Answer:
1408 packs
2 pens left over
Step-by-step explanation:
5634 / 4 = 1,408.5
half a pack is 2 pens
1408 packs
2 pens left over
Please help soon- The weight of oranges growing in an orchard is normally distributed with a mean
weight of 6 oz. and a standard deviation of 1 oz. From a batch of 2500 oranges, how
many would be expected to weight less than 4 oz., to the nearest whole number?
Find the exact value of sin A in simplest radical form.
Using the sine rule,
[tex] \frac{a}{sin(a)} = \frac{b}{sin(b)} = \frac{c}{sin(c)} [/tex]
Here we are going to use the values of A and C,
[tex] \frac{12}{sin(a)} = \frac{14}{sin(90)} \\ \frac{12}{sin(a)} = \frac{14}{1} \\ sin(a) = 12 \div 14 \\ sin(a) = 0.8571[/tex]
So sin(A) = 12/14 = 6/7 = 0.8571, but since the question says in its simplest radical form, I think the closest answer to it should be
[tex] \frac{ \sqrt{3} }{2} [/tex]
which expression defines function h?
Answer:
[tex]h(x) = (\frac{f}{g})(x)[/tex]
Step-by-step explanation:
Given
[tex]f(x) = 3x^3 + 9x^2 -12x[/tex]
[tex]g(x) = x - 1[/tex]
[tex]h(x) = 3x^2 + 12x[/tex]
Required
What defines h(x)
Looking at the degree of f(x), g(x) and h(x), we have:
[tex]h(x) = (\frac{f}{g})(x)[/tex]
See proof
[tex]h(x) = (\frac{f}{g})(x)[/tex]
This gives:
[tex]h(x) = \frac{f(x)}{g(x)}[/tex]
[tex]h(x) = \frac{3x^3 + 9x^2 -12x}{x - 1}[/tex]
Factorize
[tex]h(x) = \frac{(3x^2 + 12x)(x - 1)}{x - 1}\\[/tex]
[tex]h(x) = 3x^2 + 12x[/tex]
The times that a cashier spends processing individual customers' orders are independent random variables with mean 3.5 minutes and standard deviation 3 minutes. Find the number of customers n such that the probability that the orders of all n customers can be processed in less than 2 hours, is approximately 0.1. (Round your answer to the nearest integer.)
Answer:
26 customers
Step-by-step explanation:
First: determine the z score from standard normal probability table with an indicative area of 0.1
Z-score from probability table = - 1.28
mean = 3.5 minutes
std = 3 minutes
next determine the Z-score based on the information given in the question
Z = ( std - mean ) / processing time
= ( 3 - 3.5 ) / 2 = -0.25
Finally determine the number of customers
N = [tex](\frac{-1.28}{-0.25} )^2[/tex] = 1.6384 / 0.0625 = 26.21 ≈ 26 customers
How much is three times two
Answer:
the answer is 6.
Step-by-step explanation:
Answer:
6.
Step-by-step explanation:
3+3=6 = 2×3=6
you can do draw 3 circles 2 times and add it all together.
The scatter chart below displays the residuals verses the dependent variable, x. Which of the following conclusions can be drawn based upon this scatter chart? a. The residuals are normally distributed. b. The model over predicts the value of the dependent variable for small values and large values of the independent variable. c. The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship. d. The residuals have a constant variance.
Answer: Hello the scatter plot related to your question is missing attached below is the scatter plot
answer : The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship ( C )
Step-by-step explanation:
The conclusion that can be drawn based upon the scatter chart is that The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship
A scatter plot helps in observing the relationship within different numeric variables but the scatter plot attached fails in the showing the actual relationship
I need this please help me
Answer:
A. Right 6, Down 5
Step-by-step explanation:
I don't know how to explain this
PLSSSSSSSSSSS ASAP!!!!! Find the area of the figure shown below.
