These are the coordinates of a
quadrilateral. Determine whether it is
also a trapezoid, parallelogram, or
neither.
J(5,5), K(8,6), L(9,9), M(6,8)
A. trapezoid
B. parallelogram
C. neither
Answer:
parallelogram is the answer
Answer:
Step-by-step explanation:
The quadrilateral is a parallelogram ( more precisely is the rhombus )
20 Points Please Help
Under his cell phone plan, Jonathan pays a flat cost of $57 per month and $3 per gigabyte. He wants to keep his bill at $71.10 per month. Write and solve an equation which can be used to determine xx, the number of gigabytes of data Jonathan can use while staying within his budget.
Answer:
(71.10-57)/3=amount of gigabytes, 14.10/3=4 gigabytes allowed
Step-by-step explanation:
$71.10-$57=$14.10, the amount of money that Jonathan can spend on gigabytes. Then, determine how many times 3 can go into 14.10: 4 times. Jonathan can use four gigabytes and keep his bill under $71.10 a month.
What is the probability for a bowler to score over 136? The mean for the set is 130, and the standard deviation is 3. So I know that it is Mean + 2(Standard Deviation), so is it 2.35% or 2.5%?
Answer:
135%
Step-by-step explanation:
if m * n = √(m²-n²) then 5 * 3 =
[tex]m \cdot n = \sqrt{m^2 -n^2}\\\\\text{When m =5 and n =3,}\\\\\\5\cdot 3 = \sqrt{5^2 -3^2} =\sqrt{25 -9} = \sqrt{16} = 4[/tex]
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textbf{Assuming:}[/tex]
[tex]\mathbf{m\times n = \sqrt{(m^2 - n^2)}}[/tex]
[tex]\huge\textbf{Solving:}[/tex]
[tex]\mathbf{\rightarrow 5\times 3 = \sqrt{(5^2 - 3^2)}}[/tex]
[tex]\mathbf{\rightarrow 15 = \sqrt{(5\times5 - 3\times3)}}[/tex]
[tex]\mathbf{\rightarrow 15 = \sqrt{(25 - 9)}}[/tex]
[tex]\mathbf{\rightarrow 15 = \sqrt{16}}[/tex]
[tex]\mathbf{15\neq4}[/tex]
[tex]\huge\textbf{Thus, this answer should be:}[/tex]
[tex]\huge\boxed{\boxed{\textsf{This statement is most likely: \boxed{\textsf{FALSE}}}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
[tex]\frak{Amphitrite1040:)}[/tex]
huang 3 shirts that each cost the same amount, a pair of pants that cost $12, and he pays with a $100 bill. Which
expression represents the amount of change Huang should receive? Select three options.
100-(3)
100--12)
(100-12) - 3
(100-12)*x*)
100-x) - 12
Answer:
(100-12) - 3
Step-by-step explanation:
we dont know what the cost of the shirts are so that one should be it.
yesterday, john had $15. In 7 days, He would have 23.
Answer:
He earn approximately $2.14 everyday
Step-by-step explanation:
hope this helps :3
what is the equation of this graph?
Answer:
y = x³ +2x² +x -1
Step-by-step explanation:
The attachment shows the four points we can read from the graph and the cubic regression function that fits them.
y = x³ +2x² +x -1
_____
Additional comment
It is useful to become familiar with the regression function capability of your graphing calculator or spreadsheet. Free or inexpensive apps are available for tablet or phone, and on the web.
Can you help me explain
Answer:
6, 60, 0.6, 600 are the answers
the questions all use the same digits but that the powers of 10 are different between the dividends and divisors for some
Step-by-step explanation:
8. If APTS – APQR, find the value of x.
5x + 13
T
36
Q
P
30
6x-2
-
S
R
Answer:
x = 7
Step-by-step explanation:
you can create a proportion:
PT / ST = PQ / RQ
36 / 30 = (5x+13) / (6x-2)
cross-multiply:
36(6x-2) = 30(5x+13)
distribute:
216x - 72 = 150x + 390
216x = 150x + 462
66x = 462
x = 7
The value of x for the given triangle sides is x = 7.
