A marble is placed at the bottom of a semi-spherical bowl, as shown in the figure. The marble is then displaced from the bottom of the bowl to a position about halfway from the top of the bowl. The marble is then released from rest such that the marble always remains in contact with the bowl. Students observe that the marble rolls back and forth as it oscillates about the bottom of the bowl. Which of the following statements best explains why the marble undergoes oscillatory motion?
a)The sides of the bowl become steeper at positions farther from the bottom of the bowl.b) The net force exerted on the marble always has a component directed toward the bottom of the bowl. c) The normal force exerted on the marble decreases with increasing distance from the bottom of the bowl. D ) The gravitational force exerted on the marble is constant in magnitude and direction.
Answers
Answer:
It is D
Explanation:
The explanation why the marble undergoes oscillatory motion should be option D.
What is oscillatory motion?An object should be classified as the motion oscillates related to an equilibrium position because of the restoring force or torque. This motion should be significant to study various phenomena like electromagnetic waves, molecules. etc. In the case when the gravitational force should be exerted on the marble here the magnitude and the direction should be the same.
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Related Questions
The magnetic field due to a utility wire is 0.10 mT when you are at a distance of 10 meters from it. What current (in Amperes) flows through the wire?
Answers
Answer:
I = 5000 A
Explanation:
We will use Ampere's Law to calculate the current:
[tex]B = \frac{\mu I}{2\pi r}\\\\[/tex]
where,
B = Magnetic Field Strength = 0.1 mT = 1 x 10⁻⁴ T
μ = Permeability of Free Space = 4π x 10⁻⁷ N/A²
I = Current = ?
r = radius = 10 m
Therefore,
[tex]1\ x\ 10^{-4}\ T = \frac{(4\pi\ x\ 10^{-7}\ N/A^2)(I)}{2\pi(10\ m)}\\\\I = \frac{(1\ x\ 10^{-4}\ T)(2\pi (10\ m))}{4\pi\ x\ 10^{-7}\ N/A^2}[/tex]
I = 5000 A
State Newton’s Universal Law of Gravitation.
Answers
Answer:
This law states that every particle attract every other particle in the universe with a force that is directly proportional to the product of their mass and inversely proportional to the square of the distance between the center
A woman has one damaged fallopian tube. The damage completely blocks the opening of the tube at the ovary. How will this most likely affect her fertility?
Her likelihood of conceiving will be reduced by at least 50%.
Her eggs, if fertilized, will not implant properly.
Her eggs will not mature inside the ovary.
Her chances of conceiving twins will be doubled.
Answers
Answer:Her likelihood of conceiving will be reduced by at least 50%.
Explanation:
EDGE 2020
Answer:
Her likelihood of conceiving will be reduced by at least 50%
Explanation:
took the test on edge, got it right
: A small block with mass 0.130 kg is attached to a string passing through a hole in a frictionless, horizontal surface. The block is originally revolving in a circle with a radius of 0.800 m about the hole with a tangential speed of 4.00 m/s. The string is then pulled slowly from below, shortening the radius of the circle in which the block revolves. The breaking strength of the string is 30.0 N. What is the radius of the circle when the string breaks
Answers
Answer:
r = 0.0173 m = 1.73 cm
Explanation:
Here, the centripetal force of the block will be providing the required breaking tension in the string:
[tex]Tension = Centripetal Force\\T = F_c\\\\T = \frac{mv^2}{r} \\\\r = \frac{mv^2}{T}\\[/tex]
where,
r = radius = ?
m = mass of block = 0.13 kg
v = tangential spee of block = 4 m/s
T = Breaking Strength = 30 N
Therefore,
[tex]r = \frac{(0.13\ kg)(4\ m/s)^2}{30\ N}[/tex]
r = 0.0173 m = 1.73 cm
When finding the radius of the string at the point it breaks, the tangential
velocity is assumed to be constant.