Answer:
54 square ft
Step-by-step explanation:
Find missing sides:
8+6 = 14
9-6 = 3
Find area of full rectangle:
9×8 = 72
Find the area of the missing part of the full rectangle
3×6 = 18
Find the area of the actual shape:
72-18 = 54
Area = 54 square ft
Consider the initial value problem my''+cy'+ky=F(t), y(0)=0, y'(0)=0, modeling the motion of a spring mass dashpot system initially at rest and subjected to an applied force F(t), where the unit of force is the Newton (N). Assume that m=2 kilograms, c=8 kilograms per second, k=80 Newtons per meter, and F(t)=20 sin(6t) Newtons.
1. Solve the initial value problem. y(t)=?
2. Determine the long term behavior of the system. Is lim as t goes to infinity of y(t)=0? If it is, enter zero. If not, enter a function that approximates y(t) for very large positive values of t. For very large positive values of t, y(t) is approximately.. ?
Answer:
Hence, the [tex]y(t)=e^{-2 t}\left(\frac{75}{74} \cos 6 t+\frac{75}{148} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t))\end{array}[/tex] and approximately value of [tex]y(t)[/tex] is [tex]-0.844[/tex].
Given :
[tex]my''+cy'+ky=F(t), y(0)=0, y'(0)=0,[/tex]
Where [tex]m=2[/tex] kilograms
[tex]c=8[/tex] kilograms per second
[tex]k=80[/tex] Newtons per meter
[tex]F(t)=20\sin (6t)[/tex] Newtons
Explanation :
(1)
Solve the initial value problem. [tex]y(t)[/tex]
[tex]my''+cy'+ky=F(t), y(0)=0, y'(0)=0,[/tex]
[tex]\Rightarrow 2y''+8y'+80y=20\sin (6t)[/tex]
[tex]\Rightarrow y''+4y'+40y=10\sin (6t)[/tex]
Auxilary equations :[tex]F(t)=0[/tex]
[tex]\Rightarrow r^2+4r+40=0[/tex]
[tex]\Rightarrow r=\frac{-4\pm\sqrt{4^2-4\times 1\times 40}}{2\times 1}[/tex]
[tex]\Rightarrow r=\frac{-4\pm\sqrt{16-160}}{2}[/tex]
[tex]\Rightarrow r=\frac{-4\pm\sqrt{-144}}{2}[/tex]
[tex]\Rightarrow r=\frac{-4\pm12i}{2}[/tex]
[tex]\Rightarrow r=-2\pm6i[/tex]
The complementary solution is [tex]y_c=e^{-2t}\left(c_1\cos 6t+c_2\sin 6t\right)[/tex]
The particular Integral, [tex]y_p=\frac{1}{f(D)}F(t)[/tex]
[tex]y_{y} &=\frac{1}{D^{2}+4 D+40} 25 \sin (6 t) \\\\ y_{y} &=\frac{25}{-6^{2}+4 D+40} \sin (6 t) \quad\left(D^{2} \text { is replaced with }-6^{2}=-36\right) \\\\y_{y} &=\frac{25}{4 D+4} \sin (6 t) \\\\y_{y} &=\frac{25}{4(D+1)} \sin (6 t) \\\\y_{y} &=\frac{25(D-1)}{4(D+1)(D-1)} \sin (6 t) \\\\y_{y} &=\frac{25(D-1)}{4\left(D^{2}-1\right)} \sin (6 t) \\\\y_{y} &=\frac{25(D-1)}{4(-36-1)} \sin (6 t) \\\\y_{y} &=-\frac{25}{148}(D-1) \sin (6 t) \\y_{y} &=-\frac{25}{148}\left(\frac{d}{d t} \sin (6 t)-\sin (6[/tex]
Hence the general solution is :[tex]y=y_c+y_p=e^{-2t}(c_1\cos 6t+c_2\sin 6t)-\frac{25}{148}(6\cos 6t-\sin 6t)[/tex]
Now we use given initial condition.