What is geometry?Geometry is one of the oldest branches of mathematics, along with arithmetic. It is concerned with spatial properties such as figure distance, shape, size, and relative position. A geometer is a mathematician who works in the field of geometry.
Given that the side PQ = 5x + 13 and the QR is 6x- 2. The value of x will be calculated by the concept of similarity.
PT / ST = PQ / RQ
36 / 30 = (5x+13) / (6x-2)
Cross-multiply the equations,
36(6x-2) = 30(5x+13)
Distribute:
216x - 72 = 150x + 390
216x = 150x + 462
66x = 462
x = 7
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Matthew spent 2/3 of his birthday on books and 1/4 of his birthday money on snacks. He says he spent 3/7 of his birthday money.
Which statement is most accurate?
*Disclaimer* show work
Answer:
Step-by-step explanation:
[tex]\frac{2}{3}[/tex] + [tex]\frac{1}{4}[/tex] = [tex]\frac{8+3}{12}[/tex] = [tex]\frac{11}{12}[/tex] ≈ 1
The correct answer is the last one (C)
solve y=f(x) for x. Then find the input when the output is -3. f(x)=3x^3
x=___
The input is____when the output is-3
[tex]f(x) =-3\\\\\implies 3x^3= -3\\\\\implies x^3 = -1\\\\\implies x = \sqrt[3]{-1} ~~\text{or}~~ x= \sqrt[3]{-1} \left(\dfrac{-1 \pm i\sqrt 3}2\right)\\[/tex]
[tex]\text{For x} \in \mathbb{R}, ~\text{the answer is x} = \sqrt[3]{-1} = -1[/tex]
Troy has 5/6 ounces of sprinkles to make cupcakes. The recipe uses 1/4 ounce per dozen of cupcakes. Write an expression which can be used to determine how many dozens of cupcakes Troy can make.
Help please? :)
Answer:
[tex]\frac{\frac{1}{4}}{1}=\frac{\frac{5}{6}}{x}[/tex]
Step-by-step explanation:
Per = 1
[tex]\frac{1}{4}[/tex]
So, if we were to solve:
[tex]\frac{1}{4}=\frac{5}{6x}[/tex]
[tex]\frac{1}{4}\cdot \:6x=1\cdot \:5[/tex]
[tex]\frac{3}{2}x=5[/tex]
[tex]\frac{3}{2}x\cdot \:2=5\cdot \:2[/tex]
[tex]3x=10[/tex]
[tex]\frac{3x}{3}=\frac{10}{3}[/tex]
[tex]x=\frac{10}{3}[/tex]
Troy can make [tex]\frac{10}{3}[/tex] dozen of cupcakes.
Please help me with this math problem!! NO LINKS PLEASE!! :)
Answer:
105°.
Step-by-step explanation:
1) to calculate m(∠ABC): m(∠ABC)=180-m(∠BAC)-m(∠(ACB)=180-90-65=25°;
2) note, m(∠ABC)=m∠(ABD)=25°, then it is possible
3) to calculate m(∠BAD): m(∠BAD)=180-m(∠ABD)-m(∠ADB)=180-25-50=105°.
Find the area of the triangle
[tex] =( \frac{1}{2} \times 10.4 \times 16.9) {ft}^{2} \\ = (5.2 \times 16.9) {ft}^{2} \\ = 87.88 {ft}^{2} [/tex]
Answer:
The area of the triangle is 87.88 square feet.
Hope you could get an idea from here.
Doubt clarification - use comment section.
How can you find approximations of square roots?
Step-by-step explanation:The second way of approximating a square root is to use a calculator. Most calculators have a radical sign on them. To find the square root of a number, we enter the radical sign, then the value and press enter. This will give us a decimal approximation of the square root.
