The canyon is approximately 258 meters wide.
What is the width of the canyon?The speed of sound in air depends on the temperature, and we can use the formula:
v = 331.4 + 0.6T
where;
v is the speed of sound in meters per second, and T is the temperature in Celsius. At a temperature of 27.0°C,The speed of sound is:
v = 331.4 + 0.6(27.0)
v = 343.8 m/s
Let's call the distance to one wall "d". When the man fires the shot, the sound travels to the wall, reflects, and returns to the man.
The total distance traveled is 2d. The time it takes for the sound to travel this distance is:
t = 2d/v
Similarly, for the other wall, the total distance traveled is 2(D - d)
where;
D is the width of the canyon.The time it takes for the sound to travel this distance is:
t + 1.00 = 2(D - d)/v
We can solve these equations for d and D:
d = vt/2
D = (v/2)(t + 1.00)
Substituting in the values we have:
d = (343.8 m/s)(1.50 s)/2 = 257.85 m
D = (343.8 m/s/2)(1.50 s + 1.00 s) = 515.70 m
Therefore, the width of the canyon is:
D - d = 515.70 m - 257.85 m = 257.85 m
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How much energy is required to melt 64g of methane of 90K ? (methane is 16 g/ mol)
Answer:
12.928 kJ
Explanation:
To calculate the energy required to melt a substance, we use the formula:
Q = m * ΔHfus
where Q is the energy required, m is the mass of the substance, and ΔHfus is the heat of fusion, which is the amount of energy required to melt one gram of the substance.
For methane, the heat of fusion is 0.202 kJ/g. We can calculate the amount of energy required to melt 64g of methane as follows:
Q = m * ΔHfus
Q = 64g * 0.202 kJ/g
Q = 12.928 kJ
Therefore, it takes approximately 12.928 kJ of energy to melt 64g of methane at 90K.
Question 10: You throw a shoe with a mass of 0.3 kg towards your archnemesis
Icky Garage and it moves horizontally to the right at 20 m/s. However, Icky is slick so
she dodges the shoe and it rebounds horizontally to the left at 30 m/s. Determine
the impulse that acts on the shoe during its collision with the wall.
The impulse that acts on the shoe during its collision with the wall is -15 kg*m/s (to the left).
Calculation steps:
The initial momentum of the shoe, p1 = mv1 = 0.3 kg * 20 m/s = 6 kgm/s (to the right)
The final momentum of the shoe, p2 = mv2 = 0.3 kg * (-30 m/s) = -9 kgm/s (to the left)
The change in momentum, Δp = p2 - p1 = -9 kgm/s - 6 kgm/s = -15 kg*m/s (to the left)
Therefore, the impulse acting on the shoe during its collision with the wall is J = Δp = -15 kg*m/s (to the left)
What is impulse?
Impulse refers to the change in momentum of an object when a force is applied to it for a certain amount of time. It is defined as the product of the force and the time for which it acts on an object. Mathematically, impulse can be expressed as:
J = F * Δt
where J is the impulse, F is the force applied, and Δt is the time for which the force acts.
What is momentum?
Momentum is a physical quantity that measures the motion of an object. It is defined as the product of an object's mass and velocity. In other words, momentum = mass x velocity.
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Someone Please help!! Thanks so much
Answer:
I = Q / t definition of electric current
Q = I * t = 40 C/s * .5 s = 20 Coulombs
Is the earth round? Or is it flat like some people say
Answer: The Earth is an oblate spheroid, meaning it is roughly spherical in shape but flattened at the poles and bulges at the equator. This shape has been scientifically proven through centuries of evidence and observations. While some people may claim that the Earth is flat, this idea is not supported by scientific evidence.
can you explain how he got 60/11 please! , i got boards tomorrow grade 10 . deciding to sit and study till morning :(!
The position of the image of the object would be 7.5 cm behind the mirror.