[tex]y(t) &=e^{-2 t}\left(c_{1} \cos 6 t+c_{2} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\\y(0) &=e^{-\alpha 0)}\left(c_{1} \cos (0)+c_{2} \sin (0)\right)-\frac{25}{148}(6 \cos (0)-\sin (0)) \\\\0 &=\left(c_{1}\right)-\frac{25}{148}(6) \\\\c_{1} &=\frac{75}{74} \\\\y(t) &=e^{-2 t}\left(c_{1} \cos 6 t+c_{2} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\[/tex]
[tex]y^{\prime}(t)=-2 e^{-2 t}\left(c_{1} \cos 6 t+c_{2} \sin 6 t\right)+e^{-2 t}\left(-6 c_{1} \sin 6 t+6 c_{2} \cos 6 t\right)-\frac{25}{148}(-36 \sin (6 t)-6 \cos (6 t)) \\\\y^{\prime}(0)=-2 e^{0}\left(c_{1} \cos 0+c_{2} \sin 0\right)+e^{0}\left(-6 c_{1} \sin 0+6 c_{2} \cos 0\right)-\frac{25}{148}(-36 \sin 0-6 \cos 0) \\\\0=-2\left(c_{1}\right)+\left(6 c_{2}\right)-\frac{25}{148}(-6) \\\\0=-2 c_{1}+6 c_{2}+\frac{75}{74} \\\\0=-2\left(\frac{75}{74}\right)+6 c_{2}+\frac{75}{74} \\\\[/tex][tex]\begin{array}{l}0=-\frac{150}{74}+6 c_{2}+\frac{75}{74} \\\\\frac{150}{74}-\frac{75}{74}=6 c_{2}\end{array}[/tex]
[tex]\begin{array}{l}c_{2}=\frac{25}{148}\\\\\text { Substitute } c_{1} \text { and } c_{2} \text { in } y(t) \text { . Then }\\\\y(t)=e^{-2 t}\left(\frac{75}{74} \cos 6 t+\frac{75}{148} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t))\end{array}[/tex]
(2)
[tex]y(t)=e^{-2 t}\left(\frac{75}{74} \cos 6 t+\frac{75}{148} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\y(t)=\left(\frac{75}{74} e^{-2 t} \cos 6 t+\frac{75}{148} e^{-2 t} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\y(t)=\frac{75}{74}\left(e^{-2 t}-1\right) \cos 6 t+\frac{25}{148}\left(3 e^{-2 t}+1\right) \sin 6 t \\\\|y(t)| \leq \frac{75}{74} e^{-2 t}-1|\cos 6 t|+\frac{25}{148}\left|3 e^{-2 t}+1\right||\sin 6 t| \\\\[/tex]
[tex]|y(t)| \leq \frac{75}{74}\left|e^{-2 t}-1\right|+\frac{25}{148}\left|3 e^{-2 t}+1\right| \\\\\lim _{t \rightarrow \infty} y(t) \leq \lim _{t \rightarrow \infty}\left\{\frac{75}{74}\left|e^{-2 t}-1\right|+\frac{25}{148}\left|3 e^{-2 t}+1\right|\right\} \\\\\lim _{t \rightarrow \infty} y(t)=\left\{\frac{75}{74}\left|\lim _{t \rightarrow \infty}\left(e^{-2 t}-1\right)\right|+\frac{25}{148}\left|\lim _{t \rightarrow \infty}\left(3 e^{-2 t}+1\right)\right|\right\} \\[/tex]
[tex]\lim _{t \rightarrow \infty} y(t)=\left\{\frac{75}{74}(-1)+\frac{25}{148}(1)\right\}=-\frac{75}{74}+\frac{25}{148}=-\frac{-150+25}{148}=-\frac{125}{148} \approx-0.844[/tex]
From the equation below, where is the center of the circle located and what is the radius?
(x – 4)2 + (y + 8)2 = 16
A) Center: (4, -8) Radius = 4
B) Center: (-4, 8) Radius = 4
C) Center: (4, -8) Radius = 16
D) Center: (-4, 8) Radius = 16
Answer:
B Center: (-4, 8) Radius = 4
Step-by-step explanation:
Caroline has a rock stuck in her Jeep’s tire
Answer:
oh no
Step-by-step explanation:
sorry about that I guess
NEED HELP ASAP WILL GIVE BRAINLIEST REAL ANSWERS ONLY PLZ WILL REPORT FAKE ANSWERS
Answer:
The graph has a domain of {x|0 < x < infinite} and approaches 0 as x decreases
The graph has a domain of {y| -infinite < y < infinite} and decreases as x approaches 0.
