A horizontal force is applied to a box with a mass equal to 5.5 kg, The graph shows the net force acting on a box as a function of its horizontal position x.

Part A
Find the net work done on the box as it moves from x = 0 m to x = 8.0 m. .
Part B
Apply concepts of work and energy to solve for the speed of the box when it reaches position x = 8.0 m. Assume the box started from rest.

A Horizontal Force Is Applied To A Box With A Mass Equal To 5.5 Kg, The Graph Shows The Net Force Acting

Answers

Answer 1

From the graph, net work done on the box and  the speed of the box when it reaches position x = 8.0 m are 28 Nm and 3.2 m/s respectively

From the question, these are the given parameters;

Mass M = 5.5 KgPosition X = 0 to X = 8m

Part A

The net work done will be the area under the graph.

From position X = 2m to X = 8m gives us the shape of a trapezium.

A = 1/2( a + b )h

A = 1/2( 2 + 6 ) x 8

A = 8 x 4

A = 32 Nm

From X = 0 to X = 2 gives us the shape of a triangle.

A = 1/2bh

A = 1/2 x 2 x (-4)

A = -4 x 1

A = -4 Nm

Net Work done = 32 - 4

Net work done = 28 Nm

Part B

Applying the concepts of work and energy to solve for the speed of the box when it reaches position x = 8.0 m

Net Work done = 1/2m[tex]V^{2}[/tex]

Substitute all the necessary parameters

28 = 1/2 x 5.5 x [tex]V^{2}[/tex]

5.5[tex]V^{2}[/tex] = 56

[tex]V^{2}[/tex] = 56/5.5

[tex]V^{2}[/tex] = 10.18

V = [tex]\sqrt{10.1818}[/tex]

V = 3.19 m/s

Therefore, net work done on the box and  the speed of the box when it reaches position x = 8.0 m are 28 Nm and 3.2 m/s respectively

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Which type of border shows the division between Sonora and Chihuahua?

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The answer is the national border

What is velocity? Explain.​

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Answer:

The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time. Velocity is equivalent to a specification of an object's speed and direction of motion (e.g. 60 km/h to the north).

What does the diagram show about X and Y?
A They have the same mass and the same volume but different weights.
B They have the same mass and the same weight but different volumes.
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D They have the same weight and the same volume but different masses.

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Answer: answer is c rest of explanation is in the comments

The mass of a car is 2000 lbs, and is traveling 100 mi/hr on the freeway, what is its momentum?

Answers

Answer:

momentum= 145999324.8(kg(m/s))

Explanation:

formula for momentum: p=mv

where p= momentum, m=mass, and v=velocity.

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2000lbs=907.2kg

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100mi=160934meters.

907.2kg(160934m/s)=145999324.8

What will happen if the two plungers are pressed together firmly? Explain your answer.​

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Hope that helps. x

how to find velocity of center of mass before and after the collision

Answers

Hey there! I'll try to provide you with my best answer.

Answer: In a collision, the velocity change is always computed by subtracting the initial velocity value from the final velocity value. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.

how to read a micrometer on a clark cm-100 vickers hardness tester

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Answer:

Explanation:

Equipment manufactured by LECO(8 Corporation, St. Joseph, Michigan is warranted free from defect in material

and workmanship for a period of six months from the date of purchase. Equipment not manufactured by LECO is

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REPRESENTATION OR WARRANTY OF ANY OTHER KIND, EXPRESSED OR IMPLIED, WITH RESPECT TO

THE GOODS SOLD HEREUNDER, WHETHER AS TO MERCHANTABILITY, FITNESS FOR PURPOSE, OR

OTHERWISE.

Expendable items such as crucibles, combustion tubes, chemicals and items of like nature are not covered by

this warranty.

LECO's sole obligation under this warranty shall be to repair or replace any part or parts which, to our

satisfaction, prove to be defective upon return prepaid to LECO Corporation, St. Joseph, Michigan. This

obligation does not include labor to install replacement parts, nor does it cover any failure due to accident, abuse,

neglect, or use in disregard of instructions furnished by LECO. In no event shall damages for defective goods

exceed the purchase price of the goods, and LECO SHALL NOT BE LIABLE FOR INCIDENTAL OR

CONSEQUENTIAL DAMAGES WHATSOEVER.

All claims in regard to the parts or equipment must be made within ten (10) days after Purchaser learns of the

facts upon which the claim is based. Authorization must be obtained from LECO prior to returning any other

parts. This warranty is voided by failure to comply with these notice requirements.

NOTICE

The warranty on LECO equipment remains valid only when genuine LECO replacernent parts are employed.

Since LECO has no control over the quality or purity of consumable products not manufactured by LECO, the

specifications for accuracy of results using LECO instruments are not guaranteed unless genuine LECO

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payment or cure of default in payment shall extend the warranty period provided herein.

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can someone explain it with steps?