The radius when the string breaks is [tex]\underline{6.9 . \overline 3 \times 10^{-3}} \ m[/tex]Reasons:
The mass of the small block, m = 0.130 kg
Initial radius of the circle of rotation = 0.800 m
Tangential velocity, v = 4.00 m/s
The radius of the path of rotation is reduced as the string is pulled
Breaking strength of the string = 30.0 N
Required:
The radius of the circle when the string brakes
Solution:
[tex]Centripetal \ force = \dfrac{m \cdot v^2}{r}[/tex]
Where;
r = The radius of the circle of rotation
When the string brakes, w have;
Centripetal force = Breaking strength of the string = 30.0 N
Which gives;
[tex]\displaystyle r = \mathbf{\dfrac{m \cdot v^2}{Centrifugal \ force}} = \frac{0.130 \times 4^2}{30} =6.9\overline 3 \times 10^{-2}[/tex]
The radius of the circle when, the string breaks r = [tex]\underline{6.9\overline 3 \times 10^{-2}} \ m[/tex]
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Question 1 of 10 Which characteristic of nuclear fission makes it hazardous?
O A. The process destroys every atomic nucleus that goes through it.
O B. The process changes existing atoms into atoms of different elements
C. The process requires very high pressures.
O D. The radioactive wastes it produces can spread to any part of the environment
Answers
Answer:
D.
The radioactive wastes it produces can spread to any part of the environment.
Explanation:
Fission is the name given to the splitting of a heavy nucleus into two medium-mass nuclei. Fission is said to be induced if it results from the absorption of a neutron to form an unstable nucleus that decays by fission. The induced fission usually produces further neutrons accompanying the fission fragments.
Answer: D. The radioactive wastes it produces can spread to any part of the environment
Explanation:
A 67.0 kg person is riding in a car moving at 19.0 m/s when the car runs into a bridge abutment. (Assume the initial velocity is in the positive direction.) (a) Calculate the average force (in N) on the person if he is stopped by a padded dashboard that compresses an average of 1.00 cm. (Indicate the direction with the sign of your answer.) N (b) Calculate the average force (in N) on the person if he is stopped by an air bag that compresses an average of 15.0 cm. (Indicate the direction with the sign of your answer.) N
Answers
Answer:
a) F = - 1.21 10⁶ N, b) F = - 8.06 10⁴ N
Explanation:
a) For this part let's use the kinematics relations
v² = v₀² - 2 a x
distance traveled to stop is x = 1.00 cm = 0.0100 cm, final speed is zero
0 = v₀² - 2 ax
a = v₀² / 2x
a = [tex]\frac{19^2 }{2 \ 0.01}[/tex]
a = 1.81 10⁴ m / s²
this acceleration is in the opposite direction to velocity
let's use Newton's second law
F = ma
F = 67.0 (-1.81 10⁴)
F = - 1.21 10⁶ N
the negative sign indicates that it is going in the opposite direction to the speed
b) in this case it is stopped by an airbag x = 15.0 cm = 0.15 m
a = v₀² / 2x
a = [tex]\frac{19^2}{2 \ 0.15}[/tex]
a = 1.203 10³ m / s²
calculate the force
F = m a
F = 67.0 (- 1.203 10³)
F = - 8.06 10⁴ N
Select the correct answer.
Which graph shows the correct relationship between kinetic energy and speed?
Answers
Answer:
D
Explanation:
Kinetic energy = 1/2mV^2
From the formula above, we can deduce that kinetic energy is proportional to the square of speed. That is,
K.E = V^2
Graphically, the relationship isn't linear but a positive exponential. Therefore, option D is the correct answer.
Answer:
Its D
Explanation:
1.A body of mass 10kg falling freely was found to be falling at a rat of 20m/s what force will stop the body in 2second?
Answers
Answer:
50N
Explanation:
force it is falling with can be found by mass into acceleration and then devide by half to find force that could stop it in 2 sec
Before we make measurements, let's make sure we understand the circuit. 1. Select all of the following that correctly describe what a volt meter and ammeter measure. Select all that apply: A volt meter measures the potential difference (or voltage) across a circuit element. A volt meter measures the potential difference (or voltage) passing through a circuit element. A ammeter measures the electric current passing through a circuit element. A ammeter measures the electric current across a circuit element.