Position of the image of objects in a mirrorThe focal lengths of all convex mirrors are negative and are given by the following formula:
1/f = - (1/R)
where:
R is the radius of curvature of the mirror.Substituting for R in the equation, we are going to have:
1/f = -1/20 cm
f = -20 cm
Next, we can make use of the mirror formula to find the position of the image along the plane of the mirror:
The mirror formula goes thus:
1/f = 1/do + 1/di
where 'do' is the object distance and di is the image distance.
Substituting the values of f and di:
1/-20 cm = 1/12 cm + 1/di
Thus:
di = -7.5 cm
That the di is negative is an indication that the image is a virtual one that forms behind the mirror. In other words, the position of the image is 7.5 cm behind the mirror.
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two objects having masses m 1 and m 2 are connected to each other as shown in the figure and are released from rest. there is no friction on the table surface or in the pulley. the masses of the pulley and the string connecting the objects are completely negligible. what must be true about the tension t in the string just after the objects are released?
The tension T in the string just after the objects are released must be equal and opposite to the accelerations of each mass.
The statement refers to a physical principle known as Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.
In the context of the given statement, it means that the tension (T) in the string, which is the force transmitted through the string, must be equal in magnitude and opposite in direction to the accelerations of each mass.
When objects are released and allowed to move under the influence of gravity, they may be connected by a string or rope. As the objects accelerate due to the force of gravity, the tension in the string changes to keep the objects connected and moving together.
According to Newton's third law, the tension in the string must be equal and opposite to the accelerations of each mass.
If one of the objects has a greater acceleration, the tension in the string must be higher on that side to counteract the greater acceleration.
Similarly, if one of the objects has a lower acceleration, the tension in the string must be lower on that side. This ensures that the net force on each object is balanced and that they move together without breaking the string.
This is because Newton's Second Law states that the sum of the forces on an object is equal to the mass times the acceleration: F = ma. Therefore, the tension T must be the same for both masses, since their accelerations must be equal and opposite.
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WILL GIVE BRAINLIEST
Explain the stages of complete and incomplete metamorphosis, provide examples for each. (Counts 20% of your lesson grade.)
Metamorphosis refers to the process of development and change in the body form of certain animals as they grow from juveniles to adults.
Explain the types of metamorphosis?
Metamorphosis is classified into two types: complete and incomplete.
1. Complete metamorphosis:
Complete metamorphosis is a developmental process in which the juvenile form of an animal goes through four distinct stages: egg, larva, pupa, and adult. In this type of metamorphosis, the juvenile form looks completely different from the adult form in terms of appearance, behavior, and habitat.
Animals that undergo complete metamorphosis include:
a) Butterflies and moths: The egg hatches into a caterpillar (larva) that feeds and grows rapidly. The larva then forms a pupa or chrysalis, where the body undergoes a complete transformation into an adult butterfly or moth.
b) Flies: The egg hatches into a worm-like maggot (larva) that feeds and grows. The maggot then transforms into a pupa, and finally, an adult fly emerges.
c) Beetles: The egg hatches into a grub (larva) that feeds and grows. The grub then transforms into a pupa, and finally, an adult beetle emerges.
Incomplete metamorphosis:
Incomplete metamorphosis is a developmental process in which the juvenile form (nymph) of an animal resembles the adult in appearance and habitat, but is smaller and lacks wings. The nymph goes through several stages of growth and molting before reaching adult form.
Animals that undergo incomplete metamorphosis include:
a) Grasshoppers: The egg hatches into a nymph that resembles the adult grasshopper but lacks wings. The nymph goes through several molts and growth stages before developing wings and reaching the adult stage.
b) Cockroaches: The egg hatches into a nymph that resembles the adult cockroach but lacks wings. The nymph goes through several molts and growth stages before developing wings and reaching the adult stage.
c) Dragonflies: The egg hatches into a nymph that lives in water and resembles the adult dragonfly but lacks wings. The nymph goes through several molts and growth stages before developing wings and emerging from the water as an adult dragonfly.