A car was moving on a road at a constant speed of 15 m/s when suddenly the car driver saw some animal on the road at a distance of 21 m from the car, so he applied the brakes after a response time of 0.4 s and stopped before hitting the animal by 1 m. What was the deceleration of the car?

a-7.5 m/s^2

b-5.2 m/s^2

c-8.0 m/s^2

d-5.6 m/s^2​

Answers

Answer:

Option C is the correct answer

Explanation:

Distance travelled by car during reaction time

[tex]=15\times0.4\\\\=6m[/tex]

The car stopped before hitting the animal by [tex]1 m[/tex]

Distance travelled during deceleration is [tex]21-6-1=14m[/tex]

Hence by [tex]v^2=u^2+2as[/tex]

We have

[tex]0^2=15^2+2 \cdot a \cdot 14\\\\a=\frac{-225}{28} \\\\=-8.03m/s^2[/tex]

Option C is the correct answer

Initial velocity=15m/s=uFinal velocity=0deacceleration=a

Distance traveled during reaction time

15(0.4)=6m

Total distance

21-6-1=14m

[tex]\\ \sf\longmapsto v^2-u^2=2as[/tex]

[tex]\\ \sf\longmapsto -(15)^2=2(14)a[/tex]

[tex]\\ \sf\longmapsto -225=28a[/tex]

[tex]\\ \sf\longmapsto a=-8.0m/s^2[/tex]

define one kilogram mass ​

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Answer:

kg - one thousand grams; the basic unit of mass adopted under the Systeme International d'Unites; "a kilogram is approximately 2.2 pounds"

Explanation:

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Astronomers think there are between 1.1 and 1.9 million asteroids in the solar system.

Explanation:

what are two variables that are always in every experiment?

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the independent variable and the dependent variable.

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0.60 N, along the line tangent to the circle
0.015 N, along the line tangent to the circle
0.60 N, toward the center of the circle
0.015 N, toward the center of the circle

Answers

Answer:

0.60N along the line tangent to the circle

Answer:

A is the answer

Explanation:

Just got finished with the quiz! Hope this helps <3

You're driving your pickup truck around a curve with a radius of 22 m. A box in the back of the truck is pressed up against the wall of the truck. How fast must you drive so that the force of the wall on the box equals the weight of the box?

Answers

Answer:

Explanation:

Centrifugal force Fc = m x v2 / r

Weight  = mg

As required by the question

Fc = W

v2 /r = g

given radius r = 22 m

v2 /22 = 9.8

Solve for v

required speed v = √(22 * 9.8)

= 14.35 m/s

v=15 m/s

this may help you

The force of the wall on the box equals the weight of the box when you drive with a speed of 14.68 m/s.

What is centrifugal force?

The centrifugal force can be described as an inertial force that appears to act on all objects in a rotating frame of reference. This force is directed away from an axis that is parallel to the axis of rotation and passes through the coordinate system's origin.

The magnitude of centrifugal force of mass m at the distance r from the origin rotating with angular velocity ω is:

[tex]{\displaystyle F=m\omega ^{2}r}[/tex]

Given, the radius of the curve, r = 22m

The acceleration, a = v²/r

The weight of the box, W = mg

We know that, F = ma

mg = m(v²/r)

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v = 14.68 m/s

Therefore, you should drive at a speed of 14.68 m/s

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A cannonball explodes in mid-air, fragmenting into several pieces. How does the total
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III. The momentum of the fragments is more than the momentum of the cannonball

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Hi there!

I. They are the same.

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Answer:

Where are the images?

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I can't help if there is no image(s) to this question.

NEED HELP ASAP PLEASE
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did you end up getting the answer- im struggling

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I would think human error could cause differences like not pressing the stop watch on time.

Explanation:

If the density of gold is 19.3 g/mL, what is the mass of 5mL of gold?​

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Answer:

96.5 mL

Explanation:

*
as the mass of an object increases, the force of attraction...

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Answer:

Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.

Answer:

thanks

Explanation:

for answer byebye


A heating curve is a graph that shows the temperature change of a substance as
thermal energy is introduced.
True
False

Answers

Answer:

This statement is true, a heating curve is a graph that shows the temperature change of a substance as thermal energy is introduced.

A heating curve is a graph that represents the temperature change of a substance as thermal energy is introduced.

What is the heating curve?

The heating curve can be described as the relationship between the heating supply temperature and the outside air temperature of the system. The heating curve gives what temperature the boiler is to heat the water at an outdoor temperature.

Heating curves indicate how the temperature changes as a substance are heated up. Cooling curves are generally the opposite of the heating curve. They indicate how the temperature changes as a substance are cooled down. Similar to heating curves, cooling curves have horizontal parts where the state transforms from gas to liquid/ from liquid to solid.

The heating curve represents the material in phases of solid, liquid, and gas. As this graph is a plot of T v/s q, the slope is 1/mC. As the heating continues, the solid substance melts. During this time the temperature remains constant. The length of the line can be described as the amount of heat required to melt the solid.

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Kepler’s laws of planetary motion describe each of the three laws

Answers

Kepler's laws laid the foundation for the early study of astronomy.

Kepler was one of the earliest astronomers that contributed immensely to the study of the planets. The Kepler's laws of planetary motion are as follows;

The planets each travel along an ellipse with the sun at one focus.The line joining the sun and the planets sweeps out equal areas in equal time intervals.The square of the period of the revolution of the planets equals the cube of the planet's mean distance from the sun.