Answers
Answer:
the correct answers are a and c
Explanation:
In an electrical circuit there are two important quantities to measure, such as voltage and current.
Voltage is the potential difference between two points in a circuit
current is the number of electrons you pass through a given point per unit of time.
Now let's analyze each answer
a) true. The potential difference across an element
b) False. The potential difference is u field there is no physical entity that moves
c) True. The current is electrons in motion and these pass through the given element
d) False. There is a physical quantity that passes through the point
the correct answers are a and c
An ideal horizontal spring-mass system is set into motion. At an instant when the mass passes through its equilibrium position: The potential energy in the spring is at its _____. The kinetic energy of the mass is at its ______. The magnitude of net force acting on the mass is at its ______.
Answers
Answer:
the potential energy is zero, and the kinetic energy must be maximum
F = 0
Explanation:
In this exercise you are asked to complete the sentences of a simple harmonic movement of a mass-spring system.
In this system mechanical energy is conserved
at the most extreme point the carousel potential energy is
K_e = ½ k x²
the kinetic energy is zero for that stopped.
At the equilibrium point
the spring elongation is x = 0 so the potential energy is zero
and the kinetic energy must be maximum since total energy of the system is conserved
the spring force is
F =- k x
as in the equilibrium position x = 0 this implies that the force is also zero
F = 0
In this exercise we have to use the knowledge of force to calculate the energy of a spring, in this way we find that:
The potential energy in the spring is at its [tex]K_e = 1/2 k x^2[/tex]. The kinetic energy of the mass is at its zero . The magnitude of net force acting on the mass is at its Zero.
In this system mechanical energy is conserved, at the most extreme point the carousel potential energy is:
[tex]K_e = 1/2 k x^2[/tex]
The kinetic energy is zero for that stopped or when at the equilibrium point, so:
the spring elongation is x = 0 so the potential energy is zero the kinetic energy must be maximum since total energy of the system is conserved
the spring force is:
[tex]F =- k x\\F=0[/tex]
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sinat
Accelerationa
2 2.84
7 34
TABLE
in Elination
t2 t3 T2 2
1=0.04
2.29 1.25 1.28 1.271.61
2 460 = 0.00 4.59 1.16 1.081.12 1-25
3 so = 0.12 6.89 0.88
097 0.53
4. = 0.16 9.210.8
9.21 0.850.796. 82/0.67
(So
0.72 0.77 0.75 l 0-56/
0.28
49. al
27. 49
13 11%.
41. 2L
= 0.2 11.54
Answers
Answer:
so you have a question
Explanation:
either way,you have a nice day
A 5kg block rests on a 30° incline. The coefficient of static friction between the block and the incline is 0.20. How large a horizontal force must push on the block if the block is to be on the verge of sliding. a) up the incline, b) down the incline ?
Answers
Answer:
Hope It Help
Explanation:
That's all I know
What could we call the
grocery store?
A. Linear motion
B. Reference point
C. Rotary
Answers
Reference point
Explanation:
I am not sure
What are the issues that hinders efforts to achieve sustainability?
