:

-1

Step-by-step explanation:

cos = opp/hyp

At 180º

adj  = -1

hyp = 1

Cos 180 = -1/1 = -1

Answer:

x = 46°

Step-by-step explanation:

Appling the principle of supplementary angle in Geomentry.

Supplementary angle: These are angles that sum up to 180°

From the diagram above, x and 134° are supplementry because they sum up to 180°.

Therefore,

134+x = 180 (Supplementary angle)

Solve for x

x = 180-134

x = 46°

Therefore, the value of the missing angle is 46°

Answer:

C. 216°

Step-by-step explanation:

I calculated it logically

Answer:

A

Step-by-step explanation:

This can be rearranged as 4^3 * 1/(4^6)

or (4^3)/(4^6)

This can be changed to:

(4^3)/((4^3)*(4^3)

Which is equal to 1/(4^3)

or

4^(-3)

Answer:

[tex]Width = 4ft[/tex]

[tex]Height = 4ft[/tex]

[tex]Length = 8ft[/tex]

Step-by-step explanation:

Given

[tex]Volume = 128ft^3[/tex]

[tex]L = 2W[/tex]

[tex]Base\ Cost = \$9/ft^2[/tex]

[tex]Sides\ Cost = \$6/ft^2[/tex]

Required

The dimension that minimizes the cost

The volume is:

[tex]Volume = LWH[/tex]

This gives:

[tex]128 = LWH[/tex]

Substitute [tex]L = 2W[/tex]

[tex]128 = 2W * WH[/tex]

[tex]128 = 2W^2H[/tex]

Make H the subject

[tex]H = \frac{128}{2W^2}[/tex]

[tex]H = \frac{64}{W^2}[/tex]

The surface area is:

Area = Area of Bottom + Area of Sides

So, we have:

[tex]A = LW + 2(WH + LH)[/tex]

The cost is:

[tex]Cost = 9 * LW + 6 * 2(WH + LH)[/tex]

[tex]Cost = 9 * LW + 12(WH + LH)[/tex]

[tex]Cost = 9 * LW + 12H(W + L)[/tex]

Substitute: [tex]H = \frac{64}{W^2}[/tex] and [tex]L = 2W[/tex]

[tex]Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)[/tex]

[tex]Cost =18W^2 + \frac{768}{W^2}*3W[/tex]

[tex]Cost =18W^2 + \frac{2304}{W}[/tex]

To minimize the cost, we differentiate

[tex]C' =2*18W + -1 * 2304W^{-2}[/tex]

Then set to 0

[tex]2*18W + -1 * 2304W^{-2} =0[/tex]

[tex]36W - 2304W^{-2} =0[/tex]

Rewrite as:

[tex]36W = 2304W^{-2}[/tex]

Divide both sides by W

[tex]36 = 2304W^{-3}[/tex]

Rewrite as:

[tex]36 = \frac{2304}{W^3}[/tex]

Solve for [tex]W^3[/tex]

[tex]W^3 = \frac{2304}{36}[/tex]

[tex]W^3 = 64[/tex]

Take cube roots

[tex]W = 4[/tex]

Recall that:

[tex]L = 2W[/tex]

[tex]L = 2 * 4[/tex]

[tex]L = 8[/tex]

[tex]H = \frac{64}{W^2}[/tex]

[tex]H = \frac{64}{4^2}[/tex]

[tex]H = \frac{64}{16}[/tex]

[tex]H = 4[/tex]

Hence, the dimension that minimizes the cost is:

[tex]Width = 4ft[/tex]

[tex]Height = 4ft[/tex]

[tex]Length = 8ft[/tex]

9514 1404 393

Answer:

  3.  2n - 4 = 7(n + 8)

Step-by-step explanation:

Two times a number is 2n. Four less than 2n is (2n-4). The sum of a number and 8 is (n+8). Seven times that sum is 7(n+8). The statement says these values are equal:

  2n -4 = 7(n +8)

Answer:

98000

Step-by-step explanation:

sum of observations

no. of observations

50+55+58+90+58+92+99 502

7 7

awnser is 71.7

72 / 8 - 2 x 3 + 1 equals 1

(72 / 8) - 2 x 3 + 1 equals 4

72 / (8 - 2) x 3 + 1 equals 37

72 / (8 - 2) x (3 + 1) equals 48

Following Add-On Contains the content I think your doing:

The expressions are arranged in ascending order will be 72÷8−2×(3 + 1) > (72÷8)−2×3+1 > 72÷(8−2)×3+1 > 72÷(8−2)×(3+1).

It is the order of the numbers in which a smaller number comes first and then followed by the next number and then the last number will be the biggest one.

The expressions are given below:

72÷8−2×(3 + 1), (72÷8)−2×3+1, 72÷(8−2)×3+1, 72÷(8−2)×(3+1)

Simplify the expression, then we have

72÷8−2×(3 + 1), (72÷8)−2×3+1, 72÷(8−2)×3+1, 72÷(8−2)×(3+1)

9−2×4, 9−6+1, (72÷6)×3+1, (72÷6)×4

1, 2, 37, 48

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Answer:

x=3

Step-by-step explanation:

y=-x+3

0=-x+3

x=3

Answer:

the volume is 600

Step-by-step explanation:

15*8*5=600

v=w*h*l

Answer:

y=-4x

Step-by-step explanation:

Answer:

It would take 4 years. The formula for continuously compounded interest is: where P is the principal, r is the interest rate as a decimal number, and t is the number of years.