Step-by-step explanation:
I was confused at first because I was like "There is 2 answers" and I reread the question again and found my mistake.
And sorry for the wait because "I am in class"
Type the integer in the box.
Solve:: t/2 + 10 =-40
Answer:
t = -100
Step-by-step explanation:
Simplify to isolate t:
[tex]\frac{t}{2}+10-10=-40-10[/tex]
[tex]\frac{t}{2} * \frac{2}{1} = -50 * 2[/tex]
[tex]t = -100[/tex]
Simran has a bag containing white and yellow marbles. Simran randomly selects one marble from the bag,
records the result, and returns the marble to the bag. The results of the first 65 selections are shown below.
A white marble was selected 41 times.
A yellow marble was selected 24 times.
Based on these results, what is the probability that the next marble Simran selects, rounded to the nearest
Answer:
d. 63%
Step-by-step explanation:
percent, will be white?
A41% b50% c59% d63%
The probability of white = P (w) = 41/65= 0.63
The probability of yellow = P (y)= 24/65= 0.369=0.37
The probability of choosing white is 0.63 . When rounded to nearest percent gives
0.63*100/100
=0.63*100 percent
= 63 percent
= 63%
the probability of getting the next marble white is the same as the probability of getting a white.
If Bill hiked 6.5 miles at a rate of 10.4 mph, how long did it take him to complete his hike?
Answer:
I think it depends how far bill wants to hike..
Step-by-step explanation:
pls help me loves :((
Answer:
609 m²
Step-by-step explanation:
Area of unshaded:
(6 x 18) + ((13-6) x 7) = 157
Area of overall rectangle:
36 x 28 = 1008
Area of the chunck of rectangle not included:
11 x 22 = 242
Area of shaded:
1008 - 157 - 242 = 609
The scale on a map is 55 cm : 88 km.
If the distance between two cities is 5656 km, how far apart in cm are the two cities on the map?
Answer:
look at the picture i have sent
Answer:
The cities are 35 cm apart in map.
The scale on a map is 5 cm : 8 km.
Step-by-step explanation:
mrk me brainliest please
5% equals what fraction, in lowest terms?
Answer:
1/20
Step-by-step explanation:
According to G0ogle 5 percent equals 1/20 in lowest terms.
Answer:
5% equals 5/100 which is 1/20 in lowest terms.
Step-by-step explanation:
5% is basically equivalent to 5/100. 5/100 in lowest terms is 1/20 since you divide the numerator and denominator by 5.
I hope this helps, have a nice day.
Can someone help me please?
Slope : -2
y - intercept : 3
Equation : y = -2x+3
Answer:
Step-by-step explanation:
Slope: -0.5
Y-Intercept: 3
y = -0.5x+3
This graph shows the altitude of an airplane over time. Which story matches the graph?
A.)The aircraft rose quickly into the air at takeoff, and then it continued at a constant altitude.
B.)The aircraft rose steadily over the entire flight.
C.)The aircraft rose quickly to its maximum height, and then it immediately began going back down toward the grou
D.)The aircraft rose quickly into the air at takeoff, and then it rose slowly for the rest of the flight.
SHOW HINT
Answer:
A.) The aircraft rose quickly into the air at takeoff, and then continued at a constant altitude.:)
Answer:
Omg, thank u so much I am on this question rn on Edulatic and I have 100 Q's and I'm only on Q 45, This Question rly helped me a lot bc it came with the answer. God Bless you!!
There are 50 pennies in a roll. If you have 150 rolls of pennies, how many pennies do you have?
Answer: 7500
Step-by-step explanation:
multiply 150 by 50
1+1 why does my dog not love me?