Answers
Answer:
who will solve environmental problems, who is responsible for environmental problems, and who pays the cost of implementing solutions
Explanation:
1 kg block slides down a frictionless inclined plane that makes an angle of 300 with respect to the ground. The total length of the plane is 2 m, but midway down it collides with a second block, weighing 0.5 kg. The two blocks stick together and travel as one unit the rest of the way down the ramp. What is the kinetic energy of the combined 1.5 kg block when it reaches the bottom of the plane
Answers
Answer:
the kinetic energy of the combined 1.5 kg block when it reaches the bottom of the plane is 10.62 J
Explanation:
Given that the data in the question;
angle of inclination with respect to the ground [tex]\theta[/tex] = 30°
length of plane d = 2m
m₁ = 1 kg
m₂ = 0.5 kg
now, velocity of the first block at midpoint;
[tex]\frac{1}{2}[/tex]mv² = mgsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex]
[tex]\frac{1}{2}[/tex]v² = gsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex]
v² = gsin[tex]\theta[/tex]d
v = √( gsin[tex]\theta[/tex]d)
g is 9.8 m/s
so we substitute
v = √( 9.8 × sin30° × 2)
v = √( 19.6 )
v = 3.13 m/s
Now, velocity just after collision of the blocks will be;
(m₁ + m₂)v₂ = m₁v
v₂ = m₁v / (m₁ + m₂)
we substitute
v₂ = (1 × 3.13) / (1 + 0.5)
v₂ = 3.13 / 1.5
v₂ = 2.0866 m/s
now, final kinetic energy will be;
[tex]KE_f[/tex] = (m₁ + m₂)gsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex] + Initial Kinetic energy
[tex]KE_f[/tex] = (m₁ + m₂)gsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex] + [tex]\frac{1}{2}[/tex]mv₂²
we substitute
[tex]KE_f[/tex] = [(1 + 0.5)9.8 × sin30 × [tex]\frac{2}{2}[/tex]] + [[tex]\frac{1}{2}[/tex] × 1.5 × 2.0866 ]
[tex]KE_f[/tex] = 7.35 + 3.2654
[tex]KE_f[/tex] = 10.62 J
Therefore, the kinetic energy of the combined 1.5 kg block when it reaches the bottom of the plane is 10.62 J
Speed and time play a major factor in:
Scrimmage
Tactical movement
Situation awareness
Drill
Answers
Answer:
Tactical movement
Explanation:
Speed and time play a significant factor in Tactical movement. The correct option is B.
What is a Tactical movement?Tactical movement refers to the coordinated and strategic movement of military units or teams to achieve a specific objective. It is a fundamental aspect of military operations and involves the use of various tactics and techniques to move troops and equipment safely and efficiently on the battlefield.
Tactical movement can involve various modes of transportation, such as on foot, in vehicles, or by air. It also involves the use of cover and concealment to avoid detection by the enemy, and the use of communication and signal systems to coordinate movements and maintain situational awareness.
The success of the tactical movement depends on many factors, including the terrain and weather conditions, the size and composition of the units involved, the available resources and equipment, and the tactics and strategies employed by both friendly and enemy forces. It requires careful planning, training, and execution to ensure that the movement is successful and achieves the desired outcome.So, tactical movement is an essential component of military operations, and plays a critical role in achieving victory on the battlefield.
Here in the Question,
Tactical movement refers to the movement of military units or teams in a coordinated and strategic manner to achieve a specific objective. In such movements, speed and time are critical factors because they determine the success or failure of the mission. The speed of movement can help to surprise the enemy, take advantage of a weakness in their defense, or seize a key position before they can respond. Time is also important because the longer it takes to achieve the objective, the more likely the enemy is to detect and counter the movement. Therefore, tactical movement requires careful planning and execution to ensure that the right units move at the right speed and at the right time to achieve the desired outcome.
Therefore, the correct option is B i.e Tactical movement.
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A house is lifted from its foundations onto a truck for relocation. The house is pulled upward by a net force of 2850 N. This force causes the house to move from rest to an upward speed of 15 cm/s in 5.0 s. What is the mass of the house?
Answers
Answer:
m = 95000 kg
Explanation:
Given that,
Net force acting on the house, F = 2850 N
Initial speed, u = 0
Final speed, v = 15 cm/s = 0.15 m/s
We need to find the mass of the house. Let the mass be m. We know that the net force is given by :
F = ma
Where
a is the acceleration of the house.
So,
[tex]F=m\dfrac{v-u}{t}\\\\m=\dfrac{Ft}{(v-u)}\\\\m=\dfrac{2850\times 5}{(0.15-0)}\\\\m=95000\ kg[/tex]
So, the mass of the house is equal to 95000 kg.
If the radius of the Earth is 6400.0 km and the atmosphere is 10.0 km high, then the volume of air around the Earth is what?