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The ratio of diameter of lenses to its focal length is referred as
The ratio of diameter of lenses to its focal length is referred as the f-number or f-stop
The ratio of diameter of lenses to its focal length is referred to as the f-number or f-stop. It is a fundamental parameter that describes the aperture of a lens, which determines the amount of light that can pass through the lens. The f-number is calculated by dividing the focal length of the lens by the diameter of the aperture, which is the opening that controls the amount of light entering the lens.
A smaller f-number indicates a larger aperture, which allows more light to enter the lens, resulting in a brighter image and a shallower depth of field. Conversely, a larger f-number indicates a smaller aperture, which allows less light to enter the lens, resulting in a darker image and a greater depth of field.
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the beam of a laser pointer (or a helium-neon laser) would spread to a 610- km -diameter circle at the distance of the moon. that is approximately 20 % of the moon's diameter! the light intensity would be so low that it would not be possible to detect the tiny amount of light reflected back to earth by a small mirror. even with a laser much more powerful than a laser pointer, the laser spot on the moon needs to be no more than 2.0 km in diameter in order to detect the reflected light. to achieve this, what is the minimum possible diameter of the laser's exit aperture? continue to use 650 nm as the laser wavelength.
The minimum possible diameter of the laser's exit aperture to achieve a 2.0 km diameter spot on the moon is 2.4 meters.
What is the laser pointer? The laser pointer is a compact laser light-emitting device. A laser pointer operates on the principle of stimulated emission. It is possible to get a bright, coherent light beam when photons come together and stimulate one another's emission.
What is a Helium-Neon Laser? The He-Ne laser or Helium-Neon Laser is a gas laser in which a mixture of helium and neon is used as the active medium. This laser is widely used in research laboratories and industries due to its easy availability and low cost. The wavelength of light produced by He-Ne laser is 632.8 nm.
What is a laser beam? A laser beam is a coherent and collimated light beam of photons traveling in the same direction with the same frequency and amplitude. A laser beam emits light rays that can travel great distances with minimal dispersion, as well as exert an incredibly focused level of energy.
When a laser is pointed at the moon from Earth, the beam is so diffuse that the spot on the lunar surface is roughly 610 km in diameter, approximately 20% of the moon's diameter. The laser spot on the moon needs to be no more than 2.0 km in diameter in order to detect the reflected light.
Given that the wavelength of the laser beam is 650 nm. The minimum possible diameter of the laser's exit aperture can be determined using the formula of diffraction-limited beam radius: r = 1.22 * λ * f / D where, λ = 650 nm, the wavelength of the laser f = focal length of the beam D = diameter of the laser's exit aperture
The diameter of the laser's exit aperture is given by the formula: D = 1.22 * λ * f / r.
To achieve a 2.0 km diameter spot on the moon, the minimum possible diameter of the laser's exit aperture is 2.4 meters.
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a roller-coaster car is towed up an incline at a steady speed of 0.500 m/s by a chain parallel to the surface of the incline. the slope is 3.00%, which means that the elevation increases by 3.00 m for every 100.0 m of horizontal distance. the mass of the roller-coaster car is 604 kg. ignoring friction, what is the magnitude of the force exerted on the car by the chain?
A roller-coaster car is towed up an incline at a steady speed of 0.500 m/s by a chain parallel to the surface of the incline. the slope is 3.00%. ignoring friction, the magnitude of the force exerted on the car by the chain is: 5908.7 N
The magnitude of the force exerted on the roller-coaster car by the chain is equal to the net force on the car, which is equal to the sum of the force due to gravity and the force due to the incline. Since the roller-coaster car is moving at a steady speed, the net force on the car must be equal to zero.
Using Newton's second law of motion, we can calculate the force due to gravity (Fg) and the force due to the incline (Fi) in order to determine the magnitude of the force exerted on the car by the chain.
The force due to gravity (Fg) can be calculated as Fg = m * g, where m is the mass of the roller-coaster car and g is the acceleration due to gravity. Therefore, Fg = 604 kg * 9.8 m/s2 = 5902.8 N.