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Two gravitational forces act on a
given object. How do you determine the total gravita-
tional force acting on the object?

Answers

Answer:

Explanation:

Depends on the location of the two forces.  If they are aligned on the same side of the object, you would simply add.

X -----------F1 -------F2

X is the object. F1 and F2 are both masses which create a gravitational force. They both are the form of Fx = G * m1 * m2 / r^2. The total force is F1 + F2

If they are are on either side of the object, you subtract.

F1 ---------X ---------F2

Fx = F1 - F2

Any other location of F1 and F2 is much more complicated by the use of trigonometry.

how to prove the first linear motion

Answers

Answer:

Then solve for v as a function of t. This is the first equation of motion . It's written like a polynomial — a constant term (v0) followed by a first order term (at). Since the highest order is 1, it's more correct to call it a linear function.

Explanation:

Yep that is correct

can someone explain it please?​

Answers

Answer:

The answer is 9.4 m/s

Explanation:

Because you add 5.0 + 4.5= 9.4

a 3 kg rock is falling from a rock ledge in the absence of air resistance how much force will the rock strikes the ground with

Answers

Answer:

papi sus

Explanation:

How much work is done when mass of 3kg(weighing 30N)is lifted vertically through 6m?

Answers

Answer:

180 [J].

Explanation:

1) the required work [W] can be calculated as difference of the energy: W=E₂-E₁, where E₁=mgh₁ - the energy before lifting, E₂=mgh₂ - the energy after lifting;

2) W=mgh₂-mgh₁, where m - mass; g=10 [N/kg], h - height;

3) then the required work [W]:

W=mg*(h₂-h₁)=30*6=180 [J].

What is the velocity of a dropped object after it has fallen for 3.0 s?

Answers

Answer:

30 m/s.

Explanation:

given the formula p=mv what are the units of p

Answers

Answer:

They are kg * m/s.

The unit of the momentum p would be kg × m/s..

What is momentum?

Momentum is defined as the ability or tendency of an object to continue moving.

Also momentum is the product of mass and velocity. It can be shown as follows;

p = m × v

where,    

p = momentum

m = mass

v = velocity

Thus, we can conclude that the formula p = mv show the relationship between momentum, mass, and velocity.

Now the unit of the momentum p would be;

p = m × v

p = kg × m/s

Hence, the unit of the momentum p would be kg × m/s.

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Here's a question from ~ [ AIEEE 2002 ]

The minimum velocity ( in m/s ) with which a car driver must traverse a flat curve of radius 150 m and Coefficient of friction 0.6 to avoid skidding is ~

[ I'm looking for Proper Information, and please don't get it from any Website ]

Thanks for Answering !​

Answers

r=150mcoefficient of friction=[tex]\mu[/tex]=0.6

As car is avoid skidding

[tex]\\ \sf\hookrightarrow \dfrac{mv^2}{r}=\mu mg[/tex]

Cancel m

[tex]\\ \sf\hookrightarrow \dfrac{v^2}{r}=\mu g[/tex]

[tex]\\ \sf\hookrightarrow v^2=\mu rg[/tex]

[tex]\\ \sf\hookrightarrow v^2=0.6(10)(150)[/tex]

[tex]\\ \sf\hookrightarrow v^2=60(150)[/tex]

[tex]\\ \sf\hookrightarrow v^2=900[/tex]

[tex]\\ \sf\hookrightarrow v=30ms^{-1}[/tex]

Done

The minimum velocity of the with which the car driver must traverse the flat curve to avoid skidding is 29.7 m/s.

The given parameters:

Radius of the curve, r = 150 mCoefficient of friction, μ = 0.6

The minimum velocity of the with which the car driver must traverse the flat curve to avoid skidding is calculated as follows;

[tex]\frac{mv^2}{r} = \mu mg\\\\v^2 = \frac{\mu mgr}{m} \\\\v^2 = \mu gr\\\\v = \sqrt{\mu gr} \\\\v = \sqrt{0.6 \times 9.8 \times 150} \\\\v = 29.7 \ m/s[/tex]

Thus, the minimum velocity of the with which the car driver must traverse the flat curve to avoid skidding is 29.7 m/s.

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the normal formula to find force is F = m*a. What kind of math do you need to do
to find the mass of an object?

- Divide: F / a
- Divide: a / F
- Multiply: F* a
- Subtract: F - a

Answers

[tex]\\ \sf\Rrightarrow F=ma[/tex]

Take a to leftAs it's multiplied on right side it will be divided on right side.

[tex]\\ \sf\Rrightarrow \dfrac{F}{a}=m[/tex]

Or

[tex]\\ \sf\Rrightarrow m=\dfrac{F}{a}[/tex]

A crate slides down a ramp that makes a 20∘ angle with the ground. To keep the crate moving at a steady speed, Paige pushes back on it with a 68 N horizontal force.
Part A
How much work does Paige do on the crate as it slides 3.0 m down the ramp?

Answers

Answer:

the answer is 69.7687j

Explanation:

W =F sin Φ

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