a kayak rental shop rents 28 kayaks per week when it charges $25 per day. For each $5 increase in price, the shop loses four kayak rentals per week. How much should the kayak rental shop charge to maximize weekly revenue? What is the maximum weekly revenue?

Answers

Answer 1
found this online hope it helps :)))
A Kayak Rental Shop Rents 28 Kayaks Per Week When It Charges $25 Per Day. For Each $5 Increase In Price,
Answer 2

If a kayak rental shop rents 28 kayaks per week when it charges $25 per day. For each $5 increase in price, the shop loses four kayak rentals per week. 720 is the  maximum weekly revenue

What is Equation?

Two or more expressions with an Equal sign is called as Equation.

It is given that a kayak rental shop rents 28 kayaks per week when it charges $25 per day

For each $5 increase in price, the shop loses four kayak rentals per week. we need to find  How much should the kayak rental shop charge to maximize weekly revenue

R(x)=(25+5x)(28-4x)

=5(5+x)4(7-x)

=20(5+x)(7-x)

=-20(5+x)(x-7)

when x=1 it is maximum

Price when x =1 is 25+5(1)=30

To calculate maximize revenue

R(1)=(25+5)(28-4)

=30(24)

=720

Hence the maximum weekly revenue is $720.

To learn more on Equation:

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Perpendicular bisectors: acute/right/obtuse …… ...

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Step-by-step explanation. Hope this helps lol!

Part A: Rhett made $250 washing cars with his mobile car wash company. He charges $70 per car and earned $50 in tips. Write an equation to represent this situation. (4 points)

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

here 120 degrees would be the same as 15(x+2)

Just like how angle R on the other side of 120 Degrees is the same

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so what you have selected is correct

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Answer:

[Graph] See attached

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Hello there! :)

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Step-by-step explanation:

1.

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2.

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Hope that help! :)

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Step-by-step explanation:

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