Six grapefruit cost as much as a dozen oranges. The cost of a dozen grapefruit and two dozen oranges
is $12. If Susan purchased one orange and one grapefruit, how much did she spend? Show your
thinking.
a.Write System of equations for the above problem.
b. Solve the system of equations
c.Explain the meaning of the solution in the context of the problem.
Answer:
$0.73
Step-by-step explanation:
Let's say an orange costs O dollars and a grapefuit costs G dollars.
We add G dollars for each grapefuit and O dollars for each orange, so, for example, 12 grapefuit = G added 12 times = 12 *G = 12G
a.
6G = 10O
12G + 24O = 12
6 grapefuit = 6G = 10 oranges = 10O
b.
6G = 10O
12G + 24O = 12
We can solve this using substitution. First, we can solve the first equation for G. After that, we can plug that into the second to find O and go from there.
6G = 10O
divide both sides by 6 to remove the coefficient for G
G = (10/6)O
plug that into the second equation
12*(10/6)O + 24O = 12
20O + 24O = 12
44O = 12
divide both sides by 44 to solve for O
O=12/44 = 6/22
6G = 10O
6G = 60/22
divide both sides by 6 to solve for G
10/22 = G
c.
These solutions mean that an orange (O) costs 6/22 dollars and a grapefuit (G) costs 10/22, so 1O + 1G = 16/22 dollars ≈ $0.73. Note that O and G are kept as fractions because they are not exact dollar amounts, e.g. 0.27 repreating
3 friends share a cake in the ratio of 5:7:4. the cake costs Rs.96 how much does each share cost?
Answer:
Cost of each share is [tex]6Rs[/tex]
Step-by-step explanation:
Let the cost be [tex]5x,7x,4x[/tex]
We have
[tex]5x+7x+4x=96\\\\16x=96\\\\x=6[/tex]
Cost of each share is [tex]6Rs[/tex]
A= 3x3x3x3x3x5x7x7x7
B= 2x2x2x3x7x7x7x7
Find the Lowest Common Multiple (LCM) of A and B.
Please help
Answer:
LCM(57624, 416745) = 23,337,720 or LCM = 23337720
Step-by-step explanation:
List all prime factors for each number.
Prime Factorization of 57624 is:
2 x 2 x 2 x 3 x 7 x 7 x 7 x 7 => 23 x 31 x 74
Prime Factorization of 416745 is:
3 x 3 x 3 x 3 x 3 x 5 x 7 x 7 x 7 => 35 x 51 x 73
For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.
The new superset list is
2, 2, 2, 3, 3, 3, 3, 3, 5, 7, 7, 7, 7
Multiply these factors together to find the LCM.
LCM = 2 x 2 x 2 x 3 x 3 x 3 x 3 x 3 x 5 x 7 x 7 x 7 x 7 = 23337720
In exponential form:
LCM = 23 x 35 x 51 x 74 = 23337720
LCM = 23337720
Therefore,
LCM(57624, 416745) = 23,337,720
What is the following sum? 2 (RootIndex 3 StartRoot 16 x cubed y EndRoot) 4 (RootIndex 3 StartRoot 54 x Superscript 6 Baseline y Superscript 5 Baseline) 4 x (RootIndex 3 StartRoot 2 y EndRoot) 12 x squared y (RootIndex 3 StartRoot 2 y squared EndRoot) 8 x (RootIndex 3 StartRoot x y EndRoot) 12 x cubed y squared (RootIndex 3 StartRoot 6 y EndRoot) 16 x cubed y (RootIndex 3 StartRoot 2 y squared EndRoot) 48 x cubed y (RootIndex 3 StartRoot 2 y EndRoot).
Equivalent expressions are expressions that have the same value, and can be used interchangeably.