Answer:
2
Step-by-step explanation:
your dog doesn't love you because it saw what you did. it knows. be cautious around your dog from now on. it knows more than you think and sees all. I'm warning you
Which statement describes whether the function is continuous at x = 2?
O The function is continuous at x = 2 because f(2) exists.
O The function is continuous at x = 2 because lim f(x) exists.
X-2
The function is not continuous at x = 2 because f(2) does not exist.
The function is not continuous at x = 2 because lim f(x) does not equal f(2).
X-2
Answer: (b)
Step-by-step explanation:
Given
The function is given as
[tex]f(x)=\dfrac{x^2-12x+20}{x-2}[/tex]
Solving the function
[tex]f(x)=\dfrac{x^2-2x-10x+20}{x-2}\\\\f(x)=\dfrac{(x-2)(x-10)}{(x-2)}\\\\f(x)=x-10[/tex]
for [tex]x=2[/tex]
[tex]f(2)=2-10\\f(2)=-8[/tex]
The function is continuous at [tex]x=2[/tex] because [tex]\lim_{x \to 2} f(x)[/tex] exists.
If the limit exists at a point, then the function is continuous.
Answer:
on edge its fs not b or c
Step-by-step explanation:
My faces are not all
congruent.
I contain 12 edges.
I contain 6 faces.
Answer:
its a rectangle
Step-by-step explanation:
Please help! im extremely confused
the results of rolling a single die are shown in a table below. find the experimental probability of rolling a 5
number total
1 12
2 16
3 21
4 23
5 18
6 10
Answer:
1/12
Step-by-step explanation:
To find experimental probability you have to solve the Number of times an event occurs / Total number of trials. So since the 5 only appears once and there are 12 numbers, it would be 1/12. Did this help?
The experimental probability of rolling 5 will be 0.18.
What is probability?Its fundamental concept is that someone will nearly surely occur. The proportion of positive events in comparison to the total of occurrences. Then the probability is given as,
P = (Favorable event) / (Total event)
The table is given below:
Number Total
1 12
2 16
3 21
4 23
5 18
6 10
The experimental probability of rolling a 5 is calculated as,
P = 18 / (12 + 16 + 21 + 23 + 18 + 10)
P = 18 / 100
P = 0.18
Thus, the probability is 0.18.
More about the probability link is given below.
https://brainly.com/question/795909
#SPJ2
What is the expanded form of 8,609?
A 8,000+600+ 90
8,000+60+9
8,000 +900+ 6
8,000+600 +9
The last one 8,000 + 600 + 9
a cylinder has a diameter of 12 and height of 12. the volume of the cylinder is:
A. 1728π cubic units
B. 288π cubic units
C. 144π cubic units
D. 432π cubic units
Find the perimeter of a rectangle with a base of 12 ft and a height of 5 ft.
Answer:
P=34ft
Step-by-step explanation:
Solution
P=2(l+w)=2·(12+5)=34ft
15) Find the product. Show all your work.
Reduce all your answers into simplest
form
3 - x
5
л |N
Answer:
[tex]\frac{3}{2}[/tex]
Step-by-step explanation:
3 [tex]\frac{3}{4}[/tex] x [tex]\frac{2}{5}[/tex]
[tex]\frac{15}{4}[/tex] x [tex]\frac{2}{5}[/tex]
[tex]\frac{30}{20}[/tex] = [tex]\frac{3}{2}[/tex]
or another way
[tex]\frac{15}{4}[/tex] x [tex]\frac{2}{5}[/tex]
[tex]\frac{3}{2}[/tex] x [tex]\frac{1}{1}[/tex] = [tex]\frac{3}{2}[/tex]
What is the degree measure of FEG?
A 20°
B 31°
C 56°
D
124°
Answer:
C) 56
Step-by-step explanation:
DEG and FEG are on a straight line forming 180 degree.
Set your formula up as
180 = (3x+31)+(2x-6)
180 = 3x +2x +31 - 6
180 - 31 + 6 = 5x
155 = 5x
155/5 = x
31 = x
Now substitute 31 in place of x
FEG = (2*31-6)
FEG = 56