The force due to the incline (Fi) can be calculated as Fi = m * g * sinθ, where m is the mass of the roller-coaster car, g is the acceleration due to gravity, and θ is the angle of the incline. The angle of the incline is equal to the slope of the incline divided by 100. Therefore, θ = 3.00% / 100 = 0.03 radians.
Therefore, [tex]Fi = 604 kg * 9.8 m/s2 * sin(0.03) = 5.9 N.[/tex]
Therefore, the magnitude of the force exerted on the car by the chain is equal to the sum of the force due to gravity and the force due to the incline. [tex]F = Fg + Fi = 5902.8 N + 5.9 N = 5908.7 N.[/tex]
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Complete the following sentence: When multiple sources are connected together, their total e.m.f. will be equal to the sum of their individual e.m.fs if they are placed in ______ <, + explanation
Answer:- When they are placed in series.
When multiple emf sources are connected in series then the net or total emf is equal to the sum of their individual emfs .
Say if we have cells of emfs [tex]\epsilon_1[/tex] , [tex]\epsilon_2[/tex] , [tex]\epsilon_3[/tex] , [tex]\epsilon_4 [/tex] . . . . [tex]\epsilon_n[/tex]
Then the net emf is ,
[tex]\implies \underline{\underline{\green{\epsilon_{net}= \epsilon_1+ \epsilon_2+\dots +\epsilon_n}}}\\[/tex]
Additional information:-
If the emfs of n cells are equal and they are connected in series then the net emf is given by ,
[tex]\implies \epsilon_{net}= n\epsilon \\[/tex]
where ,
[tex]\epsilon[/tex] = emf of a single cell .Also , when n cells of emfs [tex]\epsilon_1[/tex] and [tex]\epsilon_2[/tex] . . . . . [tex]\epsilon_n[/tex] and internal resistances [tex]r_1[/tex] , [tex]r_2[/tex] . . . . . [tex]r_n[/tex] respectively are connected in parallel then the net emf is given by,
[tex]\implies \underline{\underline{\green{\epsilon_{net} = \left( \dfrac{1}{r_1}+\dfrac{1}{r_2}+\dots +\dfrac{1}{r_n}\right)^{-1}\left(\dfrac{\epsilon_1}{r_1}+\dfrac{ \epsilon_2}{r_2}+\dots +\dfrac{\epsilon_n}{r_n}\right)}}}\\[/tex]
Again suppose if we make a parallel arrangement of cells each having same emf then the net emf remains same that is equal to the emf of individual cell ( Why ? You can try yourself by using the above formula )
and we are done!
What is the distance between two spheres, each with a charge of 1. 05 X 10^-7 C when the force between them is 0. 40 N?
Answer:
Answer:please mark as brainliest
calculate the minimum coefficient of friction needed for a car to negotiate an unbanked 50.0 m radius curve at 30.0 m/s. (b) what is unreasonable about the result? (c) which premises are unreasonable or inconsistent?
A-the minimum coefficient of friction is 0.18 ,B- it is unreasonable, C-no premises is inconsistent.
(a) Calculation of the minimum coefficient of friction needed for a car to negotiate an unbanked 50.0 m radius curve at 30.0 m/s: A car moving with a velocity of 30.0 m/s in a circular path of radius 50.0 m negotiates an unbanked curve. Hence, the force required to move a car in a circular path is the frictional force between the wheels of the car and the road.
The minimum coefficient of friction needed for a car to negotiate an unbanked 50.0 m radius curve at 30.0 m/s is given by:μmin = tanθ= v² / rgWhere,μmin is the minimum coefficient of frictionv is the velocity of the carr is the radius of the curveg is the acceleration due to gravity θ is the angle of banking.
As the curve is unbanked, the angle of banking is 0°.∴ μmin = v² / rg= (30.0 m/s)² / (50.0 m × 9.81 m/s²)= 0.183 or 0.18 (approx)
(b)The result of 0.18 is not unreasonable.
(c) None of the premises is unreasonable or inconsistent.
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What process involves heavier atoms breaking down into lighter atoms?