The result of the sum [tex]2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5})[/tex] is [tex]4x\sqrt[3]{2y} + 8x^2y\sqrt[3]{2y^2})[/tex]
The expression is given as:
[tex]2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5})[/tex]
Rewrite the expression as:
[tex]2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 2 (\sqrt[3]{2^4x^3y}) + 4 (\sqrt[3]{3^3 \times 2x^6y^5})[/tex]
Evaluate the roots
[tex]2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 2 (2x\sqrt[3]{2y}) + 4 (3x^2y\sqrt[3]{2y^2})[/tex]
Open the brackets
[tex]2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 4x\sqrt[3]{2y} + 12x^2y\sqrt[3]{2y^2})[/tex]
The above expression cannot be further simplified.
Hence, the result of the sum [tex]2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5})[/tex] is [tex]4x\sqrt[3]{2y} + 8x^2y\sqrt[3]{2y^2})[/tex]
Read more about equivalent expressions at:
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The sum of the expression is [tex]4 (\sqrt[3]{x^3y} +12x^2y(\sqrt[3]{ 2 y^2})\\[/tex].
We have to determine, the sum of the given expression.
According to the question,
Expression; [tex]2(\sqrt[3]{16x^3y} +4(\sqrt[3]{56x^6y^5})[/tex]
To determine the sum of the given expression following all the steps given below.
Rewrite the expression term in the form of their cubes,
[tex]\rm = 2(\sqrt[3]{16x^3y} +4(\sqrt[3]{56x^6y^5})\\\\ = 2(\sqrt[3]{2^4x^3y} +4(\sqrt[3]{3^3 \times 2 \times x^6y^5})\\\\= 2\times 2(\sqrt[3]{x^3y} +4\times 3(\sqrt[3]{ 2 \times x^6y^5})\\\\= 4 (\sqrt[3]{x^3y} +12x^2y(\sqrt[3]{ 2 y^2})\\\\=4 (\sqrt[3]{x^3y} +12x^2y(\sqrt[3]{ 2 y^2})\\[/tex]
Hence, The sum of the expression is [tex]4 (\sqrt[3]{x^3y} +12x^2y(\sqrt[3]{ 2 y^2})\\[/tex].
For more details refer to the link given below.
https://brainly.com/question/21798224
help me pls..........
Answer:
1000x or 1000 thousand times greater
Step-by-step explanation:
every decimal to the left is 10x greater than the one right of it.
Will give brainly,5 stars,and thank if it CORRECT
Answer:
$31.68
Step-by-step explanation:
Multiply each by the correct number
almond= 1.4*9.15= 12.81
cashews= 10.75* 0.8= 8.6
Peanuts= 3.95 * 2.6= 10.27
Add them all up
12.81+8.6+10.27
you’ll get 31.68
PLEASE HELP ME 50 POINTSS 1!1!1!1!1!1!1!1!1!11!1!1!1!
How long does it take a baseball moving with an average
speed of 35 m/s to travel 18 m?
What is the average speed of a car that travels 870 km in 14.5
h?
Answer:
1) the baseball will take approx 0.514 seconds to move 18 meters.
35/1 = 18/x
x = 0.514s
2) the car's average speed is 60 km per hour.