Step-by-step explanation:

You deposit $800 in an account that pays 3.6% annual interest compounded quarterly. after 11 years your balance first exceed $1200.

If n is the number of times the interested is compounded each year, and 'r' is the rate of compound interest annually, then the final amount after 't' years would be:

[tex]a = p(1 + \dfrac{r}{n})^{nt}[/tex]

You deposit $800 in an account that pays 3.6% annual interest compounded quarterly.

[tex]a = p(1 + \dfrac{r}{n})^{nt}[/tex]

[tex]1200 = 800(1 + \dfrac{3.6}{4})^{4t}\\\\300 = (1 + 0.9)^{4t}\\\\t = 11.4[/tex]

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Answer:

I think its

ai. fx-f3

ii. 5gx

Answer:

this whole sentence confused me a lot

Step-by-step explanation:

yes there is, but it depends on how you want to do it

Answer:

I don't really get what you're implying can you please explain?

Step-by-step explanation:

haha this just really confused me :)

Answer:

80 cups

Step-by-step explanation:

1 gallon = 128 oz

5x128= 640 oz

640/8=80

Answer:

16

Step-by-step explanation:

The  following is closest to the distance that the tip of the hand travels as it moves from 12 to 4 should be considered as the 16 cm.

Since the minute hans on the clock shown below has a length of 7.5 cm

And, the tip of the hand travels as it moves from 12 to 4

So,

For full rotation it should be like [tex]2\pi[/tex] radians

Since angle turned by minute hand in 5 minutes so it should be like [tex]= 2\pi \div 12[/tex] radians

So

[tex]= 7.5 \times 2.094[/tex]

= 15.7 cm

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Answer:

Da Answer is Suppose that two investors A and B have exhibited the indifference probabilities as shown in table below. Indifference probability Investor A Investor B Net return (RM) -2000 0 0 - 1000 0.70 0.10 0 0.80 0.20 1000 0.85 0.30 2000 0.90 0.50 3000 0.95 0.60 4000 1.00 1.00 a) Determine the utility value (for each monetary value) for each investor and fill it in table above. b) Graph the utility functions for both investors and categorize each investor as either a risk- averse person or a risk seeker. c) Suppose that investor A has the chance to invest in one of two ventures. Venture I can produce a net return of RM3000 with probability 0.40 or a net loss of RM1000 with probability 0.60. Venture II can produce a net return of RM2000 with probability 0.60 and no return with probability 0.40. Based on utility function in (b), use the expected utility criterion to determine the venture investor A should select. What is the expected monetary value associated with the selected venture?

Step-by-step explanation:

LESSSSSSS GOOOOOOOOOO

Answer:

15/5

Step-by-step explanation:

because 7.5 ÷ 4.5 = 1.66667

5 ÷ 3 = 1.66667

and 45 ÷ 27 = 1.66667

but 15 ÷ 5 = 3 therefore it's the off one out.

Answer:

F. None of the above.

Step-by-step explanation:

Let the null and alternate hypothesis be

H0: p1 ≥ p2 against the claim Ha: p1 < p2

the significance level is 0.1

The critical region is z < z∝= 1.28

The test statistic is

Z= ( p^1-p^2)- (p1-p2)/√p1^q1^/n1 + p2^q2^/n2

Here n1= 45 ,   n2= 75

         p1= 0.12         p2= 0.14

         q1= 0.88        q2= 0.86

z= 0.12- 0.14/√0.12*0.88/45 +0.14*0.86/75

Z=  0.02/ √0.00235 + 0.00161

Z=  0.02/0.062891

z= 0.318

The calculated value of z= 0.318  lies in the critical region z < 1.28

therefore accept Ha.

All of the options are incorrect as the critical value for one tailed test for 0.1 is 1.28 .

Answer:

a.

Approximately [tex]24.7\; \rm in[/tex].

b.

While there are three diagonals in a box (a rectangular prism,) all three diagonals goes through the same point- the centroid of this box.  

For a maximum-length poster to fit in this box, it would have to be on one of the main diagonals of this box. Hence, any maximum-length poster that fits in this box would go through the centroid of this box.

It's not possible to force more than one posters to go through the same point (i.e., the centroid) in space. Hence, it would not be possible to fit a second maximum-length poster into this box.

This argument does not apply to  [tex]21.5\; \rm in[/tex] posters. These posters are shorter than the diagonal of this box; they could fit inside the box without having to go through a particular point in space.

Step-by-step explanation:

The longest poster that could be fit into this box (a rectangular prism) would be as long as the longest line segment in this box. That line segment would be one of the three diagonals of this box.

Apply the Pythagorean theorem twice to find the length of that diagonal.

Start by finding calculating the diagonal of the base of this box. The base of this box is a rectangle with width [tex]8\; \rm in[/tex] and length [tex]10\; \rm in[/tex]. The length of its diagonal would be [tex]\sqrt{8^2 + 10^2}[/tex] inches.

Combine that with the height of this box to find the length of the diagonal of this box.

[tex]\begin{aligned}& \sqrt{{\left(\sqrt{8^2 + 10^2}\right)}^2 + 12^2 \\ &= \sqrt{8^2 + 10^2 + 12^2} \\ &\approx 24.7 \end{aligned}[/tex].