Answer:
Fission occurs when a neutron slams into a larger atom, forcing it to excite and split into two smaller atoms—also known as fission products. Additional neutrons are also released that can initiate a chain reaction. When each atom splits, a tremendous amount of energy is released.
Explanation:
Answer:
Fission
Explanation:
this happens when the neutrons an atoms slams into a larger atom, forcing it to split into two smaller atoms
In which direction the voltage is produced in a current carrying metallic slab if the magnetic field is applied in the direction perpendicular to direction of current.
When a magnetic field is applied perpendicular to the direction of current in a metallic slab, a voltage is produced in the direction perpendicular to both the magnetic field and the current.
This phenomenon is known as the Hall effect, and the voltage produced is called the Hall voltage. The direction of the Hall voltage is determined by the right-hand rule. If you point your thumb in the direction of the current, and your fingers in the direction of the magnetic field, the Hall voltage will be in the direction perpendicular to both (i.e., it will be perpendicular to the plane defined by your thumb and fingers). The Hall effect is commonly used to measure the strength of magnetic fields and the properties of materials. It is also used in electronic devices such as Hall effect sensors and magnetometers.
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What glasses increase pupil illumination?
1. Close ones.
2. Dispersives.
3. Converging and dispersive.
4. Glasses do not increase pupil illumination.
The glasses that increase pupil illumination is Glasses do not increase pupil illumination.
Pupil illumination explained.
Pupil illumination refers to the amount of light entering the eye through the pupil. The size of the pupil determines the amount of light that enters the eye, with larger pupils allowing more light and smaller pupils allowing less light. The amount of light available in the environment also affects pupil illumination, with brighter environments causing the pupil to constrict and dimmer environments causing the pupil to dilate. Pupil illumination plays an important role in visual perception, as it affects the brightness and clarity of the visual image formed on the retina.
Pupil illumination is a function of the amount of light entering the eye, which is determined by the size of the pupil and the amount of light available in the environment. Glasses do not have a direct effect on the size of the pupil or the amount of light in the environment, so they cannot increase pupil illumination.
However, glasses can improve visual acuity and clarity by correcting refractive errors and enhancing contrast, which may indirectly improve the perception of brightness and illumination.
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What specific question does the doctor ask Annie?
The doctor asks Annie if she has had any trouble with her eyes, like drooping.
In the given text, Dr. Jones asks Annie if she has had any trouble with her eyes, specifically if they have been drooping. This question suggests that the doctor is trying to assess if Annie has been experiencing symptoms of ptosis, which is a medical condition where the upper eyelid droops due to a weakness or paralysis of the muscles responsible for lifting the eyelid.
Ptosis can be a sign of several neurological conditions and can cause visual impairment or other complications. Therefore, the doctor's question indicates that he is trying to gather more information about Annie's symptoms to make a proper diagnosis and provide appropriate treatment.
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The question is incomplete, the complete question is:
Dr. Jones looked pensive and asked, “Have you had any trouble with your eyes? Like have they been drooping?”
Annie looked confused. “I have had a lot of eye strain and double vision recently. It gets blurry when I stare at the computer screen too long; I seem to get a zillion papers every week. I also think the chlorine level in
the pool is too high. Everyone on the team complains about it because, if your goggles come off , your eyes sting like mad.
The doctor smiled, “I swam before those goggles were even invented, so I know what you mean about stinging eyes. But, I think what you’re telling me goes beyond simple fatigue. I’m going to refer you to a neurologist at the hospital.”
an 80 kg person weighs himself on a planet having a radius of 2500 km and finds that the scale shows 75 n.calculate the mass of planet.