870/14.5 = x/1
x = 60h
Solve:
A.152
B.176
C.5
D.27
Answer:
Option B
176
Step-by-step explanation:
take 11 to the next side of the equation making the division multiplication getting us 16×11=176
what is the answer to 5x+1=3x+7
Answer:
Step-by-step explanation:
5
+
1
=
3
+
7
5x+1=3x+7
Solve
1
Subtract
1
1
from both sides of the equation
5
+
1
=
3
+
7
5x+1=3x+7
5
+
1
−
1
=
3
+
7
−
1
5x+1{\color{#c92786}{-1}}=3x+7{\color{#c92786}{-1}}
2
Simplify
Subtract the numbers
Subtract the numbers
5
=
3
+
6
5x=3x+6
3
Subtract
3
3x
from both sides of the equation
5
=
3
+
6
5x=3x+6
5
−
3
=
3
+
6
−
3
5x{\color{#c92786}{-3x}}=3x+6{\color{#c92786}{-3x}}
4
Simplify
Combine like terms
Combine like terms
2
=
6
2x=6
5
Divide both sides of the equation by the same term
2
=
6
2x=6
2
2
=
6
2
\frac{2x}{{\color{#c92786}{2}}}=\frac{6}{{\color{#c92786}{2}}}
6
Simplify
Cancel terms that are in both the numerator and denominator
Solution
=
3
Solve for W
4w^2+9w= -2
Answer:
[tex]w_1=-\frac{1}{4},w_2=-2}[/tex]
Step-by-step explanation:
[tex]4w^2+9w=-2[/tex]
[tex]4w^2+9w+2=0[/tex]
[tex]w^2+9w+8=0[/tex]
[tex](w+1)(w+8)=0[/tex]
[tex](4w+1)(w+2)=0[/tex]
[tex]w_1=-\frac{1}{4},w_2=-2}[/tex]
Hi! Please help me!
Lightbulbs act as resistors. Janine is building a circuit that contains two lightbulbs in parallel. One of the lightbulbs has a
resistance of 120 ohms, but the resistance of the second lightbulb is unknown. She models the total
resistance in the
circuit, t, with this equation, in which r represents the resistance of the second lightbulb.
t =
1207
+ 120
Find the inverse of Janine's equation.
Look at photo below
Thank you have a nice day:)
Answer:
The answer is t^-1 (r)=120r/120-r
i hope this is right sry if im wrong have a good day :)
The inverse of Janine's equation is [tex]r = \frac{120t}{120-t}[/tex] .
What is resistance?Resistance is a measure of the opposition to current flow in an electrical circuit. Resistance is measured in ohms, symbolized by the Greek letter omega (Ω).
According to the question
Janine is building a circuit that contains two lightbulbs in parallel.
One of the lightbulbs has a resistance of 120 ohms.
R = 120ohms
r = resistance of the second lightbulb
t = total resistance in the circuit
[tex]t = \frac{120r}{r+120}[/tex]
Now,
The inverse of Janine's equation in which we will make r independent
[tex]t = \frac{120r}{r+120}[/tex]
[tex]t(r+120) = 120r[/tex]
[tex]tr + 120t = 120r[/tex]
[tex]120t = 120r - tr[/tex]
[tex]120t = r(120-t)[/tex]
[tex]r = \frac{120t}{120-t}[/tex]
Hence, the inverse of Janine's equation is [tex]r = \frac{120t}{120-t}[/tex] .
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ABC and XYZ are similar triangles with right angles at B and Y. AC=13 cm,
BC=5 cm. Find AB and XZ. (No links pls...)
Answer:
See belowStep-by-step explanation:
Since B is the right angle, AC is the opposite side - hypotenuse.
Use Pythagorean and find the missing side, AB:
[tex]AB = \sqrt{AC^2-BC^2} = \sqrt{13^2-5^2} =\sqrt{144} =12cm[/tex]There is no info given to link the triangles ABC and XYZ and hence can't provide solution to any dimension of XYZ.
If the scale factor was given as k, then XZ would be:
XZ = k*BC = 5kFind 48.9% of 264.Round to the nearest hundredth
Step-by-step explanation:
Simply divide the percent by 100 and multiply by the number. For example, 48.9 /100 x 264 = 129.096 or 0.489 x 264 = 129.096
Rounded to nearest hundredth
= 129.10
Answer:129.10
Step-by-step explanation:
Simply, the equation for the percentage value of a number is:
x*(z%/100%)=y
where x is your initial value, z is your percentage value, and y is the resultant value
for this question, the equations gives us as follows
264*(48.9%/100%)=129.096=129.10
(2w2+4w)÷(w–2) divide
the answer is 4