Answers
Answer:
5.16 x 10^18 m^3
Explanation:
Two scientists are experimenting with pure samples of isotope X, a highly radioactive substance. The first scientist has a sample with a mass of 20 grams. He measures a half-life of 232 seconds. The second scientist has a sample of the same substance with a mass of 80 grams. What is the half-life that she is most likely to measure?
Answers
Answer:
Half-life does not depend on sample size, only on the constituents of the sample.
The second scientist should also observe a half-life of about 232 sec or 40 grams of X remaining after 232 sec.
Answer:
As it is the same substance, the half life will remain at 232 seconds.
Explanation:
Verified with correct test results.
What do microwaves have In common with light waves?
Answers
Answer:
Both are electromagnetic waves
Explanation:
Hope this helped!!
1. You are given a bottle that contains 4.59 cm of a metallic solid. The total mass of the bottle
is 35.66 g. The empty bottle weighs 14.23 g. What is the density of the solid?
Answers
A wave has a frequency of 30Hz and wave length of 40cm. What is the velocity of the wave?
Answers
Answer:
12m/s
Explanation:
v=fλ
30×(40÷100)=
12m/s
A molecule with a charge of 9 x 10-8 C is moving with a velocity of 7 x 107 m/s perpendicular to a magnetic field with a value of 0.57 Tesla. What is the magnitude force (in N) on the molecule?
Answers
Answer:
3.591 N
Explanation:
Applying,
F = Bvq................. Equation 1
Where F = magnitude of force on the molecule, B = Magnetic field, v = Velocity of the molecule, q = charge of the molecule.
From the question,
Given: B = 0.57 Tesla, q = 9×10⁻⁸ C, v = 7×10⁷ m/s
Substitute these values into equation 1
F = 0.57×9×10⁻⁸×7×10⁷
F = 35.91×10⁻¹
F = 3.591 N
Hence the force on the molecule is 3.591 N
Why do astronomers use frequencies other than the visible ones when they are
investigating the universe?
Answers
Which has the least gravitational force?
Answers
Answer: Mount Nevado Huascarán
Explanation: Mount Nevado Huascarán in Peru has the lowest gravitational acceleration, at 9.7639 m/s2, while the highest is at the surface of the Arctic Ocean, at 9.8337 m/s2
Please Help!!!
For A&B
Answers
Answer:
A. 40N
B. 5m/s
Explanation:
A.
Impulse is equal to the area under the curve of a force vs. time graph. In this case, the area is in the shape of a triangle with base 8 (12-4=8) and perpendicular height 10:
Area of a triangle = (1/2)bh
A=(1/2)*8*10
=40
ANSWER: 40N
B.
Impulse = mass * velocity
40 = 8v
v = 5
ANSWER: 5m/s
HELP PLEASEE
when a person receives an electric shock from wires , is he most affected by a spark, corona, arc or humus solution?
Answers
Answer:
Usually an eletric shock. You can be left with numbness and MAYBE problems with your eyes.
Explanation:
Philosophy: The Big Picture Unit 8
Would an existentialist argue that the study of philosophy was a good use of a life?
A. Yes, if society valued the results of the study.
B. Yes, but only if the individual found it meaningful.
C. No, a life should be spent minimizing the role of anxiety.
D. No, there is no way that philosophy could create a meaningful life.
Answers
120CD 165
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Answers
Give the relationship between the number of valence electrons in an atom's
valence electron shell and the position of the element on the Periodic Table
Answers
Answer:
they're reactions
Explanation:
The relationship between the valence electrons and position is: the number of valence electrons determines the position
What is valence electron?This is the number of electrons in the outermost shell of an atom.
NOTE: The outermost shell is called valence shell
Position in Periodic tableThis is where an element is located in the periodic table
Relationship between valence electrons and positionThe position of an element in the periodic table is determined by the number of valence electrons.
For example
Sodium, Na (atomic number of 11) has the following electronic configuration
1st shell = 2 electrons2nd shell = 8 electrons 3rd (valence) shell = 1 electronSince the valence electron is 1, thus, sodium is located in group 1 of the periodic table.
Thus, we can see that the position of an element in the periodic table is related to the valence electron(s) in the atomic shell of the element.
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