The mass of the planet is approximately [tex]7.87 x 10^23 kg.[/tex]
We can use the formula for the gravitational force between two masses:
[tex]F = G * (m1 * m2) / r^2[/tex]
where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them. In this case, the person's weight on the planet is equal to the force of gravity between the person and the planet: F = 75 N. The person's mass is 80 kg, so their weight on Earth would be:
[tex]W = m * g = 80 kg * 9.8 m/s^2 = 784 N[/tex]
We can set these two forces equal to each other and solve for the mass of the planet: [tex]75 N = G * (80 kg * m_planet) / (r_planet)^2\\[/tex]We can rearrange this equation to solve for the mass of the planet:
[tex]m_planet = (75 N * (2500 km)^2) / (G * 80 kg)\\[/tex]
where[tex]G = 6.674 x 10^-11 N*m^2/kg^2[/tex]is the gravitational constant.
Plugging in the values, we get: m_planet = [tex](75 N * (2500 km)^2) / (6.674 x 10^-11 N*m^2/kg^2 * 80 kg)[/tex]
m_planet = [tex]7.87 x 10^23 kg[/tex]
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If a bus is running with a speed of 72km HR calculate the distance traveled in 5 sec Hint acceleration due to gravity 10 meterper second square
Answer:
To solve this problem, we need to use the formula:
distance = initial velocity x time + 1/2 x acceleration x time^2
where:
initial velocity = 72 km/hour (we need to convert this to m/s to use it in the formula)
time = 5 seconds
acceleration = 10 m/s^2 (assuming this is the acceleration due to gravity)
Converting the initial velocity from km/hour to m/s:
72 km/hour = (72 x 1000 m) / (60 x 60 s) = 20 m/s
Now we can plug in the values into the formula:
distance = 20 m/s x 5 s + 1/2 x 10 m/s^2 x (5 s)^2
distance = 100 m + 1/2 x 10 m/s^2 x 25 s^2
distance = 100 m + 125 m
distance = 225 meters
Therefore, the distance traveled by the bus in 5 seconds is 225 meters.
. Is it possible to make a steel bar into a magnet? If so, explain
the method.
Answer:
yes if you can only install a magnetic force into the bar
calculate the force due to the gravitational attraction between the earth and the spacecraft in n if the mass of the spacecraft is 2300 kg.
The force due to the gravitational attraction between the earth and the spacecraft in n if the mass of the spacecraft is 2300 kg is 2,156.4 N
The formula to calculate the gravitational force between two objects is given by:
F = (G * m1 * m2) / r²
where F is the force of gravitational attraction,
G is the gravitational constant (6.67408 × 10⁻¹¹ N·m²/kg²),
m1 and m2 are the masses of the two objects, and
r is the distance between the centers of the two objects.
Using the given values of mass of the spacecraft (m2) as 2300 kg,
the mass of the Earth (m1) as 5.97 × 10²⁴ kg and the distance between them as the sum of the radius of the Earth and the altitude of the spacecraft,
which is approximately 6,378,000 meters + 400,000 meters = 6,778,000 meters,
we can calculate the gravitational force as:
F = (G * m1 * m2) / r²
F = (6.67408 × 10⁻¹¹ N·m²/kg²) * (5.97 × 10^24 kg) * (2300 kg) / (6,778,000 meters)²
F = 2,156.4 N (approx.)
Therefore, the force due to gravitational attraction between the Earth and the spacecraft is approximately 2,156.4 N.
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A harmonic wave travels in a wire with amplitude 2. 51 mm, wavelength 1. 09 m, and frequency 649 Hz. What is the speed with which the wave travels
The speed of a harmonic wave traveling in a medium is given by the product of its wavelength and frequency, i.e.,
v = λ f, where v is the velocity of the wave, λ is the wavelength, and f is the frequency. In this case, the given amplitude of the wave is not needed to calculate the speed. We can simply use the wavelength and frequency provided to find the velocity. Substituting the given values, we get: v = (1.09 m) × (649 Hz) = 706.41 m/s. Therefore, the speed with which the wave travels is 706.41 m/s. Note that the unit of velocity in SI is meters per second (m/s).
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calculate the magnitude of the linear momentum for the following cases: (a) a proton with mass equal to 1.67 3 10227 kg, moving with a speed of 5.00 3 106 m/s; (b) a 15.0-g bullet moving with a speed of 300 m/s; (c) a 75.0-kg sprinter running with a speed of 10.0 m/s; (d) the earth (mass 5 5.98 3 1024 kg) moving with an orbital speed equal to 2.98 3 104 m/s.
To calculate the magnitude of the linear momentum for each of the cases, you need to use the following equation:
Linear momentum (p) = mass (m) x velocity (v)
Case (a): Linear momentum (p) = 1.67 x 10-27 kg x 5.00 x 106 m/s = 8.35 x 10-22 kg m/s
Case (b): Linear momentum (p) = 0.015 kg x 300 m/s = 4.5 kg m/s
Case (c): Linear momentum (p) = 75.0 kg x 10.0 m/s = 750 kg m/s
Case (d): Linear momentum (p) = 5.98 x 1024 kg x 2.98 x 104 m/s = 1.78 x 1029 kg m/s
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Calculate the ideal mechanical advantage for each of the machines show. Write your answers in the spaces provided.
For Machine 1 ideal mechanical advantage is 4, for machine 2 the IMA is 8 and for the machine 3 the IMA is 4. The load the machines can lift is 400N, 800N and 200N respectively.
The ideal mechanical advantage of a machine is an important factor in determining its efficiency and usefulness. The higher the IMA, the easier it is to lift heavy loads with less effort. However, it is important to note that the actual mechanical advantage (AMA) may differ from the ideal due to various factors such as friction and other mechanical losses. Therefore, it is essential to consider both IMA and AMA when evaluating the performance of a machine.
Machine 1:
Ideal Mechanical Advantage (IMA) = Load / Effort
IMA = 400 N / 100 N
= 4
Machine 2:
IMA = Load / Effort
IMA = 800 N / 100 N
= 8
Machine 3:
IMA = Load / Effort
IMA = 200 N / 50 N
= 4
In simple terms, the ideal mechanical advantage (IMA) of a machine is the ratio of the load it can lift to the effort or force needed to lift it. In other words, it is the number of times a machine multiplies the force or effort applied to it.
For Machine 1, the IMA is 4, which means that the machine can lift a load that is four times heavier than the applied force. Therefore, if you apply 100 N of force to the machine, it can lift a load of up to 400 N.
For Machine 2, the IMA is 8, which means that it can lift a load that is eight times heavier than the applied force. If you apply 100 N of force to this machine, it can lift a load of up to 800 N.
For Machine 3, the IMA is 4, which means that it can lift a load that is four times heavier than the applied force. If you apply 50 N of force to this machine, it can lift a load of up to 200 N.
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3.5
An experiment was pero
of conductor on the current strength. A 200 mm length of nichrome
wire with diameter 0,3 mm is wound into a coil an attached to a
circuit. The potential difference is measured across the coil. The
experiment is repeated for a 200 mm length of copper wire of
diameter 0,3 mm. Temperature was kept constant. The following
results were obtained:
Current through each wire (A)
Potential difference across the
nichrome wire(V)
Potential difference across the copper
wire(V)
0,2 0,4 0,6 0,8 1,0
0,8 1,6 2,4 3,2 4,0
0,4 0,8 1,2 1,6 2,0
what is the independent variable here
The current flowing through each wire is the experiment's independent variable because it is the one that the experimenter is actively manipulating and controlling.
How does the resistance in the circuit change depending on the thickness of a piece of nichrome wire?The resistance is influenced by the wire's thickness, so the thicker the wire, the lower the resistance. Because less water can flow through a narrower pipe in a given length, there is more resistance in a narrower pipe.
Why does a nichrome not heat up in an electric circuit whereas a nichrome wire does?Due to the alloy composition of nichrome wire, its resistance is quite high. Because of this, it generates a lot of heat when current flows through it, making it extremely hot to the touch.
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Question 2
2 pts
A 76 kg person is sledding down a hill is traveling at 20 m/s when they hit a stationary 20 kg person and they end up both riding together in the
sled. How fast will they be moving together immediately after they collide?
The speed of the sled and the two people immediately after the collision is approximately 15.8 m/s.
What is the Law of conservation of momentum?The conservation of momentum, which states that the total momentum of a closed system remains constant if no external forces act on it. In this case, the sled and the two people form a closed system, because there are no external forces acting on them.
Let's define the initial state as before the collision, and the final state as after the collision. In the initial state, the sled and the 76 kg person have a momentum of:
p1 = (76 kg)(20 m/s) = 1520 kg·m/s
The second person is stationary, so their momentum is zero:
p2 = 0 kg·m/s
The total momentum before the collision is therefore:
p1i = p1 + p2 = 1520 kg·m/s + 0 kg·m/s = 1520 kg·m/s
In the final state, the two people and the sled move together with a common velocity, which we'll call v. The total mass of the system is:
m = 76 kg + 20 kg = 96 kg
The total momentum after the collision is:
p1f = m v
By the conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision:
p1i = p1f
1520 kg·m/s = 96 kg × v
Solving for v, we get:
v = 1520 kg·m/s / 96 kg ≈ 15.8 m/s
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Please help. I do not know what to do
1) The heat is 10,800 J
2) The heat is 2400 J
3) The time is 100 s
What is the heating effect of current?The heating effect of current, also known as Joule heating or resistive heating, is a phenomenon where electrical energy is converted into heat when an electric current flows through a material that has resistance.
1) We know that;
H = I^2rt
H = (3)^2 * 4 * 5 * 60
H = 10,800 J
2) H = (V^2/R)t
H = (10)^2/5 * 2 * 60
H = 2400 J
3) H =(V^2/R)t
t = H/(V^2/R)
t = H * R/V^2
t = 4 * 10^3 * 10/20^2
t = 100 s
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How can scientists detect a black hole if it does not emit light?
A boat float on the surface of the lake sends a signal summer force vertically down to the water the sooner trace is 0. 007 sand the speed of sound is 1,500m/s. How deep is the water?
A boat float on the surface of the lake sends a signal summer force vertically down to the water the sooner trace is 0. 007 sand the speed of sound is 1,500m/s. 21 meters deep is the water.
The time it takes for the sound wave to travel from the boat to the bottom of the lake and back is given by:
t = 2d/v
Where:
d = depth of the water
v = speed of sound in water (1,500 m/s)
We can solve for d by rearranging the equation as:
d = v × t/2
Where:
t = the time it takes for the sound wave to travel from the boat to the bottom of the lake and back, which is equal to twice the time it takes for the sound wave to travel from the boat to the bottom of the lake.
The time it takes for the sound wave to travel from the boat to the bottom of the lake is given by:
t = d/v
Where:
d = distance traveled by the sound wave (which is equal to the depth of the water)
v = speed of sound in water (1,500 m/s)
We can substitute this expression for t into the equation for d to get:
d = v × d/2v
Simplifying this expression, we get:
d/0.007 = 2 × 1500
d = 21 meters
Therefore, the depth of the water is approximately 21 meters.
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With an average mass of only 30.0 gthe mouse lemur of Madagascar the smallest primate on Earth. Suppose this lemur swings on a light vine with a length of 2.4 m, so that the tension in the vine at the bot- tom point of the swing is 0.393 N. What is the lemur's tangential speed at that point?
Suppose that Reid weighs 72 kg. 2. The mouse macaque of India is the shortest primate on Earth, with an average weight of just 30.0 g. Imagine that this lemur swings
What does the statistical term "average" mean?
Average. In everyday speech, a average is a specific number chosen to represent a collection of figures. In various settings, various average ideas are utilized. The word "average" frequently refers to the mathematical mean, which is the total of the values divided by the number of numbers being averaged. Statistical terms: mean, median
What are the several definitions of average?
In various settings, various average ideas are utilized. The word "average" frequently refers to the mathematical mean, which is the total of the integers divided by the amount of numbers being averaged. Mean, average, and mode all are considered measures of normal distribution in statistics, and in common parlance, any of these could be referred to as an average